Answer:
See explanation
Step-by-step explanation:
Given
See attachment for proper presentation of question
Required
Mean and Range
To do this, we simply calculate the mean and the range of each row.
[tex]\bar x = \frac{\sum x}{n}[/tex] ---- mean
Where:
[tex]n = 4[/tex] ---- number of rows
[tex]R = Highest - Lowest[/tex] --- range
So, we have:
Sample 1
[tex]\bar x_1 = \frac{1027+ 994 +977 +994 }{4}[/tex]
[tex]\bar x_1 = 998[/tex]
[tex]R_1 = 1027- 994[/tex]
[tex]R_1 = 33[/tex]
Sample 2
[tex]\bar x_2 = \frac{975 +1013 +999 +1017}{4}[/tex]
[tex]\bar x_2 = 1001[/tex]
[tex]R_2 = 1017 - 975[/tex]
[tex]R_2 = 42[/tex]
Sample 3
[tex]\bar x_3 = \frac{988 +1016 +974 +997}{4}[/tex]
[tex]\bar x_3 = 993.75[/tex]
[tex]R_3 = 1016-974[/tex]
[tex]R_3 = 42[/tex]
Sample 4
[tex]\bar x_4 = \frac{998 +1024 +1006 +1010}{4}[/tex]
[tex]\bar x_4 = 1009.5[/tex]
[tex]R_4 = 1024 -998[/tex]
[tex]R_4 = 26[/tex]
Sample 5
[tex]\bar x_5 = \frac{990 +1012 +990 +1000}{4}[/tex]
[tex]\bar x_5 = 998[/tex]
[tex]R_5 = 1012 -990[/tex]
[tex]R_5 = 22[/tex]
Sample 6
[tex]\bar x_6= \frac{1016 + 998 +1001 +1030}{4}[/tex]
[tex]\bar x_6= 1011.25[/tex]
[tex]R_6= 1030-998[/tex]
[tex]R_6= 32[/tex]
Sample 7
[tex]\bar x_7 = \frac{1000 +983 +979 +971}{4}[/tex]
[tex]\bar x_7 = 983.25[/tex]
[tex]R_7 = 1000-971[/tex]
[tex]R_7 = 29[/tex]
Sample 8
[tex]\bar x_8 = \frac{973 +982 +975 +1030}{4}[/tex]
[tex]\bar x_8 = 990[/tex]
[tex]R_8 = 1030-973[/tex]
[tex]R_8 = 57[/tex]
Sample 9
[tex]\bar x_9 = \frac{992 +1028 +991 +998}{4}[/tex]
[tex]\bar x_9 = 1002.25[/tex]
[tex]R_9 = 1028 -991[/tex]
[tex]R_9 = 37[/tex]
Sample 10
[tex]\bar x_{10} = \frac{997 +1026 +972 +1021}{4}[/tex]
[tex]\bar x_{10} = 1004[/tex]
[tex]R_{10} = 1026 -972[/tex]
[tex]R_{10} = 54[/tex]
Sample 11
[tex]\bar x_{11} = \frac{990 +1021 +1028 +992}{4}[/tex]
[tex]\bar x_{11} = 1007.75[/tex]
[tex]R_{11} = 1028 -990[/tex]
[tex]R_{11} = 38[/tex]
Sample 12
[tex]\bar x_{12} = \frac{1021 +998 +996 +970}{4}[/tex]
[tex]\bar x_{12} = 996.25[/tex]
[tex]R_{12} = 1021 -970[/tex]
[tex]R_{12} = 51[/tex]
Sample 13
[tex]\bar x_{13} = \frac{1027 +993 +996 +996}{4}[/tex]
[tex]\bar x_{13} = 1003[/tex]
[tex]R_{13} =1027 -993[/tex]
[tex]R_{13} =34[/tex]
Sample 14
[tex]\bar x_{14} = \frac{1022 +981 +1014 +983}{4}[/tex]
[tex]\bar x_{14} = 1000[/tex]
[tex]R_{14} = 1022 -981[/tex]
[tex]R_{14} = 41[/tex]
Sample 15
[tex]\bar x_{15} = \frac{977 +993 +986 +983}{4}[/tex]
[tex]\bar x_{15} = 984.75[/tex]
[tex]R_{15} = 993-977[/tex]
[tex]R_{15} = 16[/tex]
Simplify the algebraic expression by combining like (or similar) terms.
2x−y2+3−3y2+2x+1
Answer:
-4y^2 + 4x +4
Step-by-step explanation:
add -y^2 and -3y^2 = -4y^2
add 2x + 2x = 4x
add 3+1 = 4
and then rearrange
If Logx (1 / 8) = - 3 / 2, then x is equal to what?
