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Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

Answer:

a) Calculate the current price of the corporate bond? (4 marks)

b) Calculate the current price of the ordinary share if the average return of the shares in the same industry is 9%? (3 marks)

c) Calculate the current price of the preferred share if the average return of the shares in the same industry is 10% (3 marks)

Step-by-step explanation:

total debt = $3,500,000 par value 10$ coupon with a YTM of 12%

YTM = [coupon + (F - P)/n] / [(F + P)/2]

0.12 = [100 + (1,000 - P)/20] / [(1,000 + P)/2]

0.12(500 + 0.5P) = 100 + 50 - 0.05P

60 + 0.06P = 150 - 0.05P

0.11P = 90

P = 90/0.11 = $818.18

total debt = $818.18 x 3,500

stock price:

Div₀ = $8.50

Div₁ = $8.50 x 104% = $8.84

g = 4%

rrr = 9%

using the perpetuity growth model:

stock price = $8.84 / (9% - 4%) = $8.84 / 5% = $176.80

preferred stock:

Div = $12

rrr = 10%

using the perpetuity formula:

preferred stock = $12 / 10% = $120

Answer:

[tex]0.4\%[/tex]

Step-by-step explanation:

Given: 60% of the boys play baseball and 24% of the boys play baseball and football in Seaton Park School

To find: percentage of those that play baseball also play football

Solution:

Let B denotes boys who play baseball and F denotes boys who play football.

[tex]P(B)=60\%[/tex]

[tex]P(F\cap B)=24\%[/tex]

Percentage of those that play baseball also play football = [tex]P\left ( F|B \right )=\frac{P(F\cap B)}{P(B)}=\frac{24}{60}=\frac{2}{5}=0.4\%[/tex]

Answer:

Value of Henley Inc.'s share is $16.76

Step-by-step explanation:

The present value of the dividends over for the three years and the terminal value of the dividends would give us a fair share price that an investor would pay

Year 1 PV of dividends=$1.10/(1+11%)^1=$0.99  

Year 2 PV of dividends=$1.10/(1+11%)^2=$0.89  

Year 3 PV of dividends=$1.10/(1+11%)^3=$0.80  

The terminal value formula=dividend*(1+g)/(r-g)

g is the dividend growth rate of 5%

r is the investor's required rate of return which is 11%

terminal value=$1.10*(1+5%)/(11%-5%)=$19.25

The terminal is discounted to present value using the discount factor of year 3

PV of terminal value =$19.25 /(1+11%)^3=$ 14.08  

Total present values=$0.99+$0.89+$0.80+$14.08 =$16.76

Answer:

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, [tex]V=x^2h=296352[/tex]

[tex]h=\dfrac{296352}{x^2}[/tex]

Surface Area of the box = Base Area + Area of 4 sides

[tex]A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}[/tex]

Step 2: Find the derivative of A(x)

[tex]If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}[/tex]

Step 3: Set A'(x)=0 and solve for x

[tex]A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84[/tex]

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

[tex]A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6[/tex]

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

[tex]h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42[/tex]

Therefore, the dimensions that minimizes the box surface area are:

Answer: the answer will be 7

Step-by-step explanation:

when i round my answer to the nearest tenths I got 7.

My first answer is 6.66666666667

then I round my answer and got 7 because 6 is bigger than 5 so i can put it as a whole number.

Answer: the answer will be 7

Step-by-step explanation:

when i round my answer to the nearest tenths I got 7.

My first answer is 6.66666666667

then I round my answer and got 7 because 6 is bigger than 5 so i can put it as a whole number.

Answer:

-3

Step-by-step explanation:

Answer:

[tex](x-4)^2 + y^2= 100[/tex]

Step-by-step explanation:

edgenuity 2020

hope this helps!

Answer:

An = A0 + 100 * n - (An-1) * 0.10

Step-by-step explanation:

Tenemos una regla recursiva para una secuencia es una fórmula que nos dice cómo avanzar de un término a otro en una secuencia. Por lo tanto debemos buscar a An.

Hay un valor inicial que es 5000, una ganancia y una perdida de clientes, que podemos representar así:

An = 5000 + Ganancia - Perdida

Inicial = A0 = 5000

Ganancia = 100, pero cómo sucede cada año, sería: 100 * n

Perdida = 10% de los miembros actuales, si al principio son 5000 por lo tanto A0 * 0.10, pero en este primer caso es que es A0, pero en general serían An-1

reemplazando:

An = A0 + 100 * n - (An-1) * 0.10

Answer:

131,200 units

Step-by-step explanation:

The number of units transferred to Department 2 from Department 1 is the total units to be accounted for  which is 180,200 units minus the ending work in process of 49,000 units.

The logic here is that Department 1 is to account for 180,200 units ,part of which is the ending working process while the remainder which was transferred out is the difference between the two figures

units transferred to Department 2=180,200-49,000= 131,200.00  units

Answer:

A. x - 3

Step-by-step explanation:

Set it up like this:

(3x - 2) - (2x + 1)

Combine like terms:

3x - 2 - 2x - 1

3x - 2x = x

-2 - 1 = -3

Put it together:

x - 3

Answer:

Zero(s) of multiplicity one: 11,-9

Zero(s) of multiplicity two: None

Zero(s) of multiplicity three: 5

Step-by-step explanation:

Suppose that we have a polynomial function in the following format:

[tex]f(x) = a*(x - x_{0})^{m_{0}}*(x - x_{1})^{m^{1}}*...*(x - x_{n})^{m^{n}}[/tex]

The zeros are [tex]x_{0}, x_{1}, ..., x_{n}[/tex].

The multiplicites are [tex]m_{0}, m_{1},..., m_{n}[/tex]

In this question:

f(x) = 4(x -11) (x + 9) (x - 5)^3

So

11 is a zero of multiplicity 1

-9 is a zero of multiplicity 1

5 is a zero of multiplicity 3.

So the answer is:

Zero(s) of multiplicity one: 11,-9

Zero(s) of multiplicity two: None

Zero(s) of multiplicity three: 5

Answer:

[tex]\frac{2}{13}[/tex]

Step-by-step explanation:

There are 4 suits in a standard deck of cards.

Each suit has a king and a queen.

Thus there are 4 kings and 4 queens

P(king) = [tex]\frac{4}{52}[/tex] = [tex]\frac{1}{13}[/tex]

P(queen) = [tex]\frac{4}{52}[/tex] = [tex]\frac{1}{13}[/tex]

P( king) or P(queen) = [tex]\frac{1}{13}[/tex] + [tex]\frac{1}{13}[/tex] = [tex]\frac{2}{13}[/tex]

Answer:

They should charge a price of $4.85 so that they'll break even.

Step-by-step explanation:

The expected value will be the sum of the net values multiplied by it's probabilities.

1% of their products will fall after the original warranty period but within 2 years of the purchase, with a replacement cost of $480.

So in 1% = 0.01 of the cases, the company loses $480. That is, a net value of -480.

In 99% = 0.99 of the cases, the company makes x.

The expected value is 0.

We have to find x.

So

[tex]0.99x - 0.01*480 = 0[/tex]

[tex]0.99x = 0.01*480[/tex]

[tex]x = \frac{0.01*480}{0.99}[/tex]

[tex]x = 4.85[/tex]

They should charge a price of $4.85 so that they'll break even.

Answer:

Rate = 51.74%

Step-by-step explanation:

Principal amount= $48000

Amount paid is done 2 times in a year for ten years

= $4000*2*10

Amount paid= $80000

A= p(1+r/n)^nt

80000= 48000(1+r/20)^(20*10)

(80000/48000)= (1+r/20)^(200)

(200)√(1.6667)= 1+ r/20

1.025870255-1= r/20

0.025870255*20= r

0.5174= r

Rate in decimal= 0.5174

In percentage= 51.74%

Answer: -1

Step-by-step explanation:

Here is the complete question:

Brittany rents bicycles to tourists. She recorded the height (in cm) of each customer and the frame size (in cm) of the bicycle that customer rented. After plotting her results, Brittany noticed that the relationship between the two variables was fairly linear, so she used the data to calculate the following least squares regression equation for predicting bicycle frame size from the height of the customer: y'=1/3x + 1/3.

What is the residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame?

The regression equation is given as:

y'=(1/3)x + (1/3)

Since the height is given as 155cm, x=155 cm

The predicted frame size,

y'=(1/3)x + (1/3)

y'=(1/3) × 155+ (1/3)

= 51 2/3 + 1/3

= 52

The observed frame size,

y=51

Residual = Observed y- predicted y

=51-52

= -1

The residual of a customer with a height of 155 cm who rents a bike with a 51 cm frame is -1.

Answer:

-1

Step-by-step explanation:

Answer:

40m

Step-by-step explanation:

5.25 divided by 1.75=3

120 divided by 3=40

Answer:444+555=999 then(999)^3=9970029999.97*10^8

Step-by-step explanation:

Answer:

the anwser is c

Step-by-step explanation:

Answer:

Suppose that a white ball is selected, the probability that the coin landed tails = (12/37) = 0.3243

Step-by-step explanation:

Complete Question

Urn A has 5 white and 7 black balls. Urn B has 3 white and 12 black balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed tails?

Solution

Let the probability of that a head turns up and urn A is selcted be P(A) = (1/2)

Probability that a tail turns up and urn B is selected = P(B) = (1/2)

Probability that a white ball is picked = P(W)

The probability that a white ball is picked given that the coin toss gives a head and urn A is selected = P(W|A) = (5/12)

The probability that a white ball is picked given that the coin toss gives a tail and urn B is selected = P(W|B) = (3/15) = (1/5)

We now require the probability that the coin lands on a tail and urn B is selected given that a white ball is picked, P(B|W)

Note that the conditional probability P(X|Y) is expressed mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

And P(X n Y) = P(X|Y) × P(Y)

Hence, the required probability

P(B|W) = P(B n W) ÷ P(W)

Although, we do not have the probabilities P(B n W) and P(W), we can calculate them

P(B n W) = P(W n B) = P(W|B) × P(B) = (1/5) × (1/2) = (1/10)

P(W) = P(W n A) + P(W n B) (Since the events A and B are mutually exclusive)

P(W n A) = P(W|A) × P(A) = (5/12) × (1/2) = (5/24)

P(W n B) = (1/10)

P(W) = (5/24) + (1/10) = (37/120)

P(B|W) = P(B n W) ÷ P(W) = (1/10) ÷ (37/120) = (12/37) = 0.3243

Hope this Helps!!!

Answer:

x = 24

Step-by-step explanation:

Of means multiply and is means equals

1/4 * x = 6

Multiply each side by 4

1/4*4 x = 6*4

x = 24

Answer:

idk

Step-by-step explanation:

Answer:

pounds

Step-by-step explanation:

pounds : ounces

   10      :      [tex]x[/tex]

    1        :     16

[tex]x=160[/tex]

The numerator would be pounds. [tex]\frac{10 pounds}{160 ounces}[/tex]

Answer:

The object hits the ground 5 seconds after being launched.

Step-by-step explanation:

The height of the object in t seconds after being launched is given by the following equation:

[tex]h(t) = 80t - 16t^{2}[/tex]

When will the object hit the ground after it is launched?

This is t for which h(t) = 0.

So

[tex]80t - 16t^{2} = 0[/tex]

[tex]16t(5 - t) = 0[/tex]

Then

[tex]16t = 0[/tex]

[tex]t = 0[/tex]

This is the launch point

[tex]5 - t = 0[/tex]

[tex]t = 5[/tex]

So

The object hits the ground 5 seconds after being launched.

Answer:

The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds.

Step-by-step explanation:

This is the exact answer on edg 2020

Answer:

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

Step-by-step explanation:

It is said that Actuary Rahul examines a low risk policy

Probability of a low risk policy having a claim = 10% = 0.1

Actuary Toby examines high risk policy

Probability of a high risk policy having a claim = 20% = 0.2

Let the number of policies examined by actuary Rahul before he finds a claim and stop be n

Probability that actuary Rahul examines exactly n policies =  [tex]0.9^{n-1} (0.1)[/tex]

Probability that Toby examines more than n policies = [tex]0.8^n[/tex]

Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = [tex]0.9^{n-1} (0.1) (0.8)^n[/tex]

probability that both events happen simultaneously = [tex]\frac{0.1}{0.9} (0.72^{n})[/tex]

The probability that Actuary Rahul examines fewer policies that Actuary Toby = [tex]\sum\limits^ \infty_1 {\frac{0.1}{0.9} 0.72^{n} }[/tex] = [tex]\frac{1}{9}\sum\limits^ \infty_1 { 0.72^{n} } = \frac{1}{9} (\frac{0.72}{1-0.72} ) = \frac{1}{9} (\frac{0.72}{0.28} )[/tex]

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

Answer:

[tex]1-7i[/tex]

Step-by-step explanation:

[tex]\left(1+i\right)\left(-3-4i\right)[/tex]

[tex]=\left(1\cdot \left(-3\right)-1\cdot \left(-4\right)\right)+\left(1\cdot \left(-4\right)+1\cdot \left(-3\right)\right)i[/tex]

[tex]1\cdot \left(-3\right)-1\cdot \left(-4\right)[/tex]

[tex]=-3+4[/tex]

[tex]=1[/tex]

[tex]1\cdot \left(-4\right)+1\cdot \left(-3\right)[/tex]

[tex]=-4-3[/tex]

[tex]=-7[/tex]

[tex]=1-7i[/tex]

Answer:

a) zw = 8 (Cos 40° + i Sin 40°)

b) (z/w) = 2 (Cos 260° + i Sin 260°)

Step-by-step explanation:

z = 4(Cos 150° + i Sin 150°)

w = 2 (Cos 250° + i Sin 250°)

To first simplify,

Cos 150° = -0.8660

Sin 150° = 0.50

Cos 250° = -0.3420

Sin 250° = -0.9397

z = 4(Cos 150° + i Sin 150°)

z = 4 (-0.866 + 0.5i)

z = (-3.464 + 2i)

w = 2 (Cos 250° + i Sin 250°)

w = 2 (-0.342 -0.9397i)

w = (-0.684 - 1.8794i)

a) zw = (-3.464 + 2i) (-0.684 - 1.8794i)

zw = 2.369376 + 6.5102416i - 1.368i - 3.7588i²

Note that i² = -1

zw = 2.369376 + 5.1422416i + 3.7588

zw = (6.128176 + 5.1422416i)

A general complex number z = x + it has the Polar form = r (cos θ + i sin θ)

r = √(x² + y²)

θ = arctan (y/x)

zw = (6.128176 + 5.1422416i)

x = 6.128176

y = 5.1422416

r = √(6.128176² + 5.1422416²) = 7.99997 = 8

θ = arctan (5.1422416/6.128176) = 40°

zw = 8 (Cos 40° + i Sin 40°)

b) (z/w) = (-3.464 + 2i) / (-0.684 - 1.8794i)

To simplify This, we first rationalize, that is, multiply numerator and denominator by (-0.684 + 1.8794i)

(z/w) = [(-3.464 + 2i)×(-0.684 + 1.8794i)] ÷ [((-0.684 - 1.8794i)×((-0.684 + 1.8794i)

(z/w) = [2.369376 - 6.5102416i - 1.368i + 3.7588i²] ÷ [0.467856 - 3.53214436i²]

Note that i² = -1

(z/w) = [2.369376 - 3.7588 - 7.8782416i] ÷ [0.467856 + 3.53214436]

(z/w) = (-1.389424 - 7.8782416i)/4

(z/w) = (-0.347356 - 1.9695604i)

x = -0.347356

y = -1.9695604

r = √[(-0.347356)² + (-1.9695604)²] = 1.9997 = 2

θ = arctan (-1.9695604)/(-0.347356) = 80° on the first quadrant, but the signs on x and y indicates that this is the third quadrant, hence

θ = 180° + 80° = 260°

(z/w) = 2 (Cos 260° + i Sin 260°)

Hope this Helps!!!

Answer:

Step-by-step explanation:

(a) Hail storms in western Kansas are a rare occurrence. It is reasonable to assume the events are independent

(b) The required [tex]\lambda[/tex] = 1.7 * 10/5 = 3.4

(c) P(r ≥ 4 | r ≥ 2)

= P(r ≥ 4)/P(r ≥ 2)

= {1 - P(r < 4)}/{1 - P(r < 2)}

For Poisson distribution, P(X = x)

[tex]= \frac{e^{- \lambda} \lambda ^x}{x !}[/tex]

Thus, P(r < 4) = P(r = 0) + P(r = 1) + P(r = 2) + P(r = 3)

= 0.5584

and P(r < 2) = P(r = 0) + P(r = 1) = 0.1468

Thus, P(r ≥ 4 | r ≥ 2) = (1 - 0.5584)/(1 - 0.1468)

= 0.5177

(d) P(r < 6 | r ≥ 3)

= P(3 ≤ r < 6)/P(r ≥ 3)

P(3 ≤ r < 6) = P(r = 3) + P(r = 4) + P(r = 5) = 0.5308

P(r ≥ 3) = 1 - {P(r = 0) + P(r = 1) + P(r = 2)}

= 0.6603

Thus, P(r < 6 | r ≥ 3) = 0.5308/0.6603 = 0.8309

Answer:

The answer is commutative and associative.

Step-by-step explanation:

Answer:

Total distance traveled is 100 miles

Step-by-step explanation:

The man will drive half of the trip on the first day, therefore, distance that will be traveled on the first day = 0.5x

where x is the total distance of the trip.

On the second day, he will drive half of the remaining half of the distance, i.e he will drive 0.5 x 0.5x = 0.25x

This implies that the total distance that will be traveled traveled in the final two days of the journey will also be 0.5 x 0.5x = 0.25x.

0.5x + 0.25x + 0.25x = x, which is the total distance traveled.

on the third day he will drive 4 times the distance of the fourth day, therefore, distance that will be traveled on the third day = 4 x 5 = 20 miles

on the fourth day, he will drive 5 mile.

total of the last two days = 5 + 20 = 25 miles.

this 25 miles is equal to 0.25 of the whole trip. Equating these values, we have

0.25x = 25 miles

x = 25/0.25 = 100 miles

Answer:

250 miles

Step-by-step explanation:

d= sxt

d= 125x2

125x2= 250

or

mph= miles per hour

there are two hours so 125 +125 =250

Answer=250 miles