A = πr^2 and d = 2r.
So r = 8/2 = 4 cm.
Now use the first formula
A = π(4 cm)^2 = 50.265 cm^2
here's a graph of a linear function write the equation that describes the function express it in slope-intercept form
Answer:
y = 3/4 x - 3
Step-by-step explanation:
the slope of a line is the factor of x in the equation and is expressed as ratio of y/x : defining how many units y changes, when x changes a certain number of units.
in our graph here we can see that when increasing x from e.g. 0 to 4 (the x-axis intercept point, a change of +4), y changes from -3 to 0 (a change of +3).
so, the slope and factor of x is y/x = 3/4
and for x=0 we get y=-3 as y-axis intercept point.
so, the line equation is
y = 3/4 x - 3
Which graph shows the quadratic function y = 3x2 + 12x + 10? (5 points)
The following graph is labeled A: A four quadrant graph with a parabola opening up, passing through the points negative 3, 1, negative 2, negative 2, and negative 1, 1 with the vertex at 2, negative 2. The following graph is labeled B: A four quadrant graph with a parabola opening up, passing through the points 1, 4, 2, 1, and 3, 4 with the vertex at 2, 1. The following graph is labeled C: A four quadrant graph with a parabola opening up, passing through the points negative 3, 5, negative 2, 2, and negative 1, 5 with the vertex at negative 2, 2. The following graph is labeled D: A four quadrant graph with a parabola opening up, passing through the points 1, 1, 2, negative 2, and 3, 1 with the vertex at 2, negative 2.
Answer:
The correct graph is A.
Answer:
A i got it right
Step-by-step explanation:
Match each division expression to its quotient
[tex]\frac{122}{10}*(-\frac{10}{61} )[/tex]Let's start by calculating their values one by one, and then we can match them.
Starting with [tex]-2\frac{2}{5} \div\frac{4}{5}[/tex], we can simplify this more by adding [tex]2*5[/tex] to the nominator. That gives us [tex]-\frac{12}{5} \div\frac{4}{5}[/tex]. Now we can apply the Keep-Change-Flip rule. Keep the first fraction as it is, change the division sign into multiplication, flip the second fraction. [tex]-\frac{12}{5} *\frac{5}{4}[/tex]. We apply fraction multiplication which is simply multiplying the first nominator by the first nominator and the same for the dominator. and the result is [tex]-\frac{60}{20}[/tex] or simply -3.
[tex]-2\frac{2}{5} \div\frac{4}{5} = -3[/tex]
Now, we calculate the second one, [tex]-12.2\div(-6.1)[/tex]. This can be re-written as [tex]-\frac{122}{10}\div(-\frac{61}{10} )[/tex]. As we did in the previous part we apply the Keep-Change-Flip, this will give us [tex]-\frac{122}{10}*(-\frac{10}{61} )[/tex]. Do the multiplication and the result will be [tex]\frac{1220}{610}[/tex], we can divide both the nominator and dominator by 10 which will result [tex]\frac{122}{61}[/tex] and finally we know that [tex]61*2=122[/tex] and we can divide both of them again by 61 which will result [tex]\frac{2}{1} =2[/tex]
[tex]-12.2\div(-6.1)=2[/tex]
You can try solving the rest by yourself but here's is the final answer for them both:
[tex]16\div(-8)=-2\\3\frac{3}{7} \div1\frac{1}{7} =3[/tex]
John borrowed a certain amount of money from Tebogo at a simple interest rate of 8,7% per year. After five years John owes Tebogo R10 000.Calculate how much money John initially borrowed
Both before and after a recent earthquake, surveys were conducted asking voters which of the three candidates they planned on voting for in the upcoming city council election. Has there been a change since the earthquake? Use a level of significance of 0.05. Table shows the results of the survey. Has there been a change in the distribution of voter preferences since the earthquake?
Peter Alan Sui
Before 1838 418 1475
After 1420 329 1140
What is the chi-square test-statistic for this data?
χ2=_____.
