please answer all three.​

Answer:

Volume: 52 Units Squared

Surface Area: 94 units.

Step-by-step explanation:

The volume is relatively simple to find. Just subtract the original volume by the 2x2x2 cube's volume. The original volume is 60. The cube's volume is 2x2x2 which is 8. 60-8=52.

The surface area is harder to find. Try to envision the corner of the rectangle being cut out. We see that each side of the cube has a surface area of 2x2 which is 4. In the picture, we see that three sides of the rectangle has been partially removed. But since each side of the cube has an equal surface area, it is safe to minus 3 of the sides that has been partially removed by 3. However, since that it is the corner, the "dent" that the cube made in the rectangle also needed to be counted. As we said, each of the sides of a cube has a surface area of 4, so since that the dent has 3 sides, we see that the surface area of the dent is 4x3 which is 12. Now we need to count the unaffected sides of the rectangle. There are three of them. Just multiply the edges to find the surface area of each side. Add all of the values up: 11+16+12+8+15+12+20=94 units.

If AC=10 inches and CB=5 inches what is AB...

now, AB= AC+CB

= 10+ 5

=15 inches......

hope it helps you.have a nice day/ night...........

Answer:

It depends on the positions of the points.

Step-by-step explanation:

Since there is no figure, we cannot tell what the correct answer is since there is more than one possibility.

Here is one valid possibility.

                                   10                     5

<----------------+--------------------------+------------+--------------------->

                    A                             C              B

Here we have point C between points A and B. Then according to the definition of a point between two points, we have AB = AC + CB.

AB = AC + CB

AB = 10 + 5

AB = 15

Here is another equally valid possibility.

                   <----------- AC = 10----------------->

                                                          5

<----------------+--------------------------+------------+--------------------->

                    A                             B              C

Here we have AC = 10 and CB = 5, but we have point B between points A and C. According to the definition of a point in between two points, we have AC = AB + CB

10 = AB + 5

AB = 5

AB may be 10 or 5 depending on the order of the points on the number line. That makes the problem ambiguous without a figure.

Answer:

(i) 7/10

(ii) 3/10

(iii) 1/5

(iv) Rs 40,000

Step-by-step explanation:

The fraction of the salary spent on food = 1/2

The fraction of the salary spent on rented house fee = 1/5

(i) The fraction spent for both food and rental fee = (1/2) + (1/5) = (5 + 2)/10 = 7/10

(ii) The remainder (rest) of the salary = 1 - 7/10 = 3/10

The fraction of the remainder spent for children's education = 1/3

The fraction of the total salary spent for the children's education = (1/3) × (3/10) = 1/10

(iii) The remaining portion deposited in the bank = 1 - (1/10 + 7/10)) = 2/10 = 1/5

(iv) The amount equal to portion of 1/5 of his salary deposited in the bank is Rs 8000

Let x represent his whole salary, we have;

(1/5) × x = Rs 8,000

x = 5 × Rs 8,000 = Rs 40,000

His whole salary is Rs 40,000.

Answer:

We can write a ratio between two quantities, x and y, as:

x to y.

To find if two ratios:

"a to b" and "c to d" are equal, we need to see if the quotientes:

a/b and c/d are equal.

Here we know that the ratios are:

4 apples to 5 strawberries, this gives the quotient 4/5 = 0.8

7 apples to 9 strawberries, this gives the quotient 7/9 = 0.78

So the quotients are different, which means that the ratios are not equal.

Now we want to see who used a greater ratio of apples to strawberries.

notice that in the numerator we used the number of apples, so as larger is the quotient, larger is the ratio of apples to strawberries.

We can see that the quotient of Angie is larger, then Angie used the greater ratio of apples to strawberries.

Answer:

(0,-5) and (-4,3) are the points to the equations.

Step-by-step explanation:

Solution:

Step 1: Make an equation for y to substitute to the first equation.

x^2+y^2=25

y=-2x-5

Step 2: Substitute the y-value to the first equation.

x^2+(-2x-5)^2=25

x^2+4x^2+20x+25=25

Our x-values would be 0, and -4.

Step 3: Solve for the y-values by substituting 0 and -4 to the equation y=-2x-5.

y=-2(0)-5=-5 and makes the ordered pair (0,-5)

y=-2(-4)-5=3 and makes the ordered pair (-4,3)

Therefore our answers would be (0,-5) and (-4,3)

Answer:

(-4;3), (0;-5)

Step-by-step explanation:

Answer: 1. 41.67years

2. £9.21

3. 7.75cm

Step-by-step explanation:

1. At a party, thirty people have an age of 30, forty have an age of 40 and fifty an age of fifty. What is their average age?

Total ages = (30 × 30) + (40 × 40) + (50 × 50) = 900 + 1600 + 2500 = 5000

Total number of people = 30 + 40 + 50 = 120

Average age = Total ages / Total number of people

= 5000/120

= 41.67 years

2. In a hardware shop, there are 30 spanners costing £6, 55 hacksaws costings £9 and 10 soldering irons costings £20. What is the average cost per item?

Total cost of items = (30 × £6) + (55 × £9) + (10 × £20) = £180 + £495 + £200 = £875

Total number of items = 30 + 55 + 10 = 95

Average cost per item = £875/95 = £9.21

3. Using this frequency table, find the average height of a turnip.

Height (to nearest cm)

6cm 7cm 8cm 9cm 10cm

Frequency: 3 8 12 4 1

Total height = (3 × 6cm) + (8 × 7cm) + (12 × 8cm) + (4 × 9cm) + (1 × 10cm) = 18cm + 57cm + 96cm + 36cm + 10cm = 217cm

Total number of turnips = 3 + 8 + 12 + 4 + 1 = 28

Average height = 217cm/28 = 7.75cm

Answer:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Answer:

The function that represents g(x) is the third choice: g(x) = (x − 4)^2 + 9

Step-by-step explanation:

The original function has been shifted 9 units up (a vertical transformation). To show a vertical transformation, all we have to do is either add or subtract at the end of the function.

To show a shift upwards, we add the value of change.

To show a shift downwards, we subtract the value of change.

In this case, the original function f(x) = [tex]x^{2}[/tex] was translated 9 units up. Since we shifted up, we simply add 9 to the end of the function: g(x) = [tex]x^{2}[/tex] + 9

The original function has also been shifted 4 units to the right. This is a horizontal transformation. To show a horizontal transformation, we need to either add or subtract within the function (within the parenthesis).

To show a shift to the left, we add the value of change.

To show a shift to the right, we subtract the value of change.

*Notice: Moving left does NOT mean to subtract while moving right does NOT mean to add. The rules above are counterintuitive so pay attention when doing horizontal transformations.

In this case, the original function f(x) = [tex]x^{2}[/tex] was translated 4 units to the right. Since we shifted right, we must subtract 4 units within the function/parenthesis: g(x) = [tex](x-4)^{2}[/tex]

When we combine both vertical and horizontal changes, the only equation that follows these rules is the third choice: g(x) = (x − 4)^2 + 9

Answer: C

Step-by-step explanation:

Answer:

84°

Step-by-step explanation:

angles in a quadrilateral add to 360°. 360-(114+76)=5x =170°. 170°/5 = 32°. x=32°

angles on a straight line add to 180°.

2x = 64°. 180-64=116°. y=116°.

y-x = 116-32 = 84°

Answer:

[tex]78[/tex]

Step-by-step explanation:

The inner angles of a quadrilateral all add up to 360. This means we can write the following

[tex]114 + 76 + 3x + 2x = 360\\190 + 5x = 360\\5x = 170\\x = 34[/tex]

Now that we have x we can find y. Notice that y and 2x are on the same line. Any line cutting another straight line will create two angles that add up to 180.

Therefore we can write

[tex]2x + y = 180\\2(34) + y = 180\\y = 112[/tex]

Finally computing y - x

[tex]y - x = 112 - 34 = 78[/tex]

Answer:

1733.28

Step-by-step explanation:

we want to find the surface area of the cylinder

We are given:

diameter = 12in

height = 40in

formula to find surface area of a cylinder: SA = 2πr^2 + 2πrh (where h = height and r = radius)

in order to find the SA of a cylinder we need to know the radius

we are given that the diameter is 12

we can acquire the measure of the radius by dividing the diameter by 2 ( this is because the radius is equal to half of the diameter )

so r = 12/2 = 6

now to find the surface area,

we simply plug in the values of the radius and height into the SA of a cylinder formula

SA = 2πr^2 + 2πrh

r = 6

h = 40

( note it says use 3.14 for π )

substitute values

SA = 2(3.14)(6)^2 + 2(3.14)(6)(40)

if you plug this into a calculator you get that the surface area is 1,733.28

Step-by-step explanation:

mình nghĩ là như vầy. Chúc bạn học tôt :))))

Answer:

At a distance of 400 m.

Step-by-step explanation:

From the information in the given question, a distance marker and pole are together at the start of the road.

Thus,

the distance marker would mark the road 100 m, 200 m, 300 m, 400 m, 500 m etc.

Also,

the pole would be located 80 m, 160 m, 240 m, 320 m, 400 m, 480 m etc.

Comparing the distance of location of the marker and pole, it would be observed that the next location where the two would be together is 400 m from the starting point.

Therefore, there would be a distance marker and a pole together at 400 m from the stat of the road.

================================================

Work Shown:

A = area = 6y^5

b1+b2 = sum of the parallel bases = 4y^2

h = unknown height, i.e. distance between the parallel sides

------

A = 0.5*h*(b1+b2)

6y^5 = 0.5*h*4y^2

6y^5 = 0.5*4y^2*h

6y^5 = 2y^2*h

2y^2*h = 6y^5

h = (6y^5)/(2y^2)

h = (6/2)*y^(5-2)

h = 3y^3

The parallel sides are separated by a distance of 3y^3 units.

Answer:

∠ V = 58°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

∠ WYX = 180° - (52 + 24)° = 180° - 76° = 104°

∠ VYU = ∠ WYX = 104° ( vertically opposite angles )

Then

∠ V = 180° - (104 + 18)° = 180° - 122° = 58°

Answer:

y = -3x+9

Step-by-step explanation:

Parallel lines have the same slope

y = -3x+2  

This is in slope intercept form where y =mx+b where m is the slope

The slope is -3

y = -3x+b

Using the point (2,3)

3 = -3(2)+b

3 = -6+b

Add 6 to each side

3+6 = b

9=b

y = -3x+9

Answer:

slope (m) = -3

3= -3(2)+b

b = 9

y=mx+b → y= -3x+9

OAmalOHopeO

Answer:

763 feet

Step-by-step explanation:

Volume of cylinder  = πr2h

π(18/2)^2 x 3

= 763 feet

Answered by Gauthmath

Answer:

with my own opinion the answer is b

Answer:

x ≈ 28.2

Step-by-step explanation:

Δ CAB ≅ Δ CDE then corresponding sides are in proportion, that is

[tex]\frac{CA}{CD}[/tex] = [tex]\frac{CB}{CE}[/tex] , substitute values

[tex]\frac{14+x}{x}[/tex] = [tex]\frac{18.7+9.3}{18.7}[/tex] = [tex]\frac{28}{18.7}[/tex] ( cross- multiply )

28x = 18.7(14 + x) ← distribute

28x = 261.8 + 18.7x ( subtract 18.7x from both sides )

9.3x = 261.8 ( divide both sides by 9.3 )

x ≈ 28.2 (to the nearest tenth )

x = number of hours

want to find probability (P) x >= 13

x is N(14,1) transform to N(0,1) using z = (x - mean) / standard deviation so can look up probability using standard normal probability table.

P(x >= 13) = P( z > (13 - 14)/1) = P(z > -1) = 1 - P(z < -1) = 1 - 0.1587 = 0.8413

To convert that to percentage, multiply 100, to get 84.13%

Answer:

60

Step-by-step explanation:

5*3*4

Answer:

The depth to which a BASE jumper jumps in 3 seconds is 144 feet

Step-by-step explanation:

The details of the Cave of Swallows are;

The depth of the cave = 1,220 ft.

The function that represents the duration, t, in seconds it takes to fall d feet is given as follows;

[tex]t = \dfrac{1}{4} \cdot\sqrt{d}[/tex]

The distance a BASE jumper jumps in 3 seconds = Required

By substituting t = 3 in the given function, we get;

[tex]t = 3 = \dfrac{1}{4} \cdot\sqrt{d}[/tex]

Therefore;

4 × 3 = 12 = √d

d = 12² = 144

The distance a BASE jumper jumps in 3 seconds is d = 144 feet.

Answer:

H

Step-by-step explanation:

Let represent A and B

A and B is the sum of the first 50 consecutive multiples of 3 and 6, this is the same as a arithmetic sequence because arithmetic sequences have a common sum.

We can represent this as

[tex]a _{n} = a {}^{1} + d(n - 1)[/tex]

where a^1 is the first term, d is the common sum, n is the number of multiples we adding.

The first term for both A and B respectively is 3 and 6.

Multiples implies that the Difference between A and B are 3 and 6 respectively. There are 50 consecutively. multiples.

Plug in the known parts for both.

[tex]3 + 3(49) = 150[/tex]

[tex]6 + 6(49) = 300[/tex]

We need to what percent of find 150% of 300.

B is twice as A, so this means that we need to multiply 2 by it original or 100% of it self.

[tex]2 \times 100 = 200[/tex]

So 200% is the answer.

Answer:

16

Step-by-step explanation:

Sub in the number of customers (12) into the equation for the line of best fit, and solve.

y = 5/4 (12) + 1

y = 15 + 1

y = 16

There will be 16 positive YELP reviews

Answer:

Parthava had 100 arrows.

Step-by-step explanation:

Let's define N as the number of arrows that Parthava originally has.

He uses one-half of them in defending himself, so he used N/2 arrows

Now he uses four times the square root of the number of arrows, so now he uses:

4*√N

Then he uses 6

Then he uses 3

Then he uses the last one.

If we add all these numbers of arrows that he used, we should get the initial number of arrows that he used, then:

N/2 + 4*√N  + 6 + 3 + 1  = N

Now we have an equation that we can try to solve.

First, let's move all the terms to the same side:

N/2 + 4*√N + 6 + 3 + 1 - N  = 0

now we can simpify it:

(N/2 - N) + 4*√N + (6 + 3 + 1) = 0

-(1/2)*N + 4*√N + 10 = 0

Now we can define a new variable x = √N

Then we have: x^2 = N

now we can replace these new variables in our equation to get:

-(1/2)*x^2 + 4*x + 10 = 0

Now we just have a quadratic equation.

Remember that for a quadratic equation of the form:

0 = a*x^2 + b*x + c

The solutions were given by:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2a}[/tex]

Then in our case, the solutions will be:

[tex]x = \frac{-4 \pm \sqrt{4^2 - 4*(-1/2)*10} }{2*(-1/2)} = \frac{-4 \pm 6 }{-1} = 4 \pm 6[/tex]

So there are two solutions:

x = 4 + 6 = 10

x = 4 - 6 = -2

And remember that x = √N

Then x should be positive, then we take x = 10 as our solution here.

then we can use the equation:

x = 10 = √N

then

10^2 = √N^2 = N

10^2 = 100 = N

Parthava had 100 arrows.

Answer:

cos^2(θ)

Step-by-step explanation: