Answer:
The sample mean that will cut off the upper 95% of all samples of size 20 taken from the population is of 1963.2 pounds.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds.
This means that [tex]\mu = 2000, \sigma = 100[/tex]
A sample of 20 cables is selected and tested.
This means that [tex]n = 20, s = \frac{100}{\sqrt{20}} = 22.361[/tex]
Find the sample mean that will cut off the upper 95% of all samples of size 20 taken from the population.
This is the 100 - 95 = 5th percentile, which is X when Z has a p-value of 0.05, so X when Z = -1.645. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]-1.645 = \frac{X - 2000}{22.361}[/tex]
[tex]X - 2000 = -1.645*22.361[/tex]
[tex]X = 1963.2[/tex]
The sample mean that will cut off the upper 95% of all samples of size 20 taken from the population is of 1963.2 pounds.
Order the expressions from least to greatest.
Anwser
4 then 5 then 6
Answer:
This the right order:
4^2+2^2 = 20
5^2= 25
6^2-6 = 30
Teddy wants to taste all of the flavors of ice cream at the mall, one by one. Tasting any one flavor will change the way the next flavor taste after it. The flavors are chocolate, vanilla, strawberry, birthday cake, Rocky Road, and butter pecan. In how many ways can he taste the ice cream.
A. 30
B.120
C. 360
D.720
Answer: (d)
Step-by-step explanation:
Given
There are six flavors of ice-cream that is chocolate, vanilla, strawberry, birthday cake, rocky road, and butter pecan
First ice-cream can be tasted in 6 different ways
Second can be in 5 ways
similarly, remaining in 4, 3, 2 and 1 ways
Total no of ways are [tex]6\times5\times 4\times 3\times 2\times 1=720\ \text{ways}[/tex]
Option (d) is correct.
Which expression is equivalent to
R^9/r^3?
Answer:
r^9/r^3 = r^9-3 = r^6
Step-by-step explanation:
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]r^6[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Simplifying...}}\\\\\frac{r^9}{r^3} \\--------------\\\\\text{Recall the quotient rule:}} \frac{a^x}{a^y}=a^{x-y}\\\\\rightarrow \frac{r^9}{r^3}\\\\\rightarrow r^{9-3}\\\\\rightarrow \boxed{r^6}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Find the mean of the data in the pictograph below.
Answer:
12 sundaes
Step-by-step explanation:
Help ASAP please !!
Option 4
Answered by Gauthmath must click thanks and mark brainliest
Consider possible daily uses for the Pythagorean Theorem. For what types of careers would knowledge of this theorem be useful or necessary? For each career, include an example of a use for a2 + b2 = c2.
For engineering, it would be very useful to know Pythagorean theorem. You can use it to measure the tension in each ropes.
Solve this equation for x. Round your answer to the nearest hundredth.
1 = In(x + 7)
Answer:
[tex]\displaystyle x \approx -4.28[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertiesAlgebra II
Natural logarithms ln and Euler's number eStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle 1 = ln(x + 7)[/tex]
Step 2: Solve for x
[Equality Property] e both sides: [tex]\displaystyle e^1 = e^{ln(x + 7)}[/tex]Simplify: [tex]\displaystyle x + 7 = e[/tex][Equality Property] Isolate x: [tex]\displaystyle x = e - 7[/tex]Evaluate: [tex]\displaystyle x = -4.28172[/tex]e^1 = x+7
e - 7 = x
x = -4.28
Answer this question that is given
Answer:
See explanation
Step-by-step explanation:
2) (10+4) x 2 = 28
3) (13 + 6) x 2 = 38
4) (8+4) x 2 = 24
5) (11+8) x 2 = 38
Answered by Gauthmath
vvorth 1 points
(01.02 MC)
Which of the following describes the correct process for solving the equation 2x - 4 = 20 and arrives at the correct solution?
O Add 4 to both sides, and then divide by 2. The solution is x = 12.
O Divide both sides by -4, and then subtract 2. The solution is x = -7.
O Subtract 4 from both sides, and then divide by 2. The solution is x = -12.
O Multiply both sides by -4, and then divide by 2. The solution is x = -40.
Hi there!
»»————- ★ ————-««
I believe your answer is:
"Add 4 to both sides, and then divide by 2. The solution is x = 12."
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
To solve for 'x', we would have to use inverse operations. We would first have to add four to both sides to undo the negative four. Addition is the opposite of subtraction. We would then divide by 2 to isolate 'x'. Division is the opposite of multiplication.⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'x'...}}\\\\2x - 4 = 20\\------------\\\rightarrow 2x - 4 + 4 = 20 + 4\\\\\rightarrow 2x = 24\\\\\rightarrow \frac{2x=24}{2}\\\\\rightarrow \boxed{x = 12}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Can someone please help!!! Sec. 12.7 #78
If 1100 square centimeters of material is available to make a box with a square base and an open top, find the largest possible volume of the box. Round to two decimal places if necessary.
volume= a^2 * h
area= a^2+4ah
take the second equation, solve for h
4ah=1100-a^2
h=1100/4a -1/4 a now put that expression in volume equation for h.
