Answer:
Mr. Rowley=16:14
=8:7
Ms.Rivera= 64:60
=16:15
Adam runs 13 miles in 143 minutes. How many minutes does it take him to run one mile? Adam runs at a rate of minutes per mile.
Answer:
Adam runs at a rate of 11 minutes per mile.
Step-by-step explanation:
Take 143 minutes and divide by 13 miles and you will get the answer of 11 minutes.
PLEASE MARK ME BRAINEIST.
Answer:
it would take him 11 minuets to run a mile
Step-by-step
143 divided by 13 is 11 which means each mile takes 11
you can also check the answer by multiplying 13 times 11 which is 143
i need help on 8-9 plss :))
Answer:
8. SU = 24
9. TU = 16√3
Step-by-step explanation:
Recall: SOH CAH TOA
8. Reference angle (θ) = 30°
Opposite = 8√3
Adjacent = SU
Apply TOA,
Tan θ = Opp/Adj
Substitute
Tan 30° = 8√3/SU
Tan 30° × SU = 8√3
SU = 8√3/Tan 30°
SU = 8√3/(1/√3) (tan 30° = 1/√3)
SU = 8√3*√3/1
SU = 8*3
SU = 24
9. Reference angle (θ) = 30°
Opposite = 8√3
Hypotenuse = TU
Apply SOH,
Sin θ = Opp/Hyp
Substitute
Sin 30° = 8√3/TU
Sin 30° × TU = 8√3
TU = 8√3/sin 30°
TU = 8√3/(½) (sin 30° = ½)
TU = 8√3 × 2/1
TU = 16√3
Find the exact area of this triangle: 10V3 30° 20 [?] [ square units
Answer:
50√3 square units.
Step-by-step explanation:
Let the two sides of the triangle given be 'a' and 'b'.
Let the angle between them be θ
From the question given above, the following data were obtained:
Side a = 20 units
Side b = 10√3
Angle (θ) = 30°
Area (A) =?
A = ½ × ab × Sineθ
A = ½ × 20 × 10√3 × Sine 30
A = ½ × 20 × 10√3 × ½
A = 10 × 5√3
A = 50√3 square units
Therefore, the area of the triangle is 50√3 square units
There is a sales tax of S6 on an item that costs 888 before tax. The sales tax on a second item is $21. How much does the second item cost before tax?
Step-by-step explanation:
before Tax
Coast = 888
in 2ND Item = $21
• 888/21
= $42.28
9.03 divided by 899.8 is closest to? a.0.01 b.0.001 c.1 d.100
9.03 divided by 899.8 is closest to a.0.01
Answer: a) 0.01
Step-by-step explanation:
Solve for y. 14y-6(y-3)=22
Answer:
y=0.5
Step-by-step explanation:
14y-6(y-3)=22
14y-6y+18=22
8y+18=22
8y=4
y=0.5
Then we check our work...
14(0.5)-6((0.5)-3)=22
7-6(-2.5)=22
7+15=22
7+15 does equal 22, so this solution is correct.
Find the missing length indicated
Answer:
60
Step-by-step explanation:
Use similar triangles or the ratios from the right triangle altitude theorem.
x/36 = (64 + 36)/x
x² = 3600
x = 60
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from the left end of the scaffold, and his painting equipment is 1.4 m from the right end. If the tension in the left cable is twice that in the right cable, find the tensions in the cables (in N) and the mass of the equipment (in kg). (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.)
Step-by-step explanation:
Let
[tex]m_p[/tex] = mass of the painter
[tex]m_s[/tex] = mass of the scaffold
[tex]m_e[/tex] = mass of the equipment
[tex]T[/tex] = tension in the cables
In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as
[tex]3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)[/tex]
Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of [tex]m_e[/tex]. The net torque on the scaffold is then
[tex]T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0[/tex]
Solving for T,
[tex]9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})[/tex]
or
[tex]T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})][/tex]
[tex]\:\:\:\:= 423.3\:\text{N}[/tex]
To solve for the the mass of the equipment [tex]m_e[/tex], use the value for T into Eqn(1):
[tex]m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}[/tex]
The least-squares regression equation
y = 3 + 1.16x can be used to predict the height of a plant (in centimeters) after x weeks. Suppose the height of a plant was 9.2 centimeters after 5 weeks.
Calculate and interpret the residual for this plant after 5 weeks.
The residual is
✔ 0.4
, which means that the predicted height of the plant is
✔ 0.4 centimeters less
than the actual height of the plant of
✔ 9.2
centimeters.
Answer:
✔ 0.4
✔ 0.4 centimeters less
✔ 9.2
1.16(5) + 3 = 8.8
9.2 - 8.8 = .4
ED2021
The residual is 0.4
What is regression?
'Regression takes a group of random variables, thought to be predicting Y, and tries to find a mathematical relationship between them. This relationship is typically in the form of a straight line (linear regression) that best approximates all the individual data points.'
According to the given problem,
y = 3 + 1.16x
After 5 weeks, x = 5,
⇒ y = 3 + 1.16(5)
⇒ y = 3 + 5.8
⇒ y = 8.8
Now subtracting y from actual height of plant,
⇒ 9.2 - 8.8
= 0.4
Hence, we can conclude the residual to be 0.4.
Learn more about regression here: https://brainly.com/question/7656407
#SPJ2
What is the equation
Answer:
y=3x+1
Step-by-step explanation:
Determine slope with two coordinates and use it in the formula
Use the confidence level and sample data to find a confidence interval for estimating the population μ. Round your answer to the same number of decimal places as the sample mean.
Test scores: n = 92, = 90.6, σ = 8.9; 99% confidence
Options:
A.) 88.2 < μ < 93.0
B.) 88.4 < μ < 92.8
C.) 89.1 < μ < 92.1
D.) 88.8 < μ < 92.4
Answer: Choice A.) 88.2 < μ < 93.0
=============================================================
Explanation:
We have this given info:
n = 92 = sample sizexbar = 90.6 = sample meansigma = 8.9 = population standard deviationC = 99% = confidence levelBecause n > 30 and because we know sigma, this allows us to use the Z distribution (aka standard normal distribution).
At 99% confidence, the z critical value is roughly z = 2.576; use a reference sheet, table, or calculator to determine this.
The lower bound of the confidence interval (L) is roughly
L = xbar - z*sigma/sqrt(n)
L = 90.6 - 2.576*8.9/sqrt(92)
L = 88.209757568781
L = 88.2
The upper bound (U) of this confidence interval is roughly
U = xbar + z*sigma/sqrt(n)
U = 90.6 + 2.576*8.9/sqrt(92)
U = 92.990242431219
U = 93.0
Therefore, the confidence interval in the format (L, U) is approximately (88.2, 93.0)
When converted to L < μ < U format, then we get approximately 88.2 < μ < 93.0 which shows that the final answer is choice A.
We're 99% confident that the population mean mu is somewhere between 88.2 and 93.0
Find the missing side round your answer to the nearest tenth.
Answer:
x=74.3
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan 22 = 30/x
x tan 22 = 30
x = 30/ tan 22
x=74.25260
To the nearest tenth
x=74.3
2x+3=60 thì x băng bao nhieu
Answer:
x=57/2
Step-by-step explanation:
2x+3=60
<=> 2x=57
=> x=57/2
A ladder 10m long is set against a vertical wall, Calculate the height of the wall where the ladder reached a foot of the ladder is 6m away from the wall.
Answer:
8m
Step-by-step explanation:
Find the missing length
Answer:
x=5.9
i think this the answer
answer this question ASAP
Answer:
972pi in ^3
Step-by-step explanation:
We need to find the volume of the sphere
V = 4/3 pi r^3
The diameter is 18
r = d/2 = 18/2 = 9
V = 4/3 pi ( 9)^3
V = 972pi in ^3
Which is the solution to-x/2<-4
A x<-8
B x2-8
C x <8
D x 8
Answer:
A.x<-8
Step-by-step explanation:
=1/2x<−4
=2*(1/2x)< (2)*(-4)
= x<-8
please help solve for y!
As both angles are supplementary
[tex]\\ \Large\sf\longmapsto 3x+(2x+3y)=180°[/tex]
[tex]\\ \Large\sf\longmapsto 3x+2x+3y=180[/tex]
[tex]\\ \Large\sf\longmapsto 5x+3y=180[/tex]
[tex]\\ \Large\sf\longmapsto 3y=180-5x[/tex]
[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]
And
[tex]\\ \Large\sf\longmapsto 3x=90[/tex]
[tex]\\ \Large\sf\longmapsto x=\dfrac{90}{3}[/tex]
[tex]\\ \Large\sf\longmapsto x=30[/tex]
Now
Putting value[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]
[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5(30)}{3}[/tex]
[tex]\\ \Large\sf\longmapsto y=\dfrac{180-150}{3}[/tex]
[tex]\\ \Large\sf\longmapsto y=\dfrac{30}{3}[/tex]
[tex]\\ \Large\sf\longmapsto y=10[/tex]
The difference between two positive integers is 3. If the smaller is added to the square of the larger, the sum is 129.
Step 2 of 2 : Find the integers by solving the equation.
Answer:
11 and 8
Step-by-step explanation:
Let the integers be x and y. ATQ y-x=3 and x+y^2=129. Solving it, we will get x=8 and y=11
What is the mean of the following list of extra credit points earned on a statistics test?
10,8,18,17,7
Answer:
12
Step-by-step explanation:
Given the data :
X : 10,8,18,17,7
The mean value of scores obtained can be obtained thus :
Mean = ΣX / n
n = sample size = 5
Mean = ΣX / n = (10+8+18+17+7) / 5
Mean = 60 / 5 = 12
If my classmate was born on April 9, two thousand and six and I was born on December 24, two thousand and four, how many months, years and days are we apart?
Answer:
I could be wrong but I calculated 2 years 8 months and 15 days.
2 years
8 months
15 days
Solve for x.
A. 2
B. 5
C. 0
D. 7
Answer:
We know that the angle which lineer and divided by |AB| equal to 130°
Step-by-step explanation:
if 130° look at the 2x+260 we can say that 2x+260=260° so X equal to Zero (0)
Gina charges an initial fee and an hourly fee to babysit. Using the table below find the hourly fee and the initial fee that
Gina charges to babysit. Show work.
