Answer:
h = 52.24 m
Explanation:
Given that,
A penny is dropped from the top of the hotel in New York. It hits a tourist in the head at 32 m/s.
Let it falls at a height of h.
We can find the value of h using the conservation of energy such that,
[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(32)^2}{2\times 9.8}\\\\h=52.24\ m[/tex]
So, it will fall at a distance of 52.24 m.
David tosses an egg horizontally from the top of a building, with an initial velocity of 6.5 m/s. The building is 60m high. The time takes the egg to hit the ground is
Answer: 3.5 seconds
Explanation:
Capillaries are the largest of all blood vessels.
O True
O False
Answer:
FALSE
Explanation:
does velocity, speed, and rate acceleration change if it was dropped from a higher building?
Answer:
Your answer is correct, the rates would stay the same
Explanation:
6. If an object has an acceleration of –3 m/s?, describe its motion.
Answer:
Its motion is accelerating backward or changing velocity in a backward motion.
Explanation:
We know acceleration is a vector quantity, therefore, containing both magnitude and direction. The negative sign represent direction so here, it's representing a backward motion. The magnitude here is 3, meaning that is is moving at a changing velocity of 3 m/s, meaning each second, the velocity increases 3 m/s going backward.
A billiard ball moving at 5.30 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.72 m/s, at an angle of θ = 27.0° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision.
Answer:
The velocity of the struck billiard ball after collision is 2.41 m/s at an angle of 62.8⁰.
Explanation:
Given;
initial velocity of the billiard ball, u₁ = 5.3 m/s
initial velocity of the second ball, u₂ = 0
final velocity of the first ball, v₁ = 4.72 m/s at θ = 27.0°
final velocity of the second ball, v₂ = ?
Apply the principle of conservation of kinetic energy;
¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂m₁v₁² + ¹/₂m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
m₁u₁² + m₂(0) = m₁v₁² + m₂v₂²
m₁u₁² = m₁v₁² + m₂v₂²
m₁ = m₂
u₁² = v₁² + v₂²
v₂² = u₁² - v₁²
v₂² = (5.3)² - (4.72)²
v₂² = 5.812
v₂ = √5.812
v₂ = 2.41 m/s
The direction of the second ball is given by;
v₂sinθ = v₁sin27
sinθ = (v₁sin27) / (v₂)
sinθ = (4.72 x 0.454) / (2.41)
sinθ = 0.8892
θ = sin⁻¹ (0.8892)
θ = 62.8⁰
Thus, the velocity of the struck billiard ball after collision is 2.41 m/s at an angle of 62.8⁰.
Answer the following: What are the units of mass and the units of weight for the metric system? What are the units of mass and the units of weight for the English system?
Answer:
Explanation:
Units are measure of a quantity. There are two types of units,
The fundamental units
The derived units
The fundamental units are units that are independent i.e they can stand alone while derived units are derived from fundamental units (They are dependent)
The fundamental units are the units of fundamental quantities (Length, mass and time)
Length is measured in metres (m)
Mass is measured in kilograms (kg)
Time is measured in seconds(s)
This are called the standard units where other units are derived.
Other units of mass are grams
Weight is the product of mass and acceleration due to gravity
Weight = mass×acc due to gravity
W = mg
Using units
W = kg × m.s²
Since acceleration is measured in m/s²
W = kgm/s²
Hence the metric unit of weight is kgm/s² or Newtons
who discovered the relationship between the fluctuating period of variable stars and their intrensic brightness
Answer:
Leavitt
Explanation:
In the course of her work, Leavitt discovered 2,400 new variable stars, half the known ones in her day. A certain group of variable stars, later called Cepheid variables, fluctuate in brightness (luminosity) in a regular pattern called their “period.” This period ranges from about one day to nearly four months.
hope this helps have a good day and can i have brainliest plz
1. Imagine that you take a 200.0 km trip. You travel the first half of the trip at 100.0 km/hr. Your speed for the second half is 50.0 km/hr. How much time does the entire trip take?
