sine, cosine, and tangent to calculate the height of the buildings in the diagram below.
Answers
Answer: Around 68.0858 m
Step-by-step explanation:
Set the height of 37°-53°-90° triangle as xSet the height of 50°-40°-90° triangle as yThe horizontal side both triangles share = 35To find x To find y
[tex]tan(37)=\frac{x}{35} \\\\35tan(37)=x\\\\x=26.37439...[/tex] [tex]tan(50)=\frac{y}{35} \\\\35tan(50)=y\\\\y=41.7113757...[/tex]
To find the height of the building, add the x-value and y-value:
[tex]x+y=26.3744+41.7114=68.0858[/tex]
I hope this is correct o_o
Related Questions
ASAP!! can i get some help on this question, and a step by step explanation please, it would help
a lot thanks.
Answers
Answer:
[tex]{ \tt{ {3x}^{2}(5 {x}^{3} ) = 15 {x}^{5} }}[/tex]
Step-by-step explanation:
[tex]{ \sf{3 {x}^{2}(5 {x}^{3} )}} \\ = { \sf{ {x}^{5} (3 \times 5)}} \\ = { \sf{15 {x}^{5} }}[/tex]
cho tam giác ABC vuông tại A, đường cao AH, cho biết AH= 2cm, BC= 5cm. Tính các cạnh AB, AC, CH, BH và tính diện tích tam giác ABC
Answers
Answer:
Step-by-step explanation:
SABC= 1/2 AH.BC = 1/2 .2.5 = 5
Ta co: HC = 5 – BH
Mat khac: AH2 = HB.HC 22 = HB(5-HB) HB = 4 hoac HB = 1
Ta co cong thuc: AB2 = HB.BC
AC2 = HC.BC
Voi HB = 4 => HC = 1. Vay ta co: AB = 2√5 va AC = √5
Voi HB = 1 => HC = 4. Vay ta co: AB = √5 va AC = 2√5
On a map, two mountains are 5 7/8 inches apart. If 1/2 of an inch on the map represents 80 miles, then how many miles apart
Answers
Answer:
235 miles
Step-by-step explanation:
80(5 7/8÷ 2)
Using the equation y = 30x + 45, if you have a budget of 300 dollars for this job, what are the most full hours the electrician can work? Note: You want the largest number of hours without going over your budget.
Answers
Answer:
8 hours
Step-by-step explanation:
y = 30x + 45
Assuming x is the hours and y is the cost
300 = 30x +45
Subtract 45 from each side
300-45 = 30x+45-45
225 = 30x
Divide by 30
225/30 = 30x/30
17/2 = x
8.5 =x
The largest number of hours without going over means round down
8 hours
Find the value of x. Round
the nearest tenth.
Answers
Answer:
x = 13.5
Step-by-step explanation:
We need to use the law of sines
sin 27 sin 34
------- = --------
11 x
Using cross products
x sin 27 = 11 sin 34
x = 11 sin 34/ sin 27
x=13.54901
To the nearest tenth
x = 13.5
Find the measure of one interior angle for the following polygon
Answers
Answer:
i had the same question myself
Step-by-step explanation:
I need help also
PLZZZ HELPPP, IF NOT 100% SURE PLZ DONT ANSWER…BRAINLIEST TO FIRST AND CORRECT ANSWER, THX TO SECOND AND CORRECT ANSWER
Answers
Answer:
2
Step-by-step explanation:
(1 + 1/2) ÷ (3/4)
= 3/2 ÷ 3/4
= 3/2 × 4/3
= 12/6
= 2
(0.75 × 2 = 1.5)
Answer:
2
Step-by-step explanation:
A taxi ride cost $2 for the first 1/5 of a km and 40 cents for each additional fifth of a km. Dan has $9.60. What is the longest taxi ride he can afford, in kilometres?
Answers
Answer:
4 kilometers
Step-by-step explanation:
First! Let's create an equation, with our variable (x) representing the number of additional fifth kilometers Dan can afford.
2 + 0.40x = 9.60
Now, we have to solve for our x value by subtracting 2 from both sides.
0.40x = 7.60
Next, we can divide both sides by 0.40 to find out what our x value is equal too.
x = 19
Don't forget this x value is just for the number of additional fifth kilometers Dan can afford on top of his first fifth mile.
So! Dan can afford 20 fifth kilometers, which in turn in is 4 kilometers in total.
Hope this Helps! :)
Have any questions? Ask below in the comments and I will try my best to answer.
-SGO
A company prices its tornado insurance using the following assumptions:
• In any calendar year, there can be at most one tornado.
• In any calendar year, the
probability of a tornado is 0.15.
. The number of tornadoes in any calendar year is independent of the number of tornados in any other
calendar year.
Using the company's assumptions, calculate the probability that there are fewer than 3 tornadoes in a 19 year period.
Answers
Answer:
.441320612
or
44.132%
Step-by-step explanation:
This is binomial
fewer than 3 is equal to p(0)+p(1)+p(2)
[tex]p(0)={19\choose0}*.15^0*(1-.15)^{19}=.045599448\\p(1)={19\choose1}*.15^1*(1-.15)^{18}=.152892268\\p(2)={19\choose2}*.15^2*(1-.15)^{17}=.242828896\\p(0)+p(1)+p(2)=.441320612[/tex]
