Answer:
x=19/6, x=-9/13, x=33/4
Step-by-step explanation:
1) 2^(6x+10)=2^(12x-9), 6x+10=12x-9, x=19/6
2) 3^(4x+6)=3^(-9x-3), 4x+6=-9x-3, x=-9/13
3) 2^(x+6)*2^(3x-27)=2^(6), 4x-27=6, x=33/4
The lengths of the triangle's sides are 5, 12 , 13. What is the measure of the angle opposite to side 13?
Answer:
90°
Step-by-step explanation:
i can help you in any time
A and B are squares. The length of one side of square A is 4. The length of one side of square B is twice the length of a side of square A. What is the average (mean) area of the 2 squares?
Answer:
40
Step-by-step explanation:
So square A has a side of 4, therefore its area is 16 because you square the side length.
Square B has a side of 2 times Square A's side. So Square B has sidelength 8 as 4*2 = 8.
If Square B has side length 8, it has an area of 64.
The average is found by adding the two area and then dividing by 2. So,
64 + 16 = 80
80/2 = 40
Round 2.12747677748 to the nearest ten-thousandth.
Answer:
2.1275 is 2.12747677748 rounded to the nearest ten-thousandth.
Step-by-step explanation:
Since the hundred-thousandth place is 5 or above, we would round the ten-thousandths place up. THis makes the number 2.1275.
Multiply. Write your answer in scientific notation
Answer:
3×3×10^5×10^2
9×10^5-2
9×10³
a rectangular garden is 52m long and 34m broad a path 2m wide is running inside the garden calculate the cost of travelling the path at rs 40 per sq metre snd calculate the cost of covering the empty space with tires at rs 20 per sq metre
Answer:
Answer From Gauth Math
Step-by-step explanation:
How do we derive the sum rule in differentiation? (ie. (u+v)' = u' + v')
It follows from the definition of the derivative and basic properties of arithmetic. Let f(x) and g(x) be functions. Their derivatives, if the following limits exist, are
[tex]\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h\text{ and }g'(x)\lim_{h\to0}\frac{g(x+h)-g(x)}h[/tex]
The derivative of f(x) + g(x) is then
[tex]\displaystyle \big(f(x)+g(x)\big)' = \lim_{h\to0}\big(f(x)+g(x)\big) \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)+g(x+h)\big)-\big(f(x)+g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)-f(x)\big)+\big(g(x+h)-g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{f(x+h)-f(x)}h+\lim_{h\to0}\frac{g(x+h)-g(x)}h \\\\ \big(f(x)+g(x)\big)' = f'(x) + g'(x)[/tex]
A) Write a number to represent 57 feet below sea
level.
Answer:
-57
Step-by-step explanation:
the answer is -57 because if it is below sea level it is a negative but if it is above sea level it will be a positive
Can how to solve this area of Trapezium ?
And working out
Answer:
26 cm
Step-by-step explanation:
The area of a trapezium is
A = 1/2 (b1+b2)*h where b1 and b2 are the lengths of the bases
910 = 1/2 ( 21+49) h
910 = 1/2 (70)h
910 = 35h
Divide by 35
910/35 = 35h/35
26 = h
Factor the expression completely.
-20% -40
A. -20(x-2)
B. -10(2x - 10)
C.-20(x + 2)
D. -10(2x + 10)
Answer:
C.-20(X+2)
Step-by-step explanation:
I think you wrote -20% by mistake instead of -20x
in a 41-49 right triangle, the hypotenuse is 28.83 centimeters. if cos 41= 0.7547, find the length of the side opposite the 49 angle. Estimate your answer to three decimal places
Answer:
21.758
Step-by-step explanation:
If you draw the triangle out, you find that cos 41 = x/28.83, when x is equal to the side opposite the 49 angle
Simplify this into 28.83 cos 41, and plug it into the calculator and you get
21.75827.
Heyyy could someone please help me out?? Would appreciate it. Thanks in advance!!^^
Answer:
Below,...
Step-by-step explanation:
They are saying that if you add a odd number + a odd number than you'd get a even number,... odd + even = odd,... odd x even = even,... and so on,...
Hope it helps,... Chow!
Which expression is equal to "13 more than the quotient of n and 8"? *
A) 13n + 8
B) n - 8 + 13
C) n * 8 + 13
D) (n / 8) + 13
Answer:
D
Step-by-step explanation:
The quotient of n and 8 is [tex]\frac{n}{8}[/tex] and 13 more than this is
[tex]\frac{n}{8}[/tex] + 13 → D
can some one help me on this one its confusing ill give brainly when right!!!
Geometry, please answer question ASAP
5. If A, B and C are any three points on a line and B lies between A and C, then prove that AB + BC = AC.
Answer:
B IS THE MID POINT
Step-by-step explanation:
If b lies between AC iy means b is de half
therefore a+b+c=ABC which is the straight line
Arrange in descending order 14/13,25/26,8/3
any 5
algebraic formulas
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)
Solve the equation for all values of x.
- 2x(x − 8)(10x + 1) = 0
From deltamath.com
Answer:
x=0 x=8 x = -1/10
Step-by-step explanation:
- 2x(x − 8)(10x + 1) = 0
Using the zero product property
-2x =0 x-8 = 0 10x+1= 0
x= 0 x= 8 10x = -1
x=0 x=8 x = -1/10
Find the value of this expression if x = 9.
x2 + 9
x+1
Enter the correct answer.
Step-by-step explanation:
x= 9
[tex] {x}^{2} + 9 \div x + 1[/tex]
[tex] {9 }^{2} + 9 \div 9 + 1[/tex]
[tex]81 + 9 \div 10[/tex]
[tex]90 \div 10[/tex]
[tex]9[/tex]
“The probability that you are given a car for your birthday.”
is that a conditional probability?
Answer:
No
Step-by-step explanation:
Conditional probability is an event repeating itself.
ex.) you have 3 red marbles and 4 blue ones in a hat, since you already drew a red one, there is conditional probability you will draw red again. So unless you have already gotten a car for your birthday previously, you cannot classify your question as conditional probability.
ESSENTIAL QUESTION How do graphs
and equations reveal information about a
relationship between two quantities?
Answer:
When you plot the graph, you may see a line or a curve. This presents the trend of the relationship of the two quantities when the independent variable changes.
Graphs visually depict patterns and trends, while equations provide precise mathematical descriptions, both revealing valuable information about the relationship between two quantities.
Graphs visually represent data and patterns, allowing us to identify the nature of the relationship between two quantities. The slope and intercepts of a graph provide information about the rate of change and the values when one quantity is zero.
Equations, on the other hand, offer precise mathematical descriptions of the relationship. The form of the equation reveals the nature of the relationship, while coefficients and constants provide specific information. Solving equations yields solutions that satisfy the relationship.
Both graphs and equations work together to provide a comprehensive understanding of the relationship between two quantities, with graphs offering visual insights and equations providing precise mathematical information.
Learn more about equations here;
https://brainly.com/question/4803354
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oints out of
.00
Flag
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables. Leave
your answers as radicals in simplest form.
question
60°
х
y
93
BULLY
Answer:
x = 18
y = 9
y = 9√3/√3 = 9
x = 9×2 = 18
Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.
Answer:
y = -2x + 5
[tex]\frac{risex}{run} = slope =[/tex]Δy/Δx = -8/4 = -2
Step-by-step explanation:
Anyone here who can help me with this?
Answer:
D. 16 years old
Step-by-step explanation:
Step 1: Let T be Tien's age and J as Jordan's age (today),
[tex]T=\frac{1}{4}J[/tex]
Step 2: Let T be Tien's age and J as Jordan's age (in 2 years),
[tex]T+2=\frac{1}{3} (J+2)[/tex]
[tex]T=\frac{1}{3}(J+2)-2[/tex]
Step 3: As their age differences will always be similar we can have the two equations above equal to find Jordan's age,
[tex]\frac{1}{4} J=\frac{1}{3}(J+2)-2\\\frac{1}{4}J-\frac{1}{3}J=\frac{2}{3} -2 \\-\frac{1}{12}J= -\frac{4}{3} \\\\J=16[/tex]
please please help! I'm just bad at trig..
don't bother to scam, because you won't earn points anyway. You'll be rewarded if you help!
Answer:
P=61°
Step-by-step explanation:
P²=C²+ U²–2 C U cos P
189²= 215²+123²– 2×215×123×cos p
P= 61°
I hope I helped you^_^
Arrange in ascending order: 12.4654, 784.7068, 295.6097, 267.0918, 156.6100
Step-by-step explanation:
arranging in ascending order is simply arranging from the smallest to the largest.
12.4654,156.6100,267.0918,295.6097,784.7068
I hope this helps
Which graph has a correlation coefficient, r, closest to 0.95
Answer:
A correlation coeff close to +1 would have a positive slope, and all dots representing the data set would be quite close to the regression line.
Correlation is a measure of association between two variables. IF there is a perfect linear association then correlation would be nearer to 1.
Correlation always lies between -1 and +1.
If between-1 and 0 we say there is a negative correlation.
If nearer to 1 than to 0 then we say strong correlation
Here given correlation is 0.95 i.e. positive and have almost perfect linear relation.
Hence we see that Graph C shows almost linear relationship with slope positive
So option C is answer
The measures of two sides of a triangle are 11 and 20. Between what two numbers must be the third side fall?
Answer:
Step-by-step explanation:
The largest number must be less than 31.
The smallest number must be greater than 9.
Show that:
a) The 2nd differences in the following row are constant and calculate:
b)Tn
4; 7; 12; 19;....
-1; 2; 7; 14;....
-2;-8; -18; -32; ...
• {4, 7, 12, 19, … }
has 1st differences
7 - 4 = 3
12 - 7 = 5
19 - 12 = 7
and 2nd differences
5 - 3 = 2
7 - 5 = 2
• {-1, 2, 7, 14, …}
1st differences:
2 - (-1) = 3
7 - 2 = 5
14 - 7 = 7
2nd differences:
5 - 3 = 2
7 - 5 = 2
• {-2, -8, -18, -32, …}
1st differences:
-8 - (-2) = -6
-18 - (-8) = -10
-32 - (-18) = -14
2nd differences:
-10 - (-6) = -4
-14 - (-10) = -4
Answer:
Hello,
Step-by-step explanation:
I am going to explain the method with the 1th:
[tex]\begin{array}{ccccc}n & u_n&u_{n+1}-u_{n}&u_{n+2}-2u_{n+1}+u_{n}&v_{n}\\1&4&&6\\2&7&3&9\\3&12&5&2&14\\4&19&7&2&21\\...&&&\\\end{array}\\\boxed{u_{n+2}=2u_{n+1}-u_{n}+2}\\[/tex]
[tex]Let\ say\\v_{n}=u_{n}+2\\v_{n+2}=u_{n+2}+2=(2u_{n+1}-u_{n}+2)+2=2(v_{n+1}-2)-(v{n}-2)+4\\v_{n+2}=2v_{n+1}-v{n}+2\ (1)\\v_{n+3}=2v_{n+2}-v{n+1}+2\ (2)\\(2)-(1)==> \boxed{v_{n+3}=3v_{n+2}-3v_{n+1}+v_n}\\[/tex]
[tex]Caracteristic\ equation:\\P(r)=r^3-3r^2+3r-1=0\\P(r)=(r-1)^3\\v_n=\alpha+\beta*n+\gamma*n^2\\v_1=6 ==> \alpha+\beta*1+\gamma*1=6\\u_2=9 ==> \alpha+\beta*2+\gamma*4=9\\u_3=14 ==> \alpha+\beta*3+\gamma*9=14\\[/tex]
[tex]\begin{bmatrix}1&1&1\\1&2&4\\1&3&9\end{bmatrix}*\begin{bmatrix}\alpha\\\beta\\\gamma\end{bmatrix}=\begin{bmatrix}6\\9\\14 \end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\1&2&4&9\\1&3&9&14\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&2&3&3\\0&2&8&8\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&1&4&4\end{bmatrix}\\\\[/tex]
[tex]\begin{bmatrix}1&1&1&6\\0&1&3&3\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&1&1&6\\0&1&0&0\\0&0&1&1\end{bmatrix}\\\\\\\begin{bmatrix}1&0&0&5\\0&1&0&0\\0&0&1&1\end{bmatrix}\\[/tex]
[tex]\alpha=5\\\beta=0\\\gamma=1\\\boxed{v_n=5+0*n+1*n^2}\\\boxed{u_n=5+0*n+1*n^2-2}\\\begin{array}{ccccc}n & u_n\\1&5+1-2=4\\2&5+4-2=7\\3&5+9-2=12\\4&5+16-2=19\\...&...\\\end{array}\\[/tex]
if A=(p,q,r) write all possiblesubsets of A
Answer:
Given, A={p,q,r}.
Now, possible subsets of A are ,{p},{q},(r) {p,q}.
(q,r) (p,r) (p,q,r)