Answer:
0.05547
Step-by-step explanation:
Given :
_____Peter __ Alan __ Sui__total
Before 1838 __ 418 ___1475 _3731
After _ 1420 __ 329 ___1140_2889
Total _3258 __ 747 __ 2615 _6620
The expected frequency = (Row total * column total) / N
N = grand total = 6620
Using calculator :
Expected values are :
1836.19 __ 421.006 __ 1473.8
1421.81 ___325.994__ 1141.2
χ² = Σ(Observed - Expected)² / Expected
χ² = (0.00177817 + 0.0214571 + 0.000974852 + 0.00229642 + 0.0277108 + 0.00125897)
χ² = 0.05547
It costs a clothing company $463.45 to make 169 T-shirts.
What is the unit price for 1 T-shirt?
Answer:
The unit price for 1 T-shirt is about $2.74.
Step-by-step explanation:
Set up an equation:
Variable x = unit price for 1 T-shirt
169x = 463.45
Divide both sides by 169:
x = 2.742307...
Round to the nearest cent:
x = 2.74
slope of (30, 600) (75, 1050)
Answer:
y2-y1/x2-x1
y2: 1050
y1:600
x2:75
x1:30
1050-600=450
75-30=45
450/45=10
slope is 10
Answer:
let:
A(30, 600)=(x1,y1)
B((75, 1050)=(x2,y2)
now,
[tex]slope(m) = \frac{y2 - y1}{x2 - x1} [/tex]
[tex] = \frac{1050 - 600}{75 - 30} [/tex]
[tex] = \frac{450}{ 45} [/tex]
[tex] = \frac{10}{1} [/tex]
c) The exponential model A = 513.5e0.009t describes the population, A, of a
country in millions, t years after 2005. Use the model to determine when the
population of the country will be 602 million.
Answer:
zotfnKhxitfupoydkfslfndckv
Which is the graph of Y = log(-x)?
5
4
3
3
N
1
1
A++
-4 -3 -2 -11
1 2 3 4 5 6 7 8 9
-2
-3
-4
ASAP
Can someone do #4 #5 #6?
4. Percent increase
Because Original Value < New Value
5. Percent
6. Whole
Because it's asking what number that means total.
Thanks :)
Love from India :)-1/5y+7=7
What is the value of y?
The side-by-side stemplot below displays the arm spans, in centimeters, for two classes.
A stemplot titled Arm Span (centimeters). For Class A, the values are 148, 151, 153, 155, 156, 159, 161, 162, 164, 165, 169, 169, 170, 171, 175, 176, 179, 179, 180, 182, 183, 186, 186, 190. For Class B, the values are 153, 155, 16, 160, 162, 162, 162, 163, 163, 165, 166, 167, 170, 173, 180, 181, 182, 189, 192, 202.
Which statement correctly compares the variability of the arm spans for Class A to that of Class B?
The arm spans for Class A have more variability than the arm spans for Class B.
The arm spans for Class B have less variability than the arm spans for Class A.
The arm spans for Class A have less variability than the arm spans for Class B.
The arm spans for Class B have about the same variability as the arm spans for Class A.
Answer:
The answer is in the picture below
Step-by-step explanation:
Sorry just realised the answers were different ;-;
Answer:
The arm spans for Class A are roughly symmetric, while those for Class B are skewed left.
Step-by-step explanation:
write the equation of the graph, y=? SOMEBODY PLEASE HELP
Answer:
[tex]y=\left(6\right)^{x}\ -3[/tex]
Step-by-step explanation:
I need help
With these
Answer:
"A"
Step-by-step explanation:
a+b >c
a+c>b
b+c>a
~~~~~~~~~~~~
A. T,T,T
B. T,T,F
C. T,F,T
Find the equation of the line passing through the point (-1,2)
and the points of intersections of the line 2x - 3y + 11 = 0 and
5x + y + 3 = 0
Answer:
[tex]y=-5x-3[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).
To solve for the equation of the line, we would need to:
Find the point of intersection between the two given linesUse the point of intersection and the given point (-1,2) to solve for the slope of the lineUse a point and the slope in [tex]y=mx+b[/tex] to solve for the y-interceptPlug the slope and the y-intercept back into [tex]y=mx+b[/tex] to achieve the final equation1) Find the point of intersection between the two given lines
[tex]2x - 3y + 11 = 0[/tex]
[tex]5x + y + 3 = 0[/tex]
Isolate y in the second equation:
[tex]y=-5x-3[/tex]
Plug y into the first equation:
[tex]2x - 3(-5x-3) + 11 = 0\\2x +15x+9 + 11 = 0\\17x+20 = 0\\17x =-20\\\\x=\displaystyle-\frac{20}{17}[/tex]
Plug x into the second equation to solve for y:
[tex]5x + y + 3 = 0\\\\5(\displaystyle-\frac{20}{17}) + y + 3 = 0\\\\\displaystyle-\frac{100}{17} + y + 3 = 0[/tex]
Isolate y:
[tex]y = -3+\displaystyle\frac{100}{17}\\y = \frac{49}{17}[/tex]
Therefore, the point of intersection between the two given lines is [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex].
2) Determine the slope (m)
[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the two points [tex](\displaystyle-\frac{20}{17},\frac{49}{17})[/tex] and (-1,2):
[tex]m=\displaystyle \frac{\displaystyle\frac{49}{17}-2}{\displaystyle-\frac{20}{17}-(-1)}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{20}{17}+1}\\\\\\m=\displaystyle \frac{\displaystyle\frac{15}{17} }{\displaystyle-\frac{3}{17} }\\\\\\m=-5[/tex]
Therefore, the slope of the line is -5. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-5x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=-5x+b[/tex]
Plug in the point (-1,2) and solve for b:
[tex]2=-5(-1)+b\\2=5+b\\-3=b[/tex]
Therefore, the y-intercept is -3. Plug this back into [tex]y=-5x+b[/tex]:
[tex]y=-5x+(-3)\\y=-5x-3[/tex]
I hope this helps!
4. A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution. How many liters of the 60% solution must be used?
SHOW YOUR WORK
Given:
A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.
To find:
The quantity of the 60% solution in the mixture.
Solution:
Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.
Quantity of mixture is 234. So,
[tex]x+y=234[/tex]
[tex]x=234-y[/tex] ...(i)
The mixture has 43% fertilizer. So,
[tex]\dfrac{60}{100}x+\dfrac{21}{100}y=\dfrac{43}{100}\times 234[/tex]
Multiply both sides by 100.
[tex]60x+21y=10062[/tex] ...(ii)
Using (i) and (ii), we get
[tex]60(234-y)+21y=10062[/tex]
[tex]14040-60y+21y=10062[/tex]
[tex]-39y=10062-14040[/tex]
[tex]-39y=-3978[/tex]
Divide both sides by -39.
[tex]\dfrac{-39y}{-39}=\dfrac{-3978}{-39}[/tex]
[tex]y=102[/tex]
Putting this value in (i), we get
[tex]x=234-102[/tex]
[tex]x=132[/tex]
Therefore, 132 liters of the 60% solution must be used.
Help please, but more importantly, I am really trying hard to figure out how, you arrive at the answer. Thanks in advance!
A recent social survey asked respondents whether they like Apple or Microsoft. The responses were recorded in the following table.
Male Female Total
Apple 152 194 346
Microsoft 168 126 294
Total 320 320 640
a. A respondent is randomly selected among those that prefer Apple, what is the probability that the respondent will be female?
b. A respondent is randomly selected among those that are Male, what is the probability that the respondent prefers Apple?
c. What is the relative frequency of a female who prefers Microsoft?ocial survey asked respondents whether they like Apple or Microsoft. The responses were recorded in the following table.
Male Female Total
Apple 152 194 346
Microsoft 168 126 294
Total 320 320 640
a. A respondent is randomly selected among those that prefer Apple, what is the probability that the respondent will be female?
b. A respondent is randomly selected among those that are Male, what is the probability that the respondent prefers Apple?
c. What is the relative frequency of a female who prefers Microsoft?
