Relationship between q and t pleaseeee helppppp

Answer:

See pic below.

slope = 2/3

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

Answer:

420.31

Step-by-step explanation:

A

.Rs.420.31

20ejjdj

Answer:

I think A rs 420.31 is right answet

Answer:

and practice problems to learn how to find and evaluate composite functions. ... If f(x)=(1/x) and (f/g)(x)=((x+4)/(x^2+2x)), what is the function g?

Answer:

0 and 360 - Onlinemath4all

FIND A COTERMINAL ANGLE BETWEEN 0° AND 360°. One complete rotation of a ray in the anticlockwise direction results in an angle measuring of 360°.

Missing: 452° ‎| Must include: 452°

First we need to assume that the sum of the angles is also 180°. if one is less than 90°, the other will be more. we can do this because in a plane 4-sided polygon the sum of the inner angles will always be 360°, and we already know the two angles on the right side

so we can say that:

3x + 20 + x = 180

Since we got only one variable in this equation, we can already solve for x.

4x + 20 = 180

4x = 160

x = 40

the lower left angle is just 40°

the upper left is three times that plus 20, so it's 160°

hope this helps you to get the method

Answer:

hope that helps i don't know it either tho

Answer:

x = 16.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 66 = 15/x

x sin 66 = 15

x = 15/sin 66

x=16.41954

Rounding to the nearest tenth

x = 16.4

Answer:

a = 50°

b = 130°

c = 50°

d = 50°

e = 130°

f = 130°

g = 50°

Answered by GAUTHMATH

Answer:

what?????............. :O

Answer:

The surface area of the rectangular prism is 430[tex]cm^{2}[/tex]

Step-by-step explanation:

To find the surface area of a rectangular prism you need to follow the formula

A=2(wl+hl+hw)

Hope this helps!

Answer:

45

Step-by-step explanation:

Answer:

The first option is the right one.

Step-by-step explanation:

7/2. Rate is rise/run

7 is your rise

and 2 is your run

therefore, the answer is 7/2

Answer:

It can be the line of best fit because it closely fits the data points.

Step-by-step explanation:

The line is near the data points and goes down from left to right just like the data points.  It is just above or just below the data points.

Answer:

guy above is right

Step-by-step explanation:

Answer:

you should use 1 ounce of chocolate to 6 ounces of butter

Step-by-step explanation:

if you are going from 8 ounces to 6 ounces of butter you are subtracting 2 ounces. to even it out you should use two ounces less of chocolate, leaving 1 ounce of chocolate to be used

Answer:

Option c is the correct answer

Step-by-step explanation:

Reason : -

When,

x = 6, y = 3

x / y

= 6 / 3

= 2 / 1

= 2

When,

x = 10, y = 5

x / y

= 10 / 5

= 2 / 1

= 2

When,

x = 14, y = 7

x / y

= 14 / 7

= 2 / 1

= 2

These ordered pairs represents a proportional relationships.

Answer:

14.25

Step-by-step explanation:

95*0.85=80.75

95-80.75=14.25

Answer:

The sale took $14.25 off the original price, so the item is currently $80.75 with the sale.

Answer:

600

Step-by-step explanation:

Volume=l*b*h=5*12*10=600

Answer:

h and the rest are the best for me 7-Eleven you have to go for your

Step-by-step explanation:

happy new years and hope you have not forgotten you and have been busy happy weekend to your the as is have weekend lot here well the there is you idom not you big very for hard while and there can't a help night get be to good in the world of the world and the world is a doctor that is a good friend and is not a good person .

Answer:

(x-7)²+(y+24)² = 625

Step-by-step explanation:

A circle with center (h, k) and radius r can be represented as

(x-h)²+(y-k)² = r²

We know the center and one point, and need to find the radius. The radius is equal to the distance from the center to any point on the circle. Therefore, we need to find the distance from the center to the point on the circle (in this case, the origin) to obtain the radius.

The distance formula for points (x₁, y₁) and (x₂, y₂) is √((x₁-x₂)²+(y₁-y₂)²). Note that x₁ and x₂ (as well as y₁ and y₂) are interchangeable but x₁ and y₁ or x₂ and y₂ are not.

Our distance between (7, -24) and the origin is

√((x₁-x₂)²+(y₁-y₂)²) = √((7-0)²+(-24-0)²)

= √625

= 25

Therefore, the radius is 25 and our equation is

(x-7)²+(y-(-24))² = (x-7)²+(y+24)² = 25² = 625

Answer:

20.4

Step-by-step explanation:

cos(74) = x/74

x = 74×cos(74)

x = 20.4

Answered by GAUTHMATH

Answer:

its c 120in

Step-by-step explanation:

The perimeter of the triangle is,

⇒ 138 in.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

The hypotenuse of a right triangle is 52 in.

