Mahiya and Mrinmoy are in a relay around a square field with each side of length 60m. First, Mahiya runs at a speed of 6 ms−1 for 60m to pass a baton to Mrinmoy. Then Mrinmoy runs 120m at 4ms−1 while Mahiya runs through the field to reach the other corner. Then Mrinmoy passes the baton. But Mahiya is now tired