Answer:
a. 50 m/s b. 0 m/s c. 50 m/s d. 4.04 s e. -39.6 m/s f. 63.78 m/s g. 202 m
Explanation:
a. What is the initial horizontal velocity?
Since the object is launched horizontally, it initial horizontal velocity is 50 m/s
b. What is the initial vertical velocity?
Since the object is launched horizontally, it has no initial vertical component. So, its initial vertical velocity is 0 m/s
c. What is the final horizontal velocity?
Its final horizontal velocity is 50 m/s since no force acts on it in the horizontal direction to change its value.
d. How much time did it take for the object to hit the ground?
We use the equation s = ut - 1/gt² since the object is falling under gravity where u = initial vertical velocity = 0 m/s, s = height of cliff = 80 m, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the object to hit the ground.
s = ut - 1/2gt²
80 m = 0 × t - 1/2 × -9.8 m/s² × t²
80 m = 4.9 m/s² × t²
t² = 80 m ÷ 4.9 m/s²
t² = 16.33 s²
t = √(16.33 s²)
t = 4.04 s
e. What is the final vertical velocity?
Using v = u + at where u = initial vertical velocity = 0 m/s, v = final vertical velocity, a = acceleration = -g = -9.8 m/s²and t = time it takes object to reach the ground = 4.04 s.
Substituting these values into the equation, we have
v = u + at
v = 0 m/s + (-9.8 m/s²) × 4.04 s
v = -39.6 m/s
f. What is the final resultant speed?
The final resultant speed v' is the resultant of the final horizontal velocity and the final vertical velocity. Let u' = final vertical velocity = 50 m/s.
v' = √(u'² + v²)
v' = √((50 m/s)² + (-39.6 m/s)²)
v' = √(2500 m²/s² + 1568.16 m²/s²)
v' = √(4068.16 m²/s²)
v' = 63.78 m/s
g. How far from the base of the cliff will the projectile land?
The distance from the base of the cliff, d where the projectile lands is
d = u't where u' = horizontal velocity = 50 m/s and t = time it takes object to land = 4.04 s
d = 50 m/s × 4.04 s
d = 202 m
A spacecraft is traveling in space at a velocity of 8200 m's. Turning a dial elicits the engines to accelerate the spacecraft at 2 m/s. How many seconds will it take
before the spacecraft reaches a velocity of 8400 m's?
A speeding car is traveling at a constant 30.0 m/s when it passes a sationary police car. If the police car delays for 1.00s before starting, what must be the magnitude of the constant accleration of the police car. pdf
Answer:
30.0m/s²Explanation:
Given
final speed v = 30.0m/s
initial velocity u = 0m/s
Time taken t = 1.00s
Required
constant acceleration of the police car a
Substitute the given parameters into this equation of motion
v = u + at
30 = 0 +1a
30 = a
a = 30.0m/s²
Hence the magnitude of the constant acceleration of the police car is 30.0m/s²
Science Motion Problem pelase elp
Answer:120
Vav = S / t = (120 + 45) m / (4 + 60) sec = 2.6 m/s
Physics Freefall Name 1. You decide to drop a penny from the top of the hotel in New York. It hits a tourist in the head at 32 m/s. How far did the penny fall
Answer:
h = 52.24 m
Explanation:
Given that,
A penny is dropped from the top of the hotel in New York. It hits a tourist in the head at 32 m/s.
Let it falls at a height of h.
We can find the value of h using the conservation of energy such that,
[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(32)^2}{2\times 9.8}\\\\h=52.24\ m[/tex]
So, it will fall at a distance of 52.24 m.
5.3C The nozzle on a fire hose is connected to the hose via a coupling. When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is: a) in equilibrium, so there is no force on the coupling. b) in tension. c) in compression
Answer:
Tension ( B )
Explanation:
When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is in TENSION , this is because the force of flow in a stationary object will be in a compressive nature that will in turn cause the force on the coupling to be in a form of a Tension ( i.e. Tensile )
How do mass and the type of material affect thermal energy transfer?
Answer:
Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. ... Heat is the transfer of thermal energy between objects that have different temperatures.
the whale shark is the largest of all fish and can have the mass of 3 adult elephants. suppose that a crane is lifting a whale shark into a tank for delivery to an aquarium. The crane must exert a force of 25000 N to lift the shark from rest. if the sharks acceleration equals 1.25m/s^2, what is the sharks mass ?