2. In the above problem, what is your average speed in km/hr and m/s
Answer:
Explanation:
Speed = Distance/Time
Given
Distance = 200km
Total speed = 100+50 = 150km/hr
Time = Distance/Speed
Time = 200/150
Time = 1.33hr
b) Average speed in km/hr is 150km/hr
Convert to m/s
150km/hr = 150 * 1000 m/1 * 3600s
150km/hr = 150,000/360
150km/hr = 416.67m/s
Evenly timed disturbances in a medium create a n) O A. periodic wave O B. pulse O c. electromagnetic wave D. compression wave
Answer: periodic wave
Explanation:
i just took a test and got it right
why Fahrenheit thermometer is used to measure human body temperature?
Answer:
Well that is not true we use both Celsius and Fahrenheit thermometer
it just depends on where you are from, If you are from Celsius dominated country you use Celsius to measure whereas if you are from Fahrenheit dominated country you use it to measure the body heat.
If you have seen money heist (a netflix show), Helsinki uses Celsius Thermometer to check the body temperature of Arturo BECAUSE in spain they use celsius thermometer.
HOPE MY ANSWER WAS HELPFUL xD
what capacitance is required to store an energy of 10kw.h at a potential difference of 1000v?
An oxygen-16 ion with a mass of perpendicular to a 1.20-T magnetic field, which makes it move in a circular arc with a 0.231-m radius.
Required:
a. What positive charge is on the ion?
b. What is the ratio of this charge to the charge of an electron?
c. Discuss why the ratio found in (b) should be an integer.
Answer:
a) 4.8*10^-19 C
b) 3
Explanation:
We know that
F = ma
Also, recall that a = v²/r and F = qvB
Substituting this in the first equation, we have
qvB = mv²/r, since we're looking for q, we make it the subject of the formula and solve for it.
q = mv²/rvB
q = mv/rB
q = [2.66*10^-26 * (5*10^6)] / 0.231 * 1.2
q = 1.33*10^-19 / 0.2772
q = 4.8*10^-19 C
Ratio between the charge and the electron is q/c =
4.8*10^-19 / 1.6*10^-19 = 3
Therefore, the ratio between the charge and electron is 3
On June 17th 2003, in Santa Barbara, California, the morning low tide was measured at -0.365 m. High tide was measured at 1.12 . Calculate the tidal range between these tides.
A)there was no tidal range.
b)0.755 m
c)1.485 m
This cost a lot of points pls give me an amswer before 10:50 its k if its past 10:50
Answer:
I am not sure but I think it's choice c.
c)1.485 m
Explanation:
I hope this helps.
Find the recoil velocity of a 65kg ice hockey goalie who catches a 0.15kg hockey puck slapped at him at a velocity of 50m/s. Assume that the goalie is at rest before catching the puck, and friction between the ice and the puck-goalie system is negligible.
Answer:
0.12m/sExplanation:
Given data
mass m1=65kg
velocity v1=?
mass m2=0.15kg
v2=50m/s
We know that the expression for the conservation of momentum is given as
0=m1v1+m2v2
we want to find v1
v1=(m2v2)/m1
v1=0.15*50/65
v1=7.5/65
v1=0.115
v1=0.12m/s
Therefore the recoil velocity is 0.12m/s
Which two factors have an effect on the gravitational force between two
objects?
A. Their masses
B. The strong nuclear force
C. Their charges
D. The distance between them
E. Electromagnetic force
Answer:
A. their masses
D. the distance between them
Explanation:
100% correct
Two factors have an effect on the gravitational force between two
objects are their masses and the distance between them.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
f = Gmm/r²
Two factors have an effect on the gravitational force between two
objects are their masses and the distance between them.
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buhruhburhburhburubrhubrhu
Answer:Never smoke ciga If you are a smoker, throw them away now! Smoking is the number one cause of preventable death. It causes many cancers, heart attacks, strokes, lung diseases, and other nonfatal problems, like stained teeth, poor athletic performance, erectile dysfunction, and bad breath. There is help available to quit, including free counseling at 1-800-QUIT-NOW and medications to ease the cravings. Ask your doctor for help. Stopping is the biggest favor you can do for yourself.
Find v2v1v2v1, the ratio of the speed v2v2v_2 of the two-block system after the first collision to the speed v1v1v_1 of the block of mass m1m1m_1 before the collision.
Answer:
v₂/v₁ = 0.777
Note: The question is incomplete. The complete question is given below;
A block of mass m1 1.40 kg moving at 12.00 m/s undergoes a completely inelastic collision with a stationary block of mass m2 0.400 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 2.70 kg, which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without friction Express your answer numerically using three significant figures
Part A Find , the ratio of the velocity 2 of the two-block system after the first collision to the velocity V1 of the block of mass m1 before the collision.
Explanation:
Velocity, v₁ (of mass m₁) = 12.0 m/s
Velocity of the two masses after inelastic collision = v₂
According to the principle of conservation of linear momentum, momentum before collision is equal to momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)v₂
where m₁ = mass of first block = 1.40 kg
u₁ = initial velocity of first block = 12.0 m/s
m₂ = mass of second block = 0.40 kg
u₂ = initial velocity of second block = 0 m/s
v₂ = final velocity of the two-block system = ?
Substituting the values in the conservation of momentum formula
1.4 * 12 + 0.4 * 0 = (1.4 + 0.4) * v₂
16.8 + 0 = 1.8 * v₂
v₂ = 16.8/1.8
v₂ = 9.33 m/s
v₂/v₁ = 9.33/12.0
v₂/v₁ = 0.777
The ratio of the speed should be 0.777.
Principle of conservation of linear momentum:
Since
Velocity, v₁ (of mass m₁) = 12.0 m/s
The velocity of the two masses after inelastic collision = v₂
So,
m₁u₁ + m₂u₂ = (m₁ + m₂)v₂
here
m₁ = mass of first block = 1.40 kg
u₁ = initial velocity of first block = 12.0 m/s
m₂ = mass of second block = 0.40 kg
u₂ = initial velocity of second block = 0 m/s
v₂ = final velocity of the two-block system = ?
Now
1.4 * 12 + 0.4 * 0 = (1.4 + 0.4) * v₂
16.8 + 0 = 1.8 * v₂
v₂ = 16.8/1.8
v₂ = 9.33 m/s
So,
v₂/v₁ = 9.33/12.0
v₂/v₁ = 0.777
hence, The ratio of the speed should be 0.777.
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A train travels due south at 60 m/s. It reverses its direction and travels due north at 60 m/s. What is the change in velocity of the train
The change in velocity of the train is 120 m/sec.
What is Velocity?The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity. Unit of velocity is m/sec.
Given in the question train travels due south at 60 m/s. It reverses its direction and travels due north at 60 m/s,
We see that the change in direction of the train is 180 degree,
the net change in velocity is given as,
v = 60 m/s + 60 m/s
v = 120 m/s
A train travels due south at 60 m/s. It reverses its direction and travels due north at 60 m/s the change in velocity of the train is 120 m/sec.
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Why does the man fly out of the car?
A. Newtons 1st Law
B. Newtons 2nd Law
C. Newtons 3rd Law
An airplane lands with a speed of 91 m/s traveling due west. It comes to rest in 952 m with a constant deceleration. What is the plane’s acceleration?
Answer:
The acceleration of the plane is -4.35 m/s²
Explanation:
Given;
initial speed of the airplane after landing, u = 91 m/s
final speed of the airplane after landing, v = 0
distance traveled, s = 952 m
Apply the following kinematic equation to determine the acceleration of the airplane;
v² = u² + 2as
0 = u² + 2as
0 = 91² + (2 x 952)a
0 = 8281 + 1904a
- 8281 = 1904a
a = - 8281 / 1904
a = -4.35 m/s²
Therefore, the acceleration of the plane is -4.35 m/s².
An astronaut on the surface of Mars standing on the edge of a 73.3 meter tall cliff throws a golf ball
down with an initial speed of 4.5 m/s. The ball hits the ground 5.2 seconds later. Find the
acceleration due to gravity on Mars.
Answer:
3.69m/s²
Explanation:
Using the formula;
S = ut + 1/2gt²
Where;
S = distance (m)
u = initial velocity (m/s)
t = time (s)
g = accelerate due to gravity (m/s)
Based on the information provided, S = 73.3m, u = 4.5m/s, t = 5.2s, g= ?
73.3 = (4.5 × 5.2) + 1/2 (g × 5.2²)
73.3 = 23.4 + 1/2 (27.04g)
73.3 = 23.4 + 13.52g
73.3 - 23.4 = 13.52g
49.9 = 13.52g
g = 49.9/13.52
g = 3.6908
g = 3.69m/s²
Two pendulum bobs of unequal mass are suspended from the same fixed point by strings of equal length. The lighter bob is drawn aside and then released so that it collides with the other bob on reaching the vertical position. The collision is elastic. What quantities are conserved in the collision?
Answer:
"Both kinetic energy and angular moment of the system" is the correct solution.
Explanation:
The kinetic energy is:
[tex]KE=\frac{1}{2}m_{1}v_{1}^2 + \frac{1}{2}m_{2}v_{2}^2[/tex]
Its conversion is:
⇒ [tex](KE)_{1}=(KE)_{f}[/tex]
Angular momentum is:
[tex]L=I_{1}\omega_{1}+I_{2}\omega_{2}[/tex]
Its conversion is:
⇒ [tex]L_{i}=L_{f}[/tex]
So that both "KE" and "L" of the system conserved.
A 95 N net force is applied to an ice block with a mass of 24 kg. Find the acceleration of the block if it moves on a smooth horizontal surface
Answer:
The answer is 3.96 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{95}{24} \\ = 3.95833333333...[/tex]
We have the final answer as
3.96 m/s²Hope this helps you
10a. Phoebe Physics pulls a 5 kg wagon with a force of 80 N. What is the
net force if the force of friction between the wagon and the ground is 12
N? *
Answer:
68 N
Explanation:
We have a force of 80 N going to one direction and 12 N to the other direction. we subtract 12 from 80 and get 68 N which is the total net force
The net force acting on the wagon is equal to 68 N.
What is the net force?The net force acting on an object can be defined as the vector sum of all forces acting. The net force is a single force that can give same the effect as the original forces on the object's motion.
The net force will be the resultant force with a similar effect on the rotational motion as all actual forces taken together by the object.
In the question, the applied force will act in the opposite direction of the frictional force so we need to subtract these two forces to find the net force.
Given, the applied force to push the wagon = 80 N
The frictional force between wagon and ground = 12 N
The net force on the wagon = 80N + (-12N) = 68 N
Therefore, the net force equal to 68 N will act in the direction of the applied force.
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A ball is thrown straight up in the air with a velocity of 12 m/s. Find the maximum height the ball
reaches.
Answer:
The maximum height is 7.34 meters.
Explanation:
give an example of newton’s 1st law of motion at work (write a complete sentence and use the word inertia)
Answer:
A ball rolling will eventually stop because pf the force of inertia acting on the ball.
Explanation:
In a grocery store, you push a 15.5 kg shopping cart with a force of 10.5 N. If the cart starts at rest, how far does it move in 3.00 s?
Answer:
The distance moved by the cart is 3.05 m
Explanation:
Given;
mass of the cart, m = 15.5 kg
applied force, f = 10.5 N
initial velocity, u = 0
time of motion, t = 3s
The final velocity of the cart is given by;
[tex]F = ma\\\\F = m(\frac{v-u}{t})\\\\ m(v-u) = Ft\\\\m(v-0) = Ft\\\\mv = Ft\\\\v = \frac{Ft}{m}\\\\ v = \frac{10.5*3}{15.5}\\\\ v = 2.032 \ m/s[/tex]
The acceleration of the cart is given by;
F = ma
a = F/m
a = 10.5 / 15.5
a = 0.677 m/s²
The horizontal distance moved by the cart is given by;
s = ut + ¹/₂at²
s = 0 + ¹/₂ (0.677)(3)²
s = 3.05 m
Therefore, the distance moved by the cart is 3.05 m
This problem relates to a design competition in which a 1-kg battery-powered vehicle must be propelled up a 0.9-m tall ramp within a 15-second time interval. a. For a run time of 9 seconds, how much power must the battery supply to the vehicle
Answer:
P = 0.98 W
Explanation:
Given that,
Mass, m = 1 kg
Height, h = 0.9 m
(a) We need to find power must the battery supply to the vehicle for a run time of 9 seconds. Power is given by work done divided by time. It can be given by :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{1\times 9.8\times 0.9}{9}\\\\P=0.98\ W[/tex]
So, the required power is 0.98 W.
5n right 5n left I don’t know this please help!
Answer:
this is my exception I am not sure but I think its help full 5Nr+5NL so it will be 0N which is equilibrium
The study of the relationship between life stressors s and the body’s ability to fight illness is called____.
A-neurology
B-psychoneuroimmunology
C-behavioral medicine
D-health psychology
Answer:
Explanation:
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Like if you agree :)