YOu now have a volume expression as function of a.
take the derivative, set to zero, solve for a. Then put that value back into the volume equation, solve for Volume.
Cited from jiskha
After completing the fraction division 5 / 5/3, Miko used the multiplication shown to check her work.
3 x 5/3 = 3/1 x 5/3 = 15/3 or 5
Answer:
its the same above
Step-by-step explanation:
If there are g girls and b-boys in a room, write an expression for the total number of children in the room.
Answer:
g+b
number of girls+number of boys
if i am incorrect forgive me plz
The expression for the total number of children in a room is g+ b.
What is an expression?
Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.
What is addition?Addition is the process of finding the total, or sum, by combining two or more numbers or variables.
According to the given question
We have
Number of girls = g
And, number of boys = b
Therefore, the expression for the total number of children in room is given by
Total number of children = g + b
Hence, the expression for the total number of children in a room is g+ b.
Learn more about expression and addition here:
https://brainly.com/question/10386370
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Three yellow balls, two red balls and five orange balls are placed in a bag. Mark draws a
ball out, and replaces it. He then picks another ball.
Draw a tree diagram to represent this information.
What is the probability that he gets at least one yellow ball?
Give your answer as a fraction in its simplest form
i think this could be the answer
find the missing side round to the nearest tenth brainly
Answer:
Sin43 = x/13
x= 13* sin43
x= 8.865
Answer:
8.9
Step-by-step explanation:
using sine rule
[tex] \frac{x}{sin \: 43} = \frac{13}{sin \: 90} [/tex]
cross multiply
x sin 90=13 sin 43
x=13 sin 43
x=8.9
The median age (in years) of the U.S. population over the decades from 1960 through 2010 is given by
f(t) = −0.2176t3 + 1.962t2 − 2.833t + 29.4 (0 ≤ t ≤ 5)
where t is measured in decades, with t = 0 corresponding to 1960.
(a) What was the median age of the population in the year 1970?
(b) At what rate was the median age of the population changing in the year 1970?
(c) Calculate f ''(1).
Considering the given function, we have that:
a) 28.31 years.
b) 0.3382 years a decade.
c) 2.6184.
What is the function?The median age of the U.S. population in t decades after 1960 is:
f(t) = -0.2176t³ + 1.962t² - 2.833t + 29.4.
1970 is one decade after 1960, hence the median was:
f(1) = -0.2176 x 1³ + 1.962 x 1² - 2.833 x 1 + 29.4 = 28.31 years.
The rate of change was is the derivative when t = 1, hence:
f'(t) = -0.6528t² + 3.924t - 2.933
f'(1) = -0.6528 x 1² + 3.924 x 1 - 2.933 = 0.3382 years a decade.
The second derivative is:
f''(t) = -1.3056t + 3.924
Hence:
f''(1) = -1.3056 x 1 + 3.924 = 2.6184.
More can be learned about functions at https://brainly.com/question/25537936
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if you can type 55 words in 20 seconds how much can you type in 1007 seconds
Answer:
[tex]55385[/tex]
words
Step-by-step explanation:
because
I) we have given 55 words
ii) we have given a time 20 seconds
iii) then we multiple 55 ×1007
iv) the answer will be 55385
Vietnamese: Phát biểu định nghĩa hàm số liên tục. Khảo sát tính liên tục của hàm số sau:
Answer:
litrally I don't understand what you are telling
Derive the equation of the parabola with a focus at (2,4) and a directrix of y=8
Answer:
The equation of the parabola with a focus at (2,4) and a directrix of y=8 is,
48-8y=(x-2)²
What is the probability of flipping exactly 6 heads when you flip 6 coins? Please explain your answer and those who waste an answer space shall be reported. Also the best answer will get brainliest
Binomial probability states that the probability of x successes on n repeated trials in an experiment which has two possible outcomes can be obtained by
(nCx).(p^x)⋅((1−p)^(n−x))
Where success on an individual trial is represented by p.
In the given question, obtaining heads in a trial is the success whose probability is 1/2.
Probability of 6 heads with 6 trials = (6C6).((1/2)^6).((1/2)^(6–6))
= 1/(2^6)
= 1/64
Please help me, by completing this proof!
Answer:
Step-by-step explanation:
Statement Reasons
1). Line PQ is an angle bisector of ∠MPN D). Given
2). ∠MPQ ≅ ∠NPQ A). Definition of angle bisector
3). m∠MPQ = m∠NPQ F). Definition of congruent
angles.
