Answer:
not exactly sure what the question is but
if it is "what is the max that 15 - x^2 - x can be
then 2x-1 = 0 solves that
x = 1/2
Step-by-step explanation:
Prove that the points P(-1,1) ,Q(2,3) and R(2,1) are the vertices of a salence triangle. Plz ans fast.
Step-by-step explanation:
P(-1,1), Q(2,3), R(2,1)
Let P(-1,1)be x1and y1
Q(2,3)be x2 and y2
therefore, by distance formula
d(PQ)= root (x2-x1)^2+(y2-y1)^2
= root[ 2-(-1)] + (3-1)
=root (2+1)^2+2^2
= root (3square +2square )
= root 9+4
d( PQ) = root 13.........(1)
Now find distance QR and PR then prove that the three sides are not equal and therefore it is a scalene triangle
2nd also do the same.
!!! i only need part c !!! There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B.
Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points)
Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points)
Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically. (4 points)
(10 points)
find the value of x
angle at center is twice angle at circumference
so therefore the lengths of WU and WV are proportional along with WC and WT.
WU / WV = WC / WT
4 / 2 = 11 / x
2 = 11 / x
x = 11 / 2 or 5.5 u
if (x) and 1(x) are inverse functions of each other and S(x) = 2x+5, what is (8)?
이스 NW
8
023
Answer:
B
Step-by-step explanation:
f(x) = 2x+5
f^(-1) (x) = (x-5)/2
f^(-1) (8) = 3/2
4.1<7 as a fraction. pls workout and ill mark you brainliest
Answer:
4/7
Step-by-step explanation:
hope this helps
Which inequality is represented by this graph?
OA. y<-1/5x+1
OB. y>= -1/5x+1
OC. y<= -1/5x+
OD. y>-1/5x+1
Answer:
Option A is correct
Step-by-step explanation:
Hope it is helpful....
Please help explanation if possible
Answer:
y = - [tex]\frac{3}{2}[/tex] x + 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = [tex]\frac{2}{3}[/tex] x + [tex]\frac{2}{3}[/tex] ← is in slope- intercept form
with slope m = [tex]\frac{2}{3}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{2}{3} }[/tex] = - [tex]\frac{3}{2}[/tex] , then
y = - [tex]\frac{3}{2}[/tex] x + c ← is the partial equation
To find c substitute (- 2, 4) into the partial equation
4 = 3 + c ⇒ c = 4 - 3 = 1
y = - [tex]\frac{3}{2}[/tex] x + 1 ← equation of line
Calcula el valor de “x” en:
5(3x – 4) – 17 = 5(x + 8) – 17
Answer: x = 6
Step-by-step explanation:
Sume 17 a ambos lados
5(3x-4)-17 + 17=5(x+8)-17 +17
Simplifica
5(3x-4)=5(x+8)
Expandir 5(3x -4) : 15x - 20
Expandir 5(x+8) : 5x +40
15x - 20 = 5x +40
Sume 20 a ambos lados
15x - 20 + 20 = 5x +40 +20
Simplifica
15x = 5x +60
Restar 5 de ambos lados
15x - 5x = 5x + 60 - 5x
Simplifica
10x = 60
Divide ambos lados entre 10
10x/10 = 60/10
Simplifica
x = 6
4sin²[tex]\frac{x}{2}[/tex]=3
Answer:
[tex]\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}[/tex]
Step-by-step explanation:
Hi there!
We want to solve for [tex]x[/tex] in:
[tex]4\sin^2(\frac{x}{2})=3[/tex]
Since [tex]x[/tex] is in the argument of [tex]\sin^2[/tex], let's first isolate [tex]\sin^2[/tex] by dividing both sides by 4:
[tex]\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}[/tex]
Next, recall that [tex]\sin^2x[/tex] is just shorthand notation for [tex](\sin x)^2[/tex]. Therefore, take the square root of both sides:
[tex]\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}[/tex]
Simplify using [tex]\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}[/tex]:
[tex]\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}[/tex]
Let [tex]\phi = \frac{x}{2}[/tex].
