Question 8
A student earned 30 out of 35 points on a
the total points did the student earn? Round it off to the nearest precent

Let missing one be x

If both are similar

[tex]\\ \sf\longmapsto \dfrac{20}{25}=\dfrac{16}{x}[/tex]

[tex]\\ \sf\longmapsto \dfrac{4}{5}=\dfrac{16}{x}[/tex]

[tex]\\ \sf\longmapsto 4x=16(5)[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{16(5)}{4}[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

Reflection over the line x=a is the transformation ...

  (x, y) ⇒ (2a -x, y)

Then the double reflection over x=a and x=b is the transformation ...

  (x, y) ⇒ (2b -(2a -x), y) = (2(b-a) +x, y)

That is, the result is translation by twice the distance between the lines. For a=1 and b=3, the transformation is ...

  (x, y) ⇒ (x +4, y) . . . . . . . translation to the right by 4 units.

  A(-5, 2) ⇒ A''(-1, 2)

  B(-1, 5) ⇒ B''(3, 5)

  C(0, 3) ⇒ C''(4, 3)

Answer:

(a) [tex]C(x) = 12 + 5x[/tex]

(b) [tex]C(x) = 8x[/tex]

(c) Tables

(d) See attachment for graph

(e) Banner newspaper

(f) Free press newspaper

Free Press

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {17} & {22} & {27} & {32} & {37} \ \end{array}[/tex]

Banner

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {8} & {16} & {24} & {32} & {40} \ \end{array}[/tex]

Step-by-step explanation:

Given

Free Press

[tex]Initial = 12[/tex]

[tex]Rate =5[/tex]

Banner

[tex]Initial=0[/tex]

[tex]Rate =8[/tex]

Solving (a): Free Press Equation

This is calculated as:

[tex]C(x) = Initial + Rate * x[/tex]

Where

[tex]x \to[/tex] days

So, we have:

[tex]C(x) = 12 + 5x[/tex]

Solving (b): Banner Equation

This is calculated as:

[tex]C(x) = Initial + Rate * x[/tex]

Where

[tex]x \to[/tex] days

So, we have:

[tex]C(x) = 0 + 8x[/tex]

[tex]C(x) = 8x[/tex]

Solving (c): Table of values

For free press, we have:

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {17} & {22} & {27} & {32} & {37} \ \end{array}[/tex]

C(x) is calculated as:

[tex]x = 1;\ C(1) = 12 + 5* 1 =17[/tex]

[tex]x = 2;\ C(2) = 12 + 5* 2 =22[/tex]

..

[tex]x = 5;\ C(5) = 12 + 5* 5 =37[/tex]

For banner, we have:

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {8} & {16} & {24} & {32} & {40} \ \end{array}[/tex]

C(x) is calculated as:

[tex]x = 1;\ C(1) = 8* 1 =8[/tex]

[tex]x = 2;\ C(2) = 8* 2 =16[/tex]

..

[tex]x = 5;\ C(5) = 8* 5 =40[/tex]

Solving (d): Graph of both using rapidtable

See attachment

Solving (e) Newspaper to use for 1 day

From the graph, when [tex]x = 1[/tex]

[tex]Free\ press = 17[/tex]

[tex]Banner = 8[/tex]

So, we use Banner newspaper because it is cheaper

Solving (f) Newspaper to use for 12 days

From the graph, when [tex]x = 12[/tex]

[tex]Free\ press = 72[/tex]

[tex]Banner = 96[/tex]

So, we use free press newspaper because it is cheaper

Step-by-step explanation:

well, what does the word "constant" tell you ?

e.g. "this is a constant reminder of ..."

a constant is steady and unchanging. always the same.

so, what could be the constant part/term in the expression ?

-3xy ? is that always the same value ? no matter what values you assign to x, y (and whatever other variables there might be in the system)?

or

10 ? is that always the same value, no matter what values are assigned to x, y, ... ?

there are no other parts/terms I can see here.

so, please use your common sense and pick the right one. you can do that !

this is so simple. to outright write the answer to this feels like an offense. also against your own intelligence.

Answer:

136

Step-by-step explanation:

15/100×160

=24

pages that doesn't have pictures=160-24

=136

Answer:

a. These four vectors are dependent because there are columns of 3 by 4 matrix with one free variable.

b. If one is a multiple of other

c. c1v1 + c20 = 0 has nontrivial solution.

Step-by-step explanation:

Any set of 4 or more vectors must be linearly dependent. The non trivial combination of vector may produce zero as the set is linearly dependent. The vector v1 and v2 will be dependent if one is the multiple of the other.

Answer:

175731 is one of the answers of the 6 digit number

some others are:

275732

375733

475734

575735

675735

775734

875732

The 6-digit number is 175731.

The place value strategies are defined as math strategies that use to assist you in resolving your elementary math problems, use your places values, such as tens and hundreds. It is possible to employ enlarged notation or compensation. Using regrouping techniques, you can make the problem easier by compensating for addition.

Let the number would be ABCDEF

Given the condition that the value of its thousands of digits is 5,000.

So C = 5

Given the condition that the value of its hundreds of digits is 700.

So D = 7

Given the condition that Its tens digit is 2 less than the thousand digits.

So E = 5-2 = 3

Given the condition that Its hundred thousand digits is the same as the hundred digits.

So B = 7

Therefore, all possible answers:

275732

375733

475734

575735

675735

775734

875732

Hence, the 6-digit number is 175731

Learn more about the place value strategy here:

brainly.com/question/654419

#SPJ2

Answer:

[tex] \sin(θ) = \frac{19}{41} \\ θ = 27.6 \\ θ = 28[/tex]

Answer:

73.5 Percent ...........

Answer:

The closest percentage of shots you made is 75%. Please mark brainliest.

I believe the choices are:

60%

70%

75%

80%

Therefore the answer 75%

Step-by-step explanation:

59/80 = 0.7375

Rounded up is 0.75

0.75 x 100 = 75%

Hope this helps.

Have a nice day amazing person there.

MAY GOD RICHLY BLESS YOU!!

Answer:

I say Its letter d

Step-by-step explanation:

I hope this help

Answer:

-290

Step-by-step explanation:

(-260) +(-30)

=-260-30

=-290

Answer:

the answer is -290

Step-by-step explanation:

it is telling us to add so we can see that both the numbers have the same sign which is negative

when the signs are all the same, we can add and we got -290

Answer:

x = -2

Step-by-step explanation:

the line goes through -2 on the x-axis

the line also goes through -3 on the y-axis

9514 1404 393

Answer:

  a) 16A -4B +C = 1

  b) 4A -2B +C = 0.94

  c) C = 1

Step-by-step explanation:

Substitute the x- and y-values into the general form equation.

a. A(-4)² +B(-4) +C = 1

  16A -4B +C = 1

__

b. A(-2)² +B(-2) +C = 0.94

  4A -2B +C = 0.94

__

c. A(0)² +B(0) +C = 1

  C = 1

_____

Additional comment

Solving these equations gives A=0.015, B=0.06, C=1. The quadratic is ...

  0.015x² +0.06x +1 = y

Answer:

Step-by-step explanation:

Answer:

340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.

Step-by-step explanation:

Given that a car rental agency rents 480 cars per day at a rate of $ 20 per day, and for each $ 1 increase in rate, 10 fewer cars are rented, to determine at what rate should the cars be rented to produce the maximum income and what is the maximum income, the following calculations must be performed:

480 x 20 = 9600

400 x 28 = 11200

350 x 33 = 11550

300 x 38 = 11400

310 x 37 = 11470

320 x 36 = 11520

330 x 35 = 11550

340 x 34 = 11560

Therefore, 340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.

Answer:

The margin of error for a 90% confidence interval for the mean banking fee is of $0.44.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Sample of 31:

This means that [tex]n = 31[/tex]

Assume the population standard deviation is $1.50.

This means that [tex]\sigma = 1.5[/tex]

Calculate the margin of error for a 90% confidence interval for the mean banking fee.

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]M = 1.645\frac{1.5}{\sqrt{31}}[/tex]

[tex]M = 0.44[/tex]

The margin of error for a 90% confidence interval for the mean banking fee is of $0.44.

Answer:

[tex]125 \: \: degrees[/tex]

Step-by-step explanation:

As the 2 lines are parallel

<A = <B ( Alternative Angles)

[tex]6x + 5 = 4x + 45 \\ 6x - 4x = 45 - 5 \\ 2x = 40 \\ x = 20[/tex]

[tex]<A = 6x + 5 \\ = 6 \times 20 + 5 \\ = 120 + 5 \\ = 125[/tex]

<A=6x+5

=6×20+5

=120+5

=125

<B=4x+45

=4×20+45

=80+45

=125

it is alternate angle they are equal each other

<A = < B

[tex]6x + 5 = 4x + 45 \\ 6x - 4x = 45 - 5 \\ 2x = 40 \\ x = \frac{40}{2} \\ x = 20 \\ \\ [/tex]

Answer:

U={-2,-1,0,1,2,3,4,5,6,7,8}

Let missing side be x

Using basic proportionality theorem

[tex]\\ \sf\longmapsto \dfrac{18}{14}=\dfrac{27}{x}[/tex]

[tex]\\ \sf\longmapsto \dfrac{9}{7}=\dfrac{27}{x}[/tex]

[tex]\\ \sf\longmapsto 9x=7(27)[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{7(27)}{9}[/tex]

[tex]\\ \sf\longmapsto x=21[/tex]

Answer: Hello your question is poorly written attached below is the complete question

answer:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

Step-by-step explanation:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

attached below is the detailed solution using LU factorization

Answer:

a) 0.5768 = 57.68% probability that the shop sells at least 3 in a week.

b) 0.988 = 98.8% probability that the shop sells at most 7 in a week.

c) 0.0104 = 1.04% probability that the shop sells more than 20 in a month.

Step-by-step explanation:

For questions a and b, the Poisson distribution is used, while for question c, the normal approximation is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}[/tex]

In which

x is the number of successes

e = 2.71828 is the Euler number

[tex]\lambda[/tex] is the mean in the given interval.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Poisson distribution can be approximated to the normal with [tex]\mu = \lambda, \sigma = \sqrt{\lambda}[/tex], if [tex]\lambda>10[/tex].

Poisson variable with the mean 3

This means that [tex]\lambda= 3[/tex].

(a) At least 3 in a week.

This is [tex]P(X \geq 3)[/tex]. So

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

Then

[tex]P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498[/tex]

[tex]P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240[/tex]

So

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0498 + 0.1494 + 0.2240 = 0.4232[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 1 - 0.4232 = 0.5768[/tex]

0.5768 = 57.68% probability that the shop sells at least 3 in a week.

(b) At most 7 in a week.

This is:

[tex]P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498[/tex]

[tex]P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240[/tex]

[tex]P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240[/tex]

[tex]P(X = 4) = \frac{e^{-3}*3^{4}}{(4)!} = 0.1680[/tex]

[tex]P(X = 5) = \frac{e^{-3}*3^{5}}{(5)!} = 0.1008[/tex]

[tex]P(X = 6) = \frac{e^{-3}*3^{6}}{(6)!} = 0.0504[/tex]

[tex]P(X = 7) = \frac{e^{-3}*3^{7}}{(7)!} = 0.0216[/tex]

Then

[tex]P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.0498 + 0.1494 + 0.2240 + 0.2240 + 0.1680 + 0.1008 + 0.0504 + 0.0216 = 0.988[/tex]

0.988 = 98.8% probability that the shop sells at most 7 in a week.

(c) More than 20 in a month (4 weeks).

