Answers
Answer:
HCN+CuSO4->H2SO4+Cu(CN)2
2,1,1,1
1.Add 2 to HCN it then becomes (H=2, C=2, N=2,) (had to add 2 cz on right side you had H2 in H2SO4)
2.1(nothing) cz on both sides we got 1Cu and 1SO4
3.1 cz again we have H2 on both sides and 1SO4 on both sides
4.1 cz we got 1Cu on both sides and 2C 2N on both sides (1st step)
Related Questions
An astronaut has a mass of 80kg how much mass does he weigh in Mars
Answers
Answer:
26.66kg
Explanation:
If a person has a mass of 80kg, then they will weigh 80kg x 9.8m/s^2 or 784 Newtons on the Earth. That same person would weigh 80kg x 9.8m/s^2/3 or 261.33 Newtons on Mars, which the person might think was 26.66 Kg (although he would be incorrect since his mass has not changed).
What is the molar mass of an unknown gas with a density of 2.00 g/L at 1.00 atm and 25.0 °C?
Answers
Answer:
48.9 g/mol
Explanation:
n=(atm x v)/(.08206 x 298)
The molar mass of the gas 49.0 g/mol.
Given:
Unknown gas with a density of 2.00 g/L at 1.00 atm and 25.0 °C.
To find:
The molar mass of an unknown gas.
Solution:
The mass of gas = m
The volume of the gas =V
The molar mass of the gas = M
The density of the gas = d = 2.00 g/L
[tex]d=\frac{m}{V}[/tex]
The pressure of the gas = P
The temperature of the gas T = 25.0 °C = 25.0+273.15 K=298.15 K
The ideal gas equation:
[tex]PV=nRT\\\\PV=\frac{\text{Mass of gas(m)}}{\text{Molar mass of gas(M)}}RT\\\\PM=\frac{m}{V}RT \\\\PM=dRT\\\\1 atm\times M=2.00 g/L\times 0.0821 atm L/molK\times 298.15 K\\\\M=\frac{2.00 g/L\times 0.0821 atm L/molK\times 298.15 K}{1 atm}\\\\M=48.96 g/mol \approx 49.0 g/mol[/tex]
The molar mass of the gas 49.0 g/mol.
Learn more about an ideal gas equation here:
brainly.com/question/1056445?referrer=searchResults
