Answer:
true
Explanation:
2. A box filled with books has a mass of 15.0 kg. It is pushed across the floor with a constant force of 60.0 N. If the frictional force by the floor on the box is 15.0 N, what is the acceleration of the box?
Answer:
[tex]3 m/s^{2}[/tex]
Explanation:
ΣF=ma
The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.
Which of the following is a pure
substance?
A. Heterogenous mixture
B. Homogenous mixture
C. Solution
D. Element
Answer:
B. Homogenous mixture
Explanation:
........
I need help with my homework please?
Answer:
i need the describtion like what i need to do
Explanation:
Answer:
it's easy bro once try yourself if you can't then l am here
2. FAt=p (remember p=mv). A 2.5Jg baseball moving at 8.5m/s to the left is slowed by a tipped
catch to 7.5m/s to the right in 0.25 seconds, what was the force of the tipped catch?
The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
Data obtained from the question Initial velocity (u) = 8.5 m/sFinal velocity (v) = 7.5 m/sTime (t) = 5 ms = 0.25 sMass (m) = 2.5 KgForce (F) = ?How to determine the forceThe force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
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The left side of the armature in an electric motor is pushed down. when the current changes direction, how is the motion of the armature affected? it is pulled up on the left side. it is pulled up on the right side. it is pulled toward the commutator. it is pushed away from the commutator.
Answer:
It is pulled up on the left side. took the test
Explanation:
If I am driving on the highway and see a pig on the road and go from 60m/s to 20 m/s in 5 s. What is my acceleration?
Explanation:
Acceleration = final velocity - initial velocity
______________________
time taken
= 20 m/s - 60m/s
________________
5seconds
= -40 m/s
_______
5 seconds
= -8m/s^2
I need help on this asap!!!!
During which season is the sun highest in the sky?.
Answer: summer
Explanation:
In June, when the Earth is tilted towards Sun and the Sun reaches its highest point in the sky, that is called the summer solsticeand is the longest day of the year.
2. At the earth’s surface, a projectile is launched straight up at a speed of 10. 0 km/s. To what height will it rise? ignore air resist
Answer:
5.097 m
Explanation:
H = vo t - 1/2 a t^2
= 10t - 1/2 (9.81) t^2 max occurs at -b/2a = 10/9.81=1.0194 sec
sub in this 't' value to get H =5.097 m
what particle collides with a fissionable nucleus in order to begin the fission process?
Answer:
neutrons
Explanation:
Neutrons are usually released when fission takes place. Fission of a nucleus may be spontaneous, that is, it may happen at random due to internal processes within the nucleus. Fission can also be induced by bombarding a nucleus with a neutron.
Two charges of +2.6 μC and –5.4 μC experience an attractive force of 6.5 mN. What is the separation between the charges?
Answer:
Explanation:
[tex]q_{1} =+2.6 X10^{_-6}C \\q_{2} =-5.4 X10^{_-6}C \\F=6.5mN\\F=\frac{Kq_{1}q_{2} }{d^{2} }[/tex]
A surfacing whale in an aquarium produces water wave crests having an amplitude of 1.2 meters every 0.40 second. If the water wave travels at 4.5 meters per second, the wavelength of the wave is
The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .
What is wavelength?Wavelength is the total distance traveled by a wave in one cycle.
To calculate the wavelength of the wave, we use the formula connecting
speed, wavelength, and Period.
Formula:
v = λ/T........... Equation 1Where:
v = Velocity of the waveλ = WavelengthT = PeriodMake λ the subject of the equation
λ = vT............ Equation 2From the question,
Given:
v = 4.5 m/sT = 0.40 sSubstitute these values into equation 2
λ = (4.5×0.4)λ = 1.8 mHence, The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .
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You walk 6 meters east followed by 4 meters west in 4 seconds. What is your velocity
Answer:
16 velocity
Explanation:
Place the elements c, n, and o in order of increasing ionization energy
The increasing order for the first ionization energy has been:
< C < N < O.
What is ionization energy?The first ionization energy has been the amount of energy required for removing the electron from the gaseous state. The molecules that have small structures and available valence electrons, the ionization energy has been decreased.
In the periodic table, on moving from left to right there has been an increase in the size of the atom, as well as the valence electrons. The increase in size results in more attraction by the nucleus resulting in increased first ionization energy.
The increasing order for the first ionization energy has been:
C < N < O.
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A 1.5 x 105 kg train is accelerating. The force applied to the train is 7.0 x 104 N. What is the train’s acceleration?
Answer:
See below
Explanation:
F = ma
7 X 10^4 = 1.05 x 10^5 * a
a = .666 = 2/3 m/s^2
You throw a ball straight up into the air with velocity 40 ft/sec and catch it (at the same height) when it comes back down. What is the total distance traveled by the ball
The total distance traveled by the ball is determined as 49.68 ft.
Height travelled by the ball
The height travelled by the ball or the maximum height attained by the ball is calculated as follows;
v² = u² - 2gh
at maximum height, v = 00 = u² - 2gh
2gh = u²
h = u²/2g
h = (40²)/(2 x 32.2)
h = 24.84 ft
Total distance = 2 x 24.84 ft = 49.68 ft
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An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 ev, 27 ev, and 48 ev
Answer:
l=3.5 x 10^-10m
Explanation:
just toook the test got it right good luck!
Identify the amplitude of the wave using the picture below.
Answer:
Line 2 is the amplitude
Explanation:
The amplitude is the distance from equilibrium to the top of the maximum or minimum of the wave.
Name one energy source that is used to make sure that we can provide energy consistently,even though demand varies during the day
Answer:
Water power, eg tidal and hydroelectricity , is reliable and predictable because of the Moon causing the tides and rainfall filling reservoirs. They can also be used to supply additional demand.
Explanation:
HOPE IT HELPS.
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How far away is the closest star?
Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away.
Explanation:
Answer:
The closest star is about 25,300,000,000,000 miles (39,900,000,000,000 kilometers) away
Explanation:
You really have a thing for screaming outside. So on a day where the speed of sound is 343 m/s you go outside and scream at a wall. It takes 0.5 s for you to hear your echo. How far away is the wall that you screamed at?
A radar transmits a signal towards an aeroplane. The velocity of the signal is 3.0 x 10^8 m/s. After 0.0036 s, the radar detects the reflected signal. What is the distance of the aeroplane from the radar?
The distance of the airplane from the radar will be 1.08×10⁶ m. Distance can refer to a physical length.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
The distance of the airplane from the radar is found by the formula;
Distance = velocity × time
Distance = 3.0 x 10^8 m/s× 0.0036 s,
Distance = 1.08×10⁶ m.
Hence, the distance of the airplane from the radar will be 1.08×10⁶ m.
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Two beams of coherent light are shining on the same piece of white paper. with respect to the crests and troughs of such waves, darkness will occur on the paper where
Answer:
"where crests and troughs have their maxima at the same time"
Crests and troughs are 180 deg out of phase and when they have their maxima at the same time and place, their net contribution will be zero"
For a bike that went a distance of 100 meters in 45 seconds
southeast to his friend's house. what would his velocity be?
Answer:
velocity = Displacement
Time
Velocity = 100m 45° SE
45s
= 2. 11m/s 45° SE
A proton moves with a speed of 0. 985c. (a) calculate its rest energy
The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.
What is rest energy?The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.
The rest energy is found as;
[tex]\rm E_R= mC^2\\\\ E_R=(1.67 \times 10^{-27})\times 3 \times 10^8)^2\\\\ E_R= 9.375 \times 10^8 / eV[/tex]
Convert into the mega electron volt;
[tex]\rm E_R= 938 \ MeV[/tex]
Hence, the rest energy of the proton will be 938 MeV
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If air resistance acts on a falling object will all of its potential energy be converted into kinetic energy?
Answer:
No, some energy will be dissipated energy due to work of air resistance.
Which section from the article BEST explains why wavelength and frequency are dependent on each other? (A) "Amplitude And Height" (B) "Wavelength And Cycle" (C) "Frequency And Period" (D) "Speed"
help please!
will give brainliest to the correct answer.
question; the work one by friction force to stop a car of mass 1000 kg moves with velocity 72km/h is ..........
a) 72 x 10³ J
b) 2 x 10⁴ J
c) 2 x 10⁵ J
d) 4 x 10⁵ J
an explanation for future reference would be appreciated^^
Answer:
b)
Explanation:
The work done by friction is equal to the all of the initial Kinetic Energy lost when the vehicle comes to a complete stop
KE = 1/2 m v^2
72 km / hr = 20 m/s
KE = 1/2 * 1000 kg * (20 m/s)^2 = 200 000 J = 2 x 10^4 J
A tube is open only at one end. A certain harmonic produced by the tube has a frequency of 475 hz. The next higher harmonic has a frequency of 1425 hz. The speed of sound in air is 343 m/s
The formula for the fundamental frequency for an open tube at one end is : F = nV/4L the integer n = 3 which describe the frequency 450 hertz and length of tube L = 0.6m approximately
What is frequency?Frequency of the object is defined as the number of cycles attend in a second .
Given that a tube is open only at one end. And a certain harmonic produced by the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The formula for the fundamental frequency for an open tube at one end is :
[tex]F = \dfrac{V}{4L}[/tex]
That is, 1st harmonic
[tex]\dfrac{V}{4L} = F[/tex]
2nd harmonic =
[tex]\dfrac{3V}{4L} = 3F[/tex]
3rd harmonic =
[tex]\dfrac{5V}{4L} = 5F[/tex]
The general formula can therefore be [tex]F =\dfrac{ nV}{4L}[/tex]
For the first harmonic in the question,
[tex]450 = \dfrac{343n}{4L}[/tex]
make 4L the subject of the formula
[tex]4L = \dfrac{343n}{450}[/tex]
The next higher harmonic will be
[tex]750 = \dfrac{343(n + 2)}{4L}[/tex]
make 4L the subject of the formula
[tex]4L = \dfrac{343(n + 2)}{ 750}[/tex]
Equate the two 4L
[tex]\dfrac{343n}{450} = \dfrac{343( n + 2)}{750}[/tex]
cross multiply
[tex]257250n = 154350( n + 2 )[/tex]
[tex]257250n = 154350n + 308700[/tex]
collect the likes term
[tex]257250n - 154350n = 308700[/tex]
[tex]102900n = 308700[/tex]
[tex]n =\dfrac{ 308700}{102900}[/tex]
n = 3
Given that the speed of sound in air is 343 m/s, The length of the tube can be calculate by using the same formula.
[tex]F = \dfrac{nV}{4L}[/tex]
[tex]450 = \dfrac{3(343)}{4L}[/tex]
[tex]4L = \dfrac{1029}{450}[/tex]
4L = 2.28
[tex]L = \dfrac{2.28}{4}[/tex]
L = 0.57 m
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An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due to gravity on the planet to be 12m/s2, and the mass of the planet is measured to be 7. 5E23kg. What is the radius of the new planet?
Answer:
The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.
Explanation:
We can use Newton's Law of Universal Gravitation:
[tex]\displaystyle F_g=G\frac{Mm}{r^2}[/tex]Let's look at Newton's 2nd Law:
[tex]F=ma[/tex]We can set these equations equal to each other:
[tex]\displaystyle G\frac{Mm}{r^2} =ma[/tex]The mass of the second mass (astronaut) cancels out. We are left with:
[tex]\displaystyle G\frac{M}{r^2} =a[/tex]We are solving for the radius of the new planet, so we can rearrange the equation:
[tex]\displaystyle r=\sqrt{\frac{GM}{a} }[/tex]Substitute in our known values given in the problem (G = 6.67 * 10⁻¹¹ ; M = 7.5 * 10²³ ; a = 12).
[tex]\displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }[/tex][tex]r=2.04 \times 10^6[/tex]The radius of the new planet is ~2.04 * 10⁶ m.
