the points (0.5, 1/10) and (7, 1 2/5) are on the graph of a proportional relationship

A. what is the constant of proportionality

B. Name one more point on the graph

C. Write an equation that represents the proportional relationship

The constant of proportionality is 1/5 and the equation of the line is y = (1/5)x

A linear equation is of the form:

y = mx + b

where m is the constant of proportionality, b is the y intercept, y, x are variables.

Given the points (0.5, 1/10) and (7, 1 2/5), hence, the equation of the line is:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-\frac{1}{10} =\frac{\frac{7}{5}-\frac{1}{10} }{7-0.5} (x-0.5)\\\\y=\frac{1}{5} x[/tex]

At x = 0, y = 0. Hence (0,0) is a point on the graph.

Hence the constant of proportionality is 1/5 and the equation of the line is y = (1/5)x

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