Please help and thank you

Answer: im pretty sure this is correct

- 1/42 x (21x233y)

Step-by-step explanation:

first convert the expressions (2 3/10x x5/7 x y-2 4/5 x x )

then factor the expression (23/10 x- 5/7 y- 29/6 y- 14/5x )

then collect like terms (1/210 x 483 x - 150 y - 1015 - 588x)

factor the expression (1/210 x 105x 1165y)

Multiply reduce (1/210 x -5 (21x + 233y ))

= -1/42 x (21x233y)

Answer:

√29

Step-by-step explanation:

You would use the distance formula in this case to solve the problem:

(8-3)^2+(1-3)^2=29

Now square root 29, leaving you with √29.

Answer:

5.39

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(3 - 8)² + (1 - 3)²

√(-5)² + (-2)²

√25 + 4

√29

= 5.39

Answer:

-90 degree is the correct answer

Answer:

The circle's area is 380.13 square miles.

Step-by-step explanation:

A = pie * r^2 = pie * 11^2 = 380.13

I hope this somewhat helped you find your answer.

Answer:

379.94

Step-by-step explanation:

3.14 x (11x11) = 379.94

Step-by-step explanation:

.....................

Answer:

I think it is 648³ in. I think for the second one it is 372³ in.

Step-by-step explanation:

                               HOPE THIS HELPS U!!!!!!!!! :) :) :) :) :)

                                SORRY IF IT'S WRONG. :) :) :) :) :)

Answer:

C

Step-by-step explanation:

hope this helps with the work

Answer:

option 2

Step-by-step explanation:

Answer:

Option 2

Step-by-step explanation:

Option 2

x is 4

y is -4

Answer:

5, 9,13,17

Step-by-step explanation:

5 +4 +4+4

Answer:

21708

Step-by-step explanation

Ok I am not so sure about this one, since this was a LOT of counting, and unless you want to see 5 pages of calculations, I'm just going to go on a limb and say trust me. However, if you really want to see for yourself, I'll give you a hint. For the first 1***1 numbers, the sum is 1440. For the 2***2 numbers, the sum is 1683. Try to calculate this to 9***9 to find the answer! Again, not sure about my answer if it's wrong, sorry!

Answer:

Alr

Step-by-step explanation:

Brainliest???

Answer:

Step-by-step explanation:

5^4 = 625. I hope your calculator will do this.

625 / 5 = 125

There is a more general way to do this which will be in harmony with the rest of the question.

5^4 / 5^1 = 5^(4 - 1) = 5^3 = 125

b^4 / b2 = b^(4 - 2) = b^2

a remains as it is at a^3

So the answer is 125 a^3 b^2

Answer:

Solutions given:

opposite side [0pp]=x

hypotenuse [Hypo]=7

angle A=36°

Now

relationship between opposite side and hypotenuse is given by Sin angle

Sin A=[tex] \frac{oppo}{hypo} [/tex]

Sin 36=[tex] \frac{x}{7} [/tex]

x=Sin36*7

x=4.11

So second one x=4.1 is your answer

Answer:

61 degrees

Step-by-step explanation:

Answer:

238

Step-by-step explanation:

Important note: ∠FAH is an inscribed angle and arc mFGH is it's intercepted arc

opposite angles in a quadrilateral formed inside of a circle area supplementary

Supplementary meaning that they add up to equal 180

So 13x + 15 + 8x - 3 = 180

We now solve for x

step 1 combine like terms

13x + 8x = 21x

15 - 3 = 12

12 + 21x = 180

step 2 subtract 12 from each side

12 - 12 cancels out

180 - 12 = 168  

21x = 168

step 3 divide each side by 21

21x / 21 = x

168 / 21 = 8

we're left with x = 8

Now we substitute 8 for x in 13x + 15

13 ( 8 ) + 15

13 * 8 = 104

104 + 15 = 119

So ∠FAH = 119

Recall that an included angle is equal to half the measure of its intercepted arc.

so arc mFGH = 2 (119)

2 * 119 = 238

Therefore your answer is A

Answer:

B

Step-by-step explanation:

Answer:

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}[/tex]

Step-by-step explanation:

Given

[tex]\cos(\theta) = -\frac{2}{3}[/tex]

[tex]\theta \to[/tex] Quadrant III

Required

Determine [tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta)[/tex]

We have:

[tex]\cos(\theta) = -\frac{2}{3}[/tex]

We know that:

[tex]\sin^2(\theta) + \cos^2(\theta) = 1[/tex]

This gives:

[tex]\sin^2(\theta) + (-\frac{2}{3})^2 = 1[/tex]

[tex]\sin^2(\theta) + (\frac{4}{9}) = 1[/tex]

Collect like terms

[tex]\sin^2(\theta) = 1 - \frac{4}{9}[/tex]

Take LCM and solve

[tex]\sin^2(\theta) = \frac{9 -4}{9}[/tex]

[tex]\sin^2(\theta) = \frac{5}{9}[/tex]

Take the square roots of both sides

[tex]\sin(\theta) = \±\frac{\sqrt 5}{3}[/tex]

Sin is negative in quadrant III. So:

[tex]\sin(\theta) = -\frac{\sqrt 5}{3}[/tex]

Calculate [tex]\csc(\theta)[/tex]

[tex]\csc(\theta) = \frac{1}{\sin(\theta)}[/tex]

We have: [tex]\sin(\theta) = -\frac{\sqrt 5}{3}[/tex]

So:

[tex]\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}[/tex]

[tex]\csc(\theta) = \frac{-3}{\sqrt 5}[/tex]

Rationalize

[tex]\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}[/tex]

[tex]\csc(\theta) = \frac{-3\sqrt 5}{5}[/tex]

So, we have:

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta)[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)[/tex]

Substitute: [tex]\csc(\theta) = \frac{-3\sqrt 5}{5}[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}[/tex]

Take LCM

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}[/tex]

Answer:

y = 4x...

Step-by-step explanation:

Answer:

i think its b

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

201

Step-by-step explanation:

use πr^2 formula here

Answer:

352

Step-by-step explanation:

originally 351.86 but 352 when rounded

Answer:4.12

Step-by-step explanation: I need brainliest for next rank I’d appreciate it

Answer:

a = [tex]4\sqrt{3}[/tex]

b= 4

Step-by-step explanation:

It's a 30-60-90 triangle based on the given picture. A right triangle too

Use sine, cosine, and tangent to solve for the side.

To find b, you can use sin(30) = b/8 because sin(angle) = opposite/hypotenuse.

OR you can use the rule for 30-60-90 triangle, which is x for short leg, 2x for hypotenuse, and [tex]x\sqrt{3}[/tex] for long leg

So either way, b = 4

To find a, you can use cos(30) = a/8 because cos(angle) = adjacent/hypotenuse.

OR you can use the same rule, 30-60-90 triangle to save time

a will end up = [tex]4\sqrt{3}[/tex]