The correct answer of the question is "0.7062" and "0.835". The further solution is provided below.
Given:
Probability of student smoke,
P = 27.7%
= 0.277
Number of students (n) = 632
[tex]q = 1-p[/tex]
[tex]=1-0.277[/tex]
[tex]=0.723[/tex]
(i)
Here,
Number of students (n) = 60
then,
⇒ [tex]n_P=60\times 0.277[/tex]
[tex]=16.62[/tex]
⇒ [tex]n_q=60\times 0.723[/tex]
[tex]=43.38[/tex]
We can see that [tex]n_P > 10[/tex] and [tex]n_q>10[/tex] so the normal approximation condition are met.
Now,
[tex]\mu = n_P= 16.62[/tex]
[tex]\sigma = \sqrt{n_{Pq}}[/tex]
[tex]= \sqrt{60\times 0.277\times 0.723}[/tex]
[tex]=3.9664[/tex]
Now,
⇒ [tex]P(X<19) = P(X<18.5)[/tex]
[tex]=P(Z_{18.5})[/tex]
The Z-score is:
= [tex]\frac{18.5-16.62}{3.4664}[/tex]
= [tex]0.5423[/tex]
hence,
The probability will be:
⇒ [tex]P(Z_{18.5}) = 0.7062[/tex]
or,
⇒ [tex]P(Z<19) = 0.7062[/tex]
(ii)
Here,
Number of students (n) = 75
[tex]\mu = n_P = 75\times 0.277[/tex]
[tex]=20.775[/tex]
[tex]\sigma = \sqrt{n_{Pq}}[/tex]
[tex]=\sqrt{75\times 0.277\times 0.723}[/tex]
[tex]=3.8756[/tex]
Now,
⇒ [tex]P(X>17) = P(X> 17.5)[/tex]
[tex]=1-P(X \leq 17.5)[/tex]
[tex]=1-P(Z_{17.5})[/tex]
The Z-score is:
= [tex]\frac{17.5-20.775}{3.8756}[/tex]
= [tex]-0.9740[/tex]
then, [tex]P(Z_{17.5}) = 0.165[/tex]
hence,
The probability will be:
⇒ [tex]P(X>17) = 1-0.165[/tex]
[tex]=0.835[/tex]
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Square root of 33324324323
The Square root of 33324324323 is 182549.511977.
could someone please answer this? :) thank you
Answer:
The last one
Step-by-step explanation:
What we know:
We have a total of 16 coins
The 16 coins consist of dimes and quarters
The value of the coins is 3.10
The value of a dime is .10
The value of a quarter is .25
Using this information we can create a system of linear equations
First off we know that we have a total of 16 coins which consist of dimes and quarters
The number of Quarters can be represented by q and then number of dimes can be represented by d.
If we have a total of 16 coins then q + d must equal 16
So equation 1 is q + d = 16
Now we need to create a second equation
We know that the total value of the coins is 3.10 and we know that the coins consist of dimes and quarters
As you may know a quarter has a value of .25 cents and a dime has a value of 10 cents
If the total value of the coins is 3.10 the the number of dimes (d) times .10 + the number of Quarters times .25 must equal 3.10
This can also be written as
.25q + .10d = 3.10
So the two equations are
q + d = 16 and .25q + .10d = 3.10
These equations are shown in the last answer choice
Note: b is very similar to d
However the the value of the coins are incorrect in B
In B the value of the dime is represented by 10 which is not correct because the value of a dime is .10 not 10
Area of rectangle or triangle
Answer:
48 cm²
Step-by-step explanation:
shaded area = area of rectangle - area of triangle
area of rectangle = 7 × 8 = 56 cm²
area of triangle = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )
Here b = 7 - 3 = 4 cm and h = 8 - 4 = 4 cm
area of triangle = [tex]\frac{1}{2}[/tex] × 4 × 4 = 2 × 4 = 8 cm²
Then
shaded area = 56 - 8 = 48 cm²
g A gift shop sells 40 wind chimes per month at $110 each. The owners estimate that for each $11 increase in price, they will sell 2 fewer wind chimes per month. Find the price per wind chime that will maximize revenue.
Answer:
The price that maximizes the revenue is $165
Step-by-step explanation:
We can model the price as a function of sold units as a linear relationship.
Remember that a linear relationship is something like:
y = a*x + b
where a is the slope and b is the y-intercept.
We know that if the line passes through the points (x₁, y₁) and (x₂, y₂), then the slope can be written as:
a = (y₂ - y₁)/(x₂ - x₁)
For this line, we have the point (40, $110)
which means that to sell 40 units, the price must be $110
And we know that if the price increases by $11, then he will sell 2 units less.
Then we also have the point (38, $121)
So we know that our line passes through the points (40, $110) and (38, $121)
Then the slope of the line is:
a = ($121 - $110)/(38 - 40) = $11/-2 = -$5.5
Then the equation of the line is:
p(x) = -$5.5*x + b
to find the value of b, we can use the point (40, $110)
This means that when x = 40, the price is $110
then:
p(40) = $110 = -$5.5*40 + b
$110 = -$220 + b
$110 + $220 = b
$330 = b
Then the price equation is:
p(x) = -$5.5*x + $330
Now we want to find the maximum revenue.
The revenue for selling x items, each at the price p(x), is:
revenue = x*p(x)
replacing the p(x) by the equation we get:
revenue = x*(-$5.5*x + $330)
revenue = -$5.5*x^2 + $330*x
Now we want to find the x-value for the maximum revenue.
You can see that the revenue equation is a quadratic equation with a negative leading coefficient. This means that the maximum is at the vertex.
And remember that for a quadratic equation like:
y = a*x^2 + b*x + c
the x-value of the vertex is:
x = -b/2a
Then for our equation:
revenue = -$5.5*x^2 + $330*x
the x-vale of the vertex will be:
x = -$330/(2*-$5.5) = 30
x = 30
This means that the revenue is maximized when we sell 30 units.
And the price is p(x) evaluated in x = 30
p(30) = -$5.5*30 + $330 = $165
The price that maximizes the revenue is $165
Another name for the standardized score from a normally distributed variable is the _____.
A. standard score
B. z-score
C. t-score
D. normal score
Answer:
the answer is b). z- score.
Answer:
b
Step-by-step explanation:
find the amount of time to the nearest day it would take a deposit of $2500 to grow to $1 million at 2% compounded continuously. find how many days & years
Answer:
Years = natural log (Total / Principal) / Rate
Years = natural log (1,000,000 / 2,500) / .02
Years = natural log (400) / .02
Years = 5.9914645471 / .02
It would take 299.573227355 Years
Source: http://www.1728.org/rate2.htm
Step-by-step explanation:
integrate with respect to x 2tanx secant^2x/(1+ tan²x)
[tex] \displaystyle \int \bf \: \frac{2 \: tan \: x. {sec}^{2} \: x }{1 + {tan}^{2} \: x } \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = 2 \displaystyle \int \bf \: \frac{tan \: x \: . \: \cancel{ {sec}^{2} \: x}}{ \cancel{ {sec}^{2} \: x}} \: \: dx \: \: \: \: \pink{ \{ \because \: {sec}^{2} \: x - {tan}^{2} \: x = 1 \}} \\ \\ = 2 \displaystyle \int \bf \: tan \: x \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = 2 \displaystyle \int \bf \: \frac{sin \: x}{cos \: x} \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = - 2 \displaystyle \int \bf \: \frac{ - \: sin \: x}{ \: cos \: x} \: \: dx\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = \bf \: - 2 \ln \: |cos \: x| + c\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \green{ \{ \because \: \displaystyle \int \bf \: \frac{ {f}^{′} (x)}{f(x)} \: dx = \ln \: |f(x)| + c \}}[/tex]
in which quadrant angle 90+x lies 0 <x<90
Answer:
2nd quadrant
Step-by-step explanation
if an angle is between 90 and 180 degrees, it is in the second quardrant. since 0<x<90, 90+x will be more than 90 but less than 180, hence it lies in the second quadrant
Diện tích xung quanh của hình chóp tứ giác đều có cạnh bằng 6cm và độ dài trung đoạn bằng 10cm là:
A. 120 cm2 B. 240 cm2 C. 180 cm2 D. 60 cm2
Answer:
A
Step-by-step explanation:
(6.2).10=120cm²
Đáp án đó chúc bạn học tốt
The slide is inclined at an angle of 52.0°. Danny weighs 46.0 pounds. He is sitting in a cardboard box
with a piece of wax paper on the bottom. Stacey is at the top of the slide holding on to the cardboard
box. Find the magnitude of the force Stacey must pull with, in order to keep Danny from sliding down
the slide. (We are assuming that the wax paper makes the slide into a frictionless surface, so that the
only force keeping Danny from sliding is the force with which Stacey pulls.)
