question 3 chemistry help

Answer:

By definition, electrical conductivity is a measure of how well electrical current (charge in motion) can pass through a material under the influence of an applied voltage/electric field. Thermal conductivity measures how well heat (thermal energy in motion) can pass through a material under a temperature differential.

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Answer:

HCl is a polar covalent compound, because of electronegativity difference between Cl(3.5) and hydrogen (2). Hence in this way, the bond between HCl breaks and they formed ions in the polar solvent like water .

Answer: Your answer is false.

Explanation

Most of the world's plants are flowering plants called angiosperms (from the Greek words for “vessel” and “seed”), there are hundreds of plants that do not make flowers.

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Answer: A. ( VO2)

Explanation:

Answer:

B) VO

Vanadium(II) oxide is the inorganic compound with the idealized formula VO.

Using Gay Lussac's Law

[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{30}{27}=\dfrac{90}{T_1}[/tex]

[tex]\\ \sf\longmapsto T_1=\dfrac{90\times 27}{30}[/tex]

[tex]\\ \sf\longmapsto T_1=81°C[/tex]

Gay Lussac's Law:-

It states that at constant volume (V),The pressure(P) of fixed amount of gas caries directly with its absolute temperature(T).

[tex]\\ \sf\longmapsto P\propto T[/tex]

[tex]\\ \sf\longmapsto \dfrac{P}{T}=Constant[/tex]

[tex]\\ \sf\longmapsto \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

[tex]\\ \sf\longmapsto P_1T_2=P_2T_1[/tex]

The final temperature of the gases with 90 lbs/in² is equal to 627°C assuming the volume is constant.

Gay-Lussac's law can be described as if the volume (V) of the gas remains constant then the pressure (P) is directly proportional to the absolute temperature (T) of the gas.

Gay Lussca's law in mathematical expression can be represented as:

P/T = k

It can be also represented as the pressure (P) being directly proportional to the temperature (T).

P ∝ T                            ( V of gas is constant)

or,    P₁/T₁ = P₂/T₂

Given, the initial temperature of the gas, T₁ = 27°C = 27 + 273 = 300 K

The initial pressure of the gas, P₁ = 30 lbs/in²

The final pressure of the gas,  P₂ = 90 lbs/in²

The final temperature of the gases in a hair spray can be determined as:

[tex]{\displaystyle \frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]

[tex]{\displaystyle T_2 =\frac{P_2\times T_1}{P_1}[/tex]

[tex]{\displaystyle T_2 =\frac{90\times 300}{30}[/tex]

T₂ = 900 K = 900 - 273

T₂ = 627°C

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Answer:

1. Ionic compounds have high melting points.

Ionic compounds have high melting points.2 Ionic compounds are hard and brittle.

Ionic compounds have high melting points.2 Ionic compounds are hard and brittle.3 Ionic compounds dissociate into ions when dissolved in water.

Answer:

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Explanation:

Discovery of Electron—Discharge Tube Experiment

In 1879, William Crooks studied the conduction of electricity through gases at low pressure. He performed the experiment in a discharge tube which is a cylindrical hard glass tube about 60 cm in length. It is sealed at both the ends and fitted with two metal electrodes as shown in Fig. 2.1.

The electrical discharge through the gases could be observed only at very low pressures and at very high voltages.

The pressure of different gases could be adjusted by evacuation. When sufficiently high voltage is applied across the electrodes, current starts flowing through a stream of particles moving in the tube from the negative electrode (cathode) to the positive electrode (anode). These were called cathode rays or cathode ray particles.

• Properties of Cathode Rays

(i) Cathode rays travel in straight line.

(ii) Cathode rays start from cathode and move towards the anode.

(iii) These rays themselves are not visible but their behaviour can be observed with the help of certain kind of materials (fluorescent or phosphorescent) which glow when hit by them.

(iv) Cathode rays consist of negatively charged particles. When electric field is applied on the cathode rays with the help of a pair of metal plates, these are found to be deflected towards the positive plate indicating the presence of negative charge.

(v) The characteristics of cathode rays do not depend upon the material of electrodes and the nature of gas present in the cathode ray’tube.

• Determination of Charge/Mass (elm) Ratio for Electrons

J. J. Thomson for the first time experimentally determined charge/mass ratio called elm ratio for the electrons. For this, he subjected the beam of electrons released in the discharge tube as cathode rays to influence the electric and magnetic fields. These were acting perpendicular to one another as well as to the path followed by electrons.

According to Thomson, the amount of deviation of the particles from their path in presence of electrical and magnetic field depends upon following factors:

(i) Greater the magnitude of the charge on the particle, greater is the interaction with the electric or magnetic field and thus greater is the deflection.

(ii) The mass of the particle — lighter the particle, greater the deflection.

(iii) The deflection of electrons from their original path increases with the increase in the voltage across the electrodes or strength of the magnetic field.

By carrying out accurate measurements on the amount of deflections observed by the electrons on the electric field strength or magnetic field strength, Thomson was able to determine the value of

e/me = 1.758820 x 1011 C kg-1 where me = Mass of the electron in kg

e = magnitude of charge on the electron in coulomb (C).

• Charge on the Electron

R.A. Millikan devised a method known as oil drop experiment to determine the charge on the electrons.

• Discovery of Proton—Anode Rays

In 1886, Goldstein modified the discharge tube by using a perforated cathode. On reducing the pressure, he observed a new type of luminous rays passing through the holes or perforations of the cathode and moving in a direction opposite to the cathode rays. These rays were named as positive rays or anode rays or as canal rays. Anode rays are not emitted from the anode but from a space between anode and cathode.

• Properties of Anode Rays

(i) The value of positive charge (e) on the particles constituting anode rays depends upon the nature of the gas in the discharge tube.

(ii) The charge to mass ratio of the particles is found to depend on the gas from which these originate.

(iii) Some of the positively charged particles carry a multiple of the fundamental unit of electrical charge.

(iv) The behaviour of these particles in the magnetic or electric field is opposite to that observed for electron or cathode rays.

• Proton

The smallest and lightest positive ion was obtained from hydrogen and was called proton. Mass of proton = 1.676 x 10-27 kg

Charge on a proton = (+) 1.602 x 10-19 C

• Neutron

It is a neutral particle. It was discovered by Chadwick (1932).

By the bombardment of thin sheets of beryllium with fast moving a-particles he observed • that highly penetrating rays consist of neutral particles which were named neutrons.

• Thomson Model of Atom

Answer:

I think no b

Explanation:

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CHF3

Oxygen gas O2 is a compound, a molecule and a pure substance.

Oxygen gas is a compound because it contains more than one atom( two oxygen atoms) that are chemically combined together.

Oxygen gas is a molecule because it can exist independently as a unit and the oxygen atoms are covalently bound.

It is a pure substance because it contains only oxygen molecules.

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Answer:

carbon monoxide is strong reducing agent.carbon monoxide used in the extraction of pure metals of their ores.

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Answer:

It's about mass of 40.1⋅g

Explanation:

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Answer:

NO3 will produce 2 acids

Answer:

About bonding

Explanation:

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bond.

Answer:

An ionic bond occurs between sodium and chlorine where sodium has one  electron while chlorine has seven electrons. The electron from sodium is lost and transferred to a chlorine atom which results in a sodium ion with a charge of one+ and a chloride ion with a charge of one-. These oppositely charged ions attract each other making a balanced charge to make a compound that is electrically neutral.. Sodium cation (Na+) and chlorine anion (Cl-) are attracted to each another to form sodium chloride (table salt). When dissolved in water, the sodium and chloride ions are strongly attracted to the polar water molecules because of ion-dipole interactions.  

Explanation:

Answer: lithium- 3 protons, 3 electrons, 3 neutrons

Oxygen- nucleon no. 16, Atomic no. 8, 8 protons, overall charge (-2)

Sorry I don't the others. Hope this helps

Answer:

the atomic number decreased in 2, from 100 to 100 - 2 = 98. 3) Hence the formed atom has atomic number 98, which is californium, Cf, and the isotope is californium - 253. 4) The item that completes the given alpha decay reaction is: ₉₈²⁵³ Cf.

Explanation:

Solution :

Cd(s) ---------------------->  [tex]Cd^{+2}[/tex] (aq) + 2[tex]e^-[/tex]      ,     [tex]E_0[/tex]  =   0.34 v

[tex]Cu^{+2}[/tex]  (aq)  +   2[tex]e^-[/tex]  ------------> Cu (s)             ,     [tex]E_0[/tex]  =  -0.04 v

----------------------------------------------------------------------------------------------

Cd(s)  +  [tex]Cu^{+2}[/tex]  (aq)  ------------->  [tex]Cd^{+2}[/tex] (aq)  +  Cu (s)   ,      [tex]E_0[/tex]  =  0.30 v  

The cell potential is defined as the measure of [tex]\text{ potential difference }[/tex]  between the [tex]\text{two half cells}[/tex] of an electrochemical cell.  

Answer:

Molarity is 0.08 M

Explanation:

Molarity is the number of moles in 1 litre of solution.

[tex]{ \tt{6 \: litres \: = \: 0.478 \: moles}} \\ { \tt{1 \: litre = ( \frac{1}{6} \times 0.478) \: moles}} \\ \\ { \tt{molarity = 0.08 \: mol \: {l}^{ - 1} }}[/tex]

[tex]{ \underline{ \sf{ \blue{christ \: † \: alone}}}}[/tex]

Answer:

I would have to say More than 40 years

Answer:

rise in temperature and the effect it has on our global weather patterns

ANSWER

a. actual yield

Explanation:

The amount of product generated by a chemical reaction is its actual yield. This yield is often less than the amount of product predicted by the stoichiometry of the balanced chemical equation representing the reaction (its theoretical yield).

Answer:

Each component in a mixture contributes a fraction to the total number of moles in the mixture. This fraction is called the _mole_ fraction of the component. In a mixture of gases, this fraction is proportional to the _mole_ pressure for each gas present.

Answer:

its C

Explanation:

Answer:

what is cell wall?

A cell wall is a layer located outside the cell membrane found in plants, fungi, bacteria, algae, and archaea

where is it found

They are found in bacteria, archaea, fungi, plants, and algae.

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Answer:

The cell wall is the protective, semi-permeable outer layer of a plant cell. A cell wall is a fairly rigid layer surrounding a cell located outside of the plasma membrane that provides additional support and protection.

Answer: D

Explanation:

Answer:

Atomic number ---> number of protons in the nucleus of an atom

Atomic mass ----> the total mass of protons, neutrons, and electrons in an atom

Answer: Qualitative data typically consists of words while quantitative data consists of numbers.

Explanation:

Answer:

32.4°C

Explanation:

Consider the following expression:

P•V/T =P'•V'/T'

Where P and P' are respectively the initial and the final pressure, V and V's are respectively initial and final volume, and T and T' are respectively initial and final temperature.

We know that the pressure cannot change, so it means that P = P'

We also know that the volume must be increased in 20%, and if we multiply the volume by 1.2 is like increase it in 20%, so we can write that V' = 1.2•V, and changing a little more we can write that V'/V = 1.2

So let's do some maths:

P•V/T = P'•V'/T'

T'•P•V/T = P'•V'

T'•P•V = P'•V'•T

T'=P'•V'•T/P•V

We know that P'=P so the division is equal to 1:

T'= 1•V'•T/V

We also know that V'/V = 1.2, so:

T' = 1.2•T

And we know the value of T, it's 27, so now we just have to solve it:

T' = 1.2•27

T' = 32.4°C