Answer:
Step-by-step explanation:
#1
A) P(FEMALE|APPLE)
apple total = 346
apple/female = 194
194/346 = .56 = 56 %
B) P(APPLE|MALE)
male total = 320
apple male = 152
152/320 = .475 = 47.5%
C) female prefer Microsoft
152:168 = 76:84 = 38:42 = 19:21
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The table below shows the educational attainment of a country's population, aged 25 and over. Use the data in the table, expressed in millions to find the probability that a randomly selected citizenaged 25 or over , was a man with 4 years of college (or more)
Answer:
The answer is "[tex]\bold{\frac{22}{171}}[/tex]"
Step-by-step explanation:
There are 22 million males that have completed four years of undergraduate, according to the data below: (or more). This is predicated on a population of 171 million.
The chances we're searching about [tex]\frac{(22\ million)}{(171\ million)} = \frac{22}{171}[/tex]
however
This proportion could be further reduced because 22 and 171 have no common features (other than 1).
Find the arc length of the 3/4 of a circle with a radius of 5
Answer:
7.5 pi
Step-by-step explanation:
The formula for arc length of a sector is denoted as
[tex]\frac{x}{360}2\pi r[/tex], where x is the central angle of the sector.
Since the sector is 3/4 of a circle, the central angle will be 3/4 of 360 degrees.
3/4 of 360 is 270, so we have our central angle. We also have our radius which we can plug into the formula.
[tex]\frac{270}{360}2(5)\pi[/tex]
2 times 5 is equal to 10, and 270/360 simplifies to 3/4. 3/4 times 10 is equal to 7.5, so the answer is 7.5 pi
how to solve the matrix equation for matrix Y.simplify all elements
[tex]Y\left[\begin{array}{ccc}-1&-4\\0&-5\\\end{array}\right] = \left[\begin{array}{ccc}5&-5\\8&8\\\end{array}\right][/tex]
Given YA = B, you can solve for Y by multiplying by A ⁻¹ on the right (on both sides of the equation). So we have
YA = B ==> (YA) A ⁻¹ = BA ⁻¹ ==> Y (AA ⁻¹) = BA ⁻¹ ==> Y = BA ⁻¹
provided that the inverse of A exists. In this case, det(A) = 5 ≠ 0, so the inverse does exist, and
[tex]A=\begin{bmatrix}-1&-4\\0&-5\end{bmatrix} \implies A^{-1}=\dfrac1{\det(A)}\begin{bmatrix}-5&0\\4&-1\end{bmatrix} = \begin{bmatrix}-1&0\\\frac45&-\frac15\end{bmatrix}[/tex]
Then
[tex]Y=\begin{bmatrix}5&-5\\8&-8\end{bmatrix}A^{-1} = \begin{bmatrix}-5&5\\-8&\frac{24}5\end{bmatrix}[/tex]
1/10
9/10
Q
Find the perimeter of the rectangle pictured above. Give your answer as a reduced mixed number.
Answer:2
Step-by-step explanation:
Exercise 6.2
1.
a.
The total cost function is given by C = 100 - 5x + 7x2, find
the average cost and marginal cost.
9514 1404 393
Answer:
average cost = 7x -5 +100/xmarginal cost = 14x -5Step-by-step explanation:
The average cost is the total cost divided by the number of units produced:
average cost = C/x = 100/x -5 +7x
__
The marginal cost is the derivative of the total cost function.
marginal cost = -5 +14x
17. A hospital trauma center is going to be built equidistant from three cities. Positioned on a grid, the cities would be located at (1, 5), (2, -2), and (-6, -2). What are the coordinates of the location where the trauma center should be built? A (-2, -1) C (2, -1) B (-2, 1) D (2.1)
9514 1404 393
Answer:
B (-2, 1)
Step-by-step explanation:
The trauma center will be located at the circumcenter of the triangle. That is the point of intersection of the perpendicular bisectors of the sides. Once the points are graphed, it is pretty easy to see where that will be. It is on the line x=-2, above the x-axis. Only one answer choice is appropriate:
(-2, 1)
_____
Line AC has a slope of 1. Those points are separated by 7 units horizontally and vertically, so the midpoint is 3.5 units horizontally and vertically from either point, at (-2.5, 1.5). The perpendicular line with slope -1 through that point will intersect x=2 at y=1.
