Answer:
B. The principal quantum number (n) is 6, the angular momentum quantum number (ell) is 2, and there are 5 electrons in the subshell.
Explanation:
Given;
electronic configuration of 6d⁵
where;
6 in the configuration shows that, the principal quantum number (n) is 6
d is the subshell
d orbital has angular momentum quantum number (l) of 2
s orbital, l = 0
p orbital, l = 1
d orbital, l = 2
f orbital, l = 3
5 in the configuration means that there are 5 electrons in the subshell
Therefore, 6d⁵ symbol means that "The principal quantum number (n) is 6, the angular momentum quantum number (ell) is 2, and there are 5 electrons in the subshell".
A light wave has frequency of 4.5 * 10^19 Hz. How would this number appear on a scientific calculator? a. 4.E195 b. 19E4.5 c. 4.519E d. 4.5E19
Answer:
B
Explanation:
How many grams of o2 gas are contained in 890.0 ml at 21.0 degrees Celsius and 750.0 psi
Answer:
60.288 grams of O₂ gas are contained in 890.0 mL at 21.0 degrees Celsius and 750.0 psi.
Explanation:
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P*V = n*R*T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.
In this case:
P= 750 psi= 51.0345 atm (being 1 psi = 0.068046 atm)V= 890 mL= 0.890 L (being 1 L= 1,000 mL)n= ?R= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]T= 21 °C= 294 °KReplacing:
51.0345 atm*0.890 L= n*0.082 [tex]\frac{atm*L}{mol*K}[/tex] *294 °K
Solving:
[tex]n=\frac{51.0345 atm*0.890 L}{0.082\frac{atm*L}{mol*K} *294 K}[/tex]
n=1.884 moles
Being 32 g / mole the molar mass of oxygen O₂, the following rule of three applies: if 1 mole contains 32 grams, 1,884 moles, how much mass does it have?
[tex]mass=\frac{1.884 moles*32 grams}{1mole}[/tex]
mass= 60.288 grams
60.288 grams of O₂ gas are contained in 890.0 mL at 21.0 degrees Celsius and 750.0 psi.
Answer:
The mass of the O2 gas is 60.16 grams
Explanation:
Step 1: Data given
Volume of O2 gas = 890.0 mL = 0.890 L
Temperature of the O2 gas = 21.0 °C = 294 K
Pressure = 750.0 psi = 51.03 atm
Step 2: Calculate moles of O2 gas
p*V = n*R*T
⇒with p = the pressure of the O2 gas = 51.03 atm
⇒with V = the volume = 0.890 L
⇒with R = the gas constant == 0.08206 L*atm/mol*K
⇒with T = the temperature = 294 K
⇒with n = the number of moles of O2 gas
n = (p*V) / (R*T)
n = (51.03 atm * 0.890 L) / (0.08206L*atm/mol*K * 294K)
n = 1.88 moles of O2
Step 3: Calculate the mass of O2 gas
Mass = moles * molar mass O2
Mass O2 gas = 1.88 moles * 32.0 g/mol
Mass O2 gas = 60.16 grams
The mass of the O2 gas is 60.16 grams
Classify each amino acid according to whether its side chain is predominantly protonated or deprotonated at a pHpH of 7.40.7.40. The pKapKa values of the Asp, His, and Lys side chains are 3.65, 6.00, and 10.53,3.65, 6.00, and 10.53, respectively.
Answer: His and Lys are deprotonated but Asp will be protonated.
Explanation:
As the pH is given as 7.4 and pK of His is given as 6.00. There will occur a positive charge on His when it's pH < pK therefore, it is neutral at the given pH.
As the pK value of Lys is 10.53 that is greater than the pH of 7.40. Therefore, charge on Lys is positive.
As the pK value of Asp is 3.65 which is less than the pH value of 7.40. Hence, Asp has a negative charge.
Therefore, we can conclude that His and Lys are deprotonated but Asp will be protonated.
OH- (aq) + HCO3- (aq) --- H2O (l) + CO32-(aq)
If OH is considered base 1, the right conjugates are..
