please help i need this by tonight

Answer:

= a^2 + 2.a.b + b^2

Answer:

AA

Step-by-step explanation:

We know that all three angles are similar  as shown by the markings

I would use  AA, or the Angle Angle theorem

Answer:

x = 4[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Pytago:

x[tex]x^{2} +7^{2} = 9^{2} \\\\x = \sqrt{9^{2} - 7^{2} } x = 4\sqrt{2}[/tex]

Answer:

isosceles acute

Step-by-step explanation:

We have two sides that are equal so the triangle is isosceles

None of the angles are larger than 90 degrees so non of the angles are obtuse,  and none of the angles are 90 degrees, so the triangle is acute ( which means the angles are all less than 90 degrees)

The expected value, E(x) of the given observation is 185

The expected value is the mean of the overall observed value or random value. In other words, it is the average of the observed values.

The given parameters can be represented as:

[tex]\begin{array}{cccc}x & {100} & {200} & {300} \ \\ P(x) & {40\%} & {35\%} & {25\%} \ \end{array}[/tex]

The following formula calculates the expected value:

[tex]E(x) =\sum x * P(x)[/tex]

So, we have:

[tex]E(x) = 100 * 40\% + 200 * 35\% + 300 * 25\%[/tex]

[tex]E(x) = 40 + 70 + 75[/tex]

[tex]E(x) = 185[/tex]

Learn more about expected values at:

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Answer:

The slope of a line that goes through both [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex] would be [tex](-3)[/tex].

Step-by-step explanation:

The slope of a line is the ratio between rise and run between these two points.

The rise between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex](-5) - 7 = (-12)[/tex] (subtract the first [tex]y\![/tex]-coordinate from the second.)

The run between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex]2 - (-2) = 4[/tex] (likewise, subtract the first [tex]x[/tex]-coordinate from the second.)

Hence, the slope of this line would be:

[tex]\begin{aligned} \frac{\text{rise}}{\text{run}} &= \frac{-12}{4} = -3\end{aligned}[/tex].

Answer: 13/15

Step-by-step explanation:

Given:

Total number of students = 30

Number of students received an A = 4

Solve:

STEP ONE: Find the number of students who did not receive an A

No A = Total - Yes A

No A = 30 - 4

No A = 26

STEP TWO: Find the fraction of the class that didn't receive an A

Fraction = No A / Total

Fraction = 26 / 30

Fraction = 13 / 15

Hope this helps!! :)

Please let me know if you have any questions

Answer:

The larger the sample size, the more accurate the estimation of the true population value.

Step-by-step explanation:

Answer:

126

Step-by-step explanation:

9 choose 4 (Order does not matter)

9 nCr 4 = 126

Answer:

Letter D

Step-by-step explanation:

18 is your answer

Answer:

The dimension that maximizes area is 144ft by 144ft

Step-by-step explanation:

Given

[tex]P = 576[/tex] -- perimeter

Required

The dimension that gives maximum area

Perimeter is calculated as:

[tex]P= 2 * (L + W)[/tex]

So, we have:

[tex]2 * (L + W) = 576[/tex]

Divide through by 2

[tex]L + W = 288[/tex]

Make L the subject

[tex]L = 288 -W[/tex]

Area is calculated as:

[tex]A = L * W[/tex]

Substitute [tex]L = 288 -W[/tex]

[tex]A = (288 - W) * W[/tex]

Open bracket

[tex]A = 288W - W^2[/tex]

Differentiate A with respect to W

[tex]A' = 288 - 2W[/tex]

Set to 0 to calculate W

[tex]288 - 2W = 0[/tex]

Collect like terms

[tex]2W = 288[/tex]

Divide by 2

[tex]W = 144[/tex]

Recall that:

[tex]L = 288 -W[/tex]

[tex]L = 288 - 144[/tex]

[tex]L = 144[/tex]

Answer:

ayyyy i go to RSM too? Which location r u at? ANyways the answer is

Answer:

<a=55° ,< b=55° and <c=70°

Công thức xác định tuổi thọ KL

Answer:

40 min

Step-by-step explanation:

his sister can do it twice as fast so the boy does 1 and the sister does 2. he will do 1/3 of the work and it will take 1/3 of the time

Answer:

90 mins

Step-by-step explanation:

1 hour =60 mins

1/2 hour = 60/2=30

so, 60 +30=90

Answer:

13/9l  or 1  4/9 l

Step-by-step explanation:

Answer:

quantity of alcohol = l liters

we need to make a solution of having 45% alcohol by adding water.

45% alcohol means whatever id the total quantity of solution there is 45% alcohol.

Let the total quantity of solution be x.(

then

quantity of alcohol in terms of x = 45% of x = 45/100 x

but we know that quantity of alcohol = l liters

45/100 x = l

x = 100/45 l

Thus, total quantity of solution is 100/45 l,

but in it, there are l liters of alcohol.

to find the quantity of water we need to subtract the quantity of alcohol from the total quantity of solution

quantity of water in the solution = 100l/45  - l = (100l - 45l)/45 = 65l/45

quantity of water in the solution = 13/9l = 1 4/9 l -------->answer.

Thus, 1 4/9 liters of water needs to be added to l liters of alcohol to make a solution of 45% alcohol.

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Answer:

$2884.62

Step-by-step explanation:

A year has 52 weeks

The number of times Charlie will receive a paycheck will be 52w ÷ 2w = 26 times

Charlie's gross income each paycheck will be 7500÷26 = $2884.62 every two weeks

75000 ÷ (52 ÷2)

7500 ÷ 26

$2884.62

Step-by-step explanation:

The union of two sets is the set of elements that belong to one or both sets.

Symbolically, the union of X and Y is denoted by X ∪ Y. As an example, suppose set A = {1, 2, 3} and set B = {1, 3, 5}.

Then, the union of sets A and B would be {1, 2, 3, 5}.

Answer:

Option C

Angle C has the largest measure

Answer:

The minimum number of drivers you would need to survey is 601.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

What is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.04?

The number is n for which M = 0.04.

We don't have an estimate for the proportion, so we use [tex]\pi = 0.5[/tex]. Then

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.04\sqrt{n} = 1.96*0.5[/tex]

[tex]\sqrt{n} = \frac{1.96*0.5}{0.04}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2[/tex]

[tex]n = 600.25[/tex]

Rounding up:

The minimum number of drivers you would need to survey is 601.

Answer:

4 units

Step-by-step explanation:

A'B' = 2 × AB

8 = 2×AB

AB = 8/2 = 4

Answer:

16 units

Step-by-step explanation:

The triangle will get bigger because it has a scale factor that is greater than 1.

k=scale factor

k<1=reduction

k>1=enlargement

There are 50 different possible debating teams that could be selected as obtained using COMBINATION.

Since there are EQUAL number of juniors and seniors ;

Then we have 5 of each.

Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION

since the team MUST contain 4 SENIORS and 2 JUNIORS

4 Seniors from 5  = 5C4 = 5

2 Juniors from 5 = 5C2 = 10

Hence, (5C4 * 5C2) = 5 * 10 = 50

Hence, there are 50 different possible debating teams that could be selected.

Learn more about COMBINATION :

https://brainly.com/question/8018593

The expected value of a normal distribution is the mean of the distribution, while the variance measures the squared deviation of a value from the expected value. The expected value and the variance are: [tex]13.6190 \times 10^{-5}[/tex] and [tex]580.8000 \times 10^{-9}[/tex]

Given that, the diameters are:

[tex]d_1 = 0.02[/tex]

[tex]d_2 = 0.08[/tex]

The radius is:

[tex]r = \frac{d}{2}[/tex]

So, we have:

[tex]r_1 = \frac{0.02}{2} = 0.01[/tex]

[tex]r_2 = \frac{0.08}{2} = 0.04[/tex]

The volume of the sphere is:

[tex]V = \frac{4}{3} \times \pi \times r^3[/tex]

For [tex]r_1 = 0.01[/tex], the volume is:

[tex]V_1 = \frac{4}{3} \times \frac{22}{7} \times 0.01^3 = 0.419047 \times 10^{-5}[/tex]

For [tex]r_2 = 0.04[/tex], the volume is

[tex]V_2 = \frac{4}{3} \times \frac{22}{7} \times 0.04^3 = 26.819047 \times 10^{-5}[/tex]

The mean of a uniform distribution is:

[tex]E(y) = \frac{a + b}{2}[/tex]

In this case, the mean is:

[tex]E(y) = \frac{V_1 + V_2}{2}[/tex]

So, we have:

[tex]E(y) = \frac{0.419047 \times 10^{-5} + 26.819047 \times 10^{-5}}{2}[/tex]

[tex]E(y) = \frac{27.238094\times 10^{-5} }{2}[/tex]

[tex]E(y) = 13.619047 \times 10^{-5}[/tex]

Approximate

[tex]E(y) = 13.6190 \times 10^{-5}[/tex]

The variance of a uniform distribution is:

[tex]V(y) = \frac{(b-a)^2}{12}[/tex]

In this case, the volume is:

[tex]V(y) = \frac{(V_2-V_1)^2}{12}[/tex]

So, we have:

[tex]V(y) = \frac{(26.819047 \times 10^{-5}- 0.419047 \times 10^{-5})^2}{12}[/tex]

[tex]V(y) = \frac{(26.4 \times 10^{-5})^2}{12}[/tex]

[tex]V(y) = \frac{(696.96 \times 10^{-10})}{12}[/tex]

[tex]V(y) = 58.08000 \times 10^{-10}[/tex]

Rewrite as:

[tex]V(y) = 580.8000 \times 10^{-9}[/tex]

Hence, the expected value and the variance of the sphere are:[tex]13.6190 \times 10^{-5}[/tex] and [tex]580.8000 \times 10^{-9}[/tex]

Learn more about expected values and variance at:

https://brainly.com/question/4470015

Answer:

0.33362176

Step-by-step explanation:

Probability is the ratio of the number of possible outcomes to the number of total outcomes.

Given that a football team has a probability of 0.76 of winning when playing any of the other four teams in its conference, the probability that the team wins all its conference games

= 0.76 * 0.76 * 0.76 * 0.76

= 0.33362176

This is the probability that the teams wins the 4 matches played against the other teams in the conference.

Answer:

The equation of the parabola is,

x²+4y-12=0

Answer:

The answer is "Option a, Option b, and Option d".

Step-by-step explanation:

In the given question it is used to stratifying the sampling if the population of this scenario it flights takes off when it is divided via some strata.

Answer:

For each day of the week, randomly select 5% of all flights that depart on that day of the week.

Divide all flights into the following 4 groups on the basis of scheduled departure time: before 9:00 am, 9:00 am to 1:00 pm, 1:00 pm to 5:00 pm, and after 5:00 pm. Randomly select 5% of the flights in each group.

Divide the airports from which the airline's flights depart into 4 regions: Northeast, Northwest, Southwest, and Southeast. Randomly select 5% of all flights departing from airports in each region.

Step-by-step explanation:

ll sampling methods that divide the flights into a small number of mutually exclusive categories are appropriate. These methods include all flights on the basis of a characteristic that might be associated with the variable being investigated and randomly selects a proportionate number of flights from each group.

(a) We have ⌊x⌋ = 5 if 5 ≤ x < 6, and similarly ⌊x/3⌋ = 5 if

5 ≤ x/3 < 6   ==>   15 ≤ x < 18

(b) ⌊x⌋ = -2 if -2 ≤ x < -1, so ⌊x/3⌋ = -2 if

-2 ≤ x/3 < -1   ==>   -6 ≤ x < -3

In general, ⌊x⌋ = n if n ≤ x < n + 1, where n is any integer.

I do not understand what is being asked in (c) and (d), so you'll have to clarify...

Answer:

Television = 820

DVD Player = 410

Step-by-step explanation: Imagine the television  as 2, and the DVD player as 1. If you’re were to draw it out with boxes, you’d see that the tv  has two boxes and the DVD player has 1 box. All are exactly the same amount, and there are a total of three boxes. So divided 1230 by 3 and you get 410. Using the idea of the boxes, the DVD player get’s one 410, and the tv gets two 410s, or 820.

Answer:

See attachment for graph

Step-by-step explanation:

Given

[tex]f(x) = \left[\begin{array}{cc}-1&x<-1\\0&-1\le x \le -1\\1&x>1\end{array}\right[/tex]

Required

The graph of the step function

Before plotting the graph, it should be noted that:

[tex]\le[/tex] and [tex]\ge[/tex] use closed circle at its end

[tex]<[/tex] and [tex]>[/tex] use open circle at its end

So, we have:

[tex]f(x) = -1,\ \ \ \ x < -1[/tex]

The line stops at -1 with an open circle      

[tex]f(x) = 0,\ \ \ \ -1 \le x \le 1[/tex]

The line starts at - 1 and stops at -1 with a closed circle at both ends

[tex]f(x) = 1,\ \ \ \ x > 1[/tex]

The line starts at 1 with an open circle

The options are not complete, so I will plot the graph myself.

See attachment for graph