4). m∠MPQ + m∠NPQ = m∠MPN C). Angle addition postulate
5). m∠MPQ + m∠MPQ = m∠MPN G). Substitution property of
equality
6). 2(m∠MPQ) = m∠MPN B). Distributive property
7). m∠MPQ = [tex]\frac{1}{2}(m\angle MPN)[/tex] E). Division property of equality
A hot air balloon is rising vertically with a velocity of 12.0 feet per second. A very small ball is released from the hot air balloon at the instant when it is 1120 feet above the ground. Use a(t)=−32 ft/sec^2 as the acceleration due to gravity.
Required:
a. How many seconds after its release will the ball strike the ground?
b. At what velocity will it hit the ground?
Answer:
Here we only need to analyze the vertical motion of the ball.
First, because the ball is in the air, the only force acting on the ball will be the gravitational force (we are ignoring air resistance), then the acceleration of the ball is equal to the gravitational acceleration, so we have:
a(t) = -32 ft/s^2
where the negative sign is because this acceleration is downwards.
To get the velocity equation, we need to integrate over the time, so we get:
v(t) = (-32 ft/s^2)*t + V0
where V0 is the initial velocity of the ball. In this case, the initial velocity of the ball will be the velocity that the ball had when it was dropped, which should be the same as the velocity of the hot air ballon, so we have:
V0 = 12 ft/s
Then the velocity equation of the ball is:
v(t) = (-32 ft/s^2)*t + 12 ft/s
To get the position equation we integrate again:
p(t) = (1/2)*(-32 ft/s^2)*t^2 + (12 ft/s)*t + H0
Where H0 is the initial height. We know that the ball was released at the height of 1120 ft, then we have:
H0 = 1120 ft.
Then the position equation is:
p(t) = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft
a) How many seconds after its release will the ball strike the ground?
The ball will strike the ground when its position equation is equal to zero, then we need to solve:
p(t) = 0 ft = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft
This is just a quadratic equation, the solutions are given by Bhaskara's formula, so the solutions for t are:
[tex]t = \frac{- 12ft/s \pm \sqrt{(12 ft/s)^2 - 4*(-16ft/s^2)*(1120 ft)} }{2*(-16ft/s^2)}[/tex]
We can simplify that to get:
[tex]t = \frac{-12ft/s \pm 268ft/s}{-32ft/s^2}[/tex]
So we have two solutions:
[tex]t = \frac{-12ft/s + 268ft/s}{-32ft/s^2} = -8s[/tex]
[tex]t = \frac{-12ft/s - 268ft/s}{-32ft/s^2} = 8.75s[/tex]
The negative solution does not make sense, then the correct solution is the positive one.
We can conclude that the ball will hit the ground after 8.75 seconds.
b) At what velocity will it hit the ground?
We already know that the ball strikes the ground 8.75 seconds after it is released.
The velocity at it hits the ground is given by the velocity equation evaluated in that time:
v(8.75 s) = (-32 ft/s^2)*8.75s + 12 ft/s = -268 ft/s
[tex]\int\limits^a_b {(1-x^{2} )^{3/2} } \, dx[/tex]
First integrate the indefinite integral,
[tex]\int(1-x^2)^{3/2}dx[/tex]
Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].
Then
[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,
[tex]\int\cos^4(u)du[/tex]
Use reduction formula,
[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]
to get,
[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]
Notice that,
[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]
Then integrate the obtained sum,
[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]
Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,
[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]
[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]
Substitute 2u back for s,
[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]
Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,
[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]
Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]
Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],
[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]
Hope this helps :)
Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:
Pre-Calculus
Trigonometric IdentitiesCalculus
Differentiation
DerivativesDerivative NotationIntegration
IntegralsDefinite/Indefinite IntegralsIntegration Constant CIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
U-Substitution
Trigonometric SubstitutionReduction Formula: [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]
Step 2: Integrate Pt. 1
Identify variables for u-substitution (trigonometric substitution).