Answer: The whale shark is the largest type of fish in the world. Its mass can be as large as 2.00 x 10^4kg, which is the equivalent mass of three average adult elephants. Suppose a crane lifts a net with a 2.00 x 10^4kg whale shark off the ground. The net is steadily accelerated from rest over an interval of 2.5s until the net reaches a speed of 1.0 m/s.
Explanation:
It takes an airplane nearly 3/4 of a mile to stop. Which law is being used?
A) Newton's first law
B) Newton's second law
C) Newton's third law
D) Law of conservation of momentum
E) Law of universal gravitation
Answer:
I think it is D
Explanation:
might be wrong
Calculate the rms speed of helium atoms near the surface of the Sun at a temperature of about 5200 K.
Answer: Root mean square speed, Vrms=5,694m/s
Explanation:
Root mean square speed is defined as the the square root of the average of the square of the velocity and given as [tex]\sqrt 3RT/M[/tex]
Where R =8.3145J/mol.k
M molar mass of the molecule in kg/mol
Helium= He=4g/mol = 0.004kg/mol
T= Temperature = 5200k
Vrms= [tex]\sqrt 3RT/M[/tex]
=[tex]\sqrt 3 x 8.3145 x 5200/0.004[/tex]
=[tex]\sqrt32426550[/tex]
Vrms =5,694m/s
If George Washington had become "King of America," our government might have become?
Answer:
Monachry
Explanation:
Hope this helped!!!
I need help with this science work.
Answer:
1. Radiation
2. Conduction
3. Conduction
4. Convection
5. Convection
6. Convection
7. Radiation
A conveyor belt dumps 2500 yd3 of gravel to form a cone-shaped pile. How high could this pile of gravel be, and what could the circumference of the pile of gravel be at ground level
Answer:
Explanation:
Volume of the cone = 1/3πr²h
r is the radius
h is the height
2500 = 1/3πr²h
Criss multiply
r²h = 2500 × 3π
Rewrite the expression
r²h = 50² × 3π
Compare values
r² = 50²
r = √50²
r = 50yd
The radius is 50yards
Also;
h = 3π yards
h = 3(3.14)
h = 9.42yards
Hence the pile is 9.42yards high
Circumference of the pile = 2πr
Given r = 50
Substitute
Circumference = 2π(50)
Circumference = 100π
Circumference = 100(3.14)
Circumference = 314yards
Hence the circumference of the pile at the ground level is 314yards
hello what is momentum?
Answer:
Momentum is vector quantity and it is defined as the product of mass of the object and velocity of the object.
As it is a vector quantity it has both direction and magnitude, and momentum is written as
p = m × v
p = momentum
m = mass of the object
v = velocity
Two kinds of momentum are there and they are:
Linear MomentumAngular MomentumPLEASE HELPP WITH QUESTIONS :(
Answer:no
Explanation: lol
A man accelerates at 2.52 m/s2 for 3.73s. If his initial velocity was 1.75 m/s, what is his final velocity?
Answer:
Final Velocity = 11.15 m/s
Explanation:
By using the equation v = u + at we can find the answer.
v = final velocity
u = initial velocity
a = acceleration
t = time
Plug the numbers in and you get 11.15 m/s, hope this helps!
Two ropes are tied to a 50 kg boat. One pulls with a force of 120 N due West and the other rope pulls with a force of 140 N due South. Find the net force of the boat (magnitude and direction) and the acceleration.
The net force on the boat is the vector
F = (-120 N) i + (-140 N) j
where we take West and South to be the negative directions going left-and-right and up-and-down, respectively.
The magnitude of the net force is
F = √((-120 N)² + (-140 N)²) = 20 √(85) N ≈ 180 N
and its direction is
tan(θ) = (-140 N) / (-120 N) → θ ≈ -130°
relative to due East, or approximately 50° South of West.
Problem 6 (20 points) A ballistic pendulum is a device often used for measuring the velocity of a projectile. Assume to projectile fully embeds itself in the pendulum. If the projectile mass is 25 grams, the pendulum mass is 2.5 kg, and the vertical displacement of the pendulum after the collision is 12 cm, find the velocity of the projectile just prior to the collision.
Answer:
The velocity of the projectile just prior to the collision is 154.934 meters per second.
Explanation:
Let consider the projectile-pendulum system as our system of study, from statement we know that projectile gives kinetic energy to the pendulum and turns into gravitational potential energy. By Principle of Energy Conservation we construct the following expression:
[tex]U_{g,1}+K_{1} = U_{g,2}+K_{2}[/tex] (Eq. 1)
Where:
[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Initial and final gravitational potential energies, measured in joules.
[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies, measured in joules.
By applying definitions of gravitational potential and kinetic energies, we expand and simplify the equation above:
[tex](m+M)\cdot g \cdot (y_{2}-y_{1}) = \frac{1}{2}\cdot (m+M)\cdot (v_{1}^{2}-v_{2}^{2})[/tex]
[tex]g\cdot (y_{2}-y_{1})=\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex]
And we clear the initial velocity of the pendulum-projectile system:
[tex]v_{1}=\sqrt{v_{2}^{2}+2\cdot g\cdot (y_{2}-y_{1})}[/tex] (Eq. 2)
Where:
[tex]m[/tex] - Mass of the projectile, measured in kilograms.
[tex]M[/tex] - Mass of the ballistic pendulum, measured in kilograms.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the pendulum-projectile system, measured in meters per second.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]y_{1}[/tex], [tex]y_{2}[/tex] - Initial and vertical position of the pendulum-projectile system, measured in meters.
Under the consideration of inellastic collision, we find the velocity of the projectile prior to the collision by Principle of Linear Momentum Conservation:
[tex]m\cdot v_{o, P} + M\cdot v_{o,B} = (m+M)\cdot v_{1}[/tex]
[tex]v_{o,P} = \frac{(m+M)\cdot v_{1}-M\cdot v_{o,B}}{m}[/tex] (Eq. 2)
Where:
[tex]v_{o, P}[/tex] - Velocity of the project prior to the collision, measured in meters per second.
[tex]v_{o,B}[/tex] - Velocity of the ballistic pendulum prior to the collision, measured in meters per second.
If we know that [tex]v_{2} = 0\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y_{2}-y_{1} = 0.12\,m[/tex], [tex]m = 0.025\,kg[/tex], [tex]M = 2.5\,kg[/tex] and [tex]v_{o,B} = 0\,\frac{m}{s}[/tex], then the velocity just prior to the collision is:
By (Eq. 1):
[tex]v_{1} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.12\,m)}[/tex]
[tex]v_{1} \approx 1.534\,\frac{m}{s}[/tex]
By (Eq. 2):
[tex]v_{o,P} = \frac{(0.025\,kg+2.5\,kg)\cdot \left(1.534\,\frac{m}{s} \right)-(2.5\,kg)\cdot \left(0\,\frac{m}{s} \right)}{0.025\,kg}[/tex]
[tex]v_{o,P} = 154.934\,\frac{m}{s}[/tex]
The velocity of the projectile just prior to the collision is 154.934 meters per second.
How long will it take an object that falls from rest to attain a velocity of 147 m/s?
Answer:
15 seconds
Explanation:
We can use this formula to solve this problem:
Velocity = Initial Velocity + Acceleration * Time
We know that initial velocity is 0, the velocity is 147, and acceleration is 9.8(because of earth's gravitational pull), so we can plug those numbers in and solve for time:
147 = 0 + 9.8*t
t = 15
Therefore, it will take 15 seconds for an object that falls from rest to reach 147 m/s.
In theory, if the airspeed of an airplane is doubled while in level flight, parasite drag will become
Answer:
Four times greater
Explanation:
Drag is comprised of parasite drag and induced drag. The Parasite drag is the drag that acts on an object when the said object happens to be moving through a fluid. Parasite drag is also a combination of two forms of drag. These two forms of drag are called form drag and skin friction drag.
As the speed of an airplane increases, the parasite drag also increases while the induced drag of the airplane decreases. The parasite drag of an airplane in theory becomes four times greater, when it's airspeed is doubled.
If somebody asks me if i need help on my work and i say " no ty " , is that rude???
Answer:
no
Explanation:
what is the answer to life and everything in the universe?
Neil travelled 36km at a speed of 8km/h Grant travelled 48km at a speed of 10km/h whose journey was quickest
Answer:
[tex]\boxed {\tt Neil's \ journey}[/tex]
Explanation:
We want to find who travelled faster, so we must find the time for each person's journey. Time can be found by dividing distance by speed.
Neil
[tex]t=\frac{d}{s}[/tex]
Neil travelled 36 kilometers at a speed of 8 kilometers per hour.
[tex]d= 36 \ km \\s= 8 \ km/hr[/tex]
[tex]d=\frac{36 \ km}{8 \ km/hr}[/tex]
Divide (the kilometers or "km" will cancel each other out).
[tex]d=4.5 \ hr[/tex]
Grant
[tex]t=\frac{d}{s}[/tex]
Grant travelled 48 kilometers at a speed of 10 kilometers per hour.
[tex]d= 48 \ km \\s= 10 \ km/hr[/tex]
[tex]d=\frac{48 \ km} { 10 \ km/hr}[/tex]
Divide (the kilometers or "km" will cancel each other out).
[tex]d=4.8 \ hr[/tex]
Neil's journey took 4.5 hours and Grant's took 4.8 hours. We want to find the journey that was quicker and 4.5 is less than 4.8. So Neil's journey was quicker.
I WILL MARK YOU AS BRAINLIEST IF RIGHT
What is the magnitude of the net force acting on this object? And what direction?
Answer:
20N to the North
Explanation:
the west and east forces cancel out, that leaves us with 50 to the north, and 30 to the south, the difference would be 20 N to the North
An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the object is 1.54 m/s, and its maximum acceleration is 8.13 m/s2. How much time elapses betwen an instant when the object's speed is at a maximum and the next instant when its acceleration is at a maximum
Answer:
Explanation:
The spring will move under SHM .
Maximum speed is at the middle equilibrium position . Maximum acceleration is when the particle is at one of the extreme position . So time gap between the two position is one fourth of time period of oscillation .
= T / 4
If A be the amplitude and ω be angular velocity
ω A = maximum velocity = 1.54
ω² A = maximum acceleration = 8.13
dividing
ω = 5.28
2π / T = 5.28
T = 1.189
T / 4 = 0.3 s.
A biker pushes on the pedal and accelerates her 50 kg bike from 0 m/s to 10 m/s. What is the the impulse?
Answer:
3.7
Explanation:
A bus is moving to the right at an absolute velocity U. You throw a water balloon at the bus at an absolute velocity V (greater than U) after the bus passes you. A person on the bus sees the balloon hit the bus at a speed of:
Answer:
The person on the bus will see the balloon hit the bus at a velocity = V - U
Explanation:
There is relative motion between the water balloon and the person sitting in the bus.
Relative motion is the motion of a body with respect to another body (eg. an observer) from the point of reference of the second body (observer).
The person on the bus has a velocity which is the same as that of the moving bus = U
The velocity of the thrown water balloon (greater than U) = V
The relative motion between the person and the water balloon is the difference between their velocities (since they are both moving in the same direction) = V - U
Therefore, the person on the bus will see the balloon hit the bus at a velocity = V - U
How can humans detect infrared waves?
А
They see them as color.
B
They feel them as heat.
с
They hear them as sound.
D
They feel them as vibrations.
Determine the required height h of the crest of the roller coaster to thebottom so that when it is essentially at rest at the crest of the hill it will reacha speed of 28 m/s when it comes to the bottom.
Answer:
h = 40 m
Explanation:
Assuming no friction present, total mechanical energy must be conserved, so the following expression stands:ΔK + ΔU = 0 (1)Now, if the car is at rest at the crest of the hill, the change in kinetic energy is just as follows:[tex]\Delta K = \frac{1}{2} * m* v_{b} ^{2}[/tex] (2)
where vb = speed at the bottom = 28 m/s
If we define the bottom as our zero reference level for the gravitational potential energy, we can write the following equation:[tex]\Delta U = U_{f} - U_{i} = 0- m*g*h = -m*g*h[/tex] (3)
From (1) we get:ΔK = -ΔUReplacing by (2) and (3), we get:[tex]\frac{1}{2} * m* v^{2} = m*g*h[/tex]
Simplifying and rearranging terms, we can solve for h (height required) as follows:[tex]h = \frac{v_{b} ^{2} }{2*g} = \frac{(28m/s)^{2}}{2*9.8m/s2} = 40 m[/tex]
PLS HELP PLS 10. This graph represents the velocity of an object over time. What is the average acceleration of the
object during the first 4 seconds?
Answer:
8 M/S
Explanation:
This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.
find the current of 20 c of charge pass a piticular point in a circuit in 10 seconds