Answer:
Step-by-step explanation:
Since the slide is inclined at an angle of 52.0° to the horizontal, Danny's weight (mass, m) of 46.0 pounds has a component W = mgcos52.0° perpendicular to the incline and W' = mgsin52.0° parallel to the incline where g = acceleration due to gravity = 32 ft/s²
The perpendicular component of Danny's weight is the normal force to the incline. This normal force would determine the magnitude of the friction along the incline.
Since the wax paper makes the incline surface frictionless, so, there is no friction along the surface and thus the only horizontal force acting along the surface is the component of Danny's weight along the surface.
For Stacey to keep Danny from sliding down along the incline, the force she applies along the incline, F must be equal to the component of Danny's weight along the incline.
So, F = W'
F = mgsin52.0°
F = 46lb × 32 ft/s² × sin52°
F = 1472 lb-ft/s² 0.7880
F = 1159.95 lb-f
F ≅ 1160 lb-f
What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions
Answer:
so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.
Step-by-step explanation:
let the fraction be x
(1/4 + 1/6)-x = 1/12
or, 10/24 - x = 1/12
or, 5/12-1/12 = x
so, x = 4/12 = 1/3
Plz help’
!
I’ll be giving extra points
because it's value will always be same
Answer:
This value doesn't depend on x or y
It'll be the same things always
helppppp plsss ??? plssss ??
Answer:
3 is correct dear i hope it will help uPLZ ANSWER QUESTION IN PICTURE
Answer: [tex]y=\frac{1}{3}x+\frac{13}{3}[/tex]
Step-by-step explanation:
(slope = m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-6}{-1-5}=\frac{-2}{-6}=\frac{1}{3}[/tex]
[tex]y=mx+b, (5,6), (-1,4), m=\frac{1}{3}[/tex]
[tex]y=mx+b\\6=\frac{1}{3}(5)+b\\b=6-\frac{5}{3} \\b=\frac{13}{3}\\y=\frac{1}{3}x+\frac{13}{3}[/tex]
Researchers wanting to assess skin irritation associated with a new sunscreen developed for those with photosensitivity. They randomly sample 240 men with a history of photosensitivity and 240 men without a history of photosensitivity and ask them to apply the cream and report the level of skin irritation they experience after spending 20 minutes in the sun using a scale of 0-10. The average skin irritation score for the group with a history photosensitivity was 1.2 and the average skin irritation score for the group without a history of photosensitivity was 1.4. The Levene's test for equality of variances had a p value of 0.08. You know this means:
A. The researchers should report the t test results assuming equal variances. Select The researchers should report the t test results NOT assuming equal variances. as your answer
B. The researchers should report the t test results NOT assuming equal variances.
C. The researchers should reject the null hypothesis and report there is a difference in the average skin irritation score.
D. The researchers should fail to reject the null hypothesis and conclude there is NOT a difference in the average skin irritation score.
Answer:
Blablabka
Step-by-step explanation:
Blablabla
The least-squares regression equation
y = 8.5 + 69.5x can be used to predict the monthly cost for cell phone service with x phone lines. The list below shows the number of phone lines and the actual cost.
(1, $90)
(2, $150)
(3, $200)
(4, $295)
(5, $350)
Calculate the residuals for 2 and 5 phone lines, to the nearest cent.
The residual for 2 phone lines is $___
The residual for 5 phone lines is $___
Answer:
First one: 2.5
Second: -6
8.5+69.5(5) = 147.5
150 - 147.5 = 2.5
8.5 + 69.5(5) = 356
350 - 356 = -6
ED2021
The residual for 2 phone lines is $2.5.
The residual for 5 phone lines is -$6.
What is the residual in a least-square regression equation?
The residual is the vertical distance separating the observed point from your expected y-value, or more simply put, it is the difference between the actual y and the predicted y.
How to solve the question?In the question, we are asked to find the residual for 2 and 5 lines using the least-squares regression equation y = 8.5 + 69.5x and the actual costs given to us.
We know that the residual is the vertical distance separating the observed point from your expected y-value, or more simply put, it is the difference between the actual y and the predicted y.
Thus for 2 phone lines:-
Actual Cost = $150.
Predicted Cost, y = 8.5 + 69.5*2 = 147.5.
Residual = Actual Cost - Predicted Cost = 150 - 147.5 = $2.5.
Thus, the residual for 2 phone lines is $2.5.
Thus for 5 phone lines:-
Actual Cost = $350.
Predicted Cost, y = 8.5 + 69.5*2 = 356.
Residual = Actual Cost - Predicted Cost = 350 - 356 = -$6.
Thus, the residual for 2 phone lines is -$6.
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write 11.4 in standard form
[tex]11.4[/tex]
[tex] \to \: 1.14 \times {10}^{1} [/tex]
PLEASE HELP MIGHT GIVE BRAINLIEST!!!!! IM BEGGING YOU!!!!
Find the equation of the line with an x intercept of 4 and a y intercept of -1.5
Answer:
y = 4x -1.5
Step-by-step explanation:
The slope intercept form of a line is given by
y = mx+b where m is the slope and b is the y intercept
y = 4x -1.5
The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the improper integral L{f(t)}(s) = infinity 0 e-st.f(t)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant)
1. Find L{t}. (hint: remember integration by parts)
A. 1
B. -1/s2
C. 0
D. 1/s2
E. -s2
F. None of these
2. Find L{1}.
a.1/s
b. 1
c. 0
d. -s
e. -1/s
f. none of these
(1) D
[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]
Integrate by parts, taking
[tex]u = t \implies \mathrm du=\mathrm dt[/tex]
[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]
Then
[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]
(2) A
[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]
find the maximum number of children to whom 30 sweaters and 45 trousers can be equally divided. also how many sweaters and trousers will each get?
Answer:
five kids .each 6 sweaters and 9 trousers
Step-by-step explanation:
fpls help me with this. You need to graph the equation or smt
The average weekly assignment score of students in a statistics class is 7 out of 10 points. The professor proposes new incentives to boost the score of the students (like providing internship contacts etc.) He hopes that the results of running this incentives plan for a trial during the next couple of weeks will enable him to conclude that the incentives he offers increase the average weekly assignment score of students. What is the null hypothesis.
A. The average weekly score is strictly more than or equal to 7.
B. The average weekly score is less than our equal to 7.
C. The average weekly score is strictly less than 7.
D. The average weekly score is strictly more than 7.
Answer:
B. The average weekly score is less than or equal to 7.
Step-by-step explanation:
The average weekly assignment score of students in a statistics class is 7 out of 10 points. Test if it has increased.
This means that at the null hypothesis it is tested that the mean score of the students has not increased, that is, it still is of at most 7, so:
[tex]H_0: \mu \leq 7[/tex]
And thus, the correct answer is given by option b.
Laura, Scott, and Joe served a total of 104
orders Monday at the school cafeteria. Joe served 3
times as many orders as Scott. Laura served 9
more orders than Scott. How many orders did they each serve?
9514 1404 393
Answer:
Joe: 57Scott: 19Laura: 28Step-by-step explanation:
Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...
3s +s +(s +9) = 104
5s = 95 . . . . . . . . . . . subtract 9 and collect terms
s = 19 . . . . . . . . . divide by 5
3s = 3×19 = 57
s+9 = 19+9 = 28
Joe served 57 orders, Scott served 19, and Laura served 28 orders.
Please helpppppp i need help…
///..
ASAP!!!!
!!!,,!!!!!!
Answer:
True
Step-by-step explanation:
64 - x^2
Rewriting as
8^2 - x^2
(8-x)(8+x)
This is the difference of squares
of its employees based on the number of sales per hour. One employee had the following sales for the last 20 hours 3 4 5 5 6 7 What is the median for the distribution of number of sales per hour? ____________ Express as a number
The product of the roots of the equation x2 + x=2 is:
0-2
01
Answer:
-2
Step-by-step explanation:
x^2 + x=2
Subtract 2 from each side
x^2 + x-2=2-2
x^2 + x-2=0
Factor
What 2 numbers multiply to -2 and add to 1
2*-1 = -2
2+-1 =1
(x-1)(x+2)=0
Using the zero product property
x-1 = 0 x+2 = 0
x=1 x = -2
Product of the roots
1*-2 = -2
I want a correct answer you can take your time. If I was born on December 24, two thousand and four and my classmate was born on April 9, two thousand and six, how many months, years and days are we apart?
Answer:
5years, 3months, 16 days
Solve the equation for x 11x=110
For the polynomial 6xy2-5x?y?+9x? to be a trinomial with a degree of 3 after it has been fully simplified, what is the
missing exponent of the y in the second term?
0
e 1
2.
x 3
Answer:
The exponent of y is 1
Step-by-step explanation:
Given
[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]}[/tex]
[tex]degree = 3[/tex]
Required
The exponent of y (second term)
Since the polynomial has a degree of 3, the exponents of y will decrease from left to right (i.e. 2,1,0) while x will increase from left to right (i.e. 1,2,3)
So, we have:
[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]} = 6xy^2 - 5x^{[2]}y^{[1]} + 9x^{[3]}[/tex]
Remove square brackets
[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]} = 6xy^2 - 5x^2y + 9x^3[/tex]
The second term is:
[tex]T_2 =5x^2y[/tex]
The exponent of y is 1
Fisk Corporation is trying to improve its inventory control system and has installed an online computer at its retail stores. Fisk anticipates sales of 84,500 units per year, an ordering cost of $12 per order, and carrying costs of $1.20 per unit.
Required:
a.What is the economic ordering quantity?
b. How many orders will be placed during the year?
c. What will the average inventory be?
d. What is the total cost of ordering and carrying inventory?
Answer: A) Economic ordering quantity ==$1,300
B)Orders placed during the year= 65 orders
C)average inventory= 650units
D)total cost of ordering and carrying inventory= $1,560
Step-by-step explanation:
A) Economic ordering quantity =[tex]\sqrt{2 x Annual demand x ordering cost /carrying cost}[/tex]
=[tex]\sqrt{2 x 84,500 x 12} /1.20[/tex]
=[tex]\sqrt{1,690,000}[/tex]
=$1,300
B)Orders placed during the year= Annual demand ÷ economic order quantity
= $84,500 ÷ 1,300 units
= 65 orders
C)average inventory= Economic order quantity ÷ 2
= 1,300 units ÷ 2
=650units
D)total cost of ordering and carrying inventory
Ordering cost = Number of orders × ordering cost per order
= 65 orders × $12
= $780
Carrying cost = average inventory × carrying cost per unit
= 650 units × $1.20
= $780
The total would be = $780 + $780 = $1,560
