Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probability of the length of a randomly selected Cane being between 360 and 370 cm

Answer:no it doesn’t vary

Step-by-step explanation:because if you count them up there is no possibility that they match

Answer:

9x-2

Step-by-step explanation:

Since you are adding the two functions, you should first start adding like terms. 4x + 5x is 9x. -8 + 6 is -2. Thus the value of (f+g)(x) is 9x-2.

Answer:

[tex] V = \frac{1}{3} \pi (5)^2 (12)= 314.159[/tex]

Now if we increase the radius by a factor of 2 the new volume would be:

[tex] V_f = \frac{1}{3} \pi (2*5)^2 (12)= 1256.637[/tex]

And we can find the increase factor for the volume like this:

[tex] \frac{V_f}{V}= \frac{1256.637}{314.159}= 4[/tex]

Then if we increase the radius by 2 the volume increase by a factor of 4

If we reduce the radius by a factor of 2 then we will have that the volume would be reduced by a factor of 4.

On the figure attached we have an illustration for the cases analyzed we see that when we increase the radius the volume increase and in the other case decrease.

Step-by-step explanation:

For this case we have the following info given:

[tex]r = 5 , h =12[/tex]

and we can find the initial volume:

[tex] V = \frac{1}{3} \pi r^2 h[/tex]

And replacing we got:

[tex] V = \frac{1}{3} \pi (5)^2 (12)= 314.159[/tex]

Now if we increase the radius by a factor of 2 the new volume would be:

[tex] V_f = \frac{1}{3} \pi (2*5)^2 (12)= 1256.637[/tex]

And we can find the increase factor for the volume like this:

[tex] \frac{V_f}{V}= \frac{1256.637}{314.159}= 4[/tex]

Then if we increase the radius by 2 the volume increase by a factor of 4

If we reduce the radius by a factor of 2 then we will have that the volume would be reduced by a factor of 4.

On the figure attached we have an illustration for the cases analyzed we see that when we increase the radius the volume increase and in the other case decrease.

Answer:

  13.5%

Step-by-step explanation:

The probability of interest is the cumulative probability of a binomial probability density function with 18 trials and a probability of success of 0.25. We are interested in the value for x ≤ 2.

Such a calculation can be done "by hand" by adding up the probabilities for 0, 1, and 2 people. (A calculator is needed for the arithmetic.) One may as well use the appropriate function of a calculator to find the probability:

  binomcdf(18, 0.25, 2) ≈ 0.135

The probability is about 13.5%.

Answer:

B. -4<x<2

Step-by-step explanation:

The highest x point is -4 and lowest peak is 2

Answer:

B. -4 ≤ x ≤ 2

Step-by-step explanation:

→Basically, the question is asking, "At what point is the line on the graph decreasing?"

→Looking at the graph, you can see that when x = -4, that's when the line on the graph starts to decrease. The line continues to decrease, until it reaches the point where x = 2.

This makes the correct answer "B. -4 ≤ x ≤ 2."

Answer:

Test statistic t=1.2531.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters (P-value=0.11).

Step-by-step explanation:

The question is incomplete: We need the gestation length of the population to perform the hypothesis test. We assume it to be 16 days (μ=16).

This is a hypothesis test for the population mean.

The claim is that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=16\\\\H_a:\mu> 16[/tex]

The significance level is 0.05.

The sample has a size n=27.

The sample mean is M=17.4.

The sample variance is s^2=33.7 days^2.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=33.7^(0.5)=5.81.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.81}{\sqrt{27}}=1.1172[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{17.4-16}{1.1172}=\dfrac{1.4}{1.1172}=1.2531[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=27-1=26[/tex]

This test is a right-tailed test, with 26 degrees of freedom and t=1.2531, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=P(t>1.2531)=0.11[/tex]

As the P-value (0.11) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters.

Answer:

F(2)=3

Step-by-step explanation:

The first term is -1.5= f(1).

So  F(1+1)=-2*f(1)= (-1.5)*(-2)=3

Answer:

The confidence interval is ( 0.225952516, 0.474047484)

People will get different results because, the amount of sedans may be dependent on the area in which the data is taken.

No, the sample is not really a good representation of the whole population of vehicles, since only a certain area was sampled or experimented.

Step-by-step explanation:

Solution

Given that:

From the experiment we discovered that out of 40 vehicles, 14 of them were sedans.

Let us note that:

p^ = It is the point estimate of the population proportion

Where,

n=/n  = 0.35

We also check for the standard error of p, sp:

which is,

sp =√{p^ (1-p^)/n] =0.075415516

Thus,

for the the critical z, we have the following:

α/2 = 0.05

So,

z (α)/2 = 1.644853627

Thus,

For lower bound = p^ - z(α/2) * sp = 0.225952516

For upper bound = p^ + z(α/2)* sp = 0.474047484

Hence,

The confidence interval becomes: ( 0.225952516, 0.474047484)

Answer:

279 m

Step-by-step explanation:

Work by friction = change in kinetic energy

Fd = ½ mv²

d ∝ v²

d / 29 m = (105.4 mph)² / (34.0 mph)²

d = 279 m

Answer:

-127

Step-by-step explanation:

u(x)=2x-2

w(x)= -2x^2+1

w(u(5))=?

---------

u(5)= 2*5-2= 8

W(8)= - 2*64+1= -127

Answer:

that was the wrong answer this site sucks

Answer:

Amount invested at 4% is $16,000

Amount invested at 9% is  $6,000

Step-by-step explanation:

Let one vestment be x

if total investment is $22,000 then

other investment will  $22,000 - x

simple interest earned in any year is given by

SI = p*r*t/100

where SI is the interest earned

t is the time period of investment

r is the rate of annual interest

_____________________________________

interest on one account 4%

p = x

t = 1 year

SI = x*4*1/100 = 4x/100

_____________________________

interest on one account 9%

p = 22,000 - x

t = 1 year

SI = (22,000 - x)*9*1/100 = (198000 - 9x)/100

_____________________________________

it is given that total interest earned was $1180

thus sum of SI calculated for the 9% and 4% investment will be equal to 1180

4x/100 +  (198000 - 9x)/100 = 1180

=> (4x+198000 - 9x)/100 = 1180

=> 198000 - 5x = 1180*100

=> -5x = 118,000 - 198000

=> -5x = -80,000

=> x = -80,000/-5 = 16,000

Thus,

Amount invested at 4% is $16,000

Amount invested at 9% is $(22,000 - 16,000) = $6,000

Answer & Step-by-step explanation:

We are given that m∠1 = m∠2. We are to prove that line l is parallel to line m. So, let's make a proof. Your first statement should always be the given statement. You are given the statements. All we have to do is find the reasons for those statements.

Answer:

42 13/20 km

Step-by-step explanation:

10 3/10+9 7/20+14 7/10+ 8 9/20=41+ (6+7+14+9)/20=41 + 1 13/20= 42 13/20 km

Answer:

122 miles per hour.

Step-by-step explanation:

Time:108 min ÷60 =1.8 hours

Speed = distance /time = 219/1.8 =122 miles per hour.

Hope this helps..

Answer:

No its 121.67 mph.

Step-by-step explanation:

Speed in miles per minute is 219/108 miles per minute

To convert to miles per hour we multiply by 60:

= 219 * 60 / 108

= 121.67 m p h.

Answer:

B

Step-by-step explanation:

because if you do 40 times 6 and 45 times 6 you get 270 and 240 and you add them up for 510

Answer:

[tex]3.1/13[/tex]

Step-by-step explanation:

[tex]1.5/7 =0.214286[/tex]

[tex]2.7/10=0.27[/tex]

[tex]3.1/13 =0.238462[/tex]

Answer:

3 tokens.

Step-by-step explanation:

We need the roulette image, therefore we will suppose one that I will leave as an attached image:

The main thing to keep in mind in this case is that the probabilities are the same, therefore you don't have to take that into account, just operate with the values of each sector, therefore the expected value would be:

expected value = profit - loss

expected value = (5 + 5) - (4 + 3)

expected value = 10 - 7 = 3

This means that the number of tokens waiting for the student to earn for each spin is 3 tokens.

Answer:

b < 13

Step-by-step explanation:

Idk what you're asking but I'll try.

[tex]\frac{b}{1}=b[/tex]

b < 13

Answer:

b > -27.

Step-by-step explanation:

b / -3 + 4 < 13

b/-3 < 13 - 4

b/-3 < 9

-b/ 3 < 9

Multiply both sides by -3 ( the inequality sign will flip):

b > -27

Answer:

B

Step-by-step explanation:

The coordinates of quadrilateral Q'P'R'S' is

Q'(4, 8), P'(0, 0), R'(-4, -8), S'(8, -4).

A scale factor is defined as the ratio between the scale of a given original object and a new object,

We have,

To perform a dilation centered at the origin with a scale factor of 2, we need to multiply the x and y coordinates of each vertex by 2.

So starting with the coordinates of quadrilateral QPRS:

Q(2, 4), P(0, 0), R(-2, -4), S(4, -2)

Multiplying each coordinate by 2, we get:

Q'(4, 8), P'(0, 0), R'(-4, -8), S'(8, -4)

Therefore,

The coordinates of quadrilateral Q'P'R'S' is

Q'(4, 8), P'(0, 0), R'(-4, -8), S'(8, -4).

Learn more about scale factors here:

https://brainly.com/question/20759556

#SPJ3

The complete question.

Quadrilateral QPRS is transformed by a dilation centered at the origin with a scale factor of 2 to create quadrilateral Q'P'R'S'. Which are the coordinates of quadrilateral Q'P'R'S'?

Where

The coordinates of PQRS are:

Q = (2, 4), P = (0, 0), R = (-2, -4), S = (4, -2).

Answer:

[tex]y=32[/tex]

Step-by-step explanation:

[tex]\frac{7}{4}y=56\\\mathrm{Multiply\:both\:sides\:by\:}4\\4\cdot \frac{7}{4}y=56\cdot \:4\\\mathrm{Simplify}\\7y=224\\\mathrm{Divide\:both\:sides\:by\:}7\\\frac{7y}{7}=\frac{224}{7}\\Simplify\\y=32[/tex]

Answer:

Find the point on the curve r(t) = (5Sint)i + (5Cost)j +12tk

at a distance 26pi units along the curve from the point (0,5,0) inthe direction of increasing arc length.

(My attempt):

T comes to be 2pi and when the integral is done and solved to givea value of 26pi and the position comes to be (0,5,24pi). However,this calculation and answer though correct (according to the backof the book) does not involve the use of the fact that at time t=0,the particle is at (0,5,0).

What for is that information given then?

Step-by-step explanation:

Consider the curve r(t) = (5Sint)i + (5Cost)j + (12t)k

Need to find the point on the given curve at a distance 26π unit along the curve  from the point (0,5,0) inthe direction of increasing arc length.

Length of a smooth curve is [tex]r(t)=x(t)i+y(t)j+z(t)k, \ \ a\leq t\leq b[/tex] that is traced exactly once as t increase from t = a to t = b, is

[tex]L=\int\limits^b_a \sqrt{(\frac{dx}{dt} )^2+(\frac{dy}{dt} )^2+(\frac{dz}{dt} )^2dt}[/tex]

For the given curve

x(t) = 5 sin t

y(t) = 5 cos t

z(t) = 12t

When t = 0

x(0) = 5 sin 0

= 0

y(0) = 5 cos 0

= 0

z(0) = 12(0)

=0

So, the point (0, 5, 0) corresponds to t = 0

So let t = t₀ correspond to any point (x, y, z) on the curve at a distance of 26pi  units from the point t = 0 along the increasing arc length

So, the length of curve from the point t = 0 to  t = t₀ is L = 26pi units

Substitute the known value to the arc length formula

[tex]L=\int\limits^b_a \sqrt{(\frac{dx}{dt} )^2+(\frac{dy}{dt} )^2+(\frac{dz}{dt} )^2dt}[/tex]

[tex]26\pi=\int\limits^{t_0}\sqrt{(5 \cos t)6+(-5 \sin t)^2+(12)^2dt}\\\\26\pi=\int\limits^{t_0}_0\sqrt{25 \cos ^2t+25 \sin ^2t+144dt} \\\\26\pi=\int\limits^{t_0}_0 \sqrt{25(\cos^2t+ \sin^2t)+144dt}\\\\26\pi=\int\limits^{t_0}_0\sqrt{25(1)+144dt} \\\\26\pi= \int\limits^{t_0}_0\sqrt{169dt} \\\\26\pi= \int\limits^{t_0}_013 dt\\\\26\pi=13\int\limits^{t_0}_0dt\\\\26\pi=13[t]^{t_0}_0\\\\26\pi=13[t_0-0]\\\\26\pi=13t_0\\\\t_0=\frac{26\pi}{13} \\\\t_0=2\pi[/tex]

The point corresponding to [tex]t_0 = 2\pi[/tex]

when t = 0

[tex]x(2\pi)=5 \sin (2\pi)\\\\=0\\\\y(2\pi)=5 \cos (2\pi)\\\\=5(1)=5\\\\z(2\pi)=12(2\pi)\\\\=24\pi[/tex]

Therefore the point corresponding to  [tex]t_0 = 2\pi[/tex] is [tex](0,5,24\pi)[/tex]

Hence, the required point on the given curve at distance 26\pi units along the curve from the point (0,5,0) in  the direction of increasing arc length is [tex](0,5,24\pi)[/tex]

Answer:

The formulas that will appear in

C1 is =B$2

D1 is = C$2

E1 is = D$2

Step-by-step explanation:

Given

Formula in B1 is = A$2

Required

Formulas in C1, D1 and E1 when dragged from B1.

In Microsoft Office Excel, this is called absolute reference.

But this type of absolute reference requires that only the cell name will be changed or altered, the row number will always remain the same no matter where it's been dragged to.

Since the initial column name is A and the Initial row number is 2 (from A$2),

Cell C1 will take the formula = B$2

Cell D1 will take = C$2

Cell E1 will take = D$2

Notice that only the column name changed for each formula; the row number remain unchanged.

Answer:

=B$2, C$2, D$2

Step-by-step explanation:

Answer:

? = 8.77

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opposite/ hypotenuse

sin 20  = 3/?

? = 3 / sin 20

? =8.7714132

To the nearest hundredth

? = 8.77

We can use the trigonometric function [ sin theta = opposite/hypotenuse ] to solve.

sin(20) = 3/hypotenuse

hypotenuse = 3/sin(20)

hypotenuse = 8.7714...

Round to the nearest hundredth.

8.7714... → 8.77

Therefore, the answer is 8.77

Best of Luck!

Answer:

x = 23/5 and y = 7/20

Step-by-step explanation:

2x + 8y = 12 and 3x - 8y = 11 are two given equations

Now,

Step 1:

2x + 8y = 12 ...(1)

3x - 8y = 11 ...(2)

Step 2:

From equation (2) we get the value of x

i.e.,

3x - 8y = 11

3x = 8y + 11

x = 8y + 11/3

Step 3:

Now,

Put the value of x = 8y + 11/3 in equation (1) we get,

i.e.,

2x + 8y = 12

2(8y + 11/3) + 8y = 12

16y + 22/3 + 8y = 12

16y + 22 + 8y(3)/3 = 12

16y + 22 + 24y/3 = 12

16y + 24y + 22 = 12 * 3

40y = 36 - 22

40y = 14

y = 14/40

y = 7/20

Step 4:

Now,

Substitute the value of y = 7/20 in equation (2) we get,

i.e.,

3x - 8y = 11

3x - 8(7/20) = 11

3x - 56/20 = 11

3x - 14/5 = 11

3x = 11 + 14/5

3x = 11 * 5 + 14/5

3x = 55 + 14/5

3x = 69/5

x = 69/3 * 5

x = 23/5

Answer:

30 Nickels and 188 Pennies

Step-by-step explanation:

okay, so to set up the equation first, we have to assign each coin a variable, let's call them p and n:

P= number of pennies

N= number of nickels

the value of a penny is 1 cent, so 1P, and the value of a nickel is 5 cents, so 5N

The problem states that he has 218 coins, meaning that the total number of pennies and nickels adds up to 218:

P + N = 218

the total value of the coins is $3.38, so that would mean that 1P + 5N has to equal $3.38:

1P + 5N = 338

Okay, so now that we have our equations let's solve them using elimination:

we have to get a common coefficient between both equations, so let's multiply our first equation by 5:

P x 5 = 5P

N x 5 = 5N

218 x 5 = 1090

so, now we can solve by elimination:

5P + 5N = 1090

1P + 5N = 338

the N's cancel out:

4P = 752

divide both sides by 4:

P = 188

okay, so if theres a total of 218 coins, subtract 188 from 218:

218 - 188 = 30

so, there are 30 nickels and 188 pennies.

check our work:

5 x 30 = 150

1 × 188 = 188

150 + 188 = 338

338 = 338

I hope this helps! :)

Answer:

a) [tex]7.4-1.96\frac{1.9}{\sqrt{36}}=6.78[/tex]    

[tex]7.4+1.96\frac{1.9}{\sqrt{36}}=8.02[/tex]    

b) For this case we can conclude that at 95% of confidence the true mean for the lenght of all welleye fingerprints in a fish hatchery pond is between 6.78 and 8.02

c) For this case since the value of 7.5 is included in the confidence interval we don't have enough evidence to conclude that the true mean is actually higher than 7.5 inches

Step-by-step explanation:

Information given

[tex]\bar X=7/4[/tex] represent the sample mean

[tex]\mu[/tex] population mean (variable of interest)

[tex]\sigma=1.9[/tex] represent the population standard deviation

n=36 represent the sample size  

Part a

The confidence interval for the mean is given by :

[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]   (1)

The Confidence is 0.95 or 95%, the significance is [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value would be [tex]z_{\alpha/2}=1.96[/tex]

Replacing the info we got:

[tex]7.4-1.96\frac{1.9}{\sqrt{36}}=6.78[/tex]    

[tex]7.4+1.96\frac{1.9}{\sqrt{36}}=8.02[/tex]    

Part b

For this case we can conclude that at 95% of confidence the true mean for the lenght of all welleye fingerprints in a fish hatchery pond is between 6.78 and 8.02

Part c

For this case since the value of 7.5 is included in the confidence interval we don't have enough evidence to conclude that the true mean is actually higher than 7.5 inches