The perimeter of the rectangle below is 174 units. Find the length of side BC. Write your answer without variables.

Answers

Answer 1

BC= 39

Explanation:

4z+4z+3z+3+3z+3=174

8z+6z+6=174

14z+6=174

Subtract 6 from both sides

14z=168

Z=12

So then 3*12+3=39

And you can check by doing 39+39+48+48
And it equals 174

Answer 2

The measure of the length of the sides BC of the rectangle will be 24 units.

What is the perimeter of the rectangle?

Let L be the length and W be the width of the rectangle.

Then the perimeter of the rectangle will be

Perimeter of the rectangle = 2(L + W) units

The perimeter of the rectangle below is 174 units.

The length is 3z + 3 and the width is 4z.

Then the value of z will be

174 = 2(3z + 3 + 4z)

87 = 7z + 3

7z = 84

z = 12

Then the measure of the length of the sides BC of the rectangle will be

BC = 3z + 3

BC = 3(7) + 3

BC = 21 + 3

BC = 24 units

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