Which phrase describes an unknown or changeable quality?
3 feet and 7 inches
4 quarts in a gallon
2 o'clock in the afternoon
The height of the building times 1/2
Answer:
it should be the height of the building time 1/2
Step-by-step explanation:
let me know if its correct or incorrect we'll I hope this help you
Please help me with this
Answer:
[tex]\frac{121}{14} = 8\frac{9}{14}[/tex]
Step-by-step explanation:
a playing card is chosen at random from a standard deck of cards. what is the probability of choosing 5 of diamonds or one jack
Answer:
1/52
Step-by-step explanation:
Please help with Question 2b
Answer:
MUST BE IN HLA, NOT FROM C TO ASSEMBLY.
PROGRAM 6: Same
Write an HLA Assembly language program that implements a function which correctly identifies when all four parameters are the same and returns a boolean value in AL (1 when all four values are equal; 0 otherwise). This function should have the following signature:
procedure theSam
NO LINKS OR ANSWERING WHAT YOU DON'T KNOW. THIS NOT A TEST OR AN ASSESSMENT. PLEASE HELP ME WITH THESE MATH QUESTIONS FOR AN ASSIGNMENT!!! Chapter 10 part 1
1. What is an extraneous solution and what type of functions might they occur in?
2. Given a vertical asymptote and horizontal asymptote, how would you begin to find an expression for a rational function?
Answer:
1.
An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
Find the bases for Col A and Nul A, and then state the dimension of these subspaces for the matrix A and an echelon form of A below.
A= 1 3 8 2 7 1 3 8 2 7
2 7 20 6 20 --- 0 1 4 2 6
-3 -12 -36 -7 -19 0 0 0 1 4
3 13 40 9 25 0 0 0 0 0
Start 4 By 5 Table 1st Row 1st Column 1 2nd Column 3 3rd Column 8 4st Column 2 5st Column 7 2nd Row 1st Column 2 2nd Column 7 3rd Column 20 4st Column 6 5st Column 20 3rd Row 1st Column negative 3 2nd Column negative 12 3rd Column negative 36 4st Column negative 7 5st Column negative 19 4st Row 1st Column 3 2nd Column 13 3rd Column 40 4st Column 9 5st Column 25 EndTable
tilde
Start 4 By 5 Table 1st Row 1st Column 1 2nd Column 3 3rd Column 8 4st Column 2 5st Column 7 2nd Row 1st Column 0 2nd Column 1 3rd Column 4 4st Column 2 5st Column 6 3rd Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 1 5st Column 4 4st Row 1st Column 0 2nd Column 0 3rd Column 0 4st Column 0 5st Column 0 EndTable
A basis for Col A is given by
StartSet nothing EndSet
(Use a comma to separate vectors as needed.)
The dimension of Col A is
3.
A basis for Nul A is given by
StartSet nothing EndSet
(Use a comma to separate vectors as needed.)
The dimension of Nul A .
Answer:
skip counting by 0
Step-by-step explanation:
skipcount by 0 to get to 100 for the third column.
Answer:
its the first graph
Step-by-step explanation:
I got it right bc im cool like that ig
x^{2} +y^{2} =?
cho mình hỏi với
Answer:
[tex]{ \sf{ {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy }}[/tex]
Step-by-step explanation:
[tex]{ \tt{ {(x + y)}^{2} = (x + y)(x + y) }} \\ { \tt{ {(x + y)}^{2} = ( {x}^{2} + 2xy + {y}^{2}) }} \\ { \tt{( {x}^{2} + {y}^{2} ) = {(x + y)}^{2} - 2xy}}[/tex]