And, One leg of the triangle is 8 in. more than twice the length of the other.

Hence, We get;

Lengths of legs are,

⇒ x

And, ⇒ 8 + 2x

Hence, We can formulate;

⇒ 52² = x² + (2x + 8)²

⇒ 2704 = x² + 4x² + 64 + 24x

⇒ 5x² + 24x - 2640 = 0

⇒ x = 20 and x = - 132/5

For perimeter;

Take x = 20

Hence, The perimeter of the triangle is,

⇒ 52 + x + (2x + 8)

⇒ 52 + 20 + (2 × 20 + 8)

⇒ 52 + 20 + 48

⇒ 138 in.

Thus, The perimeter of the triangle is,

⇒ 138 in.

Learn more about the triangle visit;

brainly.com/question/1058720

#SPJ7

Answer:

S = 35 + 20w

Step-by-step explanation:

Amount Samantha has in her account = $35

Additional savings per week = $20

Let

S =Totai savings in Samantha's account at the end of the week

w = number of weeks

The equation:

Totai savings in Samantha's account at the end of the week = Amount Samantha has in her account + (Additional savings per week * number of weeks)

S = 35 + 20w

Answer:

s=35+20w

Step-by-step explanation:

Answer:

the batteries are 74 cents and oranges are 5.10

Step-by-step explanation:

for the first one just divide 5.92 by 8 to get the unit price

and for the second multiply 2.7 by 1.89

Answer:

The value for C is 2.3

in this case we know of x to be 4.85

therefore subtract the summation of both X+C from the value of x.

Hence we will have the equation X - X+C =2.3

Answer:

SA=2πrh+2πr2=2·π·12·3+2·π·122≈282.7cm2

Answer:

x = 0

Step-by-step explanation:

-2(2 − 2x) = 4 − 8(1 − x)

Apply the distributive property:

−2(2 − 2x) = 4 − 8(1 − x)

(−2)(2) + (−2)(−2x) = 4 + (−8)(1) + (−8)(−x)

−4 + 4x = 4 + (−8) + 8x

Combine like terms:

4x − 4 = (8x) + (4+−8)

4x − 4 = 8x + (−4)

4x − 4 = 8x − 4

Subtract 8x from both sides:

4x − 4 − 8x = 8x − 4 − 8x

−4x − 4 = −4

Add 4 to both sides:

−4x − 4 + 4= −4 + 4

−4x = 0

Divide both sides by -4:

-4x/-4 = 0/-4

x = 0

Answer: 0

Step-by-step explanation:

Answer:

See Below (Boxed Solutions).

Step-by-step explanation:

We are given the two complex numbers:

[tex]\displaystyle z = \sqrt{3} - i\text{ and } w = 6\left(\cos \frac{5\pi}{12} + i\sin \frac{5\pi}{12}\right)[/tex]

First, convert z to polar form. Recall that polar form of a complex number is:

[tex]z=r\left(\cos \theta + i\sin\theta\right)[/tex]

We will first find its modulus r, which is given by:

[tex]\displaystyle r = |z| = \sqrt{a^2+b^2}[/tex]

In this case, a = √3 and b = -1. Thus, the modulus is:

[tex]r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2[/tex]

Next, find the argument θ in [0, 2π). Recall that:

[tex]\displaystyle \tan \theta = \frac{b}{a}[/tex]

Therefore:

[tex]\displaystyle \theta = \arctan\frac{(-1)}{\sqrt{3}}[/tex]

Evaluate:

[tex]\displaystyle \theta = -\frac{\pi}{6}[/tex]

Since z must be in QIV, using reference angles, the argument will be:

[tex]\displaystyle \theta = \frac{11\pi}{6}[/tex]

Therefore, z in polar form is:

[tex]\displaystyle z=2\left(\cos \frac{11\pi}{6} + i \sin \frac{11\pi}{6}\right)[/tex]

Part A)

Recall that when multiplying two complex numbers z and w:

[tex]zw=r_1\cdot r_2 \left(\cos (\theta _1 + \theta _2) + i\sin(\theta_1 + \theta_2)\right)[/tex]

Therefore:

[tex]\displaystyle zw = (2)(6)\left(\cos\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right) + i\sin\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right)\right)[/tex]

Simplify. Hence, our polar form is:

[tex]\displaystyle\boxed{zw = 12\left(\cos\frac{9\pi}{4} + i\sin \frac{9\pi}{4}\right)}[/tex]

To find the complex form, evaluate:

[tex]\displaystyle zw = 12\cos \frac{9\pi}{4} + i\left(12\sin \frac{9\pi}{4}\right) =\boxed{ 6\sqrt{2} + 6i\sqrt{2}}[/tex]

Part B)

Recall that when raising a complex number to an exponent n:

[tex]\displaystyle z^n = r^n\left(\cos (n\cdot \theta) + i\sin (n\cdot \theta)\right)[/tex]

Therefore:

[tex]\displaystyle z^{10} = r^{10} \left(\cos (10\theta) + i\sin (10\theta)\right)[/tex]

Substitute:

[tex]\displaystyle z^{10} = (2)^{10} \left(\cos \left(10\left(\frac{11\pi}{6}\right)\right) + i\sin \left(10\left(\frac{11\pi}{6}\right)\right)\right)[/tex]

Simplify:

Simplify using coterminal angles. Thus, the polar form is:

[tex]\displaystyle \boxed{z^{10} = 1024\left(\cos \frac{\pi}{3} + i\sin \frac{\pi}{3}\right)}[/tex]

And the complex form is:

[tex]\displaystyle z^{10} = 1024\cos \frac{\pi}{3} + i\left(1024\sin \frac{\pi}{3}\right) = \boxed{512+512i\sqrt{3}}[/tex]

Part C)

Recall that:

[tex]\displaystyle \frac{z}{w} = \frac{r_1}{r_2} \left(\cos (\theta_1-\theta_2)+i\sin(\theta_1-\theta_2)\right)[/tex]

Therefore:

[tex]\displaystyle \frac{z}{w} = \frac{(2)}{(6)}\left(\cos \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right) + i \sin \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right)\right)[/tex]

Simplify. Hence, our polar form is:

[tex]\displaystyle\boxed{ \frac{z}{w} = \frac{1}{3} \left(\cos \frac{17\pi}{12} + i \sin \frac{17\pi}{12}\right)}[/tex]

And the complex form is:

[tex]\displaystyle \begin{aligned} \frac{z}{w} &= \frac{1}{3} \cos\frac{5\pi}{12} + i \left(\frac{1}{3} \sin \frac{5\pi}{12}\right)\right)\\ \\ &=\frac{1}{3}\left(\frac{\sqrt{2}-\sqrt{6}}{4}\right) + i\left(\frac{1}{3}\left(- \frac{\sqrt{6} + \sqrt{2}}{4}\right)\right) \\ \\ &= \boxed{\frac{\sqrt{2} - \sqrt{6}}{12} -\frac{\sqrt{6}+\sqrt{2}}{12}i}\end{aligned}[/tex]

Part D)

Let a be a cube root of z. Then by definition:

[tex]\displaystyle a^3 = z = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]

From the property in Part B, we know that:

[tex]\displaystyle a^3 = r^3\left(\cos (3\theta) + i\sin(3\theta)\right)[/tex]

Therefore:

[tex]\displaystyle r^3\left(\cos (3\theta) + i\sin (3\theta)\right) = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]

If two complex numbers are equal, their modulus and arguments must be equivalent. Thus:

[tex]\displaystyle r^3 = 2\text{ and } 3\theta = \frac{11\pi}{6}[/tex]

The first equation can be easily solved:

[tex]r=\sqrt[3]{2}[/tex]

For the second equation, 3θ must equal 11π/6 and any other rotation. In other words:

[tex]\displaystyle 3\theta = \frac{11\pi}{6} + 2\pi n\text{ where } n\in \mathbb{Z}[/tex]

Solve for the argument:

[tex]\displaystyle \theta = \frac{11\pi}{18} + \frac{2n\pi}{3} \text{ where } n \in \mathbb{Z}[/tex]

There are three distinct solutions within [0, 2π):

[tex]\displaystyle \theta = \frac{11\pi}{18} , \frac{23\pi}{18}\text{ and } \frac{35\pi}{18}[/tex]

Hence, the three roots are:

[tex]\displaystyle a_1 = \sqrt[3]{2} \left(\cos\frac{11\pi}{18}+ \sin \frac{11\pi}{18}\right) \\ \\ \\ a_2 = \sqrt[3]{2} \left(\cos \frac{23\pi}{18} + i\sin\frac{23\pi}{18}\right) \\ \\ \\ a_3 = \sqrt[3]{2} \left(\cos \frac{35\pi}{18} + i\sin \frac{35\pi}{18}\right)[/tex]

Or, approximately:

[tex]\displaystyle\boxed{ a _ 1\approx -0.4309 + 1.1839i,} \\ \\ \boxed{a_2 \approx -0.8099-0.9652i,} \\ \\ \boxed{a_3\approx 1.2408-0.2188i}[/tex]

Answer:

b

Step-by-step explanation: