CaCl₂+2AgNO₃⇒Ca(NO₃)₂+2AgCl
mole CaCl₂: 3.5 g : 111 g/mole = 0.032
mole AgNO₃: 6.39 g : 170 g/mole = 0.038
mole: coefficient
CaCl₂: 0.032 : 1 = 0.032
AgNO₃: 0.038 : 2 = 0.019
AgNO₃ smaller= limiting reactant, then CaCl₂ = excess reactant
How many DIFFERENT ELEMENTS are in this compound?
H2SO4
Answer:
3 DIFFERENT ELEMENTS
Explanation:
H - Hydrogen
S- Sulfur
O- Oxygen
Therefore there are 3 elements
Different amounts of ice was added to several samples of water. The results are shown in the table. Which conclusion can be drawn from the results? A) more ice added caused a greater increase in temperature B) more ice added caused a greater change in temperature C) the final temperature of all the samples was the same D) the initial temperature was responsible for the temperature differences
The conclusion which can be drawn from the results that more ice added caused a greater change in temperature.
Why temperature of substance changes?Temperature of any substance will change if some amount of energy is absorbed or released by that substance in the form of heat.
If in simple water, we add some amount of ice then energy or heat from the whole mixture will released as a result of which temperature of the water decreases. And decrease in temperature will depend on the amount of added ice.
Hence, more ice added caused a greater change in temperature.
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Consider the chemical equation of the combustion of methane. Sort the components of the chemical equation according to whether they are reactants or products. ch4
Explanation:
The balanced equation is CH4(g)+2O2(g)→CO2(g)+2H2O(g) In the burning reaction, methane (CH₄) reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O): CH₄ + 2 O₂ → CO₂ + 2 H₂O This reaction obeys the law of conservation of mass because nothing was created or destroyed just rearranged
Answer:
Reactants: CH4
O2
Products: CO2
H20
Explanation:
Because i got it right on edge
I need help with this is for today
from the energy diagram shown to the right.
A) What species has an energy of 250 k)?
b) Calculate to
c) Calculate H
d) Is the overall reaction endothermic or
exothermic?
Which of the following is not a function of coral reefs?
Answer:
The answer is C: They are a key ingredient found in household bleach
is tomato candy good for people who didn't like the taste of tomato
Answer:
Eating tomatoes is one of the best things you can do. These beautiful, red fruit not only
thrill your taste buds and brighten your plate, they help fight disease. Studies show that
people who eat tomatoes, and lots of them, lower their risks of cancer because
tomatoes contain lycopene, a powerful antioxidant. -Tomatoe Farmers of America.
A. Is the bias negative or positive
B. What words, phrases or sentences made the paragraph biased or not biased?
Answer:
Candy Tomatoes are a low calorie fruit that is high in fiber. Their sweet flavour is a result of the high sugar content, but is balanced by the nutrition and health benefits provided by vitamin C, potassium, lycopene, and antioxidants.
Explanation:
Yeah it is good for people who didn't like the taste of tomato.
A gas has an initial volume of 5. 35l. What is the final volume if 588j of work is done on the gas by a constant external pressure of 2. 00atm?
Work done is the exchange of heat from the system and the surrounding. The final volume of the gas in the system is 2.45 L.
What is work done?Work done is the product of the pressure and the change in the volume of the gas in the system. The formula for work done is given as,
[tex]\rm w = -P\Delta V[/tex]
Given,
Initial volume = 5.35 L
Work done = 588 J
Pressure = 2.00 atm
Work done in joules is converted to L atm as, 588 joules = 5.80 Litres-atmosphere
Substituting values in the above equation:
[tex]\begin{aligned}\rm w &=\rm -P(V_{f} - V_{i})\\\\5.80 &= \rm - 2 (V_{f} - 5.35))\\\\5.80 - 10.7 &= \rm -2V\\\\&= 2.45\;\rm L\end{aligned}[/tex]
Therefore, 2.45 L is the initial volume of the gas.
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A solution is prepared by adding 91.9 g of ethanol, ch3ch2oh, to 481.0 ml of water. the final volume of the solution is 597.5 ml. assuming the density of water is 1.0 g/ml and the density of ethanol is 0.789 g/ml, calculate the molality of the ethanol in the solution.
Answer:
17.51M
Explanation:
first we make out what we've been given .
Mass of ethanol= 91.9g
volume of water = 481.0ml
volume of solution= 597.5ml
density of water = 1.0g/ml
density of ethanol= 0.789g/ml.
firstly find the volume of ethanol since the total volume of the solution is 597.5ml and we've been given the volume of water which is 481.0ml , we subtract the volume of water from the volume of the solution , to find out the volume of ethanol .
volume e =597.5ml - 481.0ml
= 116.5ml
Then we find the molecular mass of ethanol , which is 45.04g/mol .
then we find the number of moles of ethanol .
n=mass /molar mass
=91.9g/ 45.04g/mol
=2.04mols .
Then convert the volume from milliliters to liters , by dividing by a 1000 .
v= 116.5/1000
=0.1165L
since we have our number of moles and volume , we can now find the molarity . which is
M=n/v
= 2.04mols /0.1165L
= 17.51M .
