Starting from rest, a 94-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a magnitude of 750 N, and his speed at the bottom of the pole is 3.1 m/s. How far did he slide down the pole

Answers

Answer 1

Given that,

Mass of a firefighter, m = 94 kg

Frictional force, F = 750 N

Speed at the bottom of the pole is 3.1 m/s

It is required to find the distance he slide down the pole.

Using Work-energy theorem,

initial potential energy = final kinetic energy + work done

[tex]mgh=W+\dfrac{1}{2}mv^2[/tex]

[tex]mgh=Fh+\dfrac{1}{2}mv^2[/tex]

Solving for h, such that :

[tex]h(mg-F)=\dfrac{1}{2}mv^2\\\\h=\dfrac{1}{2(mg-F)}mv^2\\\\h=\dfrac{1}{2(94(9.8)-750)}\times 94\times (3.1)^2\\\\h=2.63\ m[/tex]

So, he will slide 2.63 m down the pole.


Related Questions

What role do planetesimals play in the origin of the planets?

Answers

A planetesimal is small bodies from which a planet originated in the early stages of formation of the solar system. Protoplanets are when planetesimals join together through collisions and through the force of gravity to form larger bodies. ... Because they have their gases they are not as dense as the inner planets.

what is it? and explain pls

Answers

The velocity at which an object is sent moving and the mass of the object both play a hand in the level of kinetic energy that object produces. Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

Using five or more sentences, describe petroleum and what it is used for.

(I might mark brainliest if it is a good response) :D

Answers

Answer:

A liquid mixture of hydrocarbons that is present in certain rock strata and can be extracted and refined to produce fuels including gasoline, kerosen, diesal oil. :)

Explanation:

Yea mark brainleist pls

Find the terminal velocity of a spherical bacterium (diameter ) falling in water. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be .

Answers

Complete Question

Find the terminal velocity of a spherical bacterium (diameter [tex]2.00 \mu m[/tex] ) falling in water. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be [tex]1.10 *10^{3} \ kg/m^3[/tex]

Answer:

The value is [tex]v_t = 2.38*10^{-6} \ m/s[/tex]

Explanation:

From the question we are told that

   The diameter of the  spherical bacterium is [tex]d = 2.0\mu m = 2.0 *10^{-6} \ m[/tex]

     The density of the bacterium is  [tex]\rho =1.10 *10^{3} \ kg/m^3[/tex]

Generally the radius is mathematically represented as

       [tex]r = \frac{d}{2}[/tex]

=>   [tex]r = \frac{2.0 *10^{-6}}{2}[/tex]

=>   [tex]r = 1.0*10^{-6}[/tex]

Generally the volume is mathematically represented as

     [tex]V = \frac{4}{3} * \pi * r^2[/tex]

=>[tex]V = \frac{4}{3} * 3.142 * (1.0*10^{-6})^3[/tex]

=>[tex]V = 4.189 *10^{-18} \ m^3[/tex]

Generally the mass is mathematically represented as

     [tex]m = V * \rho[/tex]

=>  [tex]m = 4.189 *10^{-12} * 1.10 *10^{3}[/tex]

=>  [tex]m = 4.608 *10^{-15} \ kg[/tex]

Generally the terminal velocity is mathematically represented as

     [tex]v_t = \frac{m * g}{ 6\pi * r * \eta}[/tex]

Here  [tex]\eta[/tex] is the viscosity of water with value  [tex]\eta = 1.005 *10^{-3} \ kg/m\cdot s[/tex]

So

     [tex]v_t = \frac{4.608 *10^{-15} * 9.8}{ 6 * 3.142 *1.0*10^{-6} * 1.005 *10^{-3}}[/tex]

=>  [tex]v_t = 2.38*10^{-6} \ m/s[/tex]

A 11.8-kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 10.4 m/s, determine the following. (a) the translational kinetic energy of its center of gravity J (b) the rotational kinetic energy about its center of gravity J (c) its total kinetic energy J

Answers

Answer:

1. 638.144j

2. 319.072 j

3. 957.216 j

Explanation:

M = 11.8 kg cylinder

V = speed of center of gravity = 10.4m/s

A.

Translational kinetic energy

= 1/2mv²

1/2x 11.8kg x 10.4²

= 11.8x108.16/2

= 1276.288/2

= 638.144 J

This is the translational energy

B.

Rotational energy

1/2Iw²

I = mv²/2

w = v/r

When we substitute

1/2[mv²/2][v/r]²

= 1/4mv²

= 1/4 x 11.8 x 10.4²

= 1276.288/4

= 319.072

This is the rotational energy

C

Total kinetic energy.

We add the values of A and B above to get this.

638.144 J + 319.072 J

= 957.216J

The exchange of oxygen and carbon dioxide takes place through the capillary wall.
True
False

Answers

Explanation:

It mainly flows blood to arteries of heart but the answer is true.. because it also exchange oxygen,nutrient etc..

Find the electric field due to an infinite plane of positive charge with uniform surface charge density

Answers

Answer:

Explanation:

The Electric field due to an infinite plane of positive charge with uniform surface charge density can be derived a s follows

let us assume An infinite positively charged sheet and lets take a cylindrical gaussian surface on this surface which is perpendicular to this plane of sheet

we know that positive charge electric field lines will be perpendicular to this sheet surface will be perpendicular to the cylindrical surface

applying gauss law

[tex]Electric field * Area =[/tex] [tex]charge/epsilon\\[/tex]

also sigma=Q/A ⇒ Q=sigma*A

so on one face

E*A=sigma*A/epsilon

also we notice this electric field on one face of the sheet is exactly equal to that on the another face hence electric field will be twice

2E*A=sigma*A/epsilon

final result

[tex]E= sigma/2*epsilon[/tex]

The spacecraft that have visited the outer planets have all flown close to inner planets (Venus, for example), often more than once, as part of their journeys. What was the primary reason for this?