Answer: The right conjugate of [tex]OH^-[/tex] is [tex]H_2O[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
[tex]OH^-(aq)+HCO_3^-(aq)\rightleftharpoons H_2O(l)+CO_3^{2-}(aq)[/tex]
Here, [tex]OH^-[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]H_2O[/tex] which is a conjugate acid.
Thus the right conjugate of [tex]OH^-[/tex] is [tex]H_2O[/tex]
How many moles of iron(lll) sulfide, Fe2S3, would be produced from the complete reaction of 449 g iron(lll) bromide, FeBr3?
Answer:
.76
Explanation:
The standard heat of combustion of ethanol, C2H5OH, is 1372 kJ/mol ethanol. How much heat (in kJ) would be liberated by completely burning a 20.0 g sample
Answer:
The correct answer is 596.5 kJ.
Explanation:
The mass of ethanol or C2H5OH mentioned in the question is 20 gm.
The molar mass of ethanol is 46 g/mol.
The moles of the compound can be determined by using the formula,
n = weight of the compound/molar mass
= 20/46 = 0.435 moles
It is mentioned in the question that standard heat of combustion of ethanol is 1372 kJ/mole, that is, one mole of ethanol is producing 1372 kilojoules of energy at the time of combustion.
Therefore, the energy liberated by completely burning the 20 grams of ethanol is 0.435*1372 = 596.5 kJ.
Since the standard heat of combustion of ethanol is -1372 kJ/mol, the heat released by the combustion of a 20.0 g sample is -593 kJ.
Let's consider the thermochemical equation for the combustion of ethanol.
C₂H₅OH(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(l) ΔH°c = -1372 kJ/mol
We can calculate the heat released by burning 20.0 g of ethanol considering the following relationships.
The molar mass of C₂H₅OH is 46.07 g/mol.1372 kJ of heat is released by the combustion of 1 mole of C₂H₅OH.[tex]20.0 g EtOH \times \frac{1molEtOH}{46.07gEtOH} \times \frac{(-1367kJ)}{1molEtOH} = -593 kJ[/tex]
Since the standard heat of combustion of ethanol is -1372 kJ/mol, the heat released by the combustion of a 20.0 g sample is -593 kJ.
Learn more: https://brainly.com/question/2874342
The standard heat of combustion of ethanol, C₂H₅OH, is -1372 kJ/mol ethanol. How much heat (in kJ) would be liberated by completely burning a 20.0 g sample.
what did thomson’s model of the atom called
Answer:
Plum pudding model
Explanation:
Thomson’s model of the atom called: PLUM PUDDING MODEL
According to collision theory, what three factors govern the effect of temperature on the rate of a chemical reaction?
Answer:
Collision theory states that the rate constant for a chemical reaction is composed
of three factors, (1) the absolute number of collisions, Z, between molecules; (2) The
fraction of collisions, f, with an energy greater than the activation energy; and (3) the
fraction of molecules, p, in which the molecules are in the correct orientation to react.
k = Zfp Equation 1
The absolute number of collisions, Z, increases with temperature. However, it has
been shown that at 25o
C, the increase in the number of collisions accompanying a 10o
C
increase in temperature accounts for only about 2% of the increase in the reaction rate.
Similarly, while it is important that molecules be in the proper orientation to react when
they collide, molecular orientation is independent of temperature. Thus it follows that the
major factor controlling reaction rates is the fraction, f, of molecules in the reaction
mixture with an energy greater than the activation energy. This factor, f, depends on the
absolute temperature. It has been shown that f is related to Ea by the following equation
Explanation:
how genetic conditions are transmitted from one person to another
Answer:
there are 5 ways this could happen
Autosomal dominant inheritance: a child recieves a normal gene from one parent and a defective gene from the other parent.
can occur on any of the 22 non-sex chromosomes and have a 50% inheritence rate, gender is not a factor, and disorder differs with inheritance.
examples: Huntington's disease, neurofibromatosis, achondroplasia, familial hypercholesterolemia
Autosomal recessive inheritance: both parents carry the defective gene but they are not affected by the disorder.
there is a 25% chance of defective gene from both parents, a 50% chance of inheriting one gene to become a carrier, gender is not a factor in the pattern of the defective gene.
examples: Tay-Sachs disease, sickle cell anemia, cystic fibrosis, phenylketonuria (PKU)
X-linked (sex-linked) recessive inheritance: mother carries the affective gene on one of the two X chromosomes.
males inherite X chromosomes from their mothers and Y from their father; which gives the son a 50% chance of inheriting the disorder.
daughters have a 50% chance, but they are not affected by the disorder.
examples: Hemophilia A, Duchenne muscular dystrophy
X-linked Dominant: females are affected more so than males; more common for males if they are in the same generation if the mom is affected (because females have two X-chromosomes)
example: Hypophatemic rickets (Vitiamin Dresistant rickets, ornithine transcarbamylase deficiency.
Mitochondrial: can affect both males and femlaes, can only be passed by females due to all mitochondria of all children is from the mother, and can appear in every generation.
examples: Lebrer's hereditary optic neuropathy and Kearns-Sayre syndrome
Explanation:
Which part of a hypothesis should the student add to this that
could also be tested in other experiments?
an explanation based on prior scientific knowledge or
observations
an explanation of how the hypothesis will inspire new
questions
O an independent variable that the student controls during
the experiment
O an independent variable that is affected by the other
experimental variable
Answer:
I believe the answer would be: D
an independent variable that is affected by the other
experimental variable
Correct me if im wrong
Explanation:
Scientific notation is
Answer:
Scientific notation is a system in which quantities are too big or too tiny to compose in decimal form.
Key words:
1: Scientific
2: Quantities
3: Decimal
Please mark brainliest
Hope this helps.
Which element is undergoing oxidation?
1) Ag
2) Ag+
3) Pb
4)Pb+2
Answer:
Explanation:
Oxidation In chemistry is the gain in oxygen, loss of hydrogen and loss of electrons. Oxidation occur when an element with gain oxygen, loss hydrogen or loss electrons, which means the element is oxidized. Compared to reduction which is loss ofoxygen, gain of hydrogen and gain of electrons.
From the the question , Ag( silver) is undergoing oxidation.
What is the chemical equation for why the Statue of Liberty turned green
Answer:
The formula is as follows
2Cu + O2 ---> 2CuO
When two copper atoms react with a diatonic oxygen, they form copper oxide (rust)
Calculate the mean free path of electrons in a metal, such as silver, at room temperature form heat capacity and heat conduction measurements. Take EF ¼ 5 eV, K ¼ 4:29 102 J/s m K, and Cel v ¼ 1% of the lattice heat capacity. (Hint: Remember that the heat capacity in (21.8) is given per unit volume!)
Answer:
= 4 * 10-8 = 400 Angstrom
Explanation:
EF = 5 eV, K = 4.29 x 102 J/(s m K), and Cvel = 1% of the lattice heat capacity
K= 1/3 (Cv)*v*l
v is fermi velocity which is equal to [tex]v = (2E_f/m)^{0.5}[/tex]
after putting mass of electron as [tex]9.1 * 10^{-31}kg[/tex] and [tex]E_f = 5 eV[/tex] we get [tex]v= 1.33 * 10^6 m/s[/tex]
[tex]C_v[/tex] is 1% of lattice heat capacity
Heat Capacity of Aluminium is [tex]0.897 J g^{-1}K^-1[/tex]
Density = [tex]2.6989 g \ cm^{-3}[/tex]
For lattice heat capacity you need to use the heat capacity for alimunium given and then multiply with density to get per unit volume term
Heat Capacity per unit volume = [tex]0.897 J g^{-1}K^-1[/tex] * [tex]2.6989 g \ cm^{-3}[/tex]
[tex]= 2.42 J K^{-1} cm^{-3} \\\\= 2.42* 10^6 J K^{-1} m^{-3}[/tex]
Cv = 1% of heat capacity per unit volume
[tex]=0.01 * 2.42* 10^8 J K^{-1} m^{-3} \\\\= 2.42* 10^4 J K^{-1} m^{-3}[/tex]
Putting values in this equation K= 1/3 (Cv)*v*l
[tex]l = 3K/(C_v * v )\\\\ = 3 * 4.29 * 10^2 / (2.42* 10^4 * 1.33 * 10^6 )[/tex]
[tex]= 4 * 10^{-8 }[/tex]
= 400 Angstrom
What is the [H+] concentration of blood, given the ph is 2.5?
