Answer:
Step-by-step explanation:
1-399
2 C
3-A 99999
4a
5b
7 b
8 C
9D
10c
what is 3/16 of 200 written as a percentage?
Answer:
Step-by-step explanation:
3/16 = 0.1875
As a % this is 18.75%
18.75/100 * 200 = 37.5
I'm not sure from the question, exactly what you want. 18.75% of 200 is one possibility.
3/16 of 200 as a percentage is 3750%
The question can be represented as:
[tex]\frac{3}{16} * 200[/tex]
Rewrite as:
[tex]\frac{3}{16} * 200 =\frac{3* 200}{16}[/tex]
Multiply the numerator
[tex]\frac{3}{16} * 200 =\frac{600}{16}[/tex]
[tex]\frac{3}{16} * 200 =37.5[/tex]
Multiply by 100% to represent it as a percentage
[tex]\frac{3}{16} * 200 =37.5 * 100\%[/tex]
[tex]\frac{3}{16} * 200 =3750\%[/tex]
Read more at:
https://brainly.com/question/19994306
Flying against the wind, an airplane travels 7760 kilometers in 8 hours. Flying with the wind, the same plane travels 3690 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind
Answer:
1100 and 130 (km/h)
Step-by-step explanation:
1. if the velocity of the wind is 'w' and the velocity of the plane in still air is 'p', then
2. it is possible to make up two equations:
the fly against the wind: (p-w)*8=7760;
the fly with the wind: (p+w)*3=3690.
3. if to solve the system made up, then:
[tex]\left \{ {{3(p+w)=3690} \atop {8(p-w)=7760}} \right. \ => \ \left \{ {{p+w=1230} \atop {p-w=970}} \right. \ => \ \left \{ {{p=1100} \atop {w=130}} \right.[/tex]
4. the required rate of the plane in still air is p=1100 km/h; the rate of the wind is w=130 km/h.
help with 30 please. thanks.
Answer:
See Below.
Step-by-step explanation:
We have the equation:
[tex]\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}[/tex]
And we want to show that:
[tex]\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}[/tex]
Instead of differentiating directly, we can first square both sides:
[tex]\displaystyle y^2 = 3e^{2x} -4x + 1[/tex]
We can find the first derivative through implicit differentiation:
[tex]\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4[/tex]
Hence:
[tex]\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}[/tex]
And we can find the second derivative by using the quotient rule:
[tex]\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}[/tex]
Substitute:
[tex]\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}[/tex]
Simplify:
[tex]\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}[/tex]
Combine fractions:
[tex]\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}[/tex]
Simplify:
[tex]\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}[/tex]
Simplify:
[tex]6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}[/tex]
Q.E.D.
a2 - ab + 8b + b2 - 1
Answer:
а²-ab+8b+b²-1=a(a-b)+b(8+b)-1
Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends on various biomechanical properties of the human nasal periosteum and fascia. An article reported that for a sample of 10 (newly deceased) adults, the mean failure strain (%) was 24.0, and the standard deviation was 3.2.
Required:
a. Assuming a normal distribution for failure strain, estimate true average strain in a way that converys information about precision and reliability.
b. Predict the strain for a single adult in a way that conveys information about precision and reliability. How does the prediction compare to the estimate calculated in part (a)?
Solution :
Given information :
A sample of n = 10 adults
The mean failure was 24 and the standard deviation was 3.2
a). The formula to calculate the 95% confidence interval is given by :
[tex]$\overline x \pm t_{\alpha/2,-1} \times \frac{s}{\sqrt n}$[/tex]
Here, [tex]$t_{\alpha/2,n-1} = t_{0.05/2,10-1}$[/tex]
= 2.145
Substitute the values
[tex]$24 \pm 2.145 \times \frac{3.2}{\sqrt {10}}$[/tex]
(26.17, 21.83)
When the [tex]\text{sampling of the same size}[/tex] is repeated from the [tex]\text{population}[/tex] [tex]n[/tex] infinite number of [tex]\text{times}[/tex], and the [tex]\text{confidence intervals}[/tex] are constructed, then [tex]95\%[/tex] of them contains the [tex]\text{true value of the population mean}[/tex], μ in between [tex](26.17, 21.83)[/tex]
b). The formula to calculate 95% prediction interval is given by :
[tex]$\overline x \pm t_{\alpha/2,-1} \times s \sqrt{1+\frac{1}{n}}$[/tex]
[tex]$24 \pm 2.145 \times 3.2 \sqrt{1+\frac{1}{10}}$[/tex]
(31.13, 16.87)
Find the difference: -18 - (-18)
Answer:
0
Step-by-step explanation:
-18-(-18)
= -18+18 [(+) + (+)=(+)]
=0 [(-) + (-)=(-)]
Which side is the “adjacent” side to θ?
Answer:
third answer "a"
Step-by-step explanation:
find the value of the trigonometric ratio. make sure to simplify the fraction if needed
Answer:
Sin A = o/h
= 9/41
Step-by-step explanation:
since Sin is equal to opposite over hypotenuse, from the question, the opposite angle of A is 9 and hypotenuse angle of A is 41. Thus the answer for Sin A= 9/41
In 10 words or fewer, what is the square root of -9?
Type answer here...
What is the square root of -9
Answer:
no solution
Step-by-step explanation:
a negative number cannot be square rooted
Answer:
"not possible". no such thing as a negative squared number
What is the slope of the line that passes through the points (-9, 8) and (–21, 10)?
Write your answer in simplest form.
Answer:
-1/6
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 10-8)/(-21 - -9)
= ( 10-8)/(-21 +9)
= 2 /-12
= -1/6
anybody willing to help me?
Answer:
The answer is a. [tex] \frac{ \sqrt{w} }{ \sqrt[3]{w} }[/tex]The value of f(x)= 5x -4x²+3 when x= -1, is
Answer:
F(x) =5(-1)-4(-1)^2+3,
=-5-4+3
=-6
Please help 20 points
An adult can lose or gain two pounds of water ina course of a day. Assume that the changes in water weight isuniformly distributed between minus two and plus two pounds in aday. What is the standard deviation of your weight over a day?
Answer:
The standard deviation of your weight over a day is of 1.1547 pounds.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b, and the standard deviation is:
[tex]S = \sqrt{\frac{(b-a)^2}{12}}[/tex]
Assume that the changes in water weight is uniformly distributed between minus two and plus two pounds in a day.
This means that [tex]a = -2, b = 2[/tex]
What is the standard deviation of your weight over a day?
[tex]S = \sqrt{\frac{(2 - (-2))^2}{12}} = \sqrt{\frac{4^2}{12}} = \sqrt{\frac{16}{12}} = 1.1547[/tex]
The standard deviation of your weight over a day is of 1.1547 pounds.
A height of 2.5 cm represents 100 goats. What should be the height for 170 goats?
Answer: 4.25
Step-by-step explanation:
2.5/100 = 0.025
0.025 × 170 = 4.25
but the question there is any goats in 2.5 cm ??
that is impossible
On average, 240 customers arrive at a bank every morning (8AM - noon), but they do so randomly (i.e., not exactly every minute). There is a single line at the bank after which a customer goes to one of the five bank tellers. A bank teller takes on average 3 minutes to help a customer, with a standard deviation of 1.5 minutes. How long does a customer spend in this bank on average?
Every morning there are expected 240 customers who arrive at bank for the customer service.
There are on average 240 customers arriving to the bank every morning.
There are total 5 bank tellers and they take average 3 minutes to help customer.
The average time each bank teller spends on satisfying a customer will be calculated using the linear model,
Using wait time calculator:
Average service time / standard deviation
Ce = 3/1.5 = 2
The spent time on a customer is 3.4 minutes.
Learn more at https://brainly.com/question/24379767
Answer:
Customers spend 3.4 minutes in the bank on average.
Step-by-step explanation:
The customer arrives at the bank every morning. There is a line at bank goes to 5 bank teller. The customer takes 3 minutes with a 1.5-minute standard deviation.
The customer = 240
Time = 3
Where R = (240/4)
=60/hr
Where CVa = 1
What type of function is represented by the following table?
Number of weeks
1 2 3 4 5
Cost of rental car 79,
158,
237,
316,
395
Answer:
Linear
Step-by-step explanation:
cost = 79 * weeks
79*1=79
79*2=158
etc.
A window is to be built in the shape of a rectangle surmounted by an isosceles triangle. The area of the window must be 6 square meters. Use Lagrange Multipliers to find the width and height of the rectangle for which the perimeter of the window will be as small as possible
Answer:
x = 2.536 m
y = 2 m
Step-by-step explanation:
Considering the three sides of the rectangle and the isosceles triangle
when resolving the width and height of the rectangle to achieve the smallest possible perimeter.
step 1 :
Area of window = xy + 1/2 xz , perimeter = x + 2y + 2c
c = [tex]\sqrt{z^2 + 1/4 x^2 }[/tex]
we are tasked with minimizing the perimeter ( p ) subject to A = 6
attached below is the detailed solution of the given problem
Luis was worried about his Spanish final exam grade. The test had 200 questions, and he got
175 of them correct. His sister Marina took her French final exam, and she got 130 out of 150
questions. Who got the better percent score (round to the nearest tenths)?
Answer:
Luis:
[tex] \frac{175}{200} \times 100\% = 87.5\%[/tex]
Marina:
[tex] \frac{130}{150} \times 100\% = 86.6\%[/tex]
Answer: Marina got the better percent score than Luis
Marina:
given the series 1+2+3+4+5+6+...+5000. Write the series in sigma notation if all the powers of 4 are removed from the series.
We have 4⁶ = 4096 and 4⁷ = 16,384, which is to say that the given sum only contains the first six powers of 4.
Now,
[tex]\displaystyle 1+2+3+\cdots+5000 = \sum_{k=1}^{5000}k[/tex]
and you subtract the sum of the first six powers of 4 to get the sum S that you want,
[tex]\displaystyle S = \boxed{\sum_{k=1}^{5000}k - \sum_{k=1}^64^k}[/tex]
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. The article "Properties of Waste Silk Shod Fiber/Cellulose Green Composite Films" (. of Composite Materials, 2012: 123-127) reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.3 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value?
Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) [tex]P-value=0[/tex]
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=10[/tex]
Mean [tex]\=x= 51.3[/tex]
Standard deviation [tex]\sigma=1.2[/tex]
Significance level is taken as [tex]\alpha=0.05[/tex]
t test statistics
[tex]t=8.169[/tex]
Therefore
[tex]P-Value=P(t>8.169)[/tex]
Critical point
[tex]t_{\alpha,df}[/tex]
[tex]\alpha=0.05[/tex]
[tex]df=10-1=>9[/tex]
Therefore
P-value from T distribution table
[tex]P-value=0[/tex]
Conclusion
[tex]P-value (0)< \alpha(0.05)[/tex]
We Reject the Null Hypothesis [tex]H_0[/tex]
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Find the slope of the line
Slope=m=_____
Answer:
4
Step-by-step explanation:
Slope = y2-y1/x2-x1
We need to find two points on the graph, let's take these two points:
(x1, y1) (X2,y2)
(0,-6) and (2,2)
(2-(-6)/ (2-0) = 8/2 = 4
Answered by Gauthmath
-9x - 5 = 67
Pls help me
Answer:
x = -8
Step-by-step explanation:
-9x = 67+ 5
x = 72/-9
x = -8
Answer:
x=-8
Step-by-step explanation:
A bag of M&M's has 6 red, 5 green, 4 blue, and 8 yellow M&M's. What is the probability of randomly picking: (give answer as a reduced fraction) 1) a yellow? w 2) a blue or green? 3) an orange?
Answer:
P( yellow) = 8/23
P( blue or green) = 9/23
P(orange) = 0
Step-by-step explanation:
6 red, 5 green, 4 blue, and 8 yellow M&M's = 23 total
P( yellow) = yellow / total = 8/23
P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23
P(orange) = orange/ total = 0/23
Answer:
there are 23 m&m's.
Step-by-step explanation:
Probability of getting red is 6/23
Probability of getting green is 5/23
Probability of getting blue is 4/23
Probability of getting yellow is 8/23
Orange = red + yellow = 6+8/23
Probability of getting Orange = 14/23
8 A test rocket is fired and follows a path described by y = 0.1x(200 – x). The height is y metres above
ground and x is the horizontal distance in metres.
How far does the rocket travel horizontally?
b How high does the rocket reach mid-flight?
Answer:
a) The rocket travels 200 meters horizontally.
b) The height of the rocket mid-flight is of 1000 meters.
Step-by-step explanation:
Height of the rocket:
The height of the rocket, in meters, after an horizontal distance of x, is given by:
[tex]y = 0.1x(200 - x)[/tex]
a) How far does the rocket travel horizontally?
This is x when [tex]y = 0[/tex]. So
[tex]0.1x(200 - x) = 0[/tex]
Then
[tex]0.1x = 0[/tex]
[tex]x = 0[/tex]
And
[tex]200 - x = 0[/tex]
[tex]x = 200[/tex]
So
The rocket travels 200 meters horizontally.
b How high does the rocket reach mid-flight?
This it the height y when x = 0, so:
[tex]y = 20*100 - 0.1*100^2 = 1000[/tex]
The height of the rocket mid-flight is of 1000 meters.
Which equation represents a line that passes through (4,1/3) and has a slope of 3/4?
Oy- 3/4= 1/3(x-4)
Oy-1/3= 3/4(x-4)
Oy- 1/3= 4(x-3/4)
Oy-4 = 3/4(x-1/3)
Step-by-step explanation:
With this kind of problem, we're looking at an equation in the form
y - y1 = m(x - x1)
(m = slope)
so we can substitute m, y1, and x1 with the values we're given.
y - y1 = m(x - x1)
y - 1/3 = 3/4(x - 4)
Answer:
y - 1/3 = 3/4(x - 4)
Determine if the statement is always, sometimes, or never true:
An equilateral triangle is an acute triangle.
never
always
sometimes
The answer is always your welcome
Answer:
always
Step-by-step explanatia;won:
the incenter of a triangle is formed by the intersection of the of a triangle
Answer:
angle bisectors
Step-by-step explanation:
The incentre is where a triangle's three angle bisectors intersect ( an angle bisector is a ray that cuts an angle in half ). The incentre is the centre of a triangle drawn inside the triangle.
The quadratic equation $ax^2+20x+c=0$ has exactly one solution. If $a+c=29$, and $a
Answer:
a² + c² = 641
Step-by-step explanation:
Given :-
ax² + 20x + c has exactly one solution .a + c = 29 .For exactly one Solution ,
b² - 4ac = 0 20² - 4*a*c = 0 4ac = 400 ac = 100Also ,
a + c = 29 ( a + c)² = 29²a² + c² + 2ac = 841 a² + c² + 2*100 = 841a²+ c² = 841 - 200 a² + c² = 6413. Find the value of x in this figure
answer:
120°
Step-by-step explanation:
∠OPM=∠ONM=90°
X°＝360°-60°-90°*2＝120°
