Please answer this and show the work/explain for me
2/7m - 1/7 = 3/14

It seems like you want to find the sum of 38 to 115:

[tex] \displaystyle \large{38 + 39 + 40 + 41 + ... + 114 + 115}[/tex]

If we notice, this is arithmetic series or the sum of arithmetic sequences.

To find the sum of the sequences, there are three types of formulas but I will demonstrate only one and the best for this problem.

[tex] \displaystyle \large{S_n = \frac{n(a_1+a_n) }{2} }[/tex]

This formula only applies to the sequences that have the common difference = 1.

Given that a1 = first term of sequence/series, n = number of terms and a_n = last term

We know the first term which is 38 and the last term is 115. The problem here is the number of sequences.

To find the n, you can use the following formula.

[tex] \displaystyle \large{n = (a_n - a_1) + 1}[/tex]

Substitute an = 115 and a1 = 38 in the formula of finding n.

[tex] \displaystyle \large{n = (115 - 38) + 1} \\ \displaystyle \large{n = (77) + 1} \\ \displaystyle \large{n = 78}[/tex]

Therefore the number of sequences is 78.

Then we substitute an = 115, a1 = 38 and n = 78 in the sum formula.

[tex] \displaystyle \large{S_{78} = \frac{78(38+115) }{2} } \\ \displaystyle \large{S_{78} = \frac{39(38+115) }{1} } \\ \displaystyle \large{S_{78} = 39(153) } \\ \displaystyle \large \boxed{S_{78} = 5967}[/tex]

Hence, the sum is 5967.

Answer:

[tex]a + 2b -3 c + - 3a + b + 2c + 2a - 3b + c \\ = a - 3a + 2a + 2b + b - 3b - 3c + 2c + c \\ 0a + 0b + 0c \\ thank \: you[/tex]

a+2b-3c+(-3a+b+2c) +(2a-3b+c)

=a+2b-3c-3a+b+2c+2a-3b+c

=a-3a+2b+2b+b-3b-3c++2b+c

=0a+0b+0c

=0

Therefore, the addition of the expressions, a+2b-3c+(-3a+b+2c) +(2a-3b+c) is zero or 0.

To know more about algebraic expressions

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Answer:

B

Step-by-step explanation:

xy=6

y=6/x (1)

substitute (1) into 3y=x-3 and solve

Answer:

50

Step-by-step explanation:

please mark me as brainliest

Answer:

50

Step-by-step explanation:

Hi there!

Determining how much 1/2 can go into 25 is the same as solving for 25÷1/2:

[tex]25\div\frac{1}{2}[/tex]

Dividing by a fraction is the same as multiplying its reciprocal:

[tex]=25\times\frac{2}{1}\\=25\times2\\=50[/tex]

I hope this helps!

Answer:

43.8 meters

Step-by-step explanation:

12 x 3.65

Answer:

SA = 153.9m^2

Step-by-step explanation:

SA = 4[tex]\pi[/tex][tex]r^{2}[/tex]

r = 3.5

SA = 4[tex]\pi[/tex][tex](3.5)^{2}[/tex]

SA = 4[tex]\pi[/tex](12.25)

SA = 49[tex]\pi[/tex]

SA = 153.9m^2

Answer:

D) Prospective observational study

Step-by-step explanation:

A study which gathers data moving forward is called a prospective study.  Since the data is gathered on students without controlling the setting moving forward, it is a prospective observational design.

Answer:

8:15

Step-by-step explanation:

Answers:

There is a  max   value of   81/8   located at (x,y) =   (9/8, 9)  

=============================================================

Explanation:

Solve the second equation for y

8x+y = 18

y = 18-8x

Plug this into the first equation

f(x,y) = x*y

g(x) = x*(18-8x)

g(x) = 18x-8x^2

This graphs out a parabola that opens downward, and has a max point at the vertex.

If you apply the derivative to this, you get g ' (x) = 18 - 16x

Set this equal to zero and solve for x

g ' (x) = 0

18 - 16x = 0

18 = 16x

16x = 18

x = 18/16

x = 9/8

Use this x value to find y

y = 18 - 8x

y = 18 - 8(9/8)

y = 18 - 9

y = 9

So the max is x*y = (9/8)*9 = 81/8

Or we could say

g(x) = 18x-8x^2

g(9/8) = 18(9/8)-8(9/8)^2

g(9/8) = 81/8

----------------

To summarize,

There is a  max   value of   81/8   located at (x,y) =   (9/8, 9)  

When saying "max value of something", we're basically talking about the largest f(x,y) value. Which in this case is the largest x*y value based on the fact that 8x+y = 18.

A practical real world example of a problem like this would be if you wanted to max out a certain rectangular area based on constraints of how much building material you have for the fence.

Answer:

Function C is the only one that matches both definitions for the domain and range.

Step-by-step explanation:

First let's understand what the domain and range definitions mean in plain English.

The following statement means x is defined such that x can be any real number except for 1.

[tex]\{x | x \ne 1, x \epsilon R \}[/tex]

The following statement means y is defined such that y can be any real number except for 3.

[tex]\{y | y \ne 3, y \epsilon R \}[/tex]

So let's see what functions match those definitions. Take a look at the denominator of the functions in question 7, if we plug in x = 1 for any of them, we would be dividing by zero, which we know we can't do since the function would not be defined at that value. Therefore the domain definition is correct for all functions, we cannot use x = 1 for any of them.

Let's move on to the range. Our goal is to find a function where plugging in y = 3 would give us an undefined result. Simply plugin y = 3 into all of the given equations and simplify.

Therefore the function C is the only one that matches both definitions for the domain and range.

Answer:

3x4≥−16

3x≥−64

x≥−643

x≥−2113

The answer is x≥−2113

Answer:

-4×2-2xy+5y2

Step-by-step explanation:

(6-5xy+2y2)-(14-3xy-3y2)

=6-5xy+2y2-14+3xy+3y2

=(6-14)+(-5xy+3xy)+(2y2+3y2)

=-4×2-2xy+5y2

Answer:

−4x2 − 2xy + 5y2

Step-by-step explanation:

Answer: Screenshot attached

Step-by-step explanation:

Answer:

Step-by-step explanation:

Take the beginning number and add or subtract each transaction to get a new balance. For example,

                  349.45

-     23.42 = 326.03

-     14.95  = 311.08

+   276.50 = 587.58

-    219.93 =  367.65

-       76.84 = 290.81

9514 1404 393

Answer:

  none

Step-by-step explanation:

No work is required to maintain an object at a constant speed with no change in direction. Work is only done when an object is accelerated, or moved some distance in the direction of the net force applied.

you would do no work

Answer:

A=13×13

=169sqr.units

Answer:

(-4,-3)

Step-by-step explanation:

When a point (x,y) is reflected over the x-axis, you take the opposite so it becomes (x,-y).

(-4,3) --> (-4,-3)

Step-by-step explanation:

5.25....................

Answer:

D) 50% of the students surveyed spend at least two hours online each day.

50% of the students surveyed spend at least two hours online each day.

Hence option d is correct.

Given that,

Number of students who spend at least two hours online = 100

Total number of students surveyed = 200

To calculate the percentage of students who spend at least two hours online each day,

we can use the formula:

percentage = (number of students who spend at least two hours online / total number of students surveyed) x 100%

Plugging in the values from the problem, we get:

percentage = (100 / 200) x 100% = 50%

Therefore, we can conclude that 50% of the students surveyed spend at least two hours online each day.

Learn more about the percent visit:

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#SPJ2

Refer to the attaachment

Answer:

I think

The choose B. center.

I hope I helped you^_^

Answer: Length 132cm, Breadth 48cm

Explanation:

Perimeter = 360cm

Let the length and breadth be x

ATQ

2(11x + 4x) = 360

22x + 8x = 360

30x = 360

x = 360/30

x = 12

Length = 11×12

= 132 cm

Breadth = 4×12

= 48cm

Must click thanks and mark brainliest

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

  125.6 cm²

Step-by-step explanation:

The relevant area formula is ...

  Area = (1/2)ac·sin(B)

  Area = (1/2)(13 cm)(21 cm)·sin(67°) ≈ 125.6 cm²

Answer:

297 square feet

Step-by-step explanation:

Let w represent the width of the garden.

Since the length is 24 ft longer than the width, it can be represented by w + 24.

Use the perimeter formula, p = 2l + 2w. Plug in the perimeter and w + 24 as l, then solve for w:

p = 2l + 2w

84 = 2(w + 24) + 2w

84 = 2w + 48 + 2w

84 = 4w + 48

36 = 4w

9 = w

So, the width is 9 ft. Add 24 to this to find the length:

24 + 9 = 33

So, the length is 33 ft.

Find the area of the garden with the formula A = lw:

A = lw

A = (33)(9)

A = 297

The area of the garden is 297 square feet.

Answer:

Step-by-step explanation:

Let t = 2

h = 122.5 - 4.9·2² = 122.5-19.6 = 102.9

Answer:

30×5=150

so 150+10=160

thus his payment in the 30th installment is

rs.160