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X 5 the number of months between successive payments. The cdf of X is as follows:
0 x<1
0.30 1< x <3
F(x)= 0.40 3< x <4
0.45 4< x <6
0.60 6< x <12
1 12< x
Required:
a. What is the pmf of x?
b. Using just the cdf, compute P(3< x <6)and P(4< x)
Answer:
(a)
[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]
(b)
[tex]P(3 \le x \le 6) = 0.30[/tex]
[tex]P(4 \le x)=0.60[/tex]
Step-by-step explanation:
Given
[tex]F(x) = \left[\begin{array}{ccc}0& x<1 &\\0.30&1 \le x<3 &\\0.40&3 \le x < 4& &0.45 &4 \le x<6 &\\0.60 & 6 \le x < 12 & & 1 & 12 \le x\end{array}\right[/tex]
Solving (a): The pmf
This means that we list out the probability of each value of x.
To do this, we simply subtract the current probability value from the next.
So, we have:
[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]
The calculation is as follows:
[tex]0.30 - 0 = 0.30[/tex]
[tex]0.40 - 0.30 = 0.10[/tex]
[tex]0.45 - 0.40 = 0.05[/tex]
[tex]0.60 - 0.45 = 0.15[/tex]
[tex]1 - 0.60 = 0.40[/tex]
The x values are gotten by considering where the equality sign is in each range.
[tex]1 \le x < 3[/tex] means [tex]x = 1[/tex]
[tex]3 \le x < 4[/tex] means [tex]x = 3[/tex]
[tex]4 \le x < 6[/tex] means [tex]x=4[/tex]
[tex]6 \le x < 12[/tex] means [tex]x = 6[/tex]
[tex]12 \le x[/tex] means [tex]x = 12[/tex]
Solving (b):
[tex](i)\ P(3 \le x \le 6)[/tex]
This is calculated as:
[tex]P(3 \le x \le 6) = F(6) - F(3-)[/tex]
From the given function
[tex]F(6)= 0.60[/tex]
[tex]F(3-) = F(1) = 0.30[/tex]
So:
[tex]P(3 \le x \le 6) = 0.60 - 0.30[/tex]
[tex]P(3 \le x \le 6) = 0.30[/tex]
[tex](ii)\ P(4 \le x)[/tex]
This is calculated as:
[tex]P(4 \le x)=1 - F(4-)[/tex]
[tex]P(4 \le x)=1 - F(3)[/tex]
[tex]P(4 \le x)=1 - 0.40[/tex]
[tex]P(4 \le x)=0.60[/tex]
The area of a rectangle is 63 ft^2, and the length of the rectangle is 11 ft more than twice the width. Find the dimensions of the rectangle.
Can someone please help
Me
Answer:
$3735
Step-by-step explanation:
2/5 = 8/20
8/20 + 7/20 = 15/20 = 3/4
3/4*4980 = 3735
A poll of 400 people from Dobbs Ferry showed 250 preferred chocolate raspberry coffee while 170 out of 350 in Irvington preferred the same flavor. To test the hypothesis that there is no difference in preferences in the two villages, what is the alternate hypothesis
Answer: The alternate hypothesis would disprove the null hypothesis and state that there are a significant difference in preferences/proportions between the two villages.
For instance, let's say:
p₁ = proportion of preference from Dobbs Ferryp₂ = proportion of preference from IrvingtonThe null hypothesis would be that p₁ = p₂, while the alternative hypothesis would be that p₁ ≠ p₂.
Betadine solution is a 10% povidone-iodine solution. Express this strength both as a fraction and as a ratio.
Step-by-step explanation:
Fraction =
[tex] \frac{10}{100} = \frac{1}{10} [/tex]
Ratio is 1 : 10
Kiểm tra 800 hạt gạo của một lô gạo người ta thấy có 750 hạt nguyên, 25 hạt tấm lớn, 25 hạt tấm bé. Hãy tìm khoảng tin cậy của tỉ lệ hạt nguyên của lô gạo nói trên với độ tin cậy 95%. Cho U(0,025) = 1,96, U(0,05) = 1,645.
Answer:
what is your Language I think it is Russian I don't understand Russian I only understand Nepali,English and Japanese
A box with a square base and no top is to be made from a square piece of carboard by cutting 4 in. squares from each corner and folding up the sides. The box is to hold 1444 in3. How big a piece of cardboard is needed
Answer:
[tex]C=27inch\ by\ 27inch[/tex]
Step-by-step explanation:
Squares [tex]h=4inch[/tex]
Volume [tex]v=1444in^3[/tex]
Generally the equation for Volume of box is mathematically given by
[tex]V=l^2h[/tex]
[tex]1444=l^2*4[/tex]
[tex]l^2=361[/tex]
[tex]l=19in[/tex]
Since
Length of cardboard is
[tex]l_c=19+4+4[/tex]
[tex]l_c=27in[/tex]
Therefore
Dimensions of the piece of cardboard is
[tex]C=27inch\ by\ 27inch[/tex]
