The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Given point: [tex](-2,2)[/tex]
Given systems:
[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]To find: The system to which the given point is a solution
If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.
(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,
[tex]2>-2(-2)+2[/tex]
[tex]2>4+2[/tex]
[tex]2>6[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,
[tex]2<-2+2[/tex]
[tex]2<0[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,
[tex]2<2(-2)+8[/tex]
[tex]2<-4+8[/tex]
[tex]2<4[/tex]
This is a true inequality. Then, the given point satisfies the first inequality of the system.
We will now check if the point satisfies the second inequality of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,
[tex]2 \geq -(-2)-3[/tex]
[tex]2 \geq 2-3[/tex]
[tex]2 \geq -1[/tex]
This is also a true inequality. Then, the given point also satisfies the second inequality of the system.
Thus, the given point is a solution of this system.
(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,
[tex]2<2(-2)+3[/tex]
[tex]2<-4+3[/tex]
[tex]2<-1[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.
Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].
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a giraffe can run 32 miles per hour. what is this speed in feet per second?
Answer:
46.9 ft/sec
Step-by-step explanation:
A giraffe can run 32 miles per hour. What is this speed in feet per second? Round your answer to the nearset tenth.
HELP PLS PLS PLS PLS
now that I have your attention help me answer this question:
Team A built 8 sandcastles in 2 hours and Team B built 5 sandcastles in 1 hour. Which team worked at a faster rate?
if you convert it all into one hour, Team B clearly worked at a faster pace.
Answer:
[tex]team \: a \: \\ 8in \: number \: with \: in \: 2 \: hours \\ so \: in \: 1 \: hour \: \frac{8}{2} = 4 \: in \: number \\ \\ team \: b \\ 5 \: in \: 1hour \\ so \: \: team \: b \: work \: in \: fast \\ thank \: you[/tex]
trigonometric identities
With 180° < θ < 270°, we know that both cos(θ) < 0 and sin(θ) < 0.
Then from the Pythagorean identity, it follows that
sin²(θ) + cos²(θ) = 1 ==> sin(θ) = -√(1 - cos²(θ))
and so
sin(θ) = -√(1 - (-8/13)²) = -√105/13
Recall the double angle identity for sine:
sin(2θ) = 2 sin(θ) cos(θ) = 2 (-√105/13) (-8/13) = 16√105/169
21. Andre grew a plant for a science experiment. At the end of his
experiment, the plant was 100.8 centimeters tall. Andre calculated
that the plant grew an average of 3.6 centimeters per day since
the start of his experiment. How many days did Andre's
experiment last?
Answer:
he answer is 140 minutes to plant 14 saplings.
Step-by-step explanation:
30 divided by 3=10
so it takes 10 minutes to plant one sapling.
10x14=140 so this is how you get your answer. im 99% sure
Answer:
100.8÷3.6=28
he grew the plant for 28 days
A retailer allowed 12% discount and sold a T- shirt at a loss of Rs 16. if he had sold it at 10% discount he would have gained Rs 20.for what price did he purchased the T- shirt.
Answer:
rs. 100
Step-by-step explanation:
Please Help
The students in a high school are being randomly split into focus and accountability groups that meet each morning for the first fifteen minutes of the school day. Each group contains four students, selected regardless of gender or grade level.
In order to explore the composition of the groups with regard to grade level, you have decided to conduct a simulation using colored discs. Since the number of students in each grade level is about the same, you put the same number of four different colored discs in a bag: red, blue, green, and yellow. You decide that red (r) represents the freshmen, blue (b) represents the sophomores, green (g) represents the juniors, and yellow (y) represents the seniors.
Next, you randomly select one disc from the bag, record the color, and put the disc bag in the bag. You do the same thing three more times to represent one group. Then, you complete this entire process twenty-five times, as shown below.
Based on the results of the simulation, the chances of a group having at least one senior is:
likely
unlikely
neither unlikely or likely
19/25 which is likely
count the ones with y and put that over 25
what is the slope in the linear equation y = 2x=1?
Answer:
The slope of the line is 2
Step-by-step explanation:
y=2x+1, compare it to the slope intercept form of a line, y=mx+c, the slope will be 2
Answer:
its 2
comment for more understanding
Good luck
5^-4 over 5^3
simplify
A. 5^7
B. 5^-1
C. 1/5
D. 1/5^7
Answer:
D is the correct answer.
helphelphelphelphelphelp
Answer:
see image
Step-by-step explanation:
2.5 kg of oranges cost $ 1.40, what is the cost of
1 kg of orange?
the ratio of 62 miles to 100 kilometers
9514 1404 393
Answer:
0.99779328
Step-by-step explanation:
The exact conversion factor is ...
1 mi = 1.609344
Then 62 miles is 62×1.609344 km = 99.779328 km.
The ratio of this to 100 km is ...
99.779328/100 = 0.99779328 . . . . ratio of 62 miles to 100 km
HELP!!! I will give brainliest, 25 points!!
Mu Alpha Theta, a math honorary club, wants to raise money. The club plans to sell cards and bouquets of flowers for Valentine's Day. Cards cost the club $2 each; bouquets cost the club $3.50 each. Mu Alpha will sell the cards for $6 each, and the flowers for $8 each. The club can spend $360 to buy the cards and the flowers. It wants to collect $900 from its sales. Which linear equation represents this scenario?
A. 2x + 3.5y =360; 6x -8y =900
B. 2x + 3.5y = 360; 8x + 6y = 900
C. 2x - 3.5y = 360; 6x + 8y = 900
D. 2x + 3.5y = 360; 6x + 8y = 900
E. 2x + 6y = 360; 3.5x + 8y = 900
F. No equation.
Answer:
900
Step-by-step explanation:
2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.
We need to find the linear equations for the given situation.
What is the simultaneous equation?Equations involving two or more unknowns that are to have the same values in each equation.
Let the number of cards be x and the number of flowers be y.
Cards cost the club $2 each; bouquets cost the club $3.50 each. The club can spend $360 to buy the cards and the flowers.
Now, 2x+3.5y=360
Mu Alpha will sell the cards for $6 each, and the flowers for $8 each. It wants to collect $900 from its sales.
Now, 6x+8y=900
Therefore, 2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.
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Help me pleaseeeeeeee
Answer:
The surface area is:
276cm^2
Step-by-step explanation:
10x5=50x2=100
4x5=20x2=40
10x4=40x2=80
100+40+80=220
6x2=12x4=48
2x2=4x2=8
48+8=56
220+56=276
Hi can someone help me with these 3 questions. Thanks :)
Answer:
a) 45° cause tan = sin/cos and sin 45 and cos 45 both give square root 2/2
b) 120°
c) sin = -1/2 = -30° or 330° both are same
Use the trig circle which i have included in the answer to better understand trig angles
hope that answers your question
I want to let you know that each angle has sets of coordinates the left number is cos and right is sin. Ex) sin of 30 is 1/2 and cos of 30 is square root 3/2 In case you dont fully understand dont hesitate to comment.
good luck!!
3. the third one please answer ASAP write it on paper, please
Answer:
1/3
Step-by-step explanation:
We have to make the denominator of all fractions to be 15:
Multiply both the 4 and the 5 in 4/5 by 3 to get 12/15.
Nothing has to be done to 3/15.
Next, multiply both the -2 and the 3 in -2/3 by 5 to get -10/15.
Solve:
12/15 + 3/15 - 10/15 = 5/15.
5/15 further simplifies to 1/3.
The final answer is 1/3.
how many solutions in 3(6x-2) = 2(9x-3)
Answer:
Infinite solutions
Step-by-step explanation:
Distribute the numbers
3(6x-2) = 18x - 6
2(9x-3) = 18x - 6
18x - 6 = 18 - 6
Since both sides of the equal sign are the same, that means you can plug any number into x, and it will always be a valid answer.
Triangle QRP is congruent to triangle YXZ. What is the perimeter of triangle YXZ?
What is the perimeter of triangle YXZ?
Answer:
Perimeter of XYZ = Perimeter of QRP
Step-by-step explanation:
Since congruent then
P of XYZ = P of QRP
Find the lateral surface area of the
following prism:
5 cm
5 cm
-apothem = 3.44 cm
5 cm
5 cm
10 cm
5 cm
Answer:
250 cm²
Step-by-step explanation:
Lateral area of the prism is,
5×10×5
= 250 cm²
Lateral surface area of the given prism is equals to [tex]250cm^{2}[/tex].
What is lateral surface area?" Lateral surface area is defined as the sum of area of the all the surfaces except top and bottom of the given geometrical shape."
Formula used
Lateral surface area of pentagonal prism [tex]=5ah[/tex]
[tex]a=[/tex] edge length of the base
[tex]h=[/tex] height of the prism
According to the question,
For the given pentagonal prism,
Edge length of the base [tex]'a' = 5cm[/tex]
Height of the prism [tex]'h' = 10cm[/tex]
Substitute the value in the formula of lateral surface area we get,
Lateral surface area of pentagonal prism [tex]= 5 \times 5\times 10[/tex]
[tex]= 250cm^{2}[/tex]
Hence, lateral surface area of the given prism is equals to [tex]250cm^{2}[/tex].
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Members of a soccer team raised $1946.50 to go to a tournament. They rented a bus for $974.50 and budgeted $60.75 per player for meals. Write and solve an equation which can be used to determine pp, the number of players the team can bring to the tournament.
Answer:
16 players can be brought to the tournament. The equation is written within my step-by-step explanation.
Step-by-step explanation:
Variable p = number of players
Set up an equation:
974.50 + 60.75p = 1946.50
Isolate variable p:
60.75p = 972
Divide:
p = 16
Check your work:
974.50 + 60.75(16) = 1946.50
974.50 + 972 = 1946.50
1946.50 = 1946.50
Correct!
Answer:
Step-by-step explanation:
Please help!!! 25 points!!
-72 + (-30) + 10 =
-72-30+10.
-72-30=-102
10-102 is also the same as
-102+10
The final answer is -92
Answer:
-92
Step-by-step explanation:
-72 + (-30) + 10 =
-72+ -30
Since they both have the same sign, add and then take the sign
72+30 = 102 and then take the negative sign
-102
-102+10
They have opposite signs, so we subtract and take the sign of the larger
102 -10 = 92
And 102 was negative so take the negative sign
-92
Two solid spheres have surface areas of 1441 cm? and 2567 cm² respectively. They are melted and recast to form a larger sphere. Find the surface area of the larger sphere in square centimetres.
Surface area of small sphere = 1441cm^2
Surface area of bigger sphere = 2567cm^2
Surface area of largest sphere = 1441 + 2567
= 4008cm²
Must click thanks and mark brainliest
The diameter of the Moon is 3.5 × 10^3 km.
The diameter of the Sun is 1.4×10^6 km.
Calculate the ratio of the diameter of the Moon to the diameter of the Sun.
Give your answer in the form 1 : n
Answer:
1 : 400
Step-by-step explanation:
[tex]\frac{3.5 x 10^{3} }{3.5 x 10^{3} } : \frac{1.4 x 10^{6 } }{3.5 x 10^{3} }[/tex]
1 : .4 x [tex]10^{3}[/tex]
1 : 4 x [tex]10^{2}[/tex]
1 : 400
Find the value of w in the equation 3w + 15 = 60? Show
your work
. Based on your value of w, what is the value of the expression
below?
8w2 + 8w + 9
PLZ HELPPPP you’ll get all of my points ❤️
Answer:
Part 1: Find w
w=15
Step-by-step explanation:
Part 1: Find w
Step 1:
3w+15=60. If this is true, then first: Subtract 15 from both sides.
Result: 3w=45
Step 2:
3w=45. If this is true, now: Divide by 3 to both sides.
Result/Answer: w=15.
Answer:
Part 2: If w=15, then what is 8w2+8w+9?
8w2+8w+9= Well I have 2 options. If you mean 8w^2+8w+9, then the answer is 14529. If you mean 16w+8w+9, then the answer is 369.
Put the following equation of a line into slope-intercept form, simplifying all
fractions.
15x — бу = 48
Answer:
Step-by-step explanation:
15x-6y=48
-6y=48-15x
y=-8+(15/6)x
y=(5/2)x-8
If m={prime integers between 1 and 11}
N={Factor of 12} find
1. MuN
2.MnN
M = {2, 3, 5, 7} (and possibly includes 11 if "between x and y" means to include both x and y)
N = {1, 2, 3, 4, 6, 12}
Then
M U N = {1, 2, 3, 4, 5, 6, 7, 12}
(or possibly {1, 2, 3, 4, 5, 6, 7, 11, 12})
M ∩ N = {2, 3}
Find the nth term of the arithmetic
sequence - 1,2,5, ....
A. 3n - 2
B. -2n + 1
C. 2n + 2
D. 3n - 4
Answer:
3n -4
Step-by-step explanation:
We are adding 3 each time
-1+3 =2
2+3 = 5
The formula for an arithmetic sequence is
an = a1+d(n-1) where a1 is the first term and d is the common difference
an = -1+3(n-1)
= -1 +3n -3
= 3n -4
a crate of medicine with a density of 167 pounds per cubic foot will ne shipped from the u.s to israel. what is the crates density in kilometers per cubic meter?
9514 1404 393
Answer:
2675.08 kg/m³
Step-by-step explanation:
[tex]\dfrac{167\text{ lb}}{\text{ft}^3}\times\dfrac{0.45359237\text{ kg}}{1\text{ lb}}\times\left(\dfrac{1\text{ ft}}{0.3048\text{ m}}\right)^3\approx\boxed{2675.08\text{ kg/m$^3$}}[/tex]
13. What is x in the diagram?
Answer:
x = 6[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the Altitude- on- Hypotenuse theorem
( leg of large triangle)² = (part of hypotenuse below it) × (whole hypotenuse) , so
x² = 9 × (9 + 3) = 9 × 12 = 108 ( take square root of both sides )
x = [tex]\sqrt{108}[/tex] = [tex]\sqrt{36(3)}[/tex] = [tex]\sqrt{36}[/tex] × [tex]\sqrt{3}[/tex] = 6[tex]\sqrt{3}[/tex]
Please help explanation if possible
Answer:
y= -2x +8
Step-by-step explanation:
perpendicular lines have a negative reciprocal gradient so
1/2 becomes -2/1 which is the gradient
sub in the values of x and y
2= -2 (3) +C
2= -6 + C
8=C
y=-2x +8
Answer:
y = -2x + 8
Step-by-step explanation:
for me the easiest way is simply to transform the slope and then just determine the y-intersect.
the slope of the original line is 1/2.
it is always the factor of x and represents the y/x ratio of the function (how many units is y changing when x changes a certain number of units).
a perpendicular line (90 degree angle) simply reverses x and y and the sign of the original slope.
so, the slope of the perpendicular line is -2, and the equation is
y = -2x + c
and c we get by using the point coordinates :
2 = -2×3 + c
2 = -6 + c
c = 8
so, we have
y = -2x + 8
For each pair of equations, write the letter of the equation that expresses an equal value.
1. a. L = 1 dm3 b. 1 L = 1 cm3
2. a. 1 mL = 1 cm3 b. 1 cm3 = 1 L
3. a. 0°C = –273 K b. 0 K = −273°C
4. a. 1 kg = 100 g b. 1,000 g = 1 kg
5. a. 400 cm = 4.0 m b. 400 cm = 0.40 m
6. a. 1 dm = 10 m b. 1 dm = 0.10 m
7. a. 100°C = 373 K b. 373 K = 10°C
We must understand that certain standards has been layed down for the conversions of measuring units. A summary of such standards are discussed below:
1. Option A. 1 L = 1 dm³
2. Option A. 1 mL = 1 cm³
3. Option B. 0 K = −273 °C
4. Option B. 1000 g = 1 kg
5. Option A. 400 cm = 4.0 m
6. Option B. 1 dm = 0.10 m
7. Option A. 100°C = 373 K
1. Option A. 1 L = 1 dm³
Option B. 1 L = 1 cm³
From standard measurement,
1 L = 1 dm³
1 L = 1000 cm³
From the measuring standard, we can see that 1 L ≠ 1 cm³.
Hence, option A gives the correct answer.
2. Option A. 1 mL = 1 cm³
Option B. 1 cm³ = 1 L
Hence, option A gives the correct answer.
From standard measurement,
1 mL = 1 cm³
1000 cm³ = 1 L
Thus, option A gives the correct answer.
3. Option A. 0°C = –273 K
Option B. 0 K = −273 °C
Recall:
T (K) = T(°C) + 273
T (K) = Temperature in Kelvin
T(°C) = Temperature in decree celcius
Next, we shall convert 0°C to K
T(°C) = 0°C
T (K) = T(°C) + 273
T (K) = 0 + 273
T (K) = 273 K
Thus, 0°C is equivalent to 273 K
Next, we shall convert 0 K to °C
T(K) = 0
T (K) = T(°C) + 273
0 = T(°C) + 273
Collect like terms
0 – 273 = T(°C)
T(°C) = –273°C
Thus, 0 K is equivalent to –273°C
Therefore, option B gives the correct answer.
4. Option A. 1 kg = 100 g
Option B. 1000 g = 1 kg
From standard measurement,
1 Kg = 1000 g
1000 g = 1 Kg
Hence, Option B gives the right answer
5. Option A. 400 cm = 4.0 m
Option B. 400 cm = 0.40 m
From standard measurement,
100 cm = 1 m
Converting 400 cm to m, we have:
[tex]400 cm = 1 m\\400 cm = \frac{400 cm * 1 m }{100 cm}\\400 cm = 4 m[/tex]
Thus, option A gives the correct answer.
6. Option A. 1 dm = 10 m
Option B. 1 dm = 0.10 m
From standard measurement,
10 dm = 1 m
Thus,
[tex]1 dm = \frac{1 dm * 1 m}{10 dm}\\1 dm = 0.1 m[/tex]
Therefore, option B gives the correct answer.
7. Option A. 100°C = 373 K
Option B. 373 K = 10°C
Recall:
T (K) = T(°C) + 273
T (K) = Temperature in Kelvin
T(°C) = Temperature in decree celcius
Next, we shall convert 100°C to K
T(°C) = 100°C
T (K) = T(°C) + 273
T (K) = 100 + 273
T (K) = 373 K
Thus, 100°C is equivalent to 373 K
Next, we shall convert 373 K to °C
T(K) = 373
T (K) = T(°C) + 273
373 = T(°C) + 273
Collect like terms
373 – 273 = T(°C)
T(°C) = 100°C
Thus, 373 K is equivalent to 100°C
Therefore, option A gives the correct answer.
SUMMARY:
1. Option A. 1 L = 1 dm³
2. Option A. 1 mL = 1 cm³
3. Option B. 0 K = −273 °C
4. Option B. 1000 g = 1 kg
5. Option A. 400 cm = 4.0 m
6. Option B. 1 dm = 0.10 m
7. Option A. 100°C = 373 K
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