PLS HELP ME ON THIS ANSWER I WILL MARK YOU AS BRAINLIEST IF YOU KNOW TGE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Answer:

vertex of 4 is 2

Step-by-step explanation:

cuh cuh uchuch uch uch uch

Answer:

-5, 2

Step-by-step explanation:

Answer:

-9/2 < x < -3/5

Step-by-step explanation:

So first, we take the left part of the inequality to solve and ignore the right part for now, which leaves us 6x + 3 < x.

1. Subtract 3 from both sides:

6x < x - 3

2. subtract x from both sides:

5x < -3

3. divide 5 from both sides:

x < -3/5

Then, we do the same thing as part 1, but this time with x < 3x + 9.

1. Subtract 9 from both sides:

x - 9 < 3x

2. subtract x from both sides:

-9 < 2x

3. divide both sides by 2:

-9/2 < x.

Notice how we have a value that x is less than and a value that x is greater than. So now, all we have to do is to put the two inequalities together, leaving only one x in the middle. Hence, -9/2 < x < -3/5.

I hope this helped! :D

[tex]\\ \sf\longmapsto 6x + 3 < x < 3x + 9 \\ \\ \sf\longmapsto 6x - 3x < x < 9 - 3 \\ \\ \sf\longmapsto 3x < x < 6 \\ \\ \sf\longmapsto x < \frac{x}{3} < 2[/tex]

[tex]\\ \sf\longmapsto 4\left(-5\dfrac{2}{3}\right)[/tex]

[tex]\\ \sf\longmapsto 4\left(-\dfrac{5(3)-2}{3}\right)[/tex]

[tex]\\ \sf\longmapsto 4\left(-\dfrac{17}{3}\right)[/tex].

[tex]\\ \sf\longmapsto \dfrac{-68}{3}[/tex]

70% - Rounded Answer

Here we need to use what we know about rectangles to make a system of equations.

By solving that system we found that the tile has a length of 36 inches and a width of 21 inches.

Remember that for a rectangle of length L and width W, the perimeter is:

P = 2*(L + W)

And the area is:

A = W*L

Here we know that the perimeter is 114 inches, then we can write:

114in = 2*(L + W)

We also know that the area is 756 in^2, then we can write:

756 in^2 = L*W

So we found two equations, which means that we have a system of two equations with two variables:

114in = 2*(L + W)

756 in^2 = L*W

To solve this, the first step is to isolate one of the variables in one of the equations, we can isolate L in the first equation:

114in = 2*(L + W)

114in/2 = (L + W)

57in = L + W

57in - W = L

Now that we have an expression equivalent to L, we can replace it in the other equation to get:

756 in^2 = L*W

756 in^2 = (57in - W)*W

Now we can solve this for W.

756 in^2 = W*57in - W^2

W^2 - W*57in + 756 in^2 = 0

The solutions are given by the Bhaskara's formula:

[tex]W = \frac{57in \pm \sqrt{(-57in)^2 - 4*1*(756in^2)} }{2*1} = \frac{57in \pm 15in}{2}[/tex]

Then the two possible values of the width will be:

W = (57in + 15in)/2 =  36 in

W = (57in - 15in)/2 = 21 in

Suppose that we choose the second solution, W = 21in

Now using the equation 57in - W = L we can find the value of L

L = 57in - W = 57in - 21in = 36in

L = 36in

Then we found that the tile has a length of 36 inches and a width of 21 inches.

If you want to learn more, you can read:

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Answer:

D. [tex]\frac{9x^2+14}{18x}[/tex]

Step-by-step explanation:

Find the common denominator, 18x.

Simplify.

Add.

I hope this helps!

Answer: D

Step-by-step explanation:

Common denominator 18x

18x/2=9x.

(9x)(x) = 9x^2

18x/9x=2

(2)(7)=14

(9x^2+14)/18x

Answer:

a) attached below

b) Ic3 = Ic2 + Ic1 + index of a fixed point in ( C°₁ U C°₂ )^c n c₃

Step-by-step explanation:

A) sketch of the arrangement of the cycles

attached below

b) prove that at least one fixed point in the attached region is bounded

Given that : Ic3 = Ic2 = Ic1 = 1

hence : Ic3 = Ic2 + Ic1 + index of a fixed point in ( C°₁ U C°₂ )^c n c₃

This is a prove that at least one fixed point is bounded by C1 , C2 , C3

Hey there! I'm happy to help!

So we want to see which of these have the greatest value. Since these are all negative numbers, we want the one that is closest to zero.

So, we know that -1000 is going to furthest from 0. -10 will be further than -8 since it is a larger negative number, so it will be more negative than -8.

-1/2 is just barely negative, so it is going to be closer to -0 than -8, so the correct answer is C. -1/2.

Have a wonderful day and keep on learning! :D

Answer:

i think it is true

Step-by-step explanation:

Step-by-step explanation:

the correct answer is option c

Answer:

Step-by-step explanation:

Area of rectangle: l×b

Length = 72mm

= 7.2cm

Breadth = 65mm

= 6.5cm

(We know that 10mm = 1cm)

Area = 7.2×6.5

= 46.8cm²

The area of the rectangle is 46.8cm²

Must click thanks and mark brainliest

Answer:

area of a rectangle is (l×w)

Step-by-step explanation:

1cm=10mm

hb65mm

1cm×65mm

allover10mm

=6.5cm

do the same to 72mm to get 7.2cm

you then say 6.5cm×7.2cm

=46.8cm2

hope this helps

Answer:

[tex]BC=40[/tex]

Step-by-step explanation:

Since AC is a tangent and PB is the raduis

[tex]\angle PBC= 9[/tex]

By pythagoras

[tex]PC^{2} =PB^{2} +BC^{2}[/tex]

[tex]41^{2} =9^{2} +BC^{2}[/tex]

[tex]1681-81=BC^{2}[/tex]

[tex]1600=BC^{2}[/tex]

[tex]BC=\sqrt{1600}[/tex]

[tex]BC=40[/tex]

OAmalOHopeO

Answer:

40

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius intersection by definition. That makes BPC a right triangle at B.  BP and PD are both equal (9) because every radius of a circle is equal.  So

PC**2 = BP**2 + BC**2   or

41**2 = 9**2 + BC**2

1681 = 81 + BC**2

1681 - 81 = BC**2

1600 = BC**2

40 = BC

⇒x (x+2) + x + 2

⇒x² + 2x + x + 2

⇒x² + 3x + 2

☛ By Splitting the middle term method

⇒x² + 3x + 2

⇒x² + 2x + x + 2

⇒ x(x+2)+1(x+2)

⇒ (x+1) (x+2)

The ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is 1: 5. Hence option C is true.

Given that;

The students in Shawn's class got to choose whether to visit the zoo or the aquarium.

Here, 3 students went to the zoo and 15 students went to the aquarium.

Hence, the ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is,

Ratio = 3 : 15

Ratio = 3/15

Ratio = 1/5

Ratio = 1 : 5

Thus, option C is true.

Learn more about the ratio visit:

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Answer: C. 6x+18

Step-by-step explanation:

Use the distributive property

First multiply 6 times x which is 6x

Then multiply 6 times 3 which is 18

Keep the sign the same

Therefore, this should give you 6x+18

Part (a)

This is the empty set

------------------

Explanation:

It doesn't matter what set A is composed of. Intersecting any set with the empty set Ø will always result in the empty set.

This is because we're asking the question: "What does some set A and the empty set have in common?". The answer of course being "nothing" because there's nothing in Ø. Not even the value zero is in this set.

We can write Ø as { } which is a set of curly braces with nothing inside it.

=========================================================

Part (b)

-----------------

Explanation:

When you union the universal set with any other set, you'll get the universal set.

The rule is [tex]A \cup B = B[/tex] where I've made B the universal set to avoid confusion of the letter U and the union symbol [tex]\cup[/tex] which looks nearly identical.

Why does this rule work? Well if an item is in set [tex]\overline{A}[/tex], then it's automatically in set U (everything is in set U; it's the universe). So we're not adding anything to the universe when applying a union involving this largest set.

It's like saying

we can see that [tex]\overline{A} \cup U[/tex] will basically form the set of every item, aka the universal set.

Perimeter of square = Perimeter of rectangle

=> 4(side) = 2(length + width)

=> 4(x+5) = 2[(x+3)+(x+7)]

=> 4(x+5) = 2[x+3+x+7]

=> 4x + 20 = 2x + 6 + 2x + 14

=> 4x + 20 = 4x + 20

=> 4x - 4x + 20 = 20

=> 20 = 20

So, any real number is the solution of this equation. It means that for every real number as x, the perimeter of the square will be same as the perimeter of the rectangle.

268 cm^2

Step-by-step explanation:

Find the SA of the purple rectangular prism:

LEFT FACE EXCLUDED

Front: (6)(2) = 12 cm^2

Back: 12 cm^2

Top: (7)(2) = 14 cm^2

Bottom: 14 cm^2

Right: (7)(6) = 42 cm^2

TOTAL: 94 cm^2

SA of the pink triangular prism:

RIGHT FACE EXCLUDED

Front: (1/2)(6)(8) = 24 cm^2

Back: 24 cm^2

Bottom: (7)(8) = 56 cm^2

Left: (10)(7) = 70 cm^2

TOTAL: 174 cm^2

Add both SAs of figures:

174 + 94 = 268 cm^2

Answer:

4.75t + 7.50b = 790

b = 2t

Step-by-step explanation:

Let t represent the number of tacos that he sold, and let b represent the number of burritos he sold.

4.75t can represent how much money he earned from selling tacos, and 7.50b can represent how much money he earned from selling burritos.

Create an equation that adds these together and sets them equal to 790:

4.75t + 7.50b = 790

Next, create another equation that represents how there were twice as many burritos sold than tacos.

This can be represented by b = 2t.

The system of equations is:

4.75t + 7.50b = 790

b = 2t

Answer:

The law of demand says that at higher prices, buyers will demand less of an economic good. The law of supply says that at higher prices, sellers will supply more of an economic good. These two laws interact to determine the actual market prices and volume of goods that are traded on a market.

Supply is generally considered to slope upward: as the price rises, suppliers are willing to produce more. Demand is generally considered to slope downward: at higher prices, consumers buy less. ... The relationship between the supply and demand for a good (or service) and changes in price is called elasticity.

Answer:

9 dam

Step-by-step explanation:

1 km = 100 dam

0.09 km = 0.09 × 100

              = 9 dam

∴ 0.09 km = 9 dam

g = -3,5

8 - |2g - 5| = 8 - |2 · (-3,5) - 5| =

= 8 - |-7 - 5| = 8 - |-12| = 8 - 12 = -4

Answer:

1. B,D

2. D

3. C

4. J

Step-by-step explanation:

Answer:

120 $12 tickets and 180 $15 tickets

Step-by-step explanation:

Given the 2 equations

12x + 15y = 4140 → (1)

x + y = 300 ( subtract y from both sides )

x = 300 - y → (2)

Substitute x = 300 - y into (1)

12(300 - y) + 15y = 4140 ← distribute and simplify left side

3600 - 12y + 15y = 4140

3600 + 3y = 4140 ( subtract 3600 from both sides )

3y = 540 ( divide both sides by 3 )

y = 180

Substitute y = 180 into (2)

x = 300 - 180 = 120

Number of $12 tickets : 120 ; Number of $15 tickets : 180

Answer:

Sample

Step-by-step explanation:

A sample refers to a small subset of a particular population of study. The sample must be chos n at random in other to ensure that it is representative of the entire population. In the scenario above, all males in the United States aged 18 - 25 years form the population of interest required for the study. However, due to the fact that it is impractical to include all in the study, then a smaller subset is selected form the population, which is referred to as the sample.

Answer:

a=2

b=-3

c=2

d=0

Step-by-step explanation:

3a+b=3......1

3c-d=6.......2

a-b=5....... 3

a+b+d=2d-1

a+b=2d-d-1

a+b=d-1......4

taking equation 1 and 3 we get,

3a+b =3....... 1

a-b=5

a=5+b

substitute the value of a in equation 1 we get,

3*(5+b)+b=3

15+3b+b=3

4b=3-15

4b=-12

b=-12/4

b=-3

now putting the value of b in equation 3 we get,

a-b=5

a+3=5

a=5-3

a=2

substitute the value of a and b in equation 4 we get,

a+b=d-1

2-3=d-1

-1=d-1

d=-1+1

d=0

substitute the value of d in equation 2 we get,

3c-d=6

3c-0=6

3c=6

c=6/3

c=2

[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]

Now constructing equations

[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]

[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]

[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]

[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]

Adding eq(1) and (2)

[tex]\\ \sf\longmapsto 4a=8[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]

[tex]\\ \bf\longmapsto a=2[/tex]

Put the value in eq(2)

[tex]\\ \sf\longmapsto a-b=5[/tex]

[tex]\\ \sf\longmapsto b=a-5[/tex]

[tex]\\ \sf\longmapsto b=2-5[/tex]

[tex]\\ \bf\longmapsto b=-3[/tex]

put the values in eq(4)

[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]

[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]

[tex]\\ \sf\longmapsto d-1=2d-1[/tex]

[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]

[tex]\\ \sf\longmapsto -d=0[/tex]

[tex]\\ \bf\longmapsto d=0[/tex]

Put the value in eq(3)

[tex]\\ \sf\longmapsto 3c-d=6[/tex]

[tex]\\ \sf\longmapsto 3c-0=6[/tex]

[tex]\\ \sf\longmapsto 3c=6+0[/tex]

[tex]\\ \sf\longmapsto 3c=6[/tex]

[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]

[tex]\\ \sf\longmapsto c=2[/tex]

Answer:

see explanation

Step-by-step explanation:

If 2 angles and the included side of one triangle are congruent to 2 angles and the included side of another triangle, then the triangles are congruent.

NQ is an angle bisector then ∠ MNQ = ∠ PNQ

∠ M = ∠ N , so the triangle is isosceles with 2 equal legs, then

MN = PN

----------------------------------------------

∠ MNQ = ∠ PNQ

MN = PN ( included sides between the 2 angles )

∠ M = ∠ N

Δ MNQ ≅ Δ PNQ by the ASA postulate

Answer:

Step-by-step explanation:

In Δ MNP,

∠NMQ ≅ ∠NPQ

⇒ NM = NP - ------> (I)     {Sides opposite to equal angles are equal}

In ΔMNQ & ΔPNQ,

∠MNQ  ≅ ∠PNQ             {NQ is angle bisector}

NM  = NP                     {from (I)}

∠NMQ ≅ ∠NPQ           {Given}

ΔMNQ ≅ ΔPNQ          -  Angle Side Angle  {ASA congruent}