Set u: [tex]\displaystyle x = sin(u)[/tex][u] Differentiate [Trigonometric Differentiation]: [tex]\displaystyle dx = cos(u) \ du[/tex]Rewrite u: [tex]\displaystyle u = arcsin(x)[/tex]Step 3: Integrate Pt. 2
[Integral] Trigonometric Substitution: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[1 - sin^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Rewrite: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[cos^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos^4(u)} \, du[/tex][Integral] Reduction Formula: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{4 - 1}{4}\int \limits^a_b {cos^{4 - 2}(x)} \, dx + \frac{cos^{4 - 1}(u)sin(u)}{4} \bigg| \limits^a_b[/tex][Integral] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4}\int\limits^a_b {cos^2(u)} \, du[/tex][Integral] Reduction Formula: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg|\limits^a_b + \frac{3}{4} \bigg[ \frac{2 - 1}{2}\int\limits^a_b {cos^{2 - 2}(u)} \, du + \frac{cos^{2 - 1}(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}\int\limits^a_b {} \, du + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Reverse Power Rule: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}(u) \bigg| \limits^a_b + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex]Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3cos(u)sin(u)}{8} \bigg| \limits^a_b + \frac{3}{8}(u) \bigg| \limits^a_b[/tex]Back-Substitute: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(arcsin(x))sin(arcsin(x))}{4} \bigg| \limits^a_b + \frac{3cos(arcsin(x))sin(arcsin(x))}{8} \bigg| \limits^a_b + \frac{3}{8}(arcsin(x)) \bigg| \limits^a_b[/tex]Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x)}{8} \bigg| \limits^a_b + \frac{x(1 - x^2)^\Big{\frac{3}{2}}}{4} \bigg| \limits^a_b + \frac{3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Rewrite: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x) + 2x(1 - x^2)^\Big{\frac{3}{2}} + 3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Miya is picking up two friends to go the beach. She drives from her house to
pick up Drea, then she drives to pick up Francine, and then they go to the
beach to play volleyball. What is the total distance of the trip?
The grid below shows the coordinates of their houses on a map. All distances
are in miles.
Answer:
Option (C)
Step-by-step explanation:
Coordinates of the point representing the location of Miya → (1, 10)
Coordinates of the point representing the location of Drea → (13, 1)
Coordinates of the point representing the location of Francine → (16, 1)
Coordinates of the point representing the location of Beach → (19, 4)
Distance between Miya and Drea = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
= [tex]\sqrt{(13-1)^2+(1-10)^2}[/tex]
= [tex]\sqrt{144+81}[/tex]
= 15 miles
Distance between Drea and Francine = [tex]\sqrt{(16-13)^2+(1-1)^2}[/tex]
= 3 miles
Distance between Francine and Beach = [tex]\sqrt{(19-16)^2+(4-1)^2}[/tex]
= [tex]\sqrt{9+9}[/tex]
≈ 4.2 miles
Total distance between Miya and the beach = 15 + 3 + 4.2
= 22.2 miles
Option (C) is the answer.
(a+b)2= c+d
answer
answer
Answer:
a+b=c+d/2
i cant understand what answer you want
The sum of two numbers is -17. Their difference is 41. Find the numbers
Answer:
x = 12
y = -29
Step-by-step explanation:
Our given equations: x + y = -17 and x - y = 41
Solve for x and substitute.
x = -17 - y
(-17 - y) - y = 41
-17 - 2y = 41
2y = -58
y = -29
Solve for x using y
x + (-29) = -17
x = 12
The length side of xy is?
Answer:
10
Step-by-step explanation:
ok so you do 12/30 and u get a 0.4 ratio. boom multiply 0.4 by 25 and u get 10. so boom the length is 10
Answer:
XY=10
Step-by-step explanation:
Since they are similar the ratio between each sides should be the same.
Ratio is .4. Found by dividing 12/30.
Multiply .4 by 25= 10
Question 6 a-c if plz show ALL STEPS like LITERALLY EVERYTHING
9514 1404 393
Answer:
a) quadrant III
b) 4π/3, -2π/3
c) (1/2, (√3)/2)
d) ((√3)/2, -1/2
Step-by-step explanation:
a) The attachment shows the point P and the numbering of the quadrants (in Roman numerals). Point P lies in quadrant III.
__
b) Measured counterclockwise, the angle to point P is 240° or 4π/3 radians. Measured clockwise, the angle is -120° or -2π/3 radians. In the diagram, these are shown in green and purple, respectively.
__
c) Adding π/2 to the angle 4π/3 or -2π/3 brings it to 11π/6, or -π/6. This point is marked as P' (blue) on the diagram. The coordinate transformation for π/2 radians CCW rotation is ...
(x, y) ⇒ (-y, x)
P(-1/2, -√3/2) ⇒ P'(√3/2, -1/2)
In terms of trig functions, the coordinates of the rotated point are ...
P'(cos(-π/6), sin(-π/6)) = P'(√3/2, -1/2)
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d) Adding or subtracting π radians to/from the angle moves it directly opposite the origin. Both coordinates change sign. This point is P'' (red) on the diagram.
I need help on this 20 points
Answer:
4^15
Step-by-step explanation:
We know a^b^c = a^(b*c)
4^3^5
4^(3*5)
4^15
A physicist examines 10 water samples for iron concentration. The mean iron concentration for the sample data is 0.711 cc/cubic meter with a standard deviation of 0.0816. Determine the 90% confidence interval for the population mean iron concentration. Assume the population is approximately normal.
Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 2 of 2: Construct the 90% confidence interval. Round your answer to three decimal places. Lower endpoint? Upper endpoint?
Answer:
Poggers
Step-by-step explanation:
