The distance of the point (5, -1) from the y axis is *

Answer:   1.4

Work Shown:

42 cupcakes : 30 minutes

42/30 cupcakes : 30/30 minutes

1.4 cupcakes : 1 minute

The unit rate is 1.4 cupcakes per minute. This assumes that the rate is kept the same.

Answer:

0.4

Step-by-step explanation:

Fraction =2/5

In decimal =0.4

Answer:

x^2 -root 15 +o = 0

Step-by-step explanation:

x^2 - (x+y) + xy

x^2 -root 15 +o = 0

Answer:

It would be 127

Step-by-step explanation:

We see that they only have 127 common in their prime factorization. Hence, HCF(1651, 2032) = 127. Hence, the greatest number which divides 1657 and 2037 leaves a remainder of 6 and 5 respectively is 127.

Answer:

B. -2

Step-by-step explanation:

Slope (m) =  

ΔY

ΔX

=  

-2

1

= -2

θ =  

arctan( ΔY ) + 360°

ΔX

= 296.56505117708°

ΔX = 3 – 0 = 3

ΔY = -2 – 4 = -6

Distance (d) = √ΔX2 + ΔY2 = √45 = 6.7082039324994

Answer from Gauth math

Answer:

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.

Answer:

2 and 3

Step-by-step explanation:

In equation 3, if you move the 3x to the other side, 5y = -1 + 3x then it's would be the same as equation 2

Answer:

5/3

Step-by-step explanation:

1) The denominator will be multiply to the whole number to find the improper fraction. 3 (denominator) x 1 (whole number)

2) 1 plus 2 (numerator) equal 5

3) Always keep the denominator (3) for you improper fraction.

4) 5 will be the numerator and 3 will be the denominator.

5/3

Answer: The Surface area is 72 units

Step-by-step explanation:

2*(3*6+2*6+2*3)=72

Answer:

Does the answer help you?

Answer:

6/(x + 4)(x - 2)

Step-by-step explanation:

(12x - 96)/(x² - 4x - 32) ÷ (6x² - 6x - 12)/(3x + 3)

12x - 96 = 12(x - 8)

x² - 4x - 32 = (x - 8)(x + 4)

(12x - 96)/(x² - 4x - 32) = 12/(x + 4)

6x² - 6x - 12 = (3x + 3)(2x - 4)

(6x² - 6x - 12)/(3x + 3) = 2x - 4 = 2(x - 2)

(12x - 96)/(x² - 4x - 32) ÷ (6x² - 6x - 12)/(3x + 3) = 12/(x + 4) ÷ 2(x - 2) = 12/(x + 4) × 1/2(x - 2) = 6/(x+4)(x-2)

Answer:

AE = 18 units

Step-by-step explanation:

Δ AEB and Δ DEC are similar , then corresponding sides are in proportion, that is

[tex]\frac{AE}{DE}[/tex] = [tex]\frac{AB}{DC}[/tex] , substitute values

[tex]\frac{2x+4}{x+8}[/tex] = [tex]\frac{12}{10}[/tex] ( cross- multiply )

10(2x + 4) = 12(x + 8) ← distribute parenthesis on both sides

20x + 40 = 12x + 96 ( subtract 12x from both sides )

8x + 40 = 96 ( subtract 40 from both sides )

8x = 56 ( divide both sides by 8 )

x = 7

Then

AE = 2x + 4 = 2(7) + 4 = 14 + 4 = 18 units

Answer:

If the area of a circular rose garden is 44 square meters, then we can write:

44 = πr^2

And since π is equal to  22/7, we have:

44 = 22/7(r^2)

Multiply both sides by 7/22 to cancel the 22/7:

14 = r^2

And finally, we see that the radius of the garden is:

[tex]\sqrt{14}[/tex]

Let me know if this helps!

Answer:

r = sqrt(14)

Step-by-step explanation:

The area of a circle is

A = pi r^2

44 = 22/7 * r^2

Multiply each side by 7/22

44 * 7/22 = 22/7 * 7/22 r^2

14 = r^2

Take the square root of each side

±sqrt(14) = r

The radius must be a positive length

r = sqrt(14)

12= 1*5^1+2*5^0

5+2

7

34=3*5^1+4*5^0

15+4

19

42=4*5^1+2*5^0

20+2

22

120=1*5^2+2*5^1+0*5^0

25+10+0

35

213=2*5^2+1*5^1+3*5^0

100+5+3

108

430=4*5^2+3*5^1+0*5^0

400+15+0

415

quinary

Answer:

x=10

y=-9

Step-by-step explanation:

eqn 2-1

-1x+10=0

x=10

in eqn 1

y=-2 ×10+11

-20+11

-9

Answer:

c = 12

Step-by-step explanation:

i'm Attaching the work

Answer:

D

Step-by-step explanation:

Simply because 25 is divisible by 5.

Answer:

x = 17

Step-by-step explanation:

-2x + 8 = -26

Subtract 8 from each side

-2x + 8-8 = -26-8

-2x = -34

Divide each side by -2

-2x/-2 = -34/-2

x = 17

Answer:

The answer is x=17

Step-by-step explanation:

−2x+8−8=−26−8

−2x=−34

−2x /−2 = −34 /−2

x=17

The ratio for Nine people fit comfortably in a 3ft by 3ft area is [tex]\frac{9}{3X3}[/tex]

Option C [tex]Ratio =\frac{9}{3X3}[/tex]

Size of crowd: [tex]\frac{9}{3 \cdot 3} \cdot 24 \cdot 5280[/tex]

Given :

Nine people fit comfortably in a 3 ft. by 3 ft. area

To find : we need to estimate the size of a crowd that is 8 feet deep and 1 mile long. we need to determine the ratio as well

Ratio = number of people / total area

[tex]Raio=\frac{9}{3X3}[/tex]

To find the size of the crowd , convert yards into feet and mile into feet

1 yard = 3 miles

8 yards= 3 times 8 = 24 feet

1 mile = 5280 feet

Now we find the area in feet

[tex]24 \cdot 5280[/tex]

size of the crowd=ratio times the area in feet

[tex]\frac{9}{3 \cdot 3} \cdot 24 \cdot 5280[/tex]

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Answer:

7

Step-by-step explanation:

Let the each leg be x so,

√(x²+x²)=√98

or, √(2x²)=√98

or, x√2=7√2

or, x=7

Answer:

In factor form, the answer is ---> 8a^2b

Step-by-step explanation:

2³a²b

= (2^3) (a^2) b

= 8a^2b

The number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers

Since there are 10 digits in our number system from 0 to 9, and we are looking for the number of different 8-digit phone numbers that do not contain the digit 2, we would be one digit short. So, for each digit position, we would have 10 - 1 digits = 9 digits.

Since we have 8 places for each digits, for the first place, we have 9 digits. For the second place, we have another 9 digits and so on till we get to the 8 th digit place.

So, for all 8 digit places, we have 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 = 9⁸.

So, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 9⁸ numbers = 43046721 numbers.

Thus, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers.

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Answer:

it's most most probably option d becoz I studied In different way so... as per me d ... figure is quite diff but d

Answer:

hhbnnnnkkkkkkkkkkkkkijkkiikkkk

Answer:

d=1, r=4/3

Step-by-step explanation:

For aritmetic sequence

a1=9

a1+3d=a4    9+3d=a4.

a1+7d=a8    9+7d=a8.

For geometric sequence

b1*r=b2

b2=a4, b1=a1=9

9*r=a4

b3= b1*r^2

b3=a8

a8=9*r^2

So 9+3d=a4

9+3d=9r

9+7d= a8=9r^2

So we have a system of equations

9+3d=9r

9+7d=9r^2

Multiply 9+3d=9r by -7 It is equal to -63-21d=-63r

And multiply 9+7d=9r^2 by 3. It is equal to 27+21d=27r^2

Then add them

-63-21d+ (27+21d)= -63r+27r^2

-36+63r-27r^2=0 /9

-4+7r-3r^2=0

3r^2-7r+4=0

r=1 r=4/3

If r=1 9+3d=9

d=0 (It is not right, d isn't equal to 0)

If r=4/3

9+3d= 9*4/3

9+3d=12

d=1

The value of the common difference,  d is 9

The value of the common ratio r is 2

The nth term of an arithmetic sequence is:

[tex]T_n=a+(n-1)d[/tex]

The first, fourth, and eighth terms are therefore:

a,  a + 3d,  a + 7d

The nth term of a geometric sequence is:

[tex]T_n=ar^{n-1}[/tex]

The first three terms of the arithmetic sequence are:

[tex]a, ar^2, ar^3[/tex]

For both sequences, the first term is 9

That is, a = 9

[tex]a+3d=ar^2\\\\9+3d=9r^2..............(1)\\\\a+7d=ar^3\\\\9+7d=9r^3..........(2)[/tex]

Make d the subject of the formula in equation (1) and substitute to equation (2)

[tex]d=\frac{9r^2-9}{3} \\\\d=3r^2-3[/tex]

Substitute equation (3) into equation (2)

[tex]9+7(3r^2-3)=9r^3\\\\9+21r^2-21=9r^3\\\\21r^2-9r^3=12\\\\7r^2-3r^3=4\\\\r=1, \frac{-2}{3}, 2[/tex]

Substitute r = 2 into (1)

[tex]9+3d=9(2^2)\\\\d = 9[/tex]

The value of the common difference,  d is 9

The value of the common ratio r is 2

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Answer:

D

Step-by-step explanation:

The correct option is the Car stops at a distance away from the starting point because the portion shows a constant function away from the starting point.

From the graph we can tell that the distance of the car is a function and it's a line

Answered by G a u t h m a t h

Answer:

9/8 or 1.125

Step-by-step explanation:

We want to find the area of a rectangular postage stamp

The area of a rectangle can be found by multiplying the length by the width

Given length: 3/2

Given width: 3/4

Area = 3/2 * 3/4 = 9/8 or 1.125

The area of a 2D form is the amount of space within its perimeter. The area of the stamp in square inches is 1 1/8 inches².

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm², m², and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

Given that a rectangular postage stamp has a length of 3/2 inches and a width of 3/4 inch. Therefore, the area of the stamp in square inches is,

Area of the stamp = Length × Width

                              = 3/2 inches × 3/4 inches

                              = 9/8 inches²

                              = 1 1/8 inches²

Hence, the area of the stamp in square inches is 1 1/8 inches².

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#SPJ2

Answer:

x = [tex]-\frac{2}{3}[/tex]

Step-by-step explanation:

I used the FOIL method

[(2x + 3) (3x + 2)] − [(3x + 2) (2x− 3)] = 0

[tex](6x^{2} +4x+9x+6) - (6x^{2} -9x+4x-6)=0[/tex]

[tex](6x^{2} +13x+6) - (6x^{2} -5x-6)=0[/tex]

[tex](6x^{2} +13x+6) - 6x^{2} +5x+6=0[/tex]

combine like terms

[tex]6x^{2} -6x^{2} = 0[/tex]

[tex]13x+5x=18x[/tex]

[tex]6+6=12[/tex]

so, [tex]18x +12 = 0[/tex]

subtract 12 on both sides

[tex]18x=-12[/tex]

divide by 18 to isolate x

[tex]x=-\frac{12}{18}[/tex]

and simplifies to

[tex]x=-\frac{2}{3}[/tex]

Answer:

3x³ + 16x² + 12x - 16

Step-by-step explanation:

(x - -4)(3x² + 4x - 4)

(x + 4) (3x² + 4x - 4)

3x³ + 4x² - 4x + 12x² + 16x - 16

3x³ + 4x² + 12x² - 4x + 16x - 16

3x³ + 16x² + 12x - 16

9514 1404 393

Answer:

  BC = 5

Step-by-step explanation:

Of course, this geometry program can tell you the length of BC.

__

If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...

  BF = 4 -1 = 3

  FC = 4 -0 = 4

  BC² = BF² +FC²

  BC² = 3² +4² = 9 +16 = 25

  BC = √25

  BC = 5

Answer:

[tex]55[/tex]

Step-by-step explanation:

We'll be using case-work to solve this problem. Let's call the ones digit of the telephone number [tex]B[/tex] and the tens digit [tex]A[/tex]. Each telephone number can be represented as [tex]AB[/tex].

Since the question states that numbers that are smaller when their digits are reversed are not used, we have the following inequality:

[tex]B\geq A[/tex]

This is because if [tex]A>B[/tex], the number would become smaller when [tex]A[/tex] and [tex]B[/tex] are switched in [tex]AB[/tex]. However, if [tex]A=B[/tex] or [tex]B>A[/tex], the number will not become smaller.

Let's work our way up starting with [tex]A=0[/tex]. If [tex]A=0[/tex], there are 10 other numbers (0-9) that we can choose for [tex]B[/tex] that adhere to the condition [tex]B\geq A[/tex]:

[tex]0B,\\01, 02, 03,...[/tex]

Therefore, there are 10 possible telephone numbers when the tens digit is 0.

Repeat the process, now assigning [tex]A=1[/tex]. Now, we only have the digits 1-9 to choose from for [tex]B[/tex], since [tex]B[/tex] needs to be greater than or equal to A. Therefore, there are 9 possible telephone numbers when the tens digit is 1.

This pattern continues. As we work our way up through the cases (when increasing [tex]A[/tex] by 1), the number of possible telephone numbers decreases by 1, since there becomes one less option for [tex]B[/tex].

The last case would be [tex]A=9[/tex] in which case there would only be one option for [tex]B[/tex] and that would be 9.

Since there are 10 cases (0-9), add up the possible telephone numbers for each case:

[tex]\displaystyle \sum_{n=1}^{10}n=1+2+3+4+5+6+7+8+9+10=\boxed{55}[/tex]

Alternatively, recall that the sum of this series can be found using [tex]\frac{n(n+1)}{2}[/tex], where [tex]n[/tex] is the number of values in the set. In this case, [tex]n=10[/tex], and we have:

[tex]1+2+3+4+5+6+7+8+9+10=\frac{10(11)}{2}=\frac{110}{2}=\boxed{55}[/tex]