Answer:
Logx(1/8) = -3/2
x = 4
Answered by GAUTHMATH
please give me correct answer
Answer:
answer of question number 1 is 2400, 2880, 3600 respectively.
answer of question number 2 is 1384 and 1680.
Step-by-step explanation:
100×24=2400
120×24=2880
150×24=3600
692×2=1384
420×4=1680
A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 millimeters and standard deviation 0.08 millimeter. (a) [5pts] What proportions of the diameters are greater than 25.4
Answer:
The proportions of the diameters that are greater than 25.4 millimeters is 5%.
Step-by-step explanation:
Given;
mean of the normal distribution, m = 25.1 millimeters
standard deviation, d = 0.08 millimeter
1 standard deviation above the mean = m + d = 25.1 + 0.08 = 25.18
2 standard deviation above mean = m + 2d = 25.1 + 2(0.08) = 25.26
3 standard deviation above the mean = m + 3d = 25.1 + 3(0.08) = 25.34
4 standard deviation above the mean = m + 4d = 25.1 + 4(0.08) = 25.42
To obtain a diameter greater than 25.4, we select data after 4 standard deviation above the mean.
Data within 4 standard deviation above the mean is 95%
Data outside 4 standard deviation above the mean is 5%
Therefore, the proportions of the diameters that are greater than 25.4 millimeters is 5%.
find the perimeter of the polygon
Answer:
50
Step-by-step explanation:
19-7=12
6+6+7+19+12
I Will Mark Brainliest
The figure shows a rectangue with its length and breadth as indicated,
Give that the perimeter of a rectangle is 120cm, find the area of rectangle .
Answer:
Length = 2x+y cm and since it's a rectangle,
2x+y=3x-y ---------------- (i)
width = 2x-3 cm
It's perimeter,
2(2x+y+2x-3)=120 ---------------- (ii)
Solving both equations,
x = 14 cm
y = 7 cm
so length is, 2×14+7 = 35 cm
and width is, 2×14-3 = 25 cm
so area will be, 35×25 = 875 cm²
Answered by GAUTHMATH
Answer:
len = 35
width = 25
Step-by-step explanation:
3x-y = 2x+y
1) x-2y = 0
9x -6= 120
x = 14
y = 7
Please help 20 points. I will give Brainly to who ever get it right.
Answer:
Step-by-step explanation:
(-∞,2)
solve similar triangles (advanced)
solve for x
Answer:
27/2 =x
Step-by-step explanation:
We can write a ratio to solve
3 2
----- = ---------
3+x 11
Using cross products
3*11 = 2(3+x)
33 = 6+2x
Subtract 6 from each side
33-6 = 6+2x-6
27 = 2x
27/2 = 2x/2
27/2 =x
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
•Please answer it correctly ( step by step)
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
[tex]\sf\underline{\underline{Question:}}[/tex]
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
$\sf\underline{\underline{Solution:}}$
$\sf\bold\purple{||100||}$$\space$
$\sf\underline\bold\red{||Step-by-Step||}$
$\sf\bold{Given:}$
$\sf\bold{S6=36}$ $\sf\bold{S16=255}$$\space$
$\sf\bold{To\:find:}$
$\sf\bold{The \: sum\:of\:the\:first\:ten\:numbers}$$\space$
$\sf\bold{Formula\:we\:are\:using:}$
$\implies$ $\sf{ Sn=}$ $\sf\dfrac{N}{2}$ $\sf\small{[2a+(n-1)d]}$
$\space$
$\sf\bold{Substituting\:the\:values:}$
→ $\sf{S6=}$ $\sf\dfrac{6}{2}$ $\sf\small{[2a+(6-1)d]}$
→ $\sf{36 = 3[2a+(6-1)d]}$
→$\sf{12=[2a+5d]}$ $\sf\bold\purple{(First \: equation)}$
$\space$
$\sf\bold{Again,Substituting \: the\:values:}$
→ $\sf{S16}$ $\sf\dfrac{16}{2}$ $\sf\small{[2a+(16-1)d]}$
→ $\sf{255=8[2a + (16-1)d]}$
:: $\sf\dfrac{255}{8}$ $\sf\small{=31.89=32}$
→ $\sf{32=[2a+15d]}$ $\sf\bold\purple{(Second\:equation)}$
$\space$
$\sf\bold{Now,Solve \: equation \: 1 \:and \:2:}$
→ $\sf{10=20}$
→ $\sf{d=}$ $\sf\dfrac{20}{10}$ $\sf{=2}$
$\space$
$\sf\bold{Putting \: d=2\: in \:equation - 1:}$
→ $\sf{12=2a+5\times 2}$
→ $\sf{a = 1}$
$\space$
$\sf\bold{All\:of\:the\:above\:eq\: In \: S10\:formula:}$
$\mapsto$ $\sf{S10=}$ $\sf\dfrac{10}{2}$ $\sf\small{[2\times1+(10-1)d]}$
$\mapsto$ $\sf{5(2\times1+9\times2)}$
$\mapsto$ $\sf\bold\purple{5(2+18)=100}$
$\space$
$\sf\small\red{||Hence , the \: sum\: of \: the \: first\:10\: terms\: is\:100||}$
_____________________________
If Y / 4 - 12 = 3.5, what is the value of y?
