PLEASE HELP ME SOLVE THIS!! PLZ
Banpo Bridge fountain is 60 metres above the water.
The water is projected with a horizontal speed of 6m/s
-Calculate:
1. The time taken to hit the river for a single droplet of water.
2. The range of the projectile for a single droplet of water.
3. The velocity (diagonal) when it hits the water.

Explanation:

It is given that,

Speed of an automobile is 25 km/h or 6.95 m/s

Kinetic energy of the automobile is [tex]10^4\ J[/tex]

(a) Kinetic energy of automobile s given by :

[tex]K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 10^4}{(6.95)^2}\\\\m=414\ kg[/tex]

(b) If the velocity of the car is increased to 45 km/hour or 12.5 m/s, new kinetic energy becomes :

[tex]K=\dfrac{1}{2}\times 414\times (12.5)^2\\\\K=32343.75\ J[/tex]

(c) If the velocity is increased to 80 km/hour, 22.23 m/s, So

[tex]K=\dfrac{1}{2}\times 414\times (22.23)^2\\\\K=102293.79\ J[/tex]

Hence, this is the required solution.

Answer:

Kepler studied the periods of the planets and their distance from the Sun, and proved the following mathematical relationship, which is Kepler's Third Law: The square of the period of a planet's orbit (P) is directly proportional to the cube of the semimajor axis (a) of its elliptical path.

Explanation:

Answer:

D

Explanation:

Just got a 100 on the test

Answer:

Abiotic

Explanation:

The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.

Examples for abiotic factors include temperature, sunlight, water, wind etc....

Answer:

B

Explanation:

is the correct answer

Answer: d)

Both Assertion and Reason are false

Explanation:

The least distance of distinct vision for normal human beings is 25 cm. That is,

normal eye can not be able to see clearly the objects placed closer than 25 Centimetre.

Havong an Assertion that normal human eye can see clearly all the objects below and above 25 cm is false. And since the assertion is false, the reason behind it is invalid. Therefore, having a reason that the human eye has the capacity to suitable adjust the focal length of its lens to a certain extent is also false.

Answer:

Solenoid with a Metal core

Answer: 15 orbits

Explanation:

Given that the

Radius of Mars = 2.28 × 10^8 km

Radius of Saturn = 1.43 × 10^9 km

For a linear speed,

One revolution = 2πR

One revolution of Mars = 2 × π 2.28×10^8

And

One revolutionary of Saturn = 2 × π × 1.43 × 10^9

Since the relationship between angular speed and linear speed is

V = wr

Or

W = V/2πR

The number of orbits that Mars completes in the time it takes for Saturn to complete one orbit will be

(Vs/2π × 1.43 × 10^9) ÷ (Vm/2π × 2.28×10^8)

Where

Vm = linear speed of Mars = 24.1 km/s

Vs = linear speed of Saturn = 9.7km/s

(24.1/2π × 2.28×10^8) ÷ (9.7/2π × 1.43 × 10^9)

(24.1/2π × 2.28×10^8) × ( 2π × 1.43 × 10^9/9.7)

2π Will cancel each other

(24.1/2.28 × 10^8) × (1.43×10^9/9.7)

(24.1 × 1.43×10^9)/(2.28×10^8 × 9.7)

3.4463×10^10 / 2.2116×10^9

15.58 times

Therefore, Mars will complete 15 orbits in the time it takes for Saturn to complete one orbit.

Answer: V = 299,958589.8 m/s

Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.

Fo = (c + Vo) f/ ( c - Vs)

Fo/f = (c + Vo) / ( c - Vs)

If Vo = Vs = V approximately

4.26 × 10^10 = (3×10^8 + V) 6.17×10^14/(3×10^8 - V)

4.26×10^10/6.17×10^14 = (3×10^8 + V)/(3×10^8 - V)

6.9×10^-5 = (3×10^8 + V)/(3×10^8 - V)

Cross multiply

20713.13 - 6.9×10^-5V = 3×10^8 + V

Collect the like terms

6.9×10^-5V + V = 3×10^8 - 20713.13

1.000069V = 299979286.9

V = 299979286.9/1.000069

V = 299,958589.8 m/s

Therefore, Rigel's velocity relative to us is 299,958589.8 m/s

KE=1/2mv^2

1/2(100)6^2

1800 J

Answer:

i. increasing the number of turns of the wire by half, so that it equals 300.

OR

ii. increasing the value of the current by half of its initial value, so that it equals 9 amp.

Explanation:

An electromagnet consists of a coil of wire wound around a conductor which becomes induced with magnetism when current flows through the coil.

The magnetic strength of the electromagnet can be increased to 1.5 of its initial strength either by;

i. increasing the number of turns by half of its initial value

OR

ii. increasing the current by half of its initial value

The magnetic strength of an electromagnet = I × N

where; I is the amount of current and N the number of turns.

Given that: I = 6 A, N = 200, then;

magnetic strength = 6 ×200

                              = 1200 Ampere turns

i. Increasing the number of turns to 300 and I = 6 A, we have;

magnetic strength = 6 × 300

                              = 1800 Ampere turns

OR

ii. increasing the value of current by half of its initial value, so that N = 200 and I = 9 A;

magnetic strength = 9 ×200

                              = 1800 Ampere turns

Answer: B

Explanation:

The reactivity of alkaline metal ( example group one ) increases down the group because of the increase in atomic mass from the top to the bottom of the group. As the mass increases, the force between the nucleus and the valence electron gets weaker and the atom will easily give up the electron as a result of this which eventually increases its reactivity.

The reactivity of halogens decreases as atomic mass increases. Therefore, option B is the correct answer.

Answer:

it will most likely turn off?

Answer: 44.89 times

Explanation:

Given that the earth's average velocity is about 6.7 times faster than that of planetoid Makemake

Given that the formula involved is:

R2/R1 = (V1/V2)^2

Let V1 = earth velocity and R1 = earth orbital distance

While R2 = Makemake velocity and R2 = orbital distance.

Since the earth's average velocity is about 6.7 times faster than that of planetoid Makemake, then,

V1/V2 = 6.7

Substitute this in the formula above

R2/R1 = (6.7)^2

R2/R1 = 44.89

Cross multiply

R2 = 44.89R1

Therefore, Makemake's orbit is about 44.89 times larger than the earth's orbit.

Answer:

Object 3

Explanation:

The object has the greatest acceleration is Object 2.

The following information should be considered;

learn more: https://brainly.com/question/5303391?referrer=searchResults

Answer:

The correct option is D

D) Gestalt

Explanation:

In the earlier 20th century, a group of German scientists named Max Wertheimer, Wolfgang Köhler and Kurt Koffka, noticed that people tend to organzie a cluster of information into a Gestalt.

Gestalt is a German word which means the way things are placed or put together as a whole. In the field of phychology, it can be defined as a pattern or configuration. In this context, it included the human mind and its behavior as a whole.

The Gestalt theory states that:

"The whole of anything is greater than its parts and that attributes of the whole can't be deduced by analyzing any of the parts on their own accord"

Answer:

Explanation:

The formula P=VI, just rearrange to find I

So

I=P/V

=75/120

=0.625amps

625mA

Answer:The answer must be The weight of the man and the vertical distance moved.

Explanation: you calculate it by the force you applied times the distance you moved

Answer:

10,000 N

Explanation:

Force = mass · acceleration

F = m · a

Jake's car:

Accelerates at 10 m/s²

Weighs 1000 kg

F = 1000 · 10

F = 10000 N

Answer:

10,000 Newtons

Please mark my answer.

