Solving systems by elimination.

C is the closest to 78.089

Answer:

130°

Step-by-step explanation:

p and the 50° angle form a straight line/straight angle, meaning they are supplementary.

Supplementary angles add to 180°.

p+50=180

p=130

130°

Answer:

130

Step-by-step explanation:

angles formed by a straight line add up to equal 180°

Thus, 180 = 50 + p

180 - 50 = 130

50 - 50 cancels out

we're left with p = 130

Answer:

Choice 3... 2x + 3 =y

Step-by-step explanation:

9514 1404 393

Answer:

  $2560.00

Step-by-step explanation:

The account balance is given by the formula ...

  A = Pe^(rt) . . . . principal P invested at rate r for t years

Filling in your numbers, we have ...

  $3287.11 = Pe^(0.05·5)

  P = $3287.11e^(-0.25) = $2560.00

The initial amount was $2560.00.

Answer:

A

Step-by-step explanation:

not sure though sorry if wrong

Answer:

The answer of upper level of A is correct

Step-by-step explanation:

f(x) = x²

f'(x) = (x-3)²   ..... x -> x-3  Horizontal translation right 3 units

g(x) = (x-3)² - 5  .... vertical translation down 5 units

Answer:

x = 5/2

y = -1/2

Step-by-step explanation:

if both equations start with 'y=' then set the expressions equal to each other

3/5x - 1 = x - 3

add 1 to each side to get:

3/5x = x - 1

subtract 5/5x from each side:

3/5x - 5/5x = -1

-2/5x = -1

multiply each side by -5/2:

x = 5/2

y = 2 1/2 - 3

y = -1/2

Answer:

$17

Step-by-step explanation:

We are assuming that snow shovels for 10 families means 10 shovel in total. If the manager is offering $2 discount per shovel, and there are ten shovels, then that is a 20 dollar discount. 85, the cost after discount, plus 20 is 105. 105/10=10.5. Your family is offering two pay for two shovels, so the total for you would come to $21, but there is the $2 discount, so subtract 4 dollars, and you have $17.

Step-by-step explanation:

1+5_1+2+3=10

Answer:

A

Step-by-step explanation:

Answer:

The 98% confidence interval for the true population proportion of all New York students who favor year round school is (0.3083, 0.4383).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

A survey of 300 students from a New York State School District reveals that 112 favor year round school with two week vacations every ten weeks.

This means that [tex]n = 300, \pi = \frac{112}{300} = 0.3733[/tex]

98% confidence level

So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.327[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3733 - 2.327\sqrt{\frac{0.3733*0.6267}{300}} = 0.3083[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3733 + 2.327\sqrt{\frac{0.3733*0.6267}{300}} = 0.4383[/tex]

The 98% confidence interval for the true population proportion of all New York students who favor year round school is (0.3083, 0.4383).

Answer:

5.59

Step-by-step explanation:

2πR(C/360)

2π8(40/360)

5.58505

The median of cumulative frequency is 67.86 and the interquartile range is 32.86.

The mean is "the middle number is sorter, ascending or descending, list of numbers and can be more descriptive of that data set than the average".

The interquartile range is "measure of where the 'middle fifty' is in data set".

According to the question,

Score               Mid value    Frequency       Cumulative frequency

10 ≤ x < 20            15                       1                                 1

20≤x < 30             25                      3                                 4

30≤x < 40             35                      6                                 10

40≤x < 50            45                       15                               25

50≤x < 60            55                       14                               39

60≤x < 70            65                        28                             67

70≤x < 80            75                         18                              85

80≤x < 90            85                         11                               96

90≤x < 100           95                         4                               100

Uniform interval is 10.

a) The median of examination mark

Frequency = 1+3+6+15+14+28+18+11+4 = 100

Median = [tex]l+\frac{(\frac{N}{2} - m )}{f}[/tex] × c       where l = lower limit of the median class, N = total frequency, m = cumulative frequency of the pre median class,

f = frequency of the median class, c = uniform class interval.  

            = 50 + [tex]\frac{\frac{100}{2} - 25 }{14}[/tex]  × 10

            = 50 + [tex]\frac{50 - 25}{14}[/tex]  × 10

            = 50 +[tex]\frac{25}{14}[/tex] × 10

           = 50 + 1.786 × 10

           = 50 + 17.86  

           = 67.86.

Thus, the median of examination mark is 67.86.

b) The number of students score less than 65 marks.

In order to find the number of students score less than 65 marks sum of all frequency below 65.

= 1 + 3 + 6 + 15 + 14

= 39

Thus, the number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks

In order to find the number of students scored between 50 and 80 marks only if add frequency between 50 and 80 marks.

= 14 + 28 + 18 + 11

= 71

Thus, the number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50.

In order to find the number of students failed, given that the pass mark is 50 only if add frequency below 50.

= 1 + 3 + 6 + 15

= 25.

Thus,  the number of students failed, given that the pass mark is 50 is 25.

f) The interquartile range

Interquartile range =  Q₃ - Q₁    [In words, difference between upper quartile range and lower quartile range]

Q₁ =  l₁ + [tex]\frac{\frac{N}{4} - m }{f}[/tex] × c  where l₁ is the lower limit of the Q₁ class, m₁ is the cumulative frequency of the pre median class, f₁ is the Frequency of the Q₁ class, c is the class interval, N  is the total frequency.

[tex]\frac{N}{4}[/tex] = [tex]\frac{100}{4} = 25[/tex]; [tex]\frac{3N}{4}[/tex] = 75

     = 40 + [tex]\frac{25 - 25}{6}[/tex] * 10 = 40

Q₁ = 40

Q₃ = l₃ + [tex]\frac{3\frac{N}{4} - m3 }{f3}[/tex]  × c

   = 60 + [tex]\frac{75 - 39}{28}[/tex] × 10

   = 60 + [tex]\frac{36}{28}[/tex] × 10

   = 60 + 1.2857 × 10

   =   60 + 12.857

   = 72.857

Interquartile range = upper quartile range - lower quartile range

                                 = 72.857 - 40

                                 = 32.8571  ≈ 32.86.

Thus, interquartile range is 32.86.

Hence, a) The median of examination mark is 67.86.

b) The number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50 below 50 is 25.

f)  The interquartile range is 32.86.

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It would be about 13 minutes.

Answer:

Step-by-step explanation:

g

okay i dont know lololololokjdgshbnjhcdgsjfre

Answer: 13P3= 1716

Step-by-step explanation:

Answer:

Linear

Step-by-step explanation:

Answer:

if you just wanted the equations fixed: y= -3x + 8 & y= 1/3x - 11/3

but if you wanted x then x = 7/2

Step-by-step explanation:

3x + y = 8 *subtract 3x from both sides*

y = -3x + 8

x - 3y = 11 *add 3y to both sides*

x = 3y + 11 subtract 11 from both sides*

x - 11 = 3y * divide both sides by 3*

1/3x - 11/3 = y --> y = 1/3x - 11/3

and to solve for x i just used ma thway but if you did want to solve it you'd need to put the equations equal to each other --> -3x + 8 = 1/3x - 11/3

Answer: 45 minutes

Step-by-step explanation:

Answer:

[tex]4\pi[/tex]

Step-by-step explanation:

Answer:

It’s C

Step-by-step explanation:

When the outlier is on the right of the rest then it’s going to be positively skewed

Answer:

Acute

Step-by-step explanation:

All triangles have to have a acute or it would be to big

Answer:

yes it is because its a triangle and its acute

Answer:

Answer0.41

Step-by-step explanation:

The following euler statement is False

For any real value θ, we have euler formula:

[tex]e^{i\theta} = \cos(\theta) + i\sin(\theta)[/tex]

where 'e' is the base of the natural logarithm, and 'i' is iota, the imaginary unit.

We are given that;

The figure

Now,

The Euler path is A-B-C-D-E-A-C-E-D.

However, the graph below does not have an Euler path because it is not connected:

There is no way to reach vertex F from the rest of the graph.

Therefore, by euler path the answer will be false.

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Answer:

D

Step-by-step explanation:

Answer:

Step-by-step explanation:

cos(30) = Adj/hyp

cos(30)  = 6 /x

x = 6 / cos(30)

x = 6 / ( [tex]\sqrt{3}[/tex]/ 2)

x = 12 / [tex]\sqrt{3}[/tex]

(  12 / [tex]\sqrt{3}[/tex] )^2  = 6^2 + y^2

(  12 / [tex]\sqrt{3}[/tex] )^2 - 36 = y^2

144/3 -36 = y^2

48-36=y^2

12 = y^2

[tex]\sqrt{12}[/tex] = y

Answer:

Any questions for us

....

Answer:

k=4

Explanation:f(x)=x3+4x2−kx+1By the remainder theorem, the remainder when dividing a polynomial f(x)by (x−a)

is f(a)In our case, we have a=−1 and we need:0=f(−1)=(−1)3+4(−1)2−k(−1)+10=f(−1)=−1+4+k+10=f(−1)=k+4

Hence k=−4

might have gotten it wrong sorry if so.

Answer:

A cubic function

Step-by-step explanation:

I graphed it and connected the lines on desmos then compared to the types of calculus graphs on the search engine.

Answer:

d. x²+2

Step-by-step explanation:

x²+2x+1-2x-2+3 = x²+2

9514 1404 393

Answer:

  x = 3/2 or 2

Step-by-step explanation:

Essentially, what you're looking for is a pair of factors of (-2)(-6) = 12 that have a sum of 7. The factors 3 and 4 have that sum, so we can write ...

  -2x² +3x +4x -6 = 0

  x(-2x+3) -2(-2x+3) = 0

  (x -2)(-2x +3) = 0

The roots are the values of x that make these factors zero.

  x -2 = 0   ⇒   x = 2

  -2x +3 = 0   ⇒   x = 3/2

These are consistent with Vieta's theorem, which tells you the sum of roots is -b/a = -7/-2 = 7/2. The sum of the two roots we found is 4/2 +3/2 = 7/2.

The product of roots is c/a = -6/-2 = 3. The product of the two roots we found is 2(3/2) = 3.

_____

Additional comment

I find it easier to find integer factors of integers than to find fractional factors of an integer. The direct use of Vieta's theorem would have you looking for factors of 3 that have a sum of 7/2. It seems easier to me to look for integer factors of 12 that have a sum of 7.

Answer:

Solution given:

-2x²+7x-6=0

2x²-7x+6=0

Comparing above equation with ax²+bx+c

we get

a=2

b=-7

c=6

By using Vieta's theorem

X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{7}{2} [/tex]

again

X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{6}{2} [/tex]=3