Answer:
3-chloro-3-methylpentane,>2-chloro-3-methylpentane> 1-chloro-3-methylpentane, > chloromethane
Explanation:
The rate of SN1 reactions decreases in the order, tertiary > secondary > primary > methyl.
This implies that, a tertiary alkyl halide is better able to undergo nucleophilic substitution by SN1 mechanism compared to a secondary, primary or methyl.
This is because, the transition state leading to the formation of an SN1 product involves a carbocation. The order of stability of carbocations is; tertiary > secondary > primary > methyl.
Hence a tertiary alkyl halide such as 3-chloro-3-methylpentane leads to a more stable transition state and undergoes SN1 reaction at a faster rate.
A silver ring has a density of 10.50 g/mL. What is the mass of the ring that has a volume of 10.0 mL?
20.5 g?
105 g?
0.952 g?
Answer:
the answer is 105 g/mL
Explanation:
beacuse mass = density×volume
how do you Pangea and plate tectonic differ?
Which of these terms describes an organism that eats green algae and shrimp?O A. a carnivore
O B. an omnivore
O C. a herbivore
O D. a detrivore
ASAP
Answer: C. a herbivore
Explanation: it's not a because omnivores eat plants and animals not Detritivores, are heterotrophs that obtain nutrients by consuming detritus
but herbivores eat vegetables and plants
i'm a herbivore i don't eat meat :)
A 293.9 mL sample of a 0.275 M solution is left on a hot plate overnight; the following morning the solution is 1.10 M. What volume of solvent in mL has evaporated from the 0.275 M solution
Answer:
220.4mL were evaporated
Explanation:
First, we are going to calculate the moles of the solution. Then, with the new concentration we can solve the volume of the solution and the evaporated volume:
Moles initial solution:
293.9mL = 0.2939L * (0.275mol / L) = 0.08082 moles of solution.
As the new concentration is 1.10M, the new volume must be:
0.08082 moles of solution * (1L / 1.10mol) = 0.07348L =
73.5mL you have still present in you solution
And evaporated volume is:
293.9mL - 73.5mL =
220.4mL were evaporatedIn this periodic table, which color or colors represent the elements that are
metals?
A. Blue and green
B. Orange and green
C. Orange only
D. Blue only
Answer:
D
Explanation:
the metal are on the left and in the middle
There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, the correct option is option D that is Blue only.
What is periodic table?Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.
Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.
The elements which is colored blue are elements that are metals. Metals are mostly on the left side of the periodic table. Metals loose lectrons easily. Metals are lustrous, malleable and ductile.
Therefore, the correct option is option D that is Blue only.
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Identify the nucleic acid DNA
1. Cholesterol
2. Proteins
3. Disacharide
Answer:
DNA
Explanation:
Choose all the answers that apply.
DNA contains coded information for _____.
hibernation
body structure
eye color
height
photosynthesis
Answer: Hibernation, Eye color and height
Explanation: DNA is the most important molecule of life. Many behaviors are controlled by DNA, such as telling bears how long to hibernate. All of the physical and chemical characteristics of an organism are also controlled by DNA, some cells will form bone, While others will form skin, hair and lungs.
If a sample contains 78.0 % of the R enantiomer and 22.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?
Answer: The enantiomeric excess of the mixture =56%
Explanation:
As per given : R isomer = 78%
S isomer = 22%
In chiral substances, Enantiomeric excess is the measure of purity.
So, Enantiomeric excess of the mixture = [tex]|\frac{R-S}{R+S}|\times100[/tex]
[tex]=|\frac{78-22}{78+22}|\times100[/tex]
[tex]=|\frac{56}{100}|\times100\% \\\\=56\%[/tex]
Hence, the enantiomeric excess of the mixture =56%
The combustion of hexane is given by the following reaction. 2 C 6 H 14 + 19 O 2 → 12 CO 2 + 14 H 2 O The enthalpy of reaction is −4163.0 kJ/mol. How much energy (in joules) will be released if 72.78 grams of hexane is burned. (Molar mass of hexane = 86.20 g/mol).
Answer:
[tex]E=3.5149kJ[/tex]
Explanation:
Hello.
In this case, for such combustion of hexane which release heat, we can compute that amount by taking into account that the reaction releases 4163.0 kJ of energy every 1 mole of hexane, it means that for 72.78 g, which in moles is:
[tex]n_{hexane}=72.78g*\frac{1mol}{86.20g}=0.8443mol[/tex]
Thus the energy released when 0.8443 moles of hexane are released turn out:
[tex]E=n_{hexane}\Delta _cH=0.8443mol*-4163.0\frac{kJ}{mol}*\frac{1000J}{1kJ} \\\\E=3.5149kJ[/tex]
Best regards!
Titanium has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.58. If the radius of the Ti atom is 0.1445 nm, calculate the density of Ti and compare it with the literature value of 4.51 g/cm3 . The atomic mass of titanium is 47.87 g/mol.
Answer:
4.81 g / mol
Explanation:
Given :
Titanium has an HCP unit cell
Radius of titanium, R = 0.1445 nm
Unit cell volume, [tex]$V_c= 6R^2 C\sqrt3$[/tex]
But for Ti, c/a = 1.58
So, c = 1.58 a
And a = 2R or c = 3.16 R
[tex]$V_c = 6R^2 \times 3.16 R \times \sqrt3$[/tex]
[tex]$V_c=6 \times 3.16 \times \sqrt3 \times (1.445 \times 10^{-8})^3 $[/tex]
[tex]$V_c= 9.91 \times 10^{-23}\ cm^3 / unit \ cell $[/tex]
Density of Ti (theoretical), [tex]$\rho=\frac{n. A_{Ti}}{V_C.N_A} $[/tex]
For HCP, n = 6 atoms per unit cell and atomic mass = 47.87 g/mol
[tex]$\rho=\frac{6 \times 47.87}{9.91 \times 10^{-23} \times 6.023 \times 10^{23}} $[/tex]
= 4.81 g/mol
This is the theoretical density of titanium.
The value given in literature is 4.51 g/mol
What volume of 6.0 M HCl would you need to add to a 800.0 mL of 0.10 M NaAc to give a final pH = 4.30? The pKa of HAc is 4.78. Give the answer in milliliters, using 2 sig. figs.
Answer:
3.33 ml
Explanation:
We have
pH to be equal to pKa + log [ NaAc / HAc]
pH = 4.30
pKA = 4.78
This is expressed as
4.30 = 4.78 + log [ NaAc / HAc]
log [ NaAc / HAc] = - 0.48
[ NaAc / HAc] = 10^-0.48
= 0.33
Naac/HAc = 0.33
From here we cross multiply to get
NaAc = 0.33 HAc
The ratio can be given as 1 : 0.33 or 3:1
Moles of NaAc = 800 x 0.10 / 1000
= 0.08
With a ratio of 3 : 1 NaAC and HAc
We have 0.06 mol NaAc and 0.02 mol HAc
moles of HCl = 0.02 mol
Volume of Hcl = 0.02x1000 = 20
20/6.0
= 3.33 Ml
The volume of 6.0 M HCL should be 3.33 ml.
Calculation of the volume:Since
pH to be equal to pKa + log [ NaAc / HAc]
pH = 4.30
pKA = 4.78
Now we can do like
4.30 = 4.78 + log [ NaAc / HAc]
log [ NaAc / HAc] = - 0.48
[ NaAc / HAc] = 10^-0.48
= 0.33
Naac/HAc = 0.33
Now
NaAc = 0.33 HAc
The ratio can be given as 1 : 0.33 or 3:1
So,
Moles of NaAc = 800 x 0.10 / 1000
= 0.08
With a ratio of 3 : 1 NaAC and HAc
We have 0.06 mol NaAc and 0.02 mol HAc
And,
moles of HCl = 0.02 mol
So,
Volume of Hcl = 0.02x1000 = 20
= 20/6.0
= 3.33 Ml
hence, The volume of 6.0 M HCL should be 3.33 ml.
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Which substance is oxidised 2MgO + O2 → 2MgO
Answer:
Here the oxidizing agent is Mg and the reducing agent is the O2.
This is because Mg is getting taking in O and is reducing itself to form MgO.
This Magnesium oxide, or magnesia, so formed is a white hygroscopic solid mineral that occurs naturally as percales and is a source of magnesium.
Explanation:
The ph of a lime is 1.90. What is the [H3O+]?
Answer:
thts the acidic presence
Explanation:
Calculate the pH at of a solution of trimethylammonium chloride . Note that trimethylamine is a weak base with a of . Round your answer to decimal place.
Answer:
pH = 11.9
Explanation:
The solution is 0.93M. The pKb is 4.19
The general equation of a weak base, X, is:
Kb = [OH⁻] [XH⁺] / [X]
Where Kb is 10^-pKb = 6.457x10⁻⁵
[OH⁻] and [XH⁺] comes both from the same equilibrium and its concentration, X, is the same = [OH⁻] = [XH⁺] = X
And [X] could be taken as the initial concentration of the weak acid, 0.93M
Kb = [OH⁻] [XH⁺] / [X]
6.457x10⁻⁵ = X² / 0.93M
6x10⁻⁵ = X²
X = 7.749x10⁻³M = [OH⁻]
As pOH = -log[OH⁻]
pOH = 2.11
pH = 14 - pOH
pH = 11.9Complete analysis question 2 from page B-63 in your book. "Was there copper in Cups 1-6? How did you know it was or was not there? Explain using evidence from this activity"
Answer:
I NEED HELP TOO AND ALSO PLEASE DONT 1 STAR 5 STAR FOR THE MEMES
Explanation:
Answer:
cup 2
Explanation:
it has more water in there therefore its more diluted
A liquid was known to be either methyl alcohol (CH3OH) or ethyl alcohol (CH3CH2OH). The Dumas method for determining molar masses was used to obtain an approximate molar mass, and this value was used to identify the alcohol. The gaseous alcohol at 98oC and 740Torr has a mass of 0.276g in a Dumas bulb of volume equal to 270mL. Which alcohol was present
Answer:
Methyl alcohol was present.
Explanation:
To solve this problem we use the PV=nRT formula:
P = 740 Torr ⇒ 740/760 = 0.973 atmV = 270 mL ⇒ 270/1000 = 0.270 LT = 98 °C ⇒ 98 + 273.16 = 371.16 KAnd solve for n:
n = PV/(RT)n = 0.973 atm * 0.27 L / (0.082atm·L·mol⁻¹·K⁻¹ * 371.16 K)n = 8.632 x 10⁻³ molNow we divide the mass and the moles to calculate the molar mass:
0.276 g / 8.632 x 10⁻³ mol = 31.97 g/molMethyl alcohol (CH₃OH) has that molar mass.
calculate the ph at 25 c of a .33 m solution of sodium benzoate. note that benzoic acid is a weak acid with a pka of 4.2
Answer:
The pH at 25°C of 0.33M solution is 5.36.
Explanation:
Let us calculate -:
[tex]NaC_6H_5CO_2$\rightarrow$ salt of weak acid + sodium benzoate[/tex]
pH of salt of weak acid and sodium benzoate is given by-
pH =[tex]7+\frac{1}{2}pk_a+\frac{1}{2}log (concentration of salt)[/tex]
concentration of salt = 0.33M
[tex]pK_a=4.2[/tex]
[tex]pH = 7 +\frac{4.2}{2} +\frac{1}{2}log (0.33)[/tex]
[tex]pH=7 +\frac{4.2}{2} + \frac{(-0.4815)}{2}[/tex]
pH = 5.36
Hence , the answer is 5.36
Which is a product of nuclear fusion?
a nucleus that has a greater mass number than the starting materials
two nuclei that are roughly half the mass of the starting materials
a nucleus that has the same atomic number as the starting materials
two nuclei that have greater atomic numbers than the starting materials
The Answer is: A
The product of nuclear fusion is a nucleus that has a greater mass number than the starting materials.
What is nuclear fusion?Nuclear fusion occurs when two or more atomic nuclei unite to generate one or more new atomic nuclei and subatomic particles.
The release or absorption of energy is caused by the mass differential between the reactants and products.
If absorption of energy takes place then the formed nuclei will have the higher mass than reactant nuclei.If release of energy takes place then the formed nuclei will have the lighter mass than reactant nuclei.Hence a nucleus that has a greater mass number than the starting materials is the product of the nuclear fusion is .
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Answer:
A
Explanation:
Compound 1 melts at 40 degrees Celsius. Compound 2 melts at 1310 degrees Celsius. Compound 3 melts at
240 degrees Celsius. Compound 4 melts at -62 degrees Celsius. Which is most likely to be an ionic compound?
Compound 4
Compound 2
Compound 3
Compound 1
Explanation:
We know that,
Ionic compound have high melting point.Here,
Compound 2 has high melting point.
So,
Compound 2 is most likely to be an ionic compound.
Volcanologists are scientists who study volcanic eruptions. However, most volcanologists rarely get to witness a volcanic eruptions actually occurring. Instead, many volcanologists use models to study volcanic eruptions. What is the most likely reason why volcanologists often rely on models to study volcanic eruptions?
A.
Volcanic eruptions are too large to be able to see with the naked eye.
B.
Volcanic eruptions are very dangerous events.
C.
Volcanic eruptions are rare occurrences so it is difficult to see them.
D.
Volcanic eruptions take too long to be able to be observed in their entirety.
Answer:
Volcanic Eruptions are a very dangerous event
Explanation:
Models represent objects, events, and processes in the real world. Models are often used when an object, event, or process occurs too slowly or too quickly; is too small or too large; is too complicated or too dangerous. Volcanic eruptions produce both molten lava and poisonous gases. Therefore, eruptions can be very dangerous. Many volcanologists have lost their lives while observing volcanic eruptions.
The image below shows a fault.
a zap
A diagram showing plate movement with labels. The footwall is on the left and the hanging wall is on the right. The plates are moving away from each other.
Which describes the motion of the plates?
The hanging wall and footwall both move vertically.
Shearing is causing the plates to slide past each other.
The hanging wall moves down in relation to the footwall.
Compression is causing the plates to move toward each other.
Answer:
This is a normal fault. Normal faults usually result from tensile stresses so D is an answer.
Additionally we can see that the hanging wall has moved down relative to the footwall so C is the other answer. =^.^=
Explanation:
this may help you >:3
Answer:
C
Explanation:
What is the speed of a rocket in units of meter/ second if its travels at a speed of 1000 km/minutes?
Answer:1,080 m
Explanation:
What is the molarity of a solution that contains 2.5 g NaCl in 2 L of water?
A. 1.25 M
B. 0.02 M
C. 2.0 M
D. 0.125 M
Answer:
0.02
Explanation:
I'm not really sure ok so sorry
g determine the mass of products formed by the combustion of 7.600 g of a compound with empirical formula c7h12
Answer:
[tex]m_{CO_2}=24.38gCO_2\\m_{H_2O}=8.550gH_2O[/tex]
Explanation:
Hello.
In this case, since the combustion of C7H12 which is probably heptyne (molar mass = 96 g/mol) is:
[tex]C_7H_1_2+10O_2\rightarrow 7CO_2+6H_2O[/tex]
In which the products are carbon dioxide (molar mass = 17 g/mol) and water (18 g/mol) that are in a 7:1 and 6:1 mole ratio with the heptyne, respectively; thus, the yielded mass of both carbon dioxide and water is:
[tex]m_{CO_2}=7.600gC_7H_{12}*\frac{1molC_7H_{12}}{96gC_7H_{12}}*\frac{7molCO_2}{1molC_7H_{12}} *\frac{44gCO_2}{1molCO_2} \\m_{CO_2}=24.38gCO_2\\\\m_{H_2O}=7.600gC_7H_{12}*\frac{1molC_7H_{12}}{96gC_7H_{12}}*\frac{6molH_2O}{1molC_7H_{12}} *\frac{18gH_2O}{1molH_2O} \\m_{H_2O}=8.550gH_2O[/tex]
Best regards.
Plants and animals that share a______ often help each other survive. Plants provide food and shelter for animals. In turn, animals help plants reproduce. When bees and other insects gather____they also carry______from flower to flower. This helps to_____the flowers. The______ of each flower then produces seeds and grows into a fruit. Other animals scatter the seeds.
Answer:
biome or habitat, nectar, pollen, pollinate, propagation
Explanation:
Do any of these terms sound familiar?
A lab group was calculating the speed of a radio car. They measured the distance traveled to be 6 meters and the time to be 3.5 seconds. Then they divided the distance by the time to find the speed. The actual speed was 2.2 m/s. What was their percent error?
