The diameter of a sphere is 4 cm. Which represents the volume of the sphere?

32/3 πcm^3

8 πcm^3

64/3 πcm^3

16 π cm^3

Answer:

Step-by-step explanation:

                 Statement                                                 Reasons

1). Line PQ is an angle bisector of ∠MPN       D). Given

2). ∠MPQ ≅ ∠NPQ                                           A). Definition of angle bisector

3). m∠MPQ = m∠NPQ                                      F). Definition of congruent

                                                                               angles.

4). m∠MPQ + m∠NPQ = m∠MPN                    C). Angle addition postulate

5). m∠MPQ + m∠MPQ = m∠MPN                   G). Substitution property of

                                                                                equality

6). 2(m∠MPQ) = m∠MPN                                 B). Distributive property

7). m∠MPQ = [tex]\frac{1}{2}(m\angle MPN)[/tex]                               E). Division property of equality  

Considering the given function, we have that:

a) 28.31 years.

b) 0.3382 years a decade.

c) 2.6184.

The median age of the U.S. population in t decades after 1960 is:

f(t) = -0.2176t³ + 1.962t² - 2.833t + 29.4.

1970 is one decade after 1960, hence the median was:

f(1) = -0.2176 x 1³ + 1.962 x 1² - 2.833 x 1 + 29.4 = 28.31 years.

The rate of change was is the derivative when t = 1, hence:

f'(t) = -0.6528t² + 3.924t - 2.933

f'(1) = -0.6528 x 1² + 3.924 x 1 - 2.933 = 0.3382 years a decade.

The second derivative is:

f''(t) = -1.3056t + 3.924

Hence:

f''(1) = -1.3056 x 1 + 3.924 = 2.6184.

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i think this could be the answer

Answer:

10

Step-by-step explanation:

ok so you do 12/30 and u get a 0.4 ratio. boom multiply 0.4 by 25 and u get 10. so boom the length is 10

Answer:

XY=10

Step-by-step explanation:

Since they are similar the ratio between each sides should be the same.

Ratio is .4. Found by dividing 12/30.

Multiply .4 by 25= 10

Hi there!  

»»————-　★　————-««

I believe your answer is:  

"Add 4 to both sides, and then divide by 2. The solution is x = 12."

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2x - 4 = 20\\------------\\\rightarrow 2x - 4 + 4 = 20 + 4\\\\\rightarrow 2x = 24\\\\\rightarrow \frac{2x=24}{2}\\\\\rightarrow \boxed{x = 12}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

12 sundaes

Step-by-step explanation:

Answer:

a+b=c+d/2

i cant understand what answer you want

Answer:

This the right order:

4^2+2^2 = 20

5^2= 25

6^2-6 = 30

Answer:

r^9/r^3 = r^9-3 = r^6

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]r^6[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Simplifying...}}\\\\\frac{r^9}{r^3} \\--------------\\\\\text{Recall the quotient rule:}} \frac{a^x}{a^y}=a^{x-y}\\\\\rightarrow \frac{r^9}{r^3}\\\\\rightarrow r^{9-3}\\\\\rightarrow \boxed{r^6}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

litrally I don't understand what you are telling

Answer:

Sin43 = x/13

x= 13* sin43

x= 8.865

Answer:

8.9

Step-by-step explanation:

using sine rule

[tex] \frac{x}{sin \: 43} = \frac{13}{sin \: 90} [/tex]

cross multiply

x sin 90=13 sin 43

x=13 sin 43

x=8.9

Answer:

its the same above

Step-by-step explanation:

For engineering, it would be very useful to know Pythagorean theorem. You can use it to measure the tension in each ropes.

Answer:

x = 12

y = -29

Step-by-step explanation:

Our given equations: x + y = -17 and x - y = 41

Solve for x and substitute.

x = -17 - y

(-17 - y) - y = 41

-17 - 2y = 41

2y = -58

y = -29

Solve for x using y

x + (-29) = -17

x = 12

Binomial probability states that the probability of x successes on n repeated trials in an experiment which has two possible outcomes can be obtained by

(nCx).(p^x)⋅((1−p)^(n−x))

Where success on an individual trial is represented by p.

In the given question, obtaining heads in a trial is the success whose probability is 1/2.

Probability of 6 heads with 6 trials = (6C6).((1/2)^6).((1/2)^(6–6))

= 1/(2^6)

= 1/64

Answer:

g+b

number of girls+number of boys

if i am incorrect forgive me plz

The expression for the total number of children in a room is g+ b.

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Addition is the process of finding the total, or sum, by combining two or more numbers or variables.

According to the given question

We have

Number of girls = g

And, number of boys = b

Therefore, the expression for the total number of children in room is given by

Total number of children = g + b

Hence, the expression for the total number of children in a room is g+ b.

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9514 1404 393

Answer:

  a) quadrant III

  b) 4π/3, -2π/3

  c) (1/2, (√3)/2)

  d) ((√3)/2, -1/2

Step-by-step explanation:

a) The attachment shows the point P and the numbering of the quadrants (in Roman numerals). Point P lies in quadrant III.

__

b) Measured counterclockwise, the angle to point P is 240° or 4π/3 radians. Measured clockwise, the angle is -120° or -2π/3 radians. In the diagram, these are shown in green and purple, respectively.

__

c) Adding π/2 to the angle 4π/3 or -2π/3 brings it to 11π/6, or -π/6. This point is marked as P' (blue) on the diagram. The coordinate transformation for π/2 radians CCW rotation is ...

  (x, y) ⇒ (-y, x)

  P(-1/2, -√3/2) ⇒ P'(√3/2, -1/2)

In terms of trig functions, the coordinates of the rotated point are ...

  P'(cos(-π/6), sin(-π/6)) = P'(√3/2, -1/2)

__

d) Adding or subtracting π radians to/from the angle moves it directly opposite the origin. Both coordinates change sign. This point is P'' (red) on the diagram.

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Calculus

Differentiation

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Step 3: Integrate Pt. 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

See explanation

Step-by-step explanation:

2) (10+4) x 2 = 28

3) (13 + 6) x 2 = 38

4) (8+4) x 2 = 24

5) (11+8) x 2 = 38

Answered by Gauthmath

Answer:

Poggers

Step-by-step explanation:

Answer:

[tex]55385[/tex]

words

Step-by-step explanation:

because

I) we have given 55 words

ii) we have given a time 20 seconds

iii) then we multiple 55 ×1007

iv) the answer will be 55385

Answer: (d)

Step-by-step explanation:

Given

There are six flavors of ice-cream that is chocolate, vanilla, strawberry, birthday cake, rocky road, and butter pecan

First ice-cream can be tasted in 6 different ways

Second can be in 5 ways

similarly, remaining in 4, 3, 2 and 1 ways

Total no of ways are  [tex]6\times5\times 4\times 3\times 2\times 1=720\ \text{ways}[/tex]

Option (d) is correct.

Answer:

Here we only need to analyze the vertical motion of the ball.

First, because the ball is in the air, the only force acting on the ball will be the gravitational force (we are ignoring air resistance), then the acceleration of the ball is equal to the gravitational acceleration, so we have:

a(t) = -32 ft/s^2

where the negative sign is because this acceleration is downwards.

To get the velocity equation, we need to integrate over the time, so we get:

v(t) = (-32 ft/s^2)*t + V0

where V0 is the initial velocity of the ball. In this case, the initial velocity of the ball will be the velocity that the ball had when it was dropped, which should be the same as the velocity of the hot air ballon, so we have:

V0 = 12 ft/s

Then the velocity equation of the ball is:

v(t) = (-32 ft/s^2)*t + 12 ft/s

To get the position equation we integrate again:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (12 ft/s)*t + H0

Where H0 is the initial height. We know that the ball was released at the height of 1120 ft, then we have:

H0 = 1120 ft.

Then the position equation is:

p(t) = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft

a)  How many seconds after its release will the ball strike the ground?

The ball will strike the ground when its position equation is equal to zero, then we need to solve:

p(t) = 0 ft = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft

This is just a quadratic equation, the solutions are given by Bhaskara's formula, so the solutions for t are:

[tex]t = \frac{- 12ft/s \pm \sqrt{(12 ft/s)^2 - 4*(-16ft/s^2)*(1120 ft)} }{2*(-16ft/s^2)}[/tex]

We can simplify that to get:

[tex]t = \frac{-12ft/s \pm 268ft/s}{-32ft/s^2}[/tex]

So we have two solutions:

[tex]t = \frac{-12ft/s + 268ft/s}{-32ft/s^2} = -8s[/tex]

[tex]t = \frac{-12ft/s - 268ft/s}{-32ft/s^2} = 8.75s[/tex]

The negative solution does not make sense, then the correct solution is the positive one.

We can conclude that the ball will hit the ground after 8.75 seconds.

b)  At what velocity will it hit the ground?

We already know that the ball strikes the ground 8.75 seconds after it is released.

The velocity at it hits the ground is given by the velocity equation evaluated in that time:

v(8.75 s) = (-32 ft/s^2)*8.75s + 12 ft/s = -268 ft/s

Answer:

[tex]\displaystyle x \approx -4.28[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 1 = ln(x + 7)[/tex]

Step 2: Solve for x

e^1 = x+7

e - 7 = x

x = -4.28

Answer:

The equation of the parabola with a focus at (2,4) and a directrix of y=8 is,

48-8y=(x-2)²

Answer

the simplied form of the given question is 1

Option 4

Answered by Gauthmath must click thanks and mark brainliest

Answer:

Option (C)

Step-by-step explanation:

Coordinates of the point representing the location of Miya → (1, 10)

Coordinates of the point representing the location of Drea → (13, 1)

Coordinates of the point representing the location of Francine → (16, 1)

Coordinates of the point representing the location of Beach → (19, 4)

Distance between Miya and Drea = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                                                        = [tex]\sqrt{(13-1)^2+(1-10)^2}[/tex]

                                                        = [tex]\sqrt{144+81}[/tex]

                                                         = 15 miles

Distance between Drea and Francine = [tex]\sqrt{(16-13)^2+(1-1)^2}[/tex]

                                                               = 3 miles

Distance between Francine and Beach = [tex]\sqrt{(19-16)^2+(4-1)^2}[/tex]

                                                                  = [tex]\sqrt{9+9}[/tex]

                                                                  ≈ 4.2 miles

Total distance between Miya and the beach = 15 + 3 + 4.2

                                                                          = 22.2 miles

Option (C) is the answer.