Answers

Answer:

1) The outer planets happened to have been on the far side of the sun, so the shortest route passes the inner planets

Explanation:

All the planets revolve around the sun in a circular orbital. The orbits of Mercury, Venus, Earth, and Mars are tightly held with sun as they are very close to the sun and revolve faster in comparison to outer planet Jupiter, Saturn, Uranus, and Neptune.

Because of the shortest distance between the sun and inner planets, the spacecraft is able to visit the inner planet more than once while outer planets are very far from the sun and revolve around a large orbit, so the spacecraft visited the outer planets less than the inner planet.

Hence, the correct answer is "1".

The magnetic dipole moment of Earth has magnitude 8.00 × 1022 J/T. Assume that this is produced by charges flowing in Earth's molten outer core. If the radius of their circular path is 3470 km, calculate the current they produce

Answers

Answer:

Explanation:

Dipole moment of a coil carrying current i with area A

M = i A , M is magnetic moment , i is current and A is area of the coil.

A = π R²

= 3.14 x ( 3470 x 10³ )²

= 3.78 x 10¹³  m²

8.00 x 10²² = 3.78 x 10¹³ x i

current i = 8.00 x 10²²  / 3.78 x 10¹³

= 2.11 x 10⁹ A .

A solid sphere, with a mass of 3 kg, is rolling across a horizontal floor without slipping. The sphere has 8.4 J of total kinetic energy and has a center of mass velocity of 2 m/s. Calculate the rotational kinetic energy of the solid sphere.

Answers

Answer:

2.4 J

Explanation:

The total kinetic energy of the solid sphere = rotational kinetic energy + translational kinetic energy

KE(total) = KE(rot) + KE(trans)

KE(rot) = KE(total) - KE(trans)

Since its total kinetic energy KE' = 8.4 J and its mass, m = 3 kg and the velocity of its center of mass, v = 2m/s, KE(trans) = 1/2mv² = 1/2 × 3 kg × (2 m/s)² = 3 kg × 2 m²/s² = 6 kgm²/s² = 6 J

So, KE(rot) = KE(total) - KE(trans)

Substituting the values of the variables, we have

KE(rot) = 8.4 J - 6 J

KE(rot) = 2.4 J

So, the rotational kinetic energy of the solid sphere is 2.4 J

The rotational kinetic energy of the solid sphere will be "2.4 J".

Kinetic energy

According to the question,

Total Kinetic energy, KE' = 8.4 J

Mass, m  = 3 kg

Center of mass's velocity, v = 2 m/s

Now,

KE(trans) = [tex]\frac{1}{2}[/tex]mv²

By substituting the values,

               = [tex]\frac{1}{2}[/tex]  × 3 × (2)²

               = [tex]\frac{1}{2}[/tex] × 3 × 4

               = 6 kgm³/s² or,

               = 6 J  

We know the relation,

→ KE(rot) = KE(total) - KE(trans)

By putting the values,

              = 8.4 - 6

              = 2.4 J

Thus the approach above is correct.  

Find out more information about kinetic energy here:

https://brainly.com/question/25959744

Does heat and temperature depend on the other or are they totally separate ideas? Explain.

Answers

Answer:

What heat means in thermodynamics, and how we can calculate heat using the heat ... Scientists define heat as thermal energy transferred between two systems

Explanation:

thermal energy

A pilot wants to fly north. The plane has an air speed of
350 km/h. There is a 25 km/h wind blowing to the west.
(a) What is the plane's velocity relative to the ground?
(b)What is its heading?

Explain me in details. I’ll give u the brainliest if you give me the right answer.

Answers

Answer:

A? Cause is needs the Velocity more than the Heading.

What best describes a bar magnet

Answers

Answer:Bar magnets are permanent magnets as opposed to electromagnets


Answer Expert Verified
Bar magnets are permanent magnets as opposed to electromagnets. While electromagnets require electric current to be magnetised, and so they can be turned on and turn off, bar magnets are made of magnetic materials and have two poles which cannot be turned

the weight of a box having a mass of 100kg is blank N.

Answers

Answer:

What is the answer we are supposed to be finding?

Explanation: Your answer is 980.7 if you are converting kilograms to Newtons

what is the average speed of a student 100cm/s Bernard 150 cm/s Chloe 50 cm/s Dev 75 cm/s Eduardo 125cm/s

Answers

Answer:

100cm/s

Explanation:

Given the speed of the following students;

Bernard 150 cm/s

Chloe 50 cm/s

Dev 75 cm/s

Eduardo 125cm/s

Their average speed of a student will be the mean of their individual speed as shown:

Average speed = 150+50+75+125/4

Average speed = 400/4

Average speed = 100

Hence the average speed of a student is 100cm/s

A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

Answers

Answer:

-62.02πrads/sec^2

Explanation:

A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

We need to convert to SI unit

9.549rev/ min= 1rad/sec

Then to convert angular speed of 3,550 rev/min to rad/sec

( 1 rad/sec)/9.549rev/min = x/5600rev/min

Then

(3,550 rev/min)/(9.549rev/min)= 371.77rad/sec

=118.4πrad/sec

6.823rad= 1rev

52.0 revolutions = 52×6.823= 354.796rads

= 113πrads

We will use expresion below to calculate our angular acceleration

w^2 - w^2(0)= 2α¢

Where w= angular speed

w(0)= initial angular

If final angular speed= 0

α=-w^2(0)/2¢

α=(-118.4π)^2/(2×113)

=-14018.56/226

-62.02πrads/sec^2

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