Answer:456
Explanation:
The density of a gas is 2.49 g/L at 3.00 atm and 25oC. Calculate the molar mass of the gas. Multiple choice question. 2.0 g/mol 20.3 g/mol 18.3 g/mol 24.9 g/mol
Answer:
Molar mass = 20.3 (Approx)
Explanation:
Given:
Density = 2.49 g/l
Pressure = 3 atm
Tempreture = 25 degree celcius = 273 + 25 = 298 k
Find:
Molar mass
Computation:
pm = drt
3(m) = (2.49)(298)(0.0821)
m = 20.3 (Approx)
Molar mass = 20.3 (Approx)
An atom of argon has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of argon. Write your answer as a percentage of the average speed, and round it to significant digits.
Here is the full question:
An atom of argon has a radius of 71 .pm and the average orbital speed of the electrons in it is about 3.9 × 10⁷ m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of argon. Write your answer as a percentage of the average speed, and round it to significant digits.
Answer:
Explanation:
From the above information:
The radius of an atom of argon = 71 .pm = 71 × 10⁻¹² m
The diameter of the atom of argon Δx =142 × 10⁻¹² m
According to Heisenberg's Uncertainty Principle,
[tex]\Delta x. \Delta p_x \geq \dfrac{h}{2}[/tex]
[tex]\Delta x. \Delta V \geq \dfrac{h}{4 \pi m_e}[/tex]
[tex]\Delta V \geq \dfrac{h}{4 \pi m_e \Delta_x}[/tex]
[tex]\Delta V \geq \dfrac{6.634 \times 10^{-34} \ J.s}{4 \pi \times 9.1 \times 10^{-3} \ kg \times 142 \times 10^{-12} \ m}[/tex]
[tex]\Delta V \geq \dfrac{6.634 \times 10^{-34} \ J.s}{1.62382641 \times 10^{-11} \ kg.m}[/tex]
[tex]\Delta V \geq 4.08 \times 10^5 \ m/s[/tex]
where; the average speed [tex]V_{avg}[/tex] = 3.9 10⁷ m/s
∴
The percentage of the average speed is expressed as a fraction of:
[tex]\% = \dfrac{4.08 \times 10^5}{3.9 \times 10^7}\times 100[/tex]
[tex]\% =1.0462[/tex]
[tex]V_{avg } = 1.046 \times 10^0[/tex]
[tex]\mathbf{V_{avg }\simeq 1.0 \%}[/tex]
A student tries to balance the equation by changing the subscript 2 on Cl to a 3. Explain why this is not correct. What is the correct balanced equation
The question is incomplete, the complete question is;
“Consider the unbalanced chemical equation. Al(s) + Cl2(g) ------> AlCl3(s) A student tries to balance the equation by changing the subscript 2 on Cl to a 3. Explain why this is not correct. What is the correct balanced equation?”
Answer:
2Al(s) + 3Cl2(g) ------> 2AlCl3(s)
Explanation:
If the student changes the subscript of Cl from 2 to 3, he/she has written a symbol for a molecule that does not exist. Halogens exist as diatomic and not triatomic gases.
The balanced equation is; 2Al(s) + 3Cl2(g) ------> 2AlCl3(s).
Notice that the basic principles of valency are not violated in any of the species in the equation above. Cl3 violates the octet rule but Cl2 obeys the octet rule.
All of the following complexes will be colored (in the visible) EXCEPT ________. a) [Zn(en)3]2 b) [Fe(CN)6]4- c) [Ni(H2O)6]2 d) [Cr(NH3)6]3 e) [Cu(NH3)4]2
Answer:
a
Explanation:
All of the complexes will be colored except [Zn(en)3]2.
Fe, Ni, Cr, and Cu all form colored complexes because of their partially-filled d-orbitals and are generally referred to as transition elements. The d-orbital can split into higher and lower orbitals and electrons can jump from one level to the other. The jumping of electrons leads to light absorption and this characteristic impacts color to elements with partially-filled d-orbitals.
Zinc does not possess a partially-filled d-orbital and as such, its electrons cannot transition between levels, even though it belongs to the 'd-block' element.
The correct option is a.
