The angular velocity of the wheel after its mass center G has traveled through a distance starting from rests is 31.62 m.
What is angular velocity?The velocity of an object when moving on a circular track.
The moment of inertia of the wheel about the center O is
I = mk²
Where radius of gyration k= 300mm =0.3 m and mass of wheel m =30kg
I = 20 x (0.3)² = 1.8 kg.m²
The final kinetic energy of wheel is
K.Ef = 1/2 x mx (rω²) + 1/2 x I x ω²
Substitute the values from the question, we have
K.Ef = 1/2 x 20 x (0.4 x ω²) +1/2 x 1.8 x ω² =2.5ω²
The initial kinetic energy is zero, K.Ei =0
According to the work energy theorem, W =K.Ef -K.Ei =2.5ω² ...............(1)
Work done = moment x angular displacement
W = 50 N.m x 20m/0.4m = 2500 N.m............(2)
Equating both the equations and solving for ω, we get
ω =31.62 rad
Thus, the angular velocity is 31.62 rad.
Learn more about angular velocity.
https://brainly.com/question/13649539
#SPJ1
1. The Falcon Heavy rocket takes off with a constant net vertical force of 6.27 x 10^5
N. How much work does it do if it moves a distance of 144 km?
Explanation:
The formula for work is
[tex]w = |f| |d| \cos(x) [/tex]
where x is the angle between the displacement and force.
F is the force that is currently being active.
D is the displacement.
We only want our force and displacement to be positve so we use the absolute value sign.
Since the rocket and the displacement is both upwards, the signs. between them is 0.
So since
[tex] \cos(0) = 1[/tex]
We can just use that
[tex]w = |f| |d| [/tex]
First, we covert km to m.
[tex]144 \: km \times \frac{1000 \: m}{1 \: km} = 144000 m[/tex]
Now, we can multiply.
[tex]w = 14400 \: km \: \times (6.27 \times 10 {}^{5} )[/tex]
[tex]w = (1.44 \times 10 {}^{5} ) \times (6.27 \times 10 {}^{5} )[/tex]
[tex]w = 9.0288 \times 10 {}^{10} [/tex]
N times Meters = J so our answer is
[tex]w = 9.0288 \times 10 {}^{10} \: j[/tex]
A force of 124 newtons pushed a 12kg object forward 13 meters. How much work is being done?
Answer:
Work = Force * Distance
Here,
force = 124 N
distance = 13m
Thus, Work = 124 * 13 = 1612 joules(J)
what is 7 times 7 times 7 plus 3
a machine is 12% efficient if useful work done by it is 6 joules what will be the total energy consumed by it
Since work is the change in kinetic energy, the efficiency of a machine can be stated as the percentage of the output work divided by the input work minus the work lost from to friction and heat. Multiply Eff by 100% to get the efficiency percentage.
Please mark me as brainliest
Find the radius and the circumference to the nearest hundredth when d ≈ 3.6 in. Use 3.14 for π. Drag and drop the correct number into each box to complete the answers.
The radius is approximately _ inches.
The circumference is approximately _ inches.
Explanation:
the radius is always half of the diameter.
so, the radius is approximately 3.6/2 = 1.8 in.
and the circumference of a circle is
2×pi×r = d×pi = 3.6×3.14 = 11.304 ≈ 11.3 in.
3. The height of a wave crest is called
a. wavelength.
c. amplitude.
b. frequency
d. energy
Answer:
C. Amplitude
Explanation:
Which of the following is a disadvantage of renewable energy?
A. It creates large amounts of pollution
B. It could be costly to initially switch to.
C. It will not produce enough power to sustain us.
D. It will not run out.
Answer:
B. It could be costly to initially switch to.
Nisha stands at the edge of an aquarium 3.0 m deep. She
shines a laser at a height of 1.7 m that hits the water of the pool
8.1 m from the edge. How far from the edge of the pool will the light hit bottom?