Answer:
0.00316
Explanation:
You have to use the following equation:
[tex]pH=-log[H^+][/tex]
You are given the pH and need to find the concentration of H+. Plug in the given components and solve.
[tex]2.5=-log[H^+]\\H^+ = 10^{-2.5}\\H^+=0.00316[/tex]
The concentration of H is 0.00316.
Lilly is doing a science experiment with a substance in a sealed jar. At first the substances molecules are moving around each other. What will happen to Lily substance if she transfers energy into the substance and causes a face change? after the phase change, the substance molecules will move...
Explanation:
faster and the substance will be a gas.
According to the forces of attraction and principles of phase change the substance molecules will move faster and the substance will be a gas.
What are forces of attraction?Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
Learn more about forces of attraction,here:
https://brainly.com/question/2122941
#SPJ5
which of the following statements is/are true for a 0.10 m solution of a strong acid (HA)?
The question is incomplete; the complete question is;
Which of the following statements is/are true for a 0.10 M solution of a weak acid HA?
a. [ H+] >> [ A−]
b. [ H+] = [ A−]
c. The pH is 1.00.
d. The pH is less than 1.00.
Answer:
b. [ H+] = [ A−]
Explanation:
Given the acid as HA, we know that being a weak acid, its dissociation in water can never be 100%. If it were a strong acid, then it could have undergone a 100% dissociation in solution. The conjugate base of a weak acid is a always a weak base hence A^- is expected to act as a weak base. At the same concentration, weak acids have a higher pH value than strong acids. Hence if the pH of a strong acid HA is 1, then the pH of a weak acid HA must be greater than 1.
But, we look at the equation for the dissociation of the weak acid HA
HA(aq)⇄H^-(aq) + A^-(aq). This implies that the HA dissociates in a 1:1 ratio therefore; [H+] = [ A−], hence the answer given above.
The formation of the silver(I) ammine complex ion is a reversible reaction that is allowed to reach equilibrium. For each subsequent change to the system, indicate how the concentration of each species in the chemical equation will change to reestablish equilibrium. An up arrow indicates an increase in concentration, a down arrow indicates a decrease in concentration and leaving t blank means there is no change in the concentration Ag+(aq) + 2NH3 (aq)-----------------> Ag(NH3 (aq) <----------------- increasing the concentration of Ag+ decreasing the concentration of NH increasing the concentration of Ag(NH)
Explanation:
Ag+(aq) + 2NH3 (aq) ⇄ Ag(NH3)2 (aq)
When it comes to question of this sort, the LeChatelier principle should come to mind. The LeChatelier principle states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.
increasing the concentration of Ag+
This would lead to an increase in concentration of reactants, the system would annul or oppose this change by moving towrds the right, favouring the forward reaction.
decreasing the concentration of NH3
This would lead to a decrease in concentration of reactants, the system would annul this change by moving to the left, favourin the backward reaction.
increasing the concentration of Ag(NH3)2
This would lead to an increase in concnetration of products, the system would annul or oppose this change by moving towards the left, favouring the backward reaction.
A 25.0g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is dropped into an insulated container containing 250.0g of water at 25.0°C and a constant pressure of 1atm. The initial temperature of the brass is 96.7°C. Assuming no heat is absorbed from or by the container, or the surroundings, calculate the equilibrium temperature of the water. Be sure your answer has 3 significant digits.
Answer:
The equilibrium temperature of water is 25.6 °C
Explanation:
Step 1: Data given
Mass of the sample of brass = 25.0 grams
The specific heat capacity = 0.375 J/g°C
Mass of water = 250.0 grams
Temperature of water = 25.0 °C
The initial temperature of the brass is 96.7°C
Step 2: Calculate the equilibrium temperature
Heat lost = heat gained
Q(sample) = -Q(water)
Q = m*C* ΔT
m(sample)*c(sample)*ΔT(sample) = - m(water)*c(water)*ΔT(water)
⇒m(sample) = the mass of the sample of brass = 25.0 grams
⇒with c(sample) =The specific heat capacity = 0.375 J/g°C
⇒with ΔT = the change of temperature = T2 - T1 =T2 - 96.7 °C
⇒with m(water) = the mass of the water = 250.0 grams
⇒with c(water) = the specific heat capacity = 4.184 J/g°C
⇒with ΔT(water) = the change of temperature of water = T2 - T1 = T2 - 25.0°C
25.0 * 0.375 * (T2 - 96.7) = - 250.0 * 4.184 J/g°C * (T2 - 25.0°C)
9.375T2 - 906.56 = -1046T2 + 26150
9.375T2 + 1046T2 = 26150 + 906.56
1055.375T2 = 27056.26
T2 = 25.6 °C
The equilibrium temperature of water is 25.6 °C
Decreasing order of C-C bond length is 1) ethene 2)ethyne 3) benzene 4) ethane
Answer:
4>3>1>2.
That is, the C-C bond length in ethane > benzene > ethene > ethyne.
Explanation:
The C-C bond in ethane is single, the C-C bond in ethene is double and the C-C bond in ethyne is triple. As the number of bonds between a C-C increases, the length of the bond decreases with an increase in strength. This explains why the C-C bond length in ethane > ethene > ethyne. For benzene, all the C-C bonds in the aromatic compound has been found to have an identical length of 1.40 Å, compared to ethane (1.54Å), ethene (1.34Å) and ethyne (1.20Å). Hence the trend in bond lengths: ethane > benzene > ethene > ethyne.
A solution of a compound in ethanol shows an absorbance of 0.58 at 236 nm in a cell with a 1-cm light path. Its molar absorptivity in ethanol at that wavelength is 12,600 M−1cm−1. What is the concentration of the compound? Express your answer to two significant figures and include the appropriate units.
Answer:
C = 4.60x10⁻⁵ M
Explanation:
The concentration of the compound can be calculated using Beer-Lambert Law:
[tex]A = \epsilon*C*l[/tex]
Where:
A: is the absorbance of the ethanol = 0.58
ε: is the molar absorptivity of the ethanol = 12600 M⁻¹cm⁻¹
C: is the concentration of the compound =?
l: is the optical path length = 1 cm
Hence, the concentration of the compound is:
[tex]C = \frac{A}{\epsilon*l} = \frac{0.58}{12600 M^{-1}cm^{-1}*1 cm} = 4.60 \cdot 10^{-5} M[/tex]
Therefore, the concentration of the compound is 4.60x10⁻⁵ M.
I hope it helps you!
Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 1.12 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 26.78 mL. What volume of base was required for the titration
Answer:
The volume of base required is = 25.66 mL
Explanation:
Volume of titrant required is given by:
Final titre value - Initial titre value
=26.78 - 1.12
= 25.66 mL
Note: repeat and average volumes for accuracy of result.
–
Introduction to elapsed time
Ryan started a race at 7:08 AM and finished it at 7:46 AM.
How long did it take him?
Juan works as a tutor for $7 an hour and as a waiter for $14 an hour. This month, he worked a combined total of 103 hours at his two jobs. Let be the number of hours Juan worked as a tutor this month. Write an expression for the combined total dollar amount he earned this month.
Answer:
An expression for the combined total dollar amount he earned this month is $(7x + 14y) where x + y = 103.
Explanation:
Let the no. of hours worked as tutor be x
Earning as tutor in 1 hour = $7
Earning as tutor in x hour = $7*x = $7x
Let the no. of hours worked as waiter be y
Earning as waiter in 1 hour = $14
Earning as waiter in y hour = $14*y = $14y
Given that total hours worked in the month = 103 hours
therefore, x + y = 103 ----> (1)
Total amount earned in the month = Earning as tutor in x hour + Earning as waiter in y hour = $(7x + 14y)
An expression for the combined total dollar amount he earned this month is $(7x + 14y) where x + y = 103.
Matter does NOT exist in which form?
Answer:
vacuum
Explanation:
vacuum is the form by which matter cant exist
In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction method or the oxidation number method. The half-reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(l), OH−(aq), and H+(aq) may be added to complete the mass balance. Which substances are used depends on the reaction conditions.
Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50 bar to p2 = 0.25 bar. Assume that N2(g) under such conditions can be considered an ideal gas with CV,m = 3 R.
A) What is the final temperature T2 of the gas?B) What is ∆U for the gas in the process?C) What are q and w exchanged by the system in the process?D) What is ∆H for the gas in the process?E) What is ∆S for the gas in the process?F) What is ∆Suni for the universe in the process?
Answer:
Part A is just T2 = 58.3 K
Part B ∆U = 10967.6 x C[tex]_{V}[/tex] You can work out C[tex]_{V}[/tex]
Part C
Part D
Part E
Part F
Explanation:
P = n (RT/V)
V = (nR/P) T
P1V1 = P2V2
P1/T1 = P2/T2
V1/T1 = V2/T2
P = Pressure(atm)
n = Moles
T = Temperature(K)
V = Volume(L)
R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.
bar = 0.986923 atm
N = 14g/mol
N2 Molar Mass 28g
n = 3.5 mol N2
T1 = 350K
P1 = 1.5 bar = 1.4803845 atm
P2 = 0.25 bar = 0.24673075 atm
Heat Capacity at Constant Volume
Q = nCVΔT
Polyatomic gas: CV = 3R
P = n (RT/V)
0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))
V = (nR/P) T
V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K
V = (0.28721/1.4803845) x 350
V = 0.194 x 350
V = 67.9036 L
So V1 = 67.9036 L
P1V1 = P2V2
1.4803845 atm x 67.9036 L = 0.24673075 x V2
100.52343693 = 0.24673075 x V2
V2 = P1V1/P2
V2 = 100.52343693/0.24673075
V2 = 407.4216 L
P1/T1 = P2/T2
1.4803845 atm / 350 K = 0.24673075 atm / T2
0.00422967 = 0.24673075 /T2
T2 = 0.24673075/0.00422967
T2 = 58.3 K
∆U= nC[tex]_{V}[/tex] ∆T
Polyatomic gas: C[tex]_{V}[/tex] = 3R
∆U= nC[tex]_{V}[/tex] ∆T
∆U= 28g x C[tex]_{V}[/tex] x (350K - 58.3K)
∆U = 28C[tex]_{V}[/tex] x 291.7
∆U = 10967.6 x C[tex]_{V}[/tex]
Oxygen is a non-metal true or false
Answer:
This is true because oxygen belongs to the non-metal part of the periodic table.
Answer:hello
Oxygen is a non-metal it's exactly true.
Explanation:
There's a good rule that if the number of electrons in the last layer is 1,2,3,and sometimes 4 it's a metal but if this number increase it's a non-metal like Oxygen or Nitrogen.
Good luck.
If methyl orange is added to a substance and it turns the substance red, what does this tell you about the pH of the substance? Would this substance be an acid or a base?
Explanation:
methyl orange turns pink in an acidic solution
yellow in basic and orange in neutral
Answer: The substance would be a strong acid.
Explanation:
Methyl orange turns orange when it is added to a medium acid and turns red when it is added to a strong acid. The pH of the acid would be above 4 because it is a strong acid. Methyl orange turns yellow when it is added to a medium base.
The combustion of propane is represented by the following chemical equation. C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(l) The standard enthalpies of formation ( ΔH∘f ) for C3H8(g), CO2(g), and H2O(l) are −103.8 kJ/mol, −393.5 kJ/mol, and −285.8 kJ/mol respectively. What is the enthalpy of combustion for propane at 25 °C and 1 atm?
Answer:
ΔH°c = -2219.9 kJ
Explanation:
Let's consider the combustion of propane.
C₃H₈(g) + 5 O₂(g) ⟶ 3 CO₂(g) + 4 H₂O(l)
We can find the standard enthalpy of the combustion (ΔH°c) using the following expression.
ΔH°c = [3 mol × ΔH°f(CO₂(g)) + 4 mol × ΔH°f(H₂O(l))] - [1 mol × ΔH°f(C₃H₈(g)) + 5 mol × ΔH°f(O₂(g))]
ΔH°c = [3 mol × (-393.5 kJ/mol) + 4 mol × (-285.8 kJ/mol)] - [1 mol × (-103.8 kJ/mol) + 5 mol × (0 kJ/mol)]
ΔH°c = -2219.9 kJ