A sample of argon has a volume of 5.00 L and the pressure is 0.920 atmIf the final temperature is 303.15 Kthe final volume is 5.70 Land the final pressure is 800mm Hg, what was the initial temperature of the argon?
Answer:
232.92K
Explanation:
The initial temperature of the argon is 232.9K.Calculation of the initial temperature:Since V₁ = 5dm³P₁ = 0.92atmT₂ = 30°CV₂ = 5.7LP₂ = 800mmHgHere we have to applied the gas lawP1V1/T1 = P2V2/T2Here p, v, and T are pressure, volume and temperature respetivelyAnd, 1 and 2 depict the initial and final states.Now we need to converttemperature to K and pressure into atmSo, it be like T₂ = 30°C = 273 + 30 = 303KP₂ = 800mmHg; 760mmHg = 1 atmSo, = 800/760 = 1.05 atmNow0.92*5 /T = 1.05*5.7/303So, the temperature is 232.92K
Calculate [h3o ] of the following polyprotic acid solution: 0. 140 m h3c6h5o7
The value of concentration of H₃O⁺ of the polyprotic acid solution 0.140M H₃C₆H₅O₇ is 2.1×10⁻⁴M.
What is Ka?Ka is the acid dissociation constant which shows its value in the equilibrium condition.
Given chemical reaction with ICE table is:
H₃C₆H₅O₇ → C₆H₅O₆⁻ + H₃O⁺
Initial: 0.140 0 0
Change: -x +x +x
Equilibrium: 0.140-x x x
Ka for the acid = (x)(x) / (0.140-x)
For the H₃C₆H₅O₇ acid value of Ka = 3.2 × 10⁻⁷
We can neglect the value of x from the term 0.140-x, as x is vey small as compared to 0.140 so that equation becomes,
3.2 × 10⁻⁷ = x² / 0.140
x = 2.1×10⁻⁴M
Hence the concentration of H₃O⁺ is 2.1×10⁻⁴M.
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Convert 0.880 moles of sucrose to cups of sugar
Answer:
2.00 Cups
Explanation:
This question isn't really possible without the density of the sugar, you can pack it tighter like if you have sugar cubes for example, but a quick search gives a density of 1.59 g/mL, so that what I will use.
Let's get the number of grams of sucrose (molar mass 342.3 g/mol) we have by taking 342.3 g/mol * 0.880 mol. Moles cancel and we get 301.224 grams of sucrose.
Now we just need to take the density, there is one mL for every 1.59 grams of sucrose, so we will take (301.224 g)/(1.59 g/mL). grams cancel and we are left with 478.94616 mL.
The question asked for cups (I'm assuming US cups) though, so let's convert by dividing by 240 to give us 1.995609 cups. Or when we round to sig figs we get 2.00 cups.
What is the molality of a solid solution containing 867 g of aluminum and 14.9 g of copper?
The molality of a solid solution containing 867 g of aluminum and 14.9 g of copper is 0.27 mol/kg.
What is the molality of a solution?The molality of a solution is a way to express the concentration of the solute in a given mass of solvent.
Molality of solution is given by the formula given below:
Molality = moles of solute/kilogram of solventIn the given solid solution, aluminium is the solvent while copper is the solute.
Mass of solvent = 867 g = 0.867 Kg
Moles of solute = mass/molar mass
molar mass of copper = 64.0 g
moles of solute = 14.9/64 = 0.233 moles
Molality of solution = 0.233 mol/0.867 kg = 0.27 mol/kg.
Therefore, the molality of a solid solution containing 867 g of aluminum and 14.9 g of copper is 0.27 mol/kg.
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PLEASE SOMEBODY EXPLAIN THIS :(((
Answer:
[tex] \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}[/tex]
Explanation:In Analytical Chemistry chromatography is widely used for the separation of samples.
In thin layer chromatography, the mixture of components are separated on the basis of their polarity. The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.Consider the mixture we have taken consist of two samples having large polar difference.Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.
Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.
Formula to calculate Rf value is
[tex] \sf R_f \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent} [/tex]
Now, solving for Rf value of sample 1
Given:
Distance moved by sample 1 = 11 mm
Distance movedby solvent = 35 mm
To find:
Rf value of sample 1 = ?
Solution:
Substituting the given data in above formula,
[tex] \small \sf R_f \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent} \\ \small \sf R_f \: value = \cancel\frac{11 \: mm}{35 \: mm} = 0.3142[/tex]
[tex] \small \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}[/tex]
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A gas occupies 47.5 Lat 0.6 atm.
What is the pressure if the volume becomes 6.8 L?
Answer:
The pressure if the volume becomes 6.8L would be 4.19atm
Explanation:
Boyle's law:
P1 V1= P2 V2
P1 = 0. 6 atm
P2 = ?
V1 = 47. 5 L
V2 = 6. 8 L
P2 = 0.6 × 47.5 ÷ 6.8
P2 = 4.19 atm
The pressure if the volume becomes 6.8L is 4.19atm
