Surveys tried out on a small number of people before they are used with a larger group of people are known as ____________ surveys.
A. predominant
B. pilot
C. preliminary
D. primary

Answer:

23 and 25

Step-by-step explanation:

Integers are whole numbers that are either positive, negative, or zero. Fractions and decimals are not integers. Therefore, 24 is between 23 and 25.

Answer:

Positive 23 and positive 25

Step-by-step explanation:

Answer:

[tex]\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\frac{2\sqrt{3} }{2}=\sqrt{3}[/tex]

I hope this helps!

pls ❤ and give brainliest pls

Answer:

It's going to take you 17 min to travel 12 miles

assuming you are going with mph

Step-by-step explanation:

I looked at a speed calculator and calculated that to go 25 miles in 35 min, you were going 42 mph. so I changed the imput to 12 miles and I got my answer.

Answer:

Hello,

Step-by-step explanation:

30°=π/6 (rad)

[tex]L=\theta*R=\dfrac{\pi}{6} *120\\\\=20*\pi\\\\\approx{20*3=60\ (cm)}[/tex]

Answer:

[tex]{ \sf{ \int 4x \cos(2 - 3x) dx = {4x}^{2} \cos(2 - 3x) + c }}[/tex]

Step-by-step explanation:

From integration by parts:

[tex]{ \boxed{ \bf{ \int u \: \frac{dv}{dx} = uv - \int v \: \frac{du}{dx} }}}[/tex]

let u be cos(2-3x) and let dv/dx be 4x:

[tex]{ \sf{ \frac{du}{dx} = 3 \sin(2 - 3x) }} \\ \\ { \sf{ v = \int 4x = 2 {x}^{2} }}[/tex]

Substitute in formular box:

[tex]{ \sf{ = (2 {x}^{2} \times \cos(2 - 3x)) - \int 2 {x}^{2} .3 \sin(2 - 3x) dx}} \\ = { \sf{2 {x}^{2} ( \cos(2 - 3x) - 3 \int \sin(2 - 3x)dx }} \\ { \sf{ = 2 {x}^{2} ( \cos(2 - 3x) - 3( - \frac{1}{3} \cos(2 - 3x) ) + c}} \\ { \sf{ = {4x}^{2} \cos(2 - 3x) + c}}[/tex]

Answer:

7.7 ft

Step-by-step explanation:

The third longest side is also the second shortest side.

The 14 ft side of quadrilateral ABCD corresponds to the 6 ft side of quadrilateral EFGH.

14/6 = 18/x

7/3 = 18/x

7x = 18 * 3

7x = 54

x = 54/7

x = 7.7

Answer: D. 7.7 feet

Answer:

Step-by-step explanation:

7.7

Answer:

X=7.9

Y=7.9

Step-by-step explanation:

We have that x=y

And form Pythagoras theorem we have

[tex]5 \sqrt{5} = \sqrt{x ^{2} + x ^{2} } \\ take \: the \: square \: of \: the \: two \: sides \\ 125 = 2x ^{2} \\ x {}^{2} = 62.5 \\ x = 7.9[/tex]

So x = y = 7.9

Answer:

absolute value

Step-by-step explanation:

Answer:

This shows the absolute value of an integer.

Step-by-step explanation:

When you see the lines | | around a number, it should always give you the answer of that number's positive integer. So lets say I out | -2 | the answer for this equation should be 2.

Answer:

it is <

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

The distance between the center are  the foci located 8 units.

It is required to find  the focus is c.

A closed plane curve generated by a point moving in such a way that the sums of its distances from two fixed points is a constant.

Given that:

The length of the major axis is 2a,  

length of the major axis

2a=10

a=5

The length of the minor axis is 2b.

Length of the minor axis

2b=6

b=3

The distance between the center and either focus is c,

c^{2} =a^{2} -b^{2}

c^{2} =5^{2} -3^{2}

c^{2} =25-9

c=8

So, the distance between the center are  the foci located 8 units.

Learn more about ellipse here:

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Answer: quit

Step-by-step explanation:

it’s really easy .

Answer:

a)7, b)-40

Step-by-step explanation:

a) 5(x-1)=30

=>5x -5=30

=>5x=30+5

=>5x=35

=>x=35/5

so, x=7

b)3(x+10)-2(x-5)=0

=>3x+30-2x+10=0

=>x+40=0

so,x=-40

Answer:

don't understand....................

Answer:

A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.

Step-by-step explanation:

Answer:

A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.

Step-by-step explanation:

Sample response

Answer:

Vertex is (-2.5, - 13.25) and x=(-5±sqrt(53))/2

Step-by-step explanation:

x^2+5x-7

x^2+5x+(2.5)^2-(2.5)^2-7

(x+2.5)^2-13.25. Vertex is (-2.5, - 13.25)

Solution of the functions are x=(-5±sqrt(53))/2

Answer:

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get

[tex]x-12=\sqrt{x}[/tex] and then square both sides to get

[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:

[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex]  If 16 is a solution, then this statement will be mathematically true.

[tex]\frac{7}{4+3}=1[/tex]  and   [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:

[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex]  We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

Answer:

x =  16

Step-by-step explanation:

[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16            {(-9)+(-16) = -25  & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0     ; x - 9 = 0

x = 16          ; x = 9

x = 9 is  an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]

       [tex]= \frac{0}{3+3}[/tex]

        = 0 ≠ RHS

So, x = 16 is the only  solution

Answer:

[tex]8 \times \frac{15}{5} - (5 + 9) \\8 \times 3 - (14) \\ 24 - 14 \\ = 10[/tex]

I hope I helped you^_^

Answer:

Step-by-step explanation:

Answer:

5/12

frsjnjjuvvffklomjyyrx

Answer:

BF = |4 – 1| = 3

FC = |4 – 0| = 4

Using the Pythagorean Theorem to find BC:

BC2  =  BF2 + FC2

BC2   =  32 + 42

BC2   =  9 + 16

BC  =  sqaure root 25

BC  =  5

Step-by-step explanation:

The length of BC is 5 unit.

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

We need to find the length of BC place point F at (4,4) and draw BF and FC now you have the right ∆BFC with BC as the hypotenuse find BC and FC using the coordinates of B,C, and,F then use the Pythagorean theorem to find BC.

Using the Pythagorean Theorem to find BC:

BC^2  =  BF^2 + FC^2

BC^2   =  32 + 42

BC^2   =  9 + 16

BC  =  √25

BC  =  5

So, BF = |4 – 1| = 3

FC = |4 – 0| = 4

Learn more about Pythagoras theorem here:

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Answer:

3/root8+root9

Step-by-step explanation:

3/root8+root9

Answer:

Option C, 832 units²

Step-by-step explanation:

l = 8

w = 7

h = 24

Surface area = 2(wl+hl+hw)

=2×(7×8+24×8+24×7)

=832 units²

Answer: YO ITS ANSWER C)832 UNITS[tex]^{2}[/tex] !!!!

Answer:

Its AA similaroty theorem

Answer: 7 miles/h and 1 miles/h

Step-by-step explanation:

With the speed of current = x + 1

Against the speed of current = x - 1

ATQ

4(x-1) = 3(x+1)

4x-4 = 3x+3

4x - 3x = 3+4

x = 7

Speed of boat = 7miles/h

Current of river = 1 miles/h

please click thanks and mark brainliest if you like :)

Answer:

Hello,

Boat speed=7 miles/h

Current speed = 1 mile/h

Step-by-step explanation:

I am going to try to explain.

Let say V the speed of the boot (V like vitesse in french)

Let say v the speed of the current.

distance=24 miles

[tex]\left\{\begin{array}{ccc}V-v&=&\dfrac{24}{4} \\V+v&=&\dfrac{24}{3} \\\end{array}\right.\\\\\left\{\begin{array}{ccc}V-v&=&6 \\V+v&=&8 \\\end{array}\right.\\\\Adding\ the\ 2\ equations\ and\ substracting\ them \\\\\\\left\{\begin{array}{ccc}2V&=&14 \\2v&=&2 \\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}V&=&7 \\v&=&1 \\\end{array}\right.\\\\[/tex]

Boat speed=7 miles/h

Current speed = 1 mile/h

Answer:

c

Step-by-step explanation:

AB and CD are opposite sides of quadrilateral.

Step-by-step explanation:

(=) 1 ( x-5 ) > 6x-17

(=) x-5 > 6x -17

(=) -5x > -12

=> x < 12/5

Hi there!

[tex]\large\boxed{y = \frac{x + 4}{7}}[/tex]

f(x) = 7x - 4

Rewrite f(x) with y:

y = 7x - 4

Swap the x and y variables:

x = 7y - 4

Solve for y:

x + 4 = 7y

y = (x + 4)/7

Answer:

[tex]n=10[/tex]

Step-by-step explanation:

[tex]\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n[/tex]

Simplify, remember, an exponent raised to the power of another exponent is equal to the product of the two exponents,

[tex]\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n[/tex]

[tex]\frac{4^8}{4^-^6}\ / 4^4=4^n[/tex]

Now bring the term in the denominator (number under the fraction bar) to the numerator (number over the fraction bar). This can be done by multiplying the exponent of the denominator by (-1).

[tex]\frac{4^8}{4^-^6}\ / 4^4=4^n[/tex]

[tex]4^8(4^(^-^1^)^(^-^6^))\ / 4^4=4^n[/tex]

Simplify,

[tex]4^8(4^6)\ / 4^4=4^n[/tex]

Remember, multiplying two numbers of the same base is the same as adding their exponents, apply this property here,

[tex]4^8(4^6)\ / 4^4=4^n[/tex]

[tex]4^1^4\ / 4^4=4^n[/tex]

Dividing two numbers of the same base is the same as subtraction their exponents,

[tex]4^1^4\ / 4^4=4^n[/tex]

[tex]4^1^0=4^n[/tex]

Thus, the following statement can be made,

[tex]4^1^0=4^n[/tex]

[tex]n=10[/tex]

Answer:

[tex]\frac{2}{a-b}[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{a+b}[/tex] + [tex]\frac{1}{a-b}[/tex] + [tex]\frac{2b}{a^2-b^2}[/tex] ← a² - b² is a difference of squares

= [tex]\frac{1}{a+b}[/tex] + [tex]\frac{1}{a-b}[/tex] = [tex]\frac{2b}{(a-b)(a+b)}[/tex] ← LCD is (a - b)(a+b)

= [tex]\frac{a-b+a+b+2b}{(a-b)(a+b)}[/tex]

= [tex]\frac{2a+2b}{(a-b)(a+b)}[/tex]

= [tex]\frac{2(a+b)}{(a-b)(a+b)}[/tex] ← cancel common factor (a + b) on numerator/ denominator

= [tex]\frac{2}{a-b}[/tex]