It's denoting to a right angle traingle
Perpendicular=P=3+1.7=4.7mBase=B=8.1mHypotenuse we need
Apply Pythagorean theorem
H²=P²+B²H²=4.7²+8.1²H²=87.7H=9.4mExplanation:
The graph of y = √x is reflected in the y-axis, is horizontally stretched by a factor of 2, shifted 3 units up and 1 unit left. What is the equation of the transformed graph?
Original: y = √(x)
Reflected in the y-axis: y = √(-x)
Horizontally stretched by a factor of 2: y = √(-x/2)
Shifted 3 units up: y = 3 + √(-x/2)
And 1 unit left: y = 3 + √(-(x+1)/2)
why Neil deGrasse Tyson says NASCAR doesn’t like the Doppler effect.
We can confirm that Neil deGrasse Tyson made this claim due to the fact that NASCAR races use speakers with the sounds of the race.
Why would using speakers ruin the Doppler effect?The Doppler effect in regards to sound is a shift in the way we hear the sound as the object is coming closer and then moving farther away, something that NASCAR cars do very often during races. Placing speakers would overlap this sound with a constant sound wave, making the audience unable to perceive the doppler effect.
Therefore, we can confirm that Neil deGrasse Tyson made this claim due to the fact that NASCAR races use speakers with the sounds of the race.
To learn more about the Doppler effect visit:
https://brainly.com/question/9165991?referrer=searchResults
6) If the mass of an object is 28kg and the gravitational force is 18G, what is the gravitational force of an object
that has half the mass?
a. 14kg
b. 56kg
C. 9G
d. 36G
Answer:
The gravitational force of an object that has half the mass is C) 9G.
Explanation:
Newton's Law of Gravitation:
[tex]\displaystyle F_g=G\frac{Mm}{r^2}[/tex]We can see that the gravitational force, [tex]F_g[/tex], and mass (let's combine M * m into just "m"), [tex]m[/tex], are directly proportional to each other.
This means that if [tex]F_g[/tex] increases, [tex]m[/tex] also increases.
Therefore, if the mass is halved, that means that the gravitational force is also going to be halved.
The answer is 18G / 2 = 9G, which corresponds to answer C) 9G.
The displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function :
x=-3.5sin(π/2t+(5π)/4)
Find
a. maximum kinetic energy
b. maximum potential energy
c. maximum mechanical energy
The maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.
What is simple harmonic motion?Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side.
Simple Harmonic Motion
The given equation of the simple harmonic motion is
[tex]x=3.5 sin (\frac{\pi }{2t} + \frac{5\pi }{4} )[/tex]
Data;
ω = π/2
k = 1.254N/m
Solving this
[tex]\frac{dx}{dt} = -3.5 X \frac{\pi }{2} cos (\frac{x\pi t}{2}+\frac{5\pi }{4} )[/tex]
Let's calculate the maximum velocity.
[tex]V_{m} =\frac{3.5\pi }{2}[/tex]
This is only possible when cos θ = -1
The maximum kinetic energy is
[tex]K_m =\frac{1}{2} mv^2 = \frac{1}{2} X \frac{500}{1000} X \frac{7^2\pi ^2}^{4} ^2[/tex]
[tex]w^2 = \frac{k}{m} \\k = w^2m\\k = \frac{\pi ^2}{4} X \frac{500}{1000} \\k =1.254 N/m[/tex]
Using the value of spring constant, we can find the maximum potential energy.
[tex]P.E =\frac{1}{2} k x^2\\P.E =\frac{1}{2} X 1.234 X 3.5^2 \\P.E = 7.56 J[/tex]
The maximum potential energy is 7.56J
The maximum mechanical energy is equal to the sum of maximum potential energy and the maximum kinetic energy.
ME = K.E + P.E
ME = 7.56J
From the calculations above, the maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.
Learn more on simple harmonic motion here;
brainly.com/question/15556430
#SPJ1
Please just give me an answer, thanks.
1. task
The resistance of the light bulb is 0.4 kΩ. To what voltage is it connected if a current of 33 mA flows through it? The answer is rounded to the nearest whole number!
2. task
The length of the cable is 69 m, its cross-sectional area is 0.4 mm2. What material is the wire made of if its resistance is 86.3 Ω? Just give me the result of numbers, i'll find myself what material corresponds to those numbers
3. task
Calculate the resistance of the galvanometer if a current of 6 μA flows through it and the voltage is 7 mV! Round to the nearest whole number!
#1
[tex]\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}[/tex]
[tex]\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}[/tex]
[tex]\\ \rm\dashrightarrow V=0.012\times 10^{-6}[/tex]
[tex]\\ \rm\dashrightarrow V=12mV[/tex]
#2
[tex]\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}[/tex]
[tex]\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}[/tex]
[tex]\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}[/tex]
[tex]\\ \rm\dashrightarrow \rho=0.5\times 10^{6}[/tex]
It should be silicon#3
Ohms law
[tex]\\ \rm\dashrightarrow R=\dfrac{V}{I}[/tex]
[tex]\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}[/tex]
[tex]\\ \rm\dashrightarrow R=1.167\times 10^9\Omega[/tex]
During which weeks of the moon cycle does the moon appear to be getting smaller
Answer:
Since the illuminated side of the moon appears to be getting smaller in size (after the full moon), the moon is said to be in the "erosion phase". For the next 7 days, the moon will remain in an “eroded gibbous stage”.
Explanation:
What's the temperature 414 K in degrees Celsius?
Answer:
140.85 is the correct answer
a man weights 800n at the earth's surface. What will be the weight of the same person when he is orbiting the earth at double the high of the earth's center
Answer:
200 N
Explanation:
F = G m1 m2 / r^2 G m1 and m2 are constant for this scenario
so this becomes
F is proprtional to 1/r^2
f = 1/r^2
800 = 1/r^2 now change r to 2r
F = 1/(2r)^2 = 1/4 * 1/r^2 <======shows force will be 1/4 of original , or 200N
A lamp has a voltage of 120 V across it and uses a current of 0.5A. What is the power used by the lamp?
Given the voltage of the lamp and the amount of current use, the power used by the lamp is 60Watts.
What is the power used by the lamp?Power is the quantity of energy transferred per unit time. It can be expressed as;
P = v × I
Where v is voltage and I is current.
Given that;
Voltage v = 120VCurrent I = 0.5APower P = ?P = v × I
P = 120V × 0.5A
P = 60Watts
Therefore, given the voltage of the lamp and the amount of current use, the power used by the lamp is 60Watts.
Learn more about Ohm's law here: https://brainly.com/question/12948166
#SPJ1
When two surfaces interact, some mechanical energy leaves the system as thermal energy due to ________.
Answer:
Friction
Explanation:
Friction is wasted energy in the form of heat and or destruction.....this is why combustion engines have oil lubriction ====> reduce friction and wear
How do you know that light travels faster than
sound? (Hint: Give an example of something that
produces sound and light at the same time.)
Answer:
Explanation:
Answer
How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.# Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.
#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.
The crust is composed primarily of basalt and _____________.
Answer:
Granite
Explanation:
Trust me I learned this 2years ago
A particle q1 with the charge of 4.5x10-⁶C is fixed in the space from a distance of 3.7cm , a particle q2 of mass 6.9g and the charge of -3.10x10-⁶C is fired with the initial velocity of 60m/s toward the fixed charge. what is the velocity when it is 1cm away from the q1
The velocity of particle 2 when it is 1cm away from particle 1 is determined as 62.18 m/s.
Force between the charges
The electrostatic force between the two charges is calculated as follows;
F = (kq1q2)/(r²)
F = (9 x 10⁹ x 4.5 x 10⁻⁶ x 3.1 x 10⁻⁶)/(0.037)²
F = 91.71 N
Acceleration of the second particleF = ma
a = F/m
a = (91.71 N)/(0.0069 kg)
a = 13,291.2 m/s²
Velocity of particle 2 at 1 cm from particle 1v² = u² + 2as
v² = 60² + 2(13,291.2)(0.01)
v² = 3865.82
v = 62.18 m/s
Learn more about velocity here: https://brainly.com/question/6504879
#SPJ1
In sound, the wavelength of the sound
determines the __ of the sound.
A. Pitch
B. Volume
C.Length
Answer:
A) Pitch
Explanation:
Wavelength determines the pitch ( or frequency which is 1/wavelength)
A body moves in the east with the velocity of 25 m/s. Another body B moves in the same direction with a velocity of 10 m/s. If both of them had started from the same point then find :
i) The velocity of w .r. t. B.
ii) The distance covered by each in 30
seconds...
iii) The distance between them after 1
minute...
Please help....ty !!!
[tex].....[/tex]
Answer:
See below
Explanation:
i) Velocity of A wrt B is 15 m/s east
ii) A 30 * 25 = 750 m east B 30 *10 = 300 m east
iii) 1 minute will be 15 m/s * 60 = 900 m apart
3- Which of the following represents a way through which thermal energy is transferred by direct contact?
a Conduction O
b. Radiation O
c. Convection O
d. Specific heat
Answer:
A. conduction
Explanation:
Conduction is the transfer of energy from one molecule to another by direct contact.
A (-8.8×10-20 C) charge is moving at (9.6×106 m/s) perpendicular a magnetic field. It
experiences a force of to (-5.2×10-16 N). What is the magnetic field strength?
6.2×10 -4 T
5.4×10 -15 T
3.2 ×10 -27 T
4.4×10 -20 T
The magnetic field strength will be 6.1 x 10⁻⁴ T.
What is magnetic field?The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.
The magnetic field strength is the magnitude of magnetic field in Tesla. It is related to velocity, magnitude of charge and force by the relation,
Magnetic force F = qVB
Given is the charge q = -8.8×10⁻²⁰ C, Force F = -5.2×10⁻¹⁶ N and the velocity v = 9.6×10⁶ m/s, then the magnetic field strength will be
B = -5.2×10⁻¹⁶/-8.8×10⁻²⁰ x9.6×10⁶
B = 6.1 x 10⁻⁴ T
Thus, the magnetic field strength will be 6.1 x 10⁻⁴ T.
Learn more about magnetic field.
https://brainly.com/question/14848188
#SPJ1
Velocity can be negative, but kinetic energy cannot. Why?
Because of the formula
Let's see
how
KE=1/2mv²m is mass
v is velocity
as it's v²
Its must be greater than or equal to 0 ,So kinetic energy can't be negative
The drawing shows a crystalline slab (refractive index 2.043) with a rectangular cross section. A ray of light strikes the slab at an incident angle of θ1= 37.0°, enters the slab, and travels to point P. This slab is surrounded by a fluid with a refractive index n. What is the maximum value of n such that total internal reflection occurs at point P?
A drawing shows a crystalline slab (refractive index 2.043) with a rectangular cross-section, the maximum value of n is mathematically given as
nm=1.627
What is the maximum value of n such that total internal reflection occurs at point P?Generally, the equation for the snells law is mathematically given as
[tex]n=\frac{sin \theta_1}{sin \theta_2}[/tex]
Therefore
[tex]\theta_2=sin-1(sin35/1.725)\\\\\theta_2=19.42[/tex]
From the image critical angle is
ic=90-19.42
ic=70.58
In conclusion, snells law for total internal reflection
[tex]gn=\frac{sinic}{sin90}[/tex]
sinic=nm/ng
nm=1.725*sin70.58
nm=1.627
Read more about Lens
https://brainly.com/question/13644773
#SPJ1
A transverse wave on a string has an amplitude of 20 cm, a wavelength of 35 cm, and a frequency of 2.0 Hz. The wave moves in the positive x-direction.
--Enter any fractional coefficients as fractions, i.e., do not approximate fractions using decimals. Enter as itself; do not multiply it with other numerical factors. Enter phase angles in inverse function form if they do not evaluate one of the special angles on the unit circle.
--Write the mathematical description of the displacement y1(x,t) from equilibrium for the wave if, at t=0, x=0, and y1=0.
y1(x,t)= ___m
--Write the mathematical description of the displacement y2(x,t) from equilibrium for the wave if, at t=0, x=0, and y2=20 cm.
y2(x,t)= ___m
Write the mathematical description of the displacement y3(x,t) from equilibrium for the wave if, at t=0, x=0, and y3=−20 cm.
y3(x,t)= ___m
Write the mathematical description of the displacement y4(x,t) from equilibrium for the wave if, at t=0, x=0, and y4=13 cm.
y4(x,t)= ___m
(a) The mathematical description of the displacement of the wave, y1(x,t) = 0.2 m.
(b) The mathematical description of the displacement of the wave, y2(x,t) = 0.4 m.
(c) The mathematical description of the displacement of the wave, y3(x,t) = 0.2 m
(d) The mathematical description of the displacement of the wave, y4(x,t) = 0.33 m
Wave functionThe general wave function is written as follows;
y(x, t) = Acos(kx - ωt)
where;
k is the wave number = 2π/λA is amplitude of the wave = 20 cmω is angular speedλ is the wave length = 35 cmy0 = Acos(kx - ωt)
y0 = 20cm x cos(0 - 0)
y0 = 20 cm
From equilibrium of the wave, at t=0, x=0, y1 = 0y1(x,t) = 20cm x cos(0 - 0) = 20 cm
y1(x,t)= 20 cm = 0.2 m
Thus, y1 = y1 + y0
From equilibrium of the wave, at t=0, x=0, y2 = 20 cmy2 = y0 + y1 + y2
y2 = 20 cm + 0 + 20 cm
y2(x,t)= 40 cm = 0.4 m
From equilibrium of the wave, at t=0, x=0, y3 = -20 cmy3 = y0 + y1 + y2 + y3
y3 = 20 cm + 0 + 20 cm - 20cm
y3(x,t)= 20 cm = 0.2 m
From equilibrium of the wave, at t=0, x=0, y4 = 13 cmy4 = y0 + y1 + y2 + y3
y4 = 20 cm + 0 + 20 cm -20 cm + 13 cm
y4 = 33 cm
y4(x,t) = 33 cm = 0.33 m
Learn more about equation of wave here: https://brainly.com/question/4692600
#SPJ1
AC 1. When a driver applies the brake of a light truck traveling a speed of 12 m/s it skids a distance of 3 m before stopping. How far will the truck skid if it is traveling at a speed of 24 is when the brakes are applied?
vf²=vi²-2ad (vf = 0, stop)
12² = 2a.3
144 = 6a
a = 24 m/s²
24² = 2 x 24 x d
576 = 48d
d = 12 m
- A particular light source gives off light waves with a measured wavelength of
2.0 X 10-7m. What is the frequency of the light source?
Answer:
f = 1.5 x 10¹⁵ Hz
Explanation:
Light is an electromagnetic wave and we know that the speed of light is a constant which is
3 x 10⁸ m/s.
Knowing this; v = λ x f
λ = wavelength
f= frequency of light
v = seed of light
f = v/λ
f = 3 x 10⁸m/s / 2.0 x 10-⁷ m
f = 1.5 x 10¹⁵ Hz
“Jonny pulls his sister Jane (weight 28 lbs), who is sitting in a wagon, up an incline ramp (θ = 17°) with a steady speed. If the coefficient of kinetic friction is 0.18, the wagon has a mass of 14 kg, and the length of the ramp is 2.4 m, find: a) the work done by the frictional force. b) the work done by the gravitational force.“
(a) The work done by the frictional force is -33.1 J.
(b) The work done by the gravitational force is 175.58 J
Work done by frictional force
The work done by frictional force is calculated as follows;
W = -μmgsinθ x L
W = -μmgsinθ x L
where;
m is mass of Jane and wagonW = -0.18 x (12.7 + 14)9.8 x sin(17) x 2.4
W = -33.1 J
Work done by the gravitational forceW = mgh
W = mgcosθ x h
W = mgcosθ x Lsinθ
W = (26.7)(9.8)cos(17) x 2.4 x sin(17)
W = 175.58 J
Learn more about work done here: https://brainly.com/question/8119756
#SPJ1