4 weeks, so:

[tex]\mu = \lambda = 4(3) = 12[/tex]

[tex]\sigma = \sqrt{\lambda} = \sqrt{12}[/tex]

The probability, using continuity correction, is P(X > 20 + 0.5) = P(X > 20.5), which is 1 subtracted by the p-value of Z when X = 20.5.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{20 - 12}{\sqrt{12}}[/tex]

[tex]Z = 2.31[/tex]

[tex]Z = 2.31[/tex] has a p-value of 0.9896.

1 - 0.9896 = 0.0104

0.0104 = 1.04% probability that the shop sells more than 20 in a month.

The probability of the selling the video recorders for considered cases are:

Let X ~ Pois(λ)

Then we have:

E(X) = λ = Var(X)

Since standard deviation is square root (positive) of variance,

Thus,

Standard deviation of X = [tex]\sqrt{\lambda}[/tex]

Its probability function is given by

f(k; λ) = Pr(X = k) = [tex]\dfrac{\lambda^{k}e^{-\lambda}}{k!}[/tex]

For this case, let we have:

X = the number of weekly demand of video recorder for the considered shop.

Then, by the given data, we have:

X ~ Pois(λ=3)

Evaluating each event's probability:

Case 1: At least 3 in a week.

[tex]P(X > 3) = 1- P(X \leq 2) = \sum_{i=0}^{2}P(X=i) = \sum_{i=0}^{2} \dfrac{3^ie^{-3}}{i!}\\\\P(X > 3) = 1 - e^{-3} \times \left( 1 + 3 + 9/2\right) \approx 1 - 0.4232 = 0.5768[/tex]

Case 2: At most 7 in a week.

[tex]P(X \leq 7) = \sum_{i=0}^{7}P(X=i) = \sum_{i=0}^{7} \dfrac{3^ie^{-3}}{i!}\\\\P(X \leq 7) = e^{-3} \times \left( 1 + 3 + 9/2 + 27/6 + 81/24 + 243/120 + 729/720 + 2187/5040\right)\\\\P(X \leq 7) \approx 0.9881[/tex]

Case 3: More than 20 in a month(4 weeks)

That means more than 5 in a week on average.

[tex]P(X > 5) = 1- P(X \leq 5) =\sum_{i=0}^{5}P(X=i) = \sum_{i=0}^{5} \dfrac{3^ie^{-3}}{i!}\\\\P(X > 5) = 1- e^{-3}( 1 + 3 + 9/2 + 27/6 + 81/24 + 243/120)\\\\P(X > 5) \approx 1 - 0.9161 \\ P(X > 5) \approx 0.0839[/tex]

Thus, the probability of the selling the video recorders for considered cases are:

Learn more about poisson distribution here:

https://brainly.com/question/7879375

Answer:

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Step-by-step explanation:

The point estimate is the sample proportion.

Sample proportion:

103 out of 249, so:

[tex]p = \frac{103}{249} = 0.4137[/tex]

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Answer:

x = 2

Step-by-step explanation:

→ Simplify

x × ( 9 ) = 10 + 8

→ Further simplify

9x = 18

→ Divide both sides by 9

x = 2

Answer:

11.75

Step-by-step explanation:

The required triangle is attached below :

The triangle AFE has it's by the mid segment as BD ;as B is the mid-point of line EA ; and D is the mid-point of line FA ;

HENCE, The Length of the midsegment BD = 1/2FE

Hence, BD =. 1/2 * 23.5

BD = 23.5 / 2 = 11.75

Answer:

Translation 2 units to the right

Vertical stretch by a factor of 3

Translation 1 unit up

Step-by-step explanation:

Correct on plato :}

Answer:

$25.80

Step-by-step explanation:

First, let's find the cost of one bag of chip:

10.32/8 = 1.29

If one bag costs $1.29, simply multiply the number of bags (20) by 1.29

1.29 x 20 = 25.80

               = $25.80

Answer:

25.80

Step-by-step explanation:

We can use a ratio to solve

8 bags             20 bags

-------------   = ----------------

10.32               x dollars

Using cross products

8x = 10.32 * 20

8x =206.40

Divide each side by 8

8x/7 = 206.40/8

x =25.80