Please help‼️
Given O below, if XY and YZ are congruent, what is the measure of chord XY?
Answers
Answer:
11.2
Step-by-step explanation:
yz = 11.2
since the corresponding arc of yz and xy are same, their measures will ba same too
Answered by GAUTHMATH
Answer:
11.2
Step-by-step explanation:
good luck!
Related Questions
The graph below represents which of the following functions?
Answers
Answer:
hiuu ui9i io9
Step-by-step explanation:
iu9uj k
Damaged items are marked down 25% to 40%. A newspaper coupon holder; to an additional 10% markdown of the new price due to the damage. What is the lowest price of a damaged item that was originally marked GHC100?
A GHC 35.60
B GH 5000
C. GHC 18.00
D. GHC 40.80
E GHC 23.40
Answers
Markdown is the difference (at sale) between the price an item is placed at for retail sale, and the actual price the item is sold
The correct option is; B. GHC 50.00
The reason for choosing option B is as follows;
The known parameters
The percentage by which damaged items are marked down = 25% to 40%
The percentage markdown offered by the newspaper coupon = 10%
The original marked price of the item = GHC 100
Strategy:
Apply the damaged items and coupon markdown percentages to the original marked price of GHC100 sum the results to find the total markdown
Solution:
Markdown due to damage:
Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40%;
40% is removed from the price to which the item marked down due to damage, as follows;
The markdown due to damage = 40/100 × GHC 100 = GHC 40
Markdown due to Coupon Holder:
The markdown the coupon holder is to get = 10% off the retail price
Given that the damage is not mentioned in the newspaper, we have;
∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10
Total markdown:
The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50
The Lowest Price of A Damaged Items marked GHC100:
The lowest price of the item = Original price - Maximum markdown
The lowest price of the item = GHC 100 - GHC 50 = GHC 50
Learn more about markdown and markup concepts here;
https://brainly.com/question/20705786
a) Everyone on the team talks until the entire team agrees on one decision. O b) Everyone on the team discusses options and then votes. O c) The team passes the decision-making responsibility to an outside person. O di The team leader makes a decision without input from the other members.
Answers
Answer:
a) Everyone on the team talks until the entire team agrees on one decision.
Step-by-step explanation:
Option B consists of voting and not everyone would like the outcome. Option C is making an outsider the decision maker, which can't be helpful since he / she won't have as strong opinions as the team itself. Option D is just plain wrong as it defeats the purpose of team work and deciding as one team. So, I believe option A makes the most sense
14/50 as as a percent?
Answers
.
.
.
.
........……………
Answer:
The answer would be 28%!
Step-by-step explanation:
14/50 is 0.28. To change a decimal to a percentage, we multiply it by 100 which we can do by moving the decimal two numbers to the right.
A farmer plants the same amount every day, adding up to 4 1/3 acres at the end of the year. If the year is 5/8 over, how many acres has the farmer planted?
Answers
Answer:
5/6
Step-by-step explanation:
12/3 × 1/2 = 5/6
hope it helps
please mark Brainliest
Part b c and d please help
Answers
Answer:
b) Y =5.73X +4.36
C) =5.73225*(21)X +4.359
124.73625
D) 163.728 = 5.73X +4.36
X = (163.728 - 4.36)/5.73
X = 27.81291449
Year would be 2027
Step-by-step explanation:
x1 y1 x2 y2
4 27.288 16 96.075
(Y2-Y1) (96.075)-(27.288)= 68.787 ΔY 68.787
(X2-X1) (16)-(4)= 12 ΔX 12
slope= 5 41/56
B= 4 14/39
Y =5.73X +4.36
Find a12 for the geometric sequence -4, -2, -1, -1/2, ...
Answers
9514 1404 393
Answer:
-1/512
Step-by-step explanation:
The first term is -4, and the common ratio is -2/-4 = 1/2. Then the n-th term is ...
an = -4·(1/2)^(n-1)
and the 12th term is ...
a12 = -4(1/2)^(12 -1) = -4/2048
a12 = -1/512
PLS HELP
If f(x) = x2 -1, what is the equation for f–1(x)?
Answers
We have a function,
[tex]f(x)=x^2-1[/tex]
and we are asked to find its inverse function.
An inverse function essentially gets you the original value that was dropped into a function.
For example,
If I put 5 into [tex]f(x)[/tex] I will get 24. Now If I take 24 and put it into the inverse function I have to get number 5 back.
The way to determine the inverse function swap the x and the [tex]f(x)[/tex], then solve for [tex]f(x)[/tex],
[tex]x=f(x)^2-1[/tex]
[tex]f(x)^2=x+1[/tex]
[tex]f(x)=\pm\sqrt{x+1}[/tex]
Of course the notation demands that the obtained function be called,
[tex]f^{-1}(x)=\pm\sqrt{x+1}[/tex]
Hope this helps :)
T
On Melissa's 6th birthday, she gets a $2000 CD that earns 5% interest, compounded semiannually. If the
CD matures on her 16th birthday, how much money will be available?
TE
$
(S
Answers
9514 1404 393
Answer:
$3277.23
Step-by-step explanation:
The future value of the CD with interest at rate r compounded semiannually for t years will be given by ...
A = P(1 +r/2)^(2t)
where P is the principal value.
For the given rate and time, this is ...
A = $2000(1 +0.05/2)^(2·10) = $2000(1.025^20) ≈ $3277.23
The value of the CD at maturity will be $3277.23.
Sharla invests $275 in a simple interest bearing account for 16 years. The annual interest rate is 8%. Using the simple
interest formula, / -Prt, how much interest will Sharla's initial investment earn over the 16 year period?
$297
$319
$352
$627
Answers
Answer:
352
Step-by-step explanation:
I = PRT where P is the principle, I is the interest rate, T is the time
I = 275 ( .08) ( 16)
I = 352
Find y' for the following.
Answers
Answer:
[tex]\displaystyle y' = \frac{\sqrt{y} + y}{4\sqrt{x}y \Big( y^\Big{\frac{3}{2}} + \sqrt{y} + 2y \Big) + \sqrt{x} + x}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Quotient Rule]: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Implicit Differentiation
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \frac{\sqrt{x} + 1}{\sqrt{y} + 1} = y^2[/tex]
Step 2: Differentiate
Implicit Differentiation: [tex]\displaystyle \frac{dy}{dx} \bigg[ \frac{\sqrt{x} + 1}{\sqrt{y} + 1} \bigg] = \frac{dy}{dx}[ y^2][/tex]Quotient Rule: [tex]\displaystyle \frac{(\sqrt{x} + 1)'(\sqrt{y} + 1) - (\sqrt{y} + 1)'(\sqrt{x} + 1)}{(\sqrt{y} + 1)^2} = \frac{dy}{dx}[ y^2][/tex]Rewrite: [tex]\displaystyle \frac{(x^\Big{\frac{1}{2}} + 1)'(y^\Big{\frac{1}{2}} + 1) - (y^\Big{\frac{1}{2}} + 1)'(x^\Big{\frac{1}{2}} + 1)}{(y^\Big{\frac{1}{2}} + 1)^2} = \frac{dy}{dx}[ y^2][/tex]Basic Power Rule [Addition/Subtraction, Chain Rule]: [tex]\displaystyle \frac{\frac{1}{2}x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - \frac{1}{2}y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}{(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Factor: [tex]\displaystyle \frac{\frac{1}{2} \bigg[ x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1) \bigg] }{(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Rewrite: [tex]\displaystyle \frac{x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}{2(y^\Big{\frac{1}{2}} + 1)^2} = 2yy'[/tex]Rewrite: [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) - y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}= 4yy'(y^\Big{\frac{1}{2}} + 1)^2[/tex]Isolate y' terms: [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) = 4yy'(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}y'(x^\Big{\frac{1}{2}} + 1)}[/tex]Factor: [tex]\displaystyle x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1) = y' \bigg[ 4y(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}(x^\Big{\frac{1}{2}} + 1)} \bigg][/tex]Isolate y': [tex]\displaystyle \frac{x^\Big{\frac{-1}{2}}(y^\Big{\frac{1}{2}} + 1)}{4y(y^\Big{\frac{1}{2}} + 1)^2 + y^\Big{\frac{-1}{2}}(x^\Big{\frac{1}{2}} + 1)} = y'[/tex]Rewrite/Simplify: [tex]\displaystyle y' = \frac{\sqrt{y} + y}{4\sqrt{x}y \Big( y^\Big{\frac{3}{2}} + \sqrt{y} + 2y \Big) + \sqrt{x} + x}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Book: College Calculus 10e
Which is the sum of the sequence {5*1, 5*8, 5*27, 5*64, 5*125, 5*216}?
Answers
Answer:
2160
Step-by-step explanation:
I find that it is easier to split the sequence into smaller, more manageable sections. For numbers beyond 13, the simplest way is to split it up into place values.
Note: * is a multiplication symbol
5*1 = 5
5*8 = 40
5*27 = (5*20) + (5*7) = 100+35 = 135
5*64 = (5*60) + (5*4) = 300+20 = 320
5*125 = (5*100) + (5*20) + (5*5) = 500+100+25 = 625
5*216 = (5*200) + (5*10) + (5*6) = 1000+50+30=1080
Now you can add all of the totals up!
135+320+625+1080 = 2160
Determine whether the following individual events are independent or dependent. Then find the probability of the combined event.
Randomly drawing and immediately eating two red pieces of candy in a row from a bag that contains red pieces of candy out of pieces of candy total.
Answers
Answer:
Dependent event
[tex]P(Red = 2) = \frac{5}{588}[/tex]
Step-by-step explanation:
Given
[tex]Total = 49[/tex]
[tex]Red = 5[/tex]
Solving (a): Are the events dependent?
Yes, they are.
When the first red candy is selected and eaten, the total number of candies reduced to 48 and the number of red candies also reduced to 4.
So, the probability of selecting a 2nd candy is dependent on the first candy selected.
Solving (b): P(Red = 2)
This is calculated as:
[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]
The first selection has the following probability:
[tex]P(Red) = \frac{Red}{Total}[/tex]
[tex]P(Red) = \frac{5}{49}[/tex]
The second selection has the following probability:
[tex]P(Red|Red) = \frac{Red - 1}{Total - 1}[/tex]
[tex]P(Red|Red) = \frac{5 - 1}{49 - 1}[/tex]
[tex]P(Red|Red) = \frac{4}{48}[/tex]
So, we have:
[tex]P(Red = 2) = P(Red) * P(Red | Red)[/tex]
[tex]P(Red = 2) = \frac{5}{49} * \frac{4}{48}[/tex]
Reduce fraction
[tex]P(Red = 2) = \frac{5}{49} * \frac{1}{12}[/tex]
Multiply
[tex]P(Red = 2) = \frac{5}{588}[/tex]
Please show work. The way that you solve for surface area and vol confuse me.
Answers
Answer:
search up the formula
Step-by-step explanation:
Consider an urn initially containing n balls, numbered 1 through n, and suppose that balls will be randomly drawn from the urn, one by one, and without replacement (so that after n draws, it is empty). Letting X be the number of successes that will occur, where a success is considered to occur on the ith draw if the ball obtained is numbered i or smaller, give the expected value of X. (E.g., if n = 5, and the balls are drawn in the order 3, 1, 5, 4, 2, then x = 3, because the 2nd, 4th, and 5th draws result in successes, but the 1st and 3rd draws don’t.)
Answers
A restaurant interest survey of 230 citizens in a town showed that 80 want a new Chili's, 120 want a new Red Lobster, and 20 want both. Determine the probability that:
...
Answers
Answer:
2/23
6/23
5/23
Step-by-step explanation:
60 only want chilis
20 wants both
100 only want red lobster
50 want neither
The right solution to the given question is "[tex]\frac{2}{23}[/tex]", "[tex]\frac{6}{23}[/tex]" and "[tex]\frac{5}{23}[/tex]".
According to the question,
[tex]a+b+c+d = 230[/tex][tex]b = 20[/tex][tex]a+b = 80[/tex]By putting the value of "b", we get
[tex]a+20=80[/tex][tex]a = 80-20[/tex]
[tex]a = 60[/tex]
[tex]b + c=120[/tex]By putting the value of "b", we get
[tex]20+c=120[/tex]
[tex]c = 120-20[/tex]
[tex]c = 100[/tex]
[tex]d = 230-60-100-20[/tex]By putting the values of "a", "b", "c" and "d", we get
[tex]d = 50[/tex]
(a)
P(both Chili's and Red lobster),
= [tex]\frac{b}{a+b+c+d}[/tex]
= [tex]\frac{2}{23}[/tex]
(b)
P(only chili's),
= [tex]\frac{a}{a+b+c+d}[/tex]
= [tex]\frac{6}{23}[/tex]
(c)
P(neither),
= [tex]\frac{d}{a+b+c+d}[/tex]
= [tex]\frac{5}{23}[/tex]
Learn more about probability here:
https://brainly.com/question/24269622
The best basketball player
Answers
Answer:
c
Step-by-step explanation:
hope it helps!!!!!!!!!!!!!!
Help once again thanks! !!!!!!!
Answers
1. 52° because it’s the same as angle 5, which is opposite of 7 so it’s the same
2. Is Also 52° because it is the same as angle 7 which is 52°
help me please !
4,5 and 6
Answers
9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
4.a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
__
b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
__
5.The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
__
6.The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
A route up a mountain is 20 Km long. john followed this route at an average speed of xkm/h. write down an expression in terms of x,for the number of hours he took to walk up the mountain.
Answers
Answer:
20/x
Step-by-step explanation:
speed = distance /time
x km/h is speed
20 km is distance
x= 20/t
t= 20/x
T = d/ speed
T = 20/ X
I need you guy’s help answer thanks so much
Answers
Answer:
D
Step-by-step explanation:
inverse just means opposite so if its shown dividing it first then adding, then the inverse is multiplying then subtracting
The weights of items produced by a company are normally distributed with a mean of 4.5 ounces and a standard deviation of 0.3 ounce. a. What is the probability that a randomly selected item from the production will weigh at least 4.14 ounces? b. What percentage of the items weighs between 4.8 and 5.04 ounces? c. Determine the minimum weight of the heaviest 5% of all items produced. d. If 27,875 items of the entire production weigh at least 5.01 ounces, how many items have been produced?
Answers
Answer:
The right solution is:
(a) 0.8849
(b) 12.28%
(c) 4.9935
(d) 28004
Step-by-step explanation:
Given:
Mean,
= 4.5
Standard deviation,
= 0.3
(a)
P(x > 4.14)
As we know,
⇒ [tex]z = \frac{4.14-4.5}{0.3}[/tex]
[tex]=-1.20[/tex]
then,
⇒ [tex]P(z>-1.20) = P(z<1.20)[/tex]
[tex]=0.8849[/tex]
(b)
P(4.8 < x < 5.04)
= [tex]P(\frac{4.8-4.5}{0.3} < \frac{x-\mu}{\sigma} < \frac{5.04-4.5}{0.3} )[/tex]
= [tex]P(1<z<1.80)[/tex]
= [tex]P(z<1.80)-P(z<1)[/tex]
= [tex]0.9641 -0.8413[/tex]
= [tex]0.1228[/tex]
or,
= [tex]12.28[/tex] (%)
(c)
P(x > x) = 0.05
z value will be,
= 1.645
⇒ [tex]1.645 = \frac{x - 4.5}{0.3}[/tex]
[tex]x = 4.9935[/tex]
(d)
P(x < 5.01)
⇒ [tex]z = \frac{x- \mu}{\sigma}[/tex]
[tex]=\frac{5.01-4.5}{0.3}[/tex]
[tex]=1.7[/tex]
P(z < 1.70) = 0.9554
⇒ [tex]n = \frac{27875}{0.9954}[/tex]
[tex]=28004[/tex]
Conan puts tennis balls into tubes after gym class. There are 17 tennis balls, and each tube holds 3 balls. How many tubes does Conan completely fill? How many tennis balls are left?
Answers
A toy rocket is shot vertically into the air from a launching pad 9 feet above the ground with an initial velocity of 88 feet per second. The height h, in feet, of the rocket above the ground at t seconds after launch is given by the function
h(t) - 16^2 + 88ft +9. How long will it take the rocket to reach its maximum height? What is the maximum height?
The rocket reaches its maximum height at ____ second(s) after launch.
(Simplify your answer.)
Answers
Answer:
Step-by-step explanation:
The position function for this is:
[tex]s(t)=-16t^2+88t+9[/tex]. We can use this equation to find the position (or height) of the rocket at ANY TIME during its flight. I could find out the height of the rocket at 3 seconds by plugging in a 3 for t and solving for s(t); I could find the height of the rocket at 12 seconds by plugging in a 12 for t and solving for s(t), etc.
The first derivative of position is velocity:
v(t) = -32t + 88.
If we are looking for the time the rocket reaches it max height, we need to remember from physics class that this happens when the velocity of the object is at 0. We set the velocity equation equal to 0 then and solve for t:
0 = -32t + 88 and
-88 = -32t so
t = 2.75 seconds. This means that 2.75 seconds after the rocket is launched, it reaches its max height. In order to find what that max height is we plug 2.75 into the position equation for t and solve:
[tex]s(2.75)=-16(2.75)^2+88(2.75)+9[/tex] to get that
s(2.75) = 130
The max height is 130 feet and it reaches this point at 2.75 seconds into its motion.
I need to know the answer ASAP
Answers
Answer:
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The numerical coefficient is sqrt(8/3), so all you have eliminated is D.
Now you have to consider the literal all by itself.
sqrt(x^2)/sqrt(x) can be written as (sqrt(x^2/x)) = sqrt(x)
x^2 when divided by x leaves x
another way of looking at it is sqrt(x)*sqrt(x) / sqrt(x) = sqrt(x)
So the answer is sqrt(8/3 * x)
How many different arrangements of 5 letters can be formed if the first letter must be W or K (repeats of letters are allowed)?
There are ___ different 5-letter combinations that can be formed.
(Simplify your answer.)
Answers
Answer:
2.5
Step-by-step explanation:
i had it
(b) How much the selling price should be fixed for pulse bought for Rs.70 per kg. to earn a profit of Rs.6 after allowing a 5 % discount?
Answers
Answer:
Rs. 80
Step-by-step explanation:
Given that :
Purchase price = 70
Profit = 6
Discount = 5%
Let selling price = x
Selling price * (1 - discount) = (purchase price + profit)
x * (1 - 5%) = (70 + 6)
x * (1 - 0.05) = 76
x * 0.95 = 76
0.95x = 76
x = 76 / 0.95
x = 80
Hence, selling price = Rs. 80
[tex]2i+3x=4-ix[/tex]
Show work.
No wrong answers or you will be reported. I will mark Brainliest! Thank you!
Answers
Answer:
Step-by-step explanation:
I am assuming i is the imaginary number:
Factor:
(3 + i)x - (4-2i) = 0.
In order for this to equal 0, x must be equal to 1-i.
I don't want to be reported to so take my word for it.
Also I plugged it into wolfram alpha so if it is wrong, blame the most powerful math equation solver available on the internet.
Using BTS he properties, find the unit's digit of the cube of each of the following numbers
In ΔABC, if AB = 10 and BC = 6, AC can NOT be equal to
Answers
Answer:
Step-by-step explanation:
4
=10-6
=4
If it is a right angled triangle then
AB=8cm
So Ac can not be equal to other number rather than 8 and 6
Find x on this triangle
Answers
Answer:
I didn't find the answer in the options
the height of the bigger triangle is 11√6/√3 = 11√2
x = 11√2 × √2 = 11×2 = 22
Answered by GAUTHMATH