The gcf of two numbers is 3 and their lcm is 180, if one of the numbers is 45 then found the second number
Answer:
answer is 12
Step-by-step explanation:
gcf = 3
lcm = 180
let 45 be y
let unknown be X
to get x
X=( lcm * gcf) / y
X=(180*3)/45
X=(540)/45
X=12
the other number is 12
A tourist from Britain wants to exchange her British pounds for US dollar. She has 25 British pounds. How many US dollars would she get in exchange for her British pound if 1 British pound can be exchanged for 1.53 US dollars?
Answer:
$38.25 US dollars.
Step-by-step explanation:
25 / 1 = 25
To find the number of US dollars that can be exchanged for 25 British pounds, multiply 1.53 by 25 to get $38.25 US dollars.
Hope this helps!
if there is something wrong, just let me know.
3.
Steve went to buy clothes for his school uniform. He bought five shirts that each cost the same
amount and one school jacket costing $20. The items he bought cost a total of $95 before tax was
added. What was the cost of each shirt?
Cost of jacket = $20
No. Of jackets = 1
Let the cost of shirt be x
No of shirts = 5
ATQ
5x + 1(20) = 95
5x + 20 = 95
5x = 95 - 20
5x = 75
x = 75/5
x = 15
Therefore cost of each shirt was $15
Answered by Gauthmath must click thanks and mark brainliest
20,30,13,10,14,10,10,?,?,?
Answer:
10,13,14,20,30.............
help with math it would help with summer school
Answer:
[tex]A). \ \ \frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
Step-by-step explanation:
Given;
radius of the circle, r = 9 inches
the part of the circle cut out = one-forth of the complete circle
the angle of the sector cut out θ= ¹/₄ x 360 = 90⁰
Area of the complete circle = πr² = π x 9² = 81π in²
Area of the sector cut out = [tex]= \frac{\theta }{360} \pi r^2 = \frac{90}{360} \pi (9^2) = \frac{1}{4} \times 81\pi = \frac{81 \pi}{4} = \frac{(72\pi + 9\pi)}{4} \ in^2[/tex]
Therefore, the only correct option is A. [tex]\frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
The time it takes me to wash the dishes is uniformly distributed between 8 minutes and 17 minutes.
What is the probability that washing dishes tonight will take me between 14 and 16 minutes?
Give your answer accurate to two decimal places.
The time it takes to wash has the probability density function,
[tex]P(X=x) = \begin{cases}\frac1{17-8}=\frac19&\text{for }8\le x\le 17\\0&\text{otherewise}\end{cases}[/tex]
The probability that it takes between 14 and 16 minutes to wash the dishes is given by the integral,
[tex]\displaystyle\int_{14}^{16}P(X=x)\,\mathrm dx = \frac19\int_{14}^{16}\mathrm dx = \frac{16-14}9 = \frac29 \approx \boxed{0.22}[/tex]
If you're not familiar with calculus, the probability is equal to the area under the graph of P(X = x), which is a rectangle with height 1/9 and length 16 - 14 = 2, so the area and hence probability is 2/9 ≈ 0.22.
A control variable is:
A. Measured to show the effect of a change.
B. Kept the same to make an experiment a fair test.
C. Collected to draw conclusions.
D. Changed to test a hypothesis.
It’s in between a and b, they’re both technically true no?
Answer:
B: kept the same to make an experiment a faith test
Mr. Cole packed 20 pounds into a suitcase, and Mrs. Cole packed 23 pounds into the same suitcase. They then had to remove 8 pounds because it was too heavy. How many pounds was their suitcase after making it lighter?
Answer:
35 lbs is the final weight
Step-by-step explanation:
20 +23 = 43 lbs
Then they had to remove 8 lbs
43 - 8 =35
35 lbs is the final weight
The mean output of a certain type of amplifier is 102102 watts with a standard deviation of 1212 watts. If 6363 amplifiers are sampled, what is the probability that the mean of the sample would differ from the population mean by greater than 3.43.4 watts
Answer:
0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 102, standard deviation of 12:
This means that [tex]\mu = 102, \sigma = 12[/tex]
Sample of 63:
This means that [tex]n = 63, s = \frac{12}{\sqrt{63}}[/tex]
What is the probability that the mean of the sample would differ from the population mean by greater than 3.4 watts?
Below 102 - 3.4 = 98.6 or above 102 + 3.4 = 105.4. Since the normal distribution is symmetric, these probabilities are equal, and thus, we find one of them and multiply by two.
Probability the mean is below 98.6.
p-value of Z when X = 98.6. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{98.6 - 102}{\frac{12}{\sqrt{63}}}[/tex]
[tex]Z = -2.25[/tex]
[tex]Z = -2.25[/tex] has a p-value of 0.0122.
2*0.0122 = 0.0244
0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.
Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)
Answer:
3. 3x^2 + 15x
4. x=36
Step-by-step explanation:
The area of a rectangle is
A = l*w
A = (3x)*(x+5)
Distribute
3x^2 + 15x
2/3x - 4 = 20
Add 4 to each side
2/3x -4+4 = 20+4
2/3x = 24
Multiply each side by 3/2
2/3*3/2 =24*3/2
x = 12*3
x=36
Complete the remainder
Answer:
-14 is the answer for the second term (?)
A call center receives 25 callers per minute on average. On average, a caller spends 1 minute on hold and 4 minutes talking to a service representative. On average, how many callers are "in" the call center
Answer:
"125 callers" is the right answer.
Step-by-step explanation:
Given values:
Arrival calls rate,
= 25 per minute
Talking time,
= 4 minutes
Hold time,
= 1 minute
The flow time will be:
= [tex]1 \ minute \ + 4 \ minutes[/tex]
= [tex]5 \ minutes[/tex]
Flow rate,
= [tex]Arrival \ calls \ rate[/tex]
= [tex]25 \ per \ minute[/tex]
By using the Little's law,
⇒ [tex]WIP = Flow \ rate\times Flow \ time[/tex]
By substituting the values, we get
[tex]= 25\times 5[/tex]
[tex]=125[/tex]
Thus the above is the correct approach.
find the missing side lengths
Answer:
x=2
y=1.732
Step-by-step explanation:
we use the formulae.....
SOHCAHTOA
where..Cos 60°=1/x
cos60=0.5
0.5=1/1
X=2
0.8660=y/2
y= 1.732
A publisher reports that 54% of their readers own a personal computer. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 200 found that 44% of the readers owned a personal computer. Is there sufficient evidence at the 0.10 level to support the executive's claim
The null and alternate hypotheses are
H0 : u = 0.44 vs Ha: u > 0.44
Null hypothesis: 44% of readers own a personal computer.
Alternate Hypothesis : greater than 44% of readers own a personal computer.
This is one tailed test and the critical region for this one tailed test for the significance level 0.1 is Z > ±1.28
The given values are
p1= 0.54 , p2= 0.44 ; q2= 1-p2= 0.56
Using z test
Z = p1-p2/√p2(1-p2)/n
Z= 0.54-0.44/ √0.44*0.56/200
z= =0.1/ 0.03509
z= 2.849
Since the calculated value of Z= 2.849 is greater than Z= 1.28 reject the null hypothesis therefore there is sufficient evidence to support the executive's claim.
Null hypothesis is rejected
There is sufficient evidence to support the executive's claim at 0.10 significance level.
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Trish's punch recipe calls for 8 liters of lemon-lime soda and 4 liters of cranberry juice, Jenny's punch recipe requires 7
liters of lemon-lime soda and 6 liters of cranberry juice. Which recipe has a higher ratio of lemon-lime soda to cranberry
juice?
( A, neither, the ratios are equivalent
B. Trish's recipe
c. Jenny's recipe
D. not enough information
PLEASE HELP!!
Indicate the method you would use to prove the two ▵‘s ≅. If no method applies, enter “none”
A. SSS
B. SAS
C. ASA
D. AAS
E. None
(I attached the triangle thing that goes with the question)
Consider the functions f and g in the tables below. f(x) = 90x2 + 180x + 92 x y 0 92 1 362 2 812 3 1,442 4 2,252 5 3,242 g(x) = 6x x y 0 1 1 6 2 36 3 216 4 1,296 5 7,776 Which of the following statements is true? A. At approximately x = 4.39, the rate of change of f is equal to the rate of change of g. B. As x increases, the rate of change of g exceeds the rate of change of f. C. As x increases, the rate of change of f exceeds the rate of change of g. D. For every value of x, the rate of change of g exceeds the rate of change of f.
Answer:
As x increases, the rate of change of g exceeds the rate of change of f.
Step-by-step explanation:
Given
[tex]f(x) = 90x^2 + 180x + 92[/tex]
[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & f(x) & {92} & {362} & {812} & {1442} & {2252} & {3242} \ \end{array}[/tex]
[tex]g(x) = 6^x[/tex]
[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & g(x) & {1} & {6} & {36} & {216} & {1296} & {7776} \ \end{array}[/tex]
Required
Which of the options is true?
A. At [tex]x \approx 4.39[/tex], f(x) has the same rate of change as g(x)
Rate of change is calculated as:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
For f(x)
[tex]f(x) = 90x^2 + 180x + 92[/tex]
[tex]f(4.39) = 90*4.39^2 + 180*4.39 + 92 = 2616.689[/tex]
So, the rate of change is:
[tex]m = \frac{2616.689}{4.39} = 596.06[/tex]
For g(x)
[tex]g(x) = 6^x[/tex]
[tex]g(4.39) = 6^{4.39} = 2606.66[/tex]
So, the rate of change is:
[tex]m = \frac{2606.66}{4.39} = 593.77[/tex]
The rate of change of both functions are not equal at x = 4.39. Hence, (a) is false.
B. Rate of change of g(x) is greater than f(x) with increment in x
Using the formula in (a), we have:
[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & f(x) & {92} & {362} & {812} & {1442} & {2252} & {3242} & m &\infty & 362 & 406 & 480 & 563 &648.4\ \end{array}[/tex]
[tex]\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4} & {5} & g(x) & {1} & {6} & {36} & {216} & {1296} & {7776} & m & \infty & 6 & 18 & 72 & 324 & 1555 \ \end{array}[/tex]
From x = 1 to 4, the rate of change of f is greater than the rate of g.
However, from x = 5, the rate of change of g is greater than the rate of f.
This means that (b) is true.
The above table further shows that (c) and (d) are false.
Answer:
Step-by-step explanation:
C
To mix weed killer with water correctly, it is necessary to mix 18 teaspoons of weed killer with 3 gallons of water. How many gallons of water are needed to mix with the entire box if it contains 24 teaspoons of weed killer
Please help! Thank you.
Answer:
B at -1 minus we go to - ∞
at -1 plus we to + ∞
Step-by-step explanation:
x^2 -x
g(x) = ---------
x+1
Factor out x
x(x-1)
g(x) = ---------
x+1
As x is to the left of -1
x is negative (x-1) is negative
x+1 will be slightly negative
g(-1 minus) = -*-/ - = - and we know that the denominator is very close to zero we are close to infinity so we go to - ∞
As x is to the right of -1
x is negative (x-1) is negative
x+1 will be slightly positive
g(-1 plus) = -*-/ + = + and we know that the denominator is very close to zero we are close to infinity so we go to ∞
A rocket is fired upward with an initial velocity v of 100 meters per second. The quadratic function S(t)=-5t^2+100t can be used to find the height s of the rocket, in meters, at any time t in seconds. Find the height of the rocket 7 seconds after it takes off. During the course of its flight, after how many seconds will the rocket be at a height of 450 meters?
The rocket will be at the height of 450metres at 13.16secs and 6.84secs
Given the expression modeled by the height S(t)=-5t^2+100t where
t is the time taken by the rocket to take off
s is the height traveled by rocket
In order to find the height of the rocket 7 seconds after it takes off, we will substitute t = 7 into the equation
S(7) = -5(7)²+100(7)
S(7) = -5(49)+700
S(7) = -245+700
S(7) = 455metres
Hence the height of the rocket 7 seconds after it takes off is 455metres
Given that S = 450m, we can also get the time taken by the rocket at this height.
Recall that S(t)= -5t²+100t
450 = -5t²+100t
Rearrange
-5t²+100t - 450 = 0
5t²-100t + 450 = 0
Divide through by 5
t²-20t + 90 = 0
On factorizing above equation;
t= 10+√10 or t=10−√10
t = 10+3.1623 or 10 - 3.1623
t = 13.16 and 6.84secs
Hence the rocket will be at the height of 450metres at 13.16secs and 6.84secs
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