Cheers, Jake

Answer: K.E = 8.3 J

Explanation:

The given parameters are

Height h = 169.2 m

Mass m = 0.005kg

From conservation of energy, at the top of the monument, the total energy will be kinetic energy which is equal to the potential energy. That is,

K.E = P.E

And

P.E = mgh

Where g = 9.81 m/s^2

Substitutes all the parameters into the formula

P.E = 0.005 × 9.81 × 169.2

P.E = 8.2908 J

Therefore, the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is approximately 8.3 Joule.

The kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument is 8.2908 Joules.

Given the following data:

Scientific data:

To calculate the kinetic energy (KE) of the nickel in her shirt pocket at the top of the monument, we would apply the law of conservation of energy.

According to the law of conservation of energy, the kinetic energy (KE) of the nickel is equal to the potential energy (PE) possessed by the nickel at the top of the monument.

Mathematically, this is given by this expression:

[tex]K.E =P.E =mgh[/tex]

Substituting the given parameters into the formula, we have;

[tex]K.E = 0.005 \times 9.8 \times 169.20[/tex]

K.E = 8.2908 Joules.

Read more on kinetic energy here: https://brainly.com/question/22599382

Answer:

The mechanical advantage of the wheel and axle is the ratio of the distances from the fulcrum to the applied loads, or what is the same thing the ratio of the diameter of the wheel and axle

Explanation:

i looked on Google

The wheel and axle simple machine is closely related to gears. Like all other simple machines the wheel and axle system changes the force by changing the distance over which the force must be applied; if the input force is reduced to the output force, then the force must be applied over five times the distance.

Answer:

Pressure= force/ area

12/ 2033.33= 24400 N/m2.

i believe this is it :)

Answer:

The relation between frequency and time period is given by:

f = 1/T

Explanation:

In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.

The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:

T = 2π/ω

Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by

f = ω/2π

or

f = 1/T

Answer:

False

Explanation:

First we need to know the definition of work.

Work is done when a body moves through a distance with an applied force.

When swimming in water, you exert a force while moving through a distance. Therefore, work is done!

Answer:

no

Explanation:

the goalie can move side to side but cant go out of the goalie box.

pls mark me brainliest

Answer:

radios work when electrons are speeding up and dow the attena, patters structure and shape make music pleasing to hear. (more info below)

Explanation:

a radio works when electrons are speeding up and down the antenna, sending out electromagnetic waves. Radiation waves travel through the air at the speed of light. When the radio waves reach the antenna, the electrons vibrate within the antenna and reproduce the initial signal. to make music pleasing to hear it has to have patterns, structure, shape.

hope this helped!

Answer:

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

Explanation:

You have four charges at the corners of a square of side a=5.2cm

In order to calculate the electric field at the center of the square, you sum the contribution of the electric field generated by each charge.

The total electric field is given by:

[tex]E_T=E_1+E_2+E_3+E_4\\\\[/tex]    (1)

each contribution to the total electric field has two components x and y. The signs of the components depends of the direction of the field, which is given by the sign of the charge that produced the electric field. Then, you have

[tex]E_1=k\frac{q_1}{r^2}cos\theta\hat{i}-k\frac{q_1}{r^2}sin\theta\hat{j}\\\\E_1=k\frac{q_1}{r^2}(cos\theta \hat{i}-sin\theta \hat{j})[/tex]   (2)

q1 = 11.8*10^-9 C

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

For a square you obtain that

[tex]r=\sqrt{2}a=\sqrt{2}(5.2cm)=7.35cm=7.35*10^{-2}m[/tex]

and the angle is 45°

Then, you have in the equation (2):

[tex]E_1=(8.98*10^9Nm^2/C^2)\frac{11.8*10^{-9}C}{(7.35*10^{-2}m)^2}(cos45\° \hat{i}-sin45\° \hat{j})=[13869.7\hat{i}-13869.7\hat{j}]\frac{N}{C}[/tex]

In the same way you obtain for the other contributions to the total electric field:

For E2:

[tex]E_2=k\frac{q_2}{r^2}(cos45\°\hat{i}+sin45\° \hat{j})\\\\E_2=[13869.7\hat{i}+13869.7\hat{j}]\frac{N}{C}[/tex]

For E3:

[tex]E_3=k\frac{q_3}{r^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=(8.98*10^9Nm2/C^2)\frac{23.6*10^{-9}C}{(7.35*10^{-2}m)^2}(-cos45\°\hat{i}+sin45\°\hat{j})\\\\E_3=39229.58(-cos45\°\hat{i}+sin45\°\hat{j})\frac{N}{C}\\\\E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\frac{N}{C}[/tex]

for E4:

[tex]E_4=k\frac{q_4}{r^2}(-cos45\°\hat{i}-sin45\°\hat{j})\\\\E_4=[-27739.5\hat{i}-27739.5\hat{j}]\frac{N}{C}[/tex]

Finally, you sum component by component the four contributions to the total electric field (equation (1)):

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

There still are four chargers in the corners of a square with side a=5.2cm. To compute the electric field just at the center of the composition, add the contributions of each shield's electromagnetic current.

entire electric field

[tex]\to E_T=E_1+E_2+E_3+E_4\ \ \ \ \ \ \ (1)[/tex]

Every contribution to the total electric field is comprised of two components, x, and y. These components' signs were determined by the direction of the field, which is determined by the sign of the charge that produced the electric field. There's

[tex]\to E_1=k\frac{q_1}{r^2}\cos\theta\hat{i}-k\frac{q_1}{r^2}\sin\theta\hat{j}\\\\\to E_1=k\frac{q_1}{r^2}(\cos\theta \hat{i}-\sin\theta \hat{j}) \ \ \ \ (2)\\\\\to q_1 = 11.8\times 10^{-9}\ C\\\\[/tex]

Coulomb’s constant (K) [tex]= 8.98\times 10^9\ \frac{Nm^2}{C^2}[/tex]

square, you obtain that

[tex]\to r=\sqrt{2}\\\\\to a=\sqrt{2}(5.2\ cm)=7.35\ cm=7.35\times 10^{-2}\ m[/tex]

angle= [tex]45\°[/tex]  then, you have in the equation (2):

[tex]\to E_1=(8.98\times 10^9\ \frac{Nm^2}{C^2})\frac{11.8 \times 10^{-9}\ C}{(7.35 \times 10^{-2}m)^2}(\cos 45^{\circ} \hat{i}-\sin 45^{\circ} \hat{j})[/tex]

         [tex]=[13869.7\hat{i}-13869.7\hat{j}]\ \frac{N}{C}[/tex]

Similarly, for other components to the overall electric field, you get:

For E2:

[tex]\to E_2=k\frac{q_2}{r^2}(\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\ \to E_2=[13869.7\hat{i}+13869.7\hat{j}]\ \frac{N}{C}[/tex]

For E3:

[tex]\to E_3=k\frac{q_3}{r^2}(-\cos45^{\circ}\hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=(8.98\times 10^9 \ \frac{Nm^2}{C^2}) \ \frac{23.6 \times 10^{-9}\ C}{(7.35\times 10^{-2}\ m)^2}(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\\\\\to E_3=39229.58(-\cos45^{\circ} \hat{i}+\sin45^{\circ} \hat{j})\frac{N}{C}\\\\\to E_3=[-27739.5\hat{i}+-27739.5\hat{j}]\ \frac{N}{C}\\[/tex]

For E4:  

[tex]\to E_4=k\frac{q_4}{r^2}(-\cos45^{\circ}\hat{i}-\sin45^{\circ}\hat{j})\\\\ \to E_4=[-27739.5\hat{i}-27739.5\hat{j}]\ \frac{N}{C}[/tex]

Finally, we add up the four contributions to the total electric field (equation (1)):

[tex]E_T=[-27739.6\hat{i}-55479\hat{j}]\frac{N}{C}[/tex]

Learn more:

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