Case 1 (positive root):[tex]\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}[/tex]
Therefore, we have:
[tex]\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}[/tex]
Case 2 (negative root):[tex]\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}[/tex]
Alex has collected apples. It has 40 boxes of 8.5 kg each and 6 sacks of 90kg each. Pack the apples in bags of 2.5 kg each. how many bags do you get?
Answer:
40*8.5=340
6*90=540
total=880/2.5=352bags
deandre downloaded 8 apps onto his tablet in 12 secs at this rate how many apps could he download in one minute
Because 1 minute is 60 seconds, and it takes 12 seconds to download 8 apps, the first thing we need to do is find out how many "sets" of 12 seconds can go in 60 seconds:
60 / 12 = 5
Now, all we have to do is multiply the number of apps by 5, and we get our answer:
8 · 5 = 40
So, it would take Deandre 1 minute to download 40 apps.
please help meeee!!!!!
Step-by-step explanation:
3. First, let's find the length of AB:
22²+14² = AB²
680 = AB²
AB = √680
AB ≈ 26.08
The sin of x° is equal to 14/2608
14/26.08 ≈ 0.54
Now you do the asin of 0.54:
asin(0.54) = 32.68°
4. The cos(41°) = x/34, and also the value of cos(41°) ≈ 0.75, so:
0.75 = x/34
x = 34•0.75
x = 25.5°
Need help asap algebra 2
Answer:
Hello,
Step-by-step explanation:
a)
[tex]\Large h(x)=\sqrt[3]{x+2} \ -3\\\\h(x)=-3\\\Longrightarrow\ \sqrt[3]{x+2} \ -3=-3 \\\\\Longrightarrow\ \sqrt[3]{x+2} =0\\\\\Longrightarrow\ (\sqrt[3]{x+2}) ^3=0^3\\\\\Longrightarrow\ x+2=0\\\\\Longrightarrow\ x=-2\\[/tex]
b)
[tex]-3=k(x)=h(x-1)+2=\sqrt[3]{(x-1)+2} -3=\large \sqrt[3]{x+1} -3\\\\\\\Longrightarrow\ \sqrt[3]{x+1}=0\\\\x+1=0\\\\x=-1\\\\[/tex]
Question Number 19 of 40 - Algebra II Boyle's Law states that, for a fixed amount of gas, the volume of the gas at a constant temperature is inversely proportional to the pressure. If a certain gas occupies 9.84 liters at a pressure of 50 centimeters of mercury (cm Hg), what is the approximate pressure when the volume is increased to 12 liters
Answer:
41 cm Hg
Step-by-step explanation:
Round 7,582.149 to:
tens
and
hundredths
Answer:
Round to Tens
7,580
Round to hundredths
7,582.15
What is the mode of the data shown in the table?
Scores: 5, 12, 13, 18
Frequency: 3, 2, 5, 4
A. 12
B. 13
C. 51.5
D. 12.5
Answer: Option B - 13
Explanation:
The mode is the value that appears most frequently in a data set
So 13 appears 5 times so it is the mode
Must click thanks and mark brainliest
Answer:
B
Step-by-step explanation:
The mode is the score which occurs most often.
From the table a score of 13 occurs 5 times, that is
The mode is 13 → B
The perimeter of a rectangle is 40 inches. If the width is 9 inches, what is the area of the rectangle?
Answer:
99 in²
Step-by-step explanation:
Perimeter = 2(length) + 2(width)
40 = 2(length) + 2(9)
40 = 2L + 18
40 - 18 = 2l
22 = 2l
L = 11
Area = length x width
Area = 9 x 11 = 99
99 square inches
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer: 360
Step-by-step explanation:
you multiply 40 and 9.
first you multiply 9 and 0 that is 0 then 9 to 4 and that is 36 so you get 360
NEED some HElp please
Explain why the amount of money in the account at the end of the first year is given by the formula with n as the exponent:
P = P∨0 (1 + r/n)^n
Answer:
Is this answer correct.Does the anwer help you
Triangle OPR has length OR=5m, angle OPR = 90, find length QP
Answer:
i don't know
Step-by-step explanation:
i don't know
7.
Explain why the equation 6|x| + 25 = 15 has no solution.
When one solves, they arrive at a step where |x| is equal to a fraction that may not be represented as an integer. Since | x| must be an integer, there is no solution.
When one solves, they arrive at a step where x is equal to a negative number. Since x can never be negative inside of the absolute value bars, there is no solution.
When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.
The statement is false. There is a solution.
Answer:
When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.
Step-by-step explanation:
6|x| + 25 = 15
Subtract 25 from each side
6|x| + 25-25 = 15-25
6|x| = -10
Divide by 6
6|x| /6 = -10/6
|x| = -5/3
There is no solution because the absolute value must be greater than or equal to zero. This equation has it negative.
Determine whether the graph is the graph of a function. Yes or no.
It is a graph of a function
Evaluate. (-2 1/4)^2
Answer:
[tex]5 \frac{1}{16}[/tex]
Step-by-step explanation:
I did this before. Also sometimes once I look at the question I just find out the answer without steps.
ABCD is a parallelogram, AE=16, AB=24, EC=2y-4, DE=67, and EB = 2x+7. Solve for x. (Round your answer to one decimal place, if necessary.) Plz help will give brainliest
Answer:
x = 30
Step-by-step explanation:
The diagonals are bisected so DE =EB
67 = 2x+7
Subtract 7
67-7 = 2x+7-7
60 =2x
Divide by 2
60/2 =2x/2
30 = x
Another distribution problem. Can someone solve?
Answer:
Hello,
Step-by-step explanation:
[tex]P(3000<x<4000)\\\\=P(\dfrac{3000-3262}{1100} \leq z\leq \dfrac{4000-3262}{1100})\\\\=P(z\leq 0,6709)-(1-P(z\leq 3524) \leq z))\\\\=0.7515-0.5941\\\\=0.1574\\[/tex]
My table have 4 digits but i have made a linear interpolation .
Answer:
-.238, .67, .7486, .4052, .3434
Step-by-step explanation:
standardize them both
(3000-3262)/1100= -.238 which rounds to -.24 which has a probability of .4052
(4000-3262)/1100= .67 which has a probability of .7486
subtract them
.7486-.4052=.3434
Can someone please help me with these 4 questions?
It costs $36.00 to get into an amusement park. Treats, like cotton candy, caramel apples, and
funnel cakes cost $4.00 each. If you have $52.00, find x, the number of $4.00 treats you can
buy, after paying to get into the park.
a.
x ≤
1
4
b. x = 3
c. x ≥ 4
d. x ≤ 4
Answer:
d
Step-by-step explanation:
So the problem states,
52 = 36 + 4x
16 = 4x
x = 4 (must be less than or equal to)
Simplify.
[tex] \frac{6a + 18b - 12c}{6} [/tex]
8th grade maths
Step-by-step explanation:
[tex] \frac{6a + 18b - 12c}{6} \\ = \frac{6a}{6} + \frac{18b}{6} - \frac{12c}{6} \\ = a + 3b - 2c \\ thank \: you[/tex]
The price of a laptop is fixed 20% above it's cost price and sold it at 13%discount to gain rs 1980 . How much should a customer pay for it
Answer:
Rs 46980Step-by-step explanation:
Let the cost is x, we have then:
1.2x*(0.87) = x + 1980(1.2*0.87 - 1)x = 19800.044x = 1980x = 1980/0.044x = 45000Cost is 45000, then SP is:
SP = 45000 + 1980 = 46980how many inches is 775 centimeters
Answer:
305.11
Step-by-step explanation:
Just use a calculator. A centimeter is 2.5 inches. Divide 775 by that.
Someone help please
Answer: Choice A
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex]
============================================================
Explanation:
Recall that [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex] and [tex]\cot(x) = \frac{\cos(x)}{\sin(x)}[/tex]. The connection between tangent and cotangent is simply involving the reciprocal
From this, we can say,
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.
All of this shows why [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is identical to [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
Therefore, [tex]\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.
You can visually confirm that [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is the same as [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.