Nicolas is playing with his toy car. A parachute in the back of the car is released to help slow down the car.
If the forces act on the car as shown in the picture, what is the net force?

Answer:

Perception: Perception is a cognitive process that allows people to take in information through their senses (sensation) and then utilize this information to respond and interact with the world. Thought: Thought is an essential part of every cognitive process.

I hope it helped

Answer:

a. The pressure in the tubing is equal to the barometric pressure.

Explanation:

Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.

Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure

Hence, the correct option is a.

Answer:

i would tell you but im a hobbit

Explanation:

biden 2020

Answer:

5778.1931

Explanation:

Given that:

Mass (M) = 5.98 x 10^24 kg

Radius (r) = 6.96 x 10^6 m

Gravitational constant (G) = 6.67 * 10^-11

Using the relation:

T² / R³ = 4π² / GM

Where T = period of orbit

T = 2π√(R³ /GM)

T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)

T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))

T = 2π √845715.64

T = 2π * 919.62799

T = 5778.1931

Answer:

300 L of water

Explanation:

Solution:

The gravitational force that acts on the bicycle system is

[tex]$F_{g} = 500 \ N$[/tex]

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

[tex]$F_g=mg$[/tex]

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

[tex]$F_f = ma$[/tex]

[tex]$a=\frac{F_f}{m}$[/tex]

  [tex]$=\frac{250}{50}$[/tex]

Therefore [tex]$a= 5 \ m/s^2$[/tex]

Hence (C) is correct option.  

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

       [tex]R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)[/tex]

       [tex]R = \rho* \frac{L}{A} (2)[/tex]

      [tex]A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)[/tex]

       [tex]\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m[/tex]

Answer:

Newton

Explanation:

Answer:

Can't see anything, please share clearly

Answer:

the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

Explanation:

The computation of the minimum energy that needed to break the nucleus is shown below:

The Change in mass is

= 11.99671 - 3 × 4.00151

= 0.00782

The Energy = mc^2

= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2

= 1.12608 × 10^-12 J

Hence, the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

The same is to be considered

Answer:

Acceleration

Explanation:

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

Answer:

A. 14 meters/second to the west

Explanation:

The collision is inelastic, which means that:

- only the total momentum is conserved (not the kinetic energy)

Answer:

14 meters/second to the west

Explanation:

That's the answer!

Answer:

it should be a new moon

Explanation:

B.) Elastic

Took the test and this is the answer

27.52g grams of sodium would there be in 70 g of NaCl.

The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.

The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.

Here I have direct method for the calculation of mass of particular atom in the molecule.

Molecular weight of the NaCl is,

(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.

in this we can see that 58.5 g of Nacl contains 23 g of Na.

we can write 58.5 NaCl = 23g Na

therefore 70g of NaCl = (23÷58.5)×70 Na

70g of NaCl = 27.52g of Na

Hence 70g of NaCl contains 27.52g of sodium.

To know more about molecular mass, click :

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Answer:

True

Nitrogen family elements consists of atoms having 5 electrons in their outer energy level.

Please mark me the brainliest

Hope it may helps you

Answer:

light is a longitudinal wave.

Explanation:

lol

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

Answer:

yes a body can have mass but no wt at a centre of the earth

Explanation:

this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre

Answer:

Meeee

Explanation:

Answer:

The unknown mass is 3.87 kg.

Explanation:

Given;

spring constant of the spring, k = 13.6 N/m

period of oscillation, T = 3.35 s

The period of oscillation of the mass-spring system is given by;

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where;

m is the mass attached to the spring

[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]

Therefore, the unknown mass is 3.87 kg.

Answer:

x=6 m, y= 3 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the components of the velocity at a given time t are:

[tex]v_x=v_o\cos\theta[/tex]

[tex]v_y=v_o\sin\theta-g.t[/tex]

And the components of the displacement are:

[tex]x=v_o\cos\theta .t[/tex]

[tex]\displaystyle y=v_o\sin\theta.t-\frac{g.t^2}{2}[/tex]

The projectile of the problem is fired at θ=53° with an initial speed of vo=10 m/s.

Thus, after 1 second, the components of the displacement are:

[tex]x=10\cos 53^\circ \cdot 1[/tex]

[tex]x\approx 6~m[/tex]

[tex]\displaystyle y=10\sin 53^\circ\cdot 1-\frac{9.8\cdot 1^2}{2}[/tex]

[tex]y\approx3~m[/tex]

Answer: x=6 m, y= 3 m

None of the options match this answer.

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

Answer:

The gravitational force between Royce and Earth would be doubled at 16 years.

Explanation:

"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.

Given:

At 10 years old,

Mass,

now,

→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]

                                          [tex]= mg[/tex]

or,

→ [tex]g = \frac{GM}{r^2}[/tex]

then,

Gravitational force = 30 g

Now,

At 16 years old,

Mass,

Now,

→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]

       [tex]=\frac{1}{2}[/tex]

  [tex]F_2 = 2F_1[/tex]

Thus the above response is right.

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Answer:

c. 1.0 mu T

Explanation:

From, the ampere's  circuit law:

∫B.dl = μ₀ I

B.(2πr) = μ₀ I

where,

B = Magnetic Field = ?

r = radius of the circle = length of wire = 3 m

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

I = Current = 15 A

Therefore,

B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)

B = 10 x 10⁻⁷ T

B = 1 x 10⁻⁶ T = 1 μT

Hence, the correct option is:

c. 1.0 mu T

Answer:

[tex]\boxed {\boxed {\sf 7.84 \ Joules}}[/tex]

Explanation:

The formula for potential energy is:

[tex]PE=m*g*h[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

[tex]m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m[/tex]

Substitute the values into the formula.

[tex]PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]

Multiply the first two numbers.

[tex]PE=(3.92 \ N )(2 \ m)[/tex]

Multiply.

[tex]PE=7.84 \ J[/tex]

Answer:

7.84 is your answer ok bye

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation: