Part C
What is the area of the whole target?

Select the correct answer.

A) 38
B) 144
C) 361
D) 400

The perimeter of the quadrilateral is the sum of the side lenths, and the perimeter is 72 units

The given parameters are:

AP = 10

EO = 12

The perimeter of the quadrilateral is calculated using:

Perimeter = 2 * (EO + 2AP) + 4

So, we have

Perimeter = 2 * (10 + 2 * 12) + 4

Evaluate

Perimeter = 72

Hence, the perimeter of the quadrilateral is 72 units

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Answer:

19 sq cm

Step-by-step explanation:

2x2=4

2x3=6

1x3=3

2x3=6

6+6+4+3=19

Answer:

D. 159

Step-by-step explanation:

Answer:

f(x)=2x(3x-7) is what I got.

Answer:

10 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (8, 5 ) and (x₂, y₂ ) = (- 2, 5 )

d = [tex]\sqrt{(-2-8)^2+(5-5)^2}[/tex]

   = [tex]\sqrt{(-10)^2+0^2}[/tex]

   = [tex]\sqrt{100}[/tex]

   = 10

Answer:

Angle B = 120.5°

Step-by-step explanation:

When two angles are supplementary, it means that they add up to 180°. Therefore, you can find the measure of Angle B by doing the following:

Angle B = 180 - 59.5

Angle B = 120.5°

Hope this helps

Answer: MQ=16, QL=32

Step-by-step explanation:

The centroid splits the median in a 2:1 ratio.

The measure of MQ and QL are 16 and 32 respectively.

Centroid is the point on the median which divides it in the ratio 2:1.

The ratio of lengths QL and MQ will be 2:1.

[tex]\frac{QL}{MQ}=\frac{2}{1}\\QL=2MQ[/tex]

It is known that ML is the sum of MQ and QL.

MQ+QL=ML

Substitute QL=2MQ and ML=48 into the obtained equation.

MQ+2MQ=48

3MQ=48

MQ=16

Substitute MQ=16 into QL=2MQ

QL=2(16)

=32

Thus, the lengths are MQ=16 and QL=32.

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Answer:

1.5

Step-by-step explanation:

The maximum number of parking spaces that will fit in the lot given the area of the parking lot is 30.

The parking lot has the shape of a rectangle. The area of a rectangle is length x width

The area of the available parking space =  length of the lot - [width of the lot - (width of the alley x 2)

80 x (77 - 10 - 10) = 4560 ft²

Maximum number of parking spaces = 4560 / (19 x 8) = 30

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Option B is correct after applying the property of integer exponent and simplification.

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

We have:

[tex]=\rm (x.x^{-3}.y^{\dfrac{1}{3}})^2[/tex]

[tex]=\rm (x^{-2}.y^{\dfrac{1}{3}})^2\\\\=\rm (x^{-4}.y^{\dfrac{2}{3}})\\\\=\rm \dfrac{y^{\dfrac{2}{3}}}{x^{4}}\\\\[/tex]

Thus, option B is correct after applying the property of integer exponent and simplification.

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The inverse function value in degrees will be 45°. Option C is correct.

Assuming function 'f' is a one-to-one and onto function which is a need for inverses to exist. The inverse of the considered function is. f⁻¹(x).

The given function is;

f(x)=sin⁻¹(1/2)

The given function is arranged is;

x=sin⁻¹(1/2)

The given function in terms of  sin;

sinx=1/2

Putting the values in terms of sin we get;

sinx=sin30°

x=30°

The inverse function value in degrees will be 45°.

Hence,option C is correct.

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Answer:

1/5

Step-by-step explanation:

0.2 is the same as 2/10. you then must reduce the fraction

Step-by-step explanation:

here is the single fraction of it

[tex] \frac{1}{5} = 0.2[/tex]

Using the angle addition theorem, the measure of angle 2 in the given diagram is: m∠2 = 35°

Based on the angle addition theorem, the sum of two smaller angles that make up a bigger angle equals the sum of the bigger angle.

Given the following:

m∠EBC = m∠EBD + m∠2 [angle addition theorem]

Substitute

55 = 20 + m∠2

m∠2 = 55 - 20

m∠2 = 35°

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The solution of the function [tex]\rm \int{sin(t) (1 + cos(t) )} \, dt[/tex] is - cos t - ¹/₄cos 2t + c.

An indefinite integral is a function that practices the antiderivative of another function.

It can be visually represented as an integral symbol, a function, and then a dx at the end.

The given function is;

[tex]\rm \int{sin(t) (1 + cos(t) )} \, dt[/tex]

Multiply by sint in the function and simplify;

[tex]\rm \int{sin(t) (1 + cos(t) )} \, dt\\\\\rm \int{sin(t) + sin(t)cos(t) \, dt[/tex]

Use trigonometric formulas for double angles:

[tex]\rm 2sintcost =sin2t\\\\sin t cost =\dfrac{1}{2} sin2t[/tex]

Substitute the values in the function

[tex]\rm \int{sin(t) (1 + cos(t) )} \, dt\\\\\rm \int{sin(t) + sin(t)cos(t) \, dt}\\\\ \int{sin(t) + \dfrac{1}{2} sin2t \, dt}\\\\[/tex]

And now we integrate this trigonometric form.

[tex]\rm \int{sin(t) + \dfrac{1}{2} sin2t \, dt}\\\\ \int{sin(t) dt } +\dfrac{1}{2}\int{sin(2t)\, dt}\\\\-cost -\dfrac{1}{2} \times \dfrac{1 \times -cos2t}{2}\\\\-cost -\dfrac{{1 \times -cos2t}}{4}+c[/tex]

Hence, the solution of the given function is - cos t - ¹/₄cos 2t + c.

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Answer:

the 2 one and the last one

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

I have none I got it wrong lol

Answer:

It's 44 in²

Remember the diagonal formula, whereas there is p and q for the diagonals.

[tex]A = \frac{pq}{2} = \frac{11*8}{2} = 44~in.[/tex]

Answer:

Area of rhombus  = 44 square inches

Step-by-step explanation:

[tex]\sf \boxed{Area \ of \ rhombus = \dfrac{d_1*d_2}{2}}[/tex]

[tex]\sf \text{Here, $d_1$ and $d_2$ are the diagonals}[/tex]

                             [tex]\sf = \dfrac{11 *8}{2}\\\\ = 11*4\\\\ = 44 \ in^{2}[/tex]

Answer:

no 2³ = 8

Step-by-step explanation:

2³ = 2 times 2 times 2 which = 8

Step-by-step explanation:

15÷3=5

There are 5 equal groups of 3

8÷4=2

There are 4 equal groups of 2

18÷6=2

There are 3 equal groups of 3

45÷5=9

There are 9 equal groups of 5.

Step-by-step explanation:

Given quadratic equation is

px²-6qx-(9p-10q) = 0

On comparing with the standard quadratic equation ax²+bx+c = 0

a = p

b = -6q

c = -(9p-10q) = -9p+10q

Given roots of the equation = 2 Ⴛ - 3 and

2 Ⴛ - 3 and 2β – 3

We know that

Sum of the roots = -b/a

=> 2 Ⴛ - 3 + 2β – 3 = -(-6q)/p

=> 2 Ⴛ + 2β - 6 = 6q/p

=> 2 Ⴛ + 2β = (6q/p)-6

=> 2 Ⴛ + 2β = (6q-6p)/p

=> 2(Ⴛ + β) = (6q-6p)/p

=> Ⴛ + β = (6q-6p)/(2p)

=> Ⴛ + β = 2(3q-3p)/(2p)

=> Ⴛ + β = (3q-3p)/p ---------(1)

Product of the roots = c/a

=> (2 Ⴛ - 3 )( 2β – 3) = (-9p+10q)/p

=> 4Ⴛ β-6Ⴛ - 6β+9 = (-9p+10q)/p

=> 4Ⴛ β-6(Ⴛ +β)+9 = (-9p+10q)/p

=> 4Ⴛ β-6[(3q-3p)/p]+9 = (-9p+10q)/p

=> 4Ⴛ β-6[(3q-3p)/p] =[ (-9p+10q)/p]-9

=> 4Ⴛ β-6[(3q-3p)/p] = (-9p+10q-9p)/p

=> 4Ⴛ β-6[(3q-3p)/p] = (-18p+10q)/p

=> 4Ⴛ β =[(-18p+10q)/p]+6[(3q-3p)/p]

=> 4Ⴛ β =[(-18p+10q)/p]+[(18q-18p)/p]

=> 4Ⴛ β =[(-18p+10q)+18q-18p)]/p

=> 4Ⴛ β = (-36p+28q)/p

=> 4Ⴛ β = 4(-9p+7q)/p

=> Ⴛ β = 4(-9p+7q)/4p

=> Ⴛ β = (-9p+7q)/p

=> Ⴛ β = (7q-9p)/p ----------(2)

We know that

The quadratic equation whose roots are Ⴛ and β is x²-(Ⴛ+ β)x +Ⴛ β = 0

=> x²- [ (3q-3p)/p]x + [ (7q-9p)/p] = 0

=> [px²-(3q-3p)x+(7q-9p)]/p = 0

=> [px²-(3q-3p)x+(7q-9p)] = 0×p

=> px²-(3q-3p)x+(7q-9p) = 0

The required quadratic equation is

px²-(3q-3p)x+(7q-9p) = 0

Answer:

(D) -2

Step-by-step explanation:

Plug in r=5 and s=-7 to the equation:

-6(5)+(-7)-(5)(-7)

Now we can solve and simplify:

-30-7+35

Combine:

-2

Hey there!

-6r + s - rs

= -6(5) + (-7) - 5(-7)

= -6(5) - 7 - 5(-7)

= -30 - 7 - 5(-7)

= -30 - 7 + 5

= -37 - (-35)

= -2

Therefore, your answer is: -2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Hey there!

5(4r + 3) - 2x

DISTRIBUTE 5 WITHIN the PARENTHESES

= 5(4r) + 5(3) - 2x

= 20r + 15 - 2x

COMBINE the LIKE TERMS (if they are any)

Seems like you don’t have any like terms so we could leave it as it is!

= 20r + 15 - 2x

= 20r - 2x + 15

Therefore, the answer should be:

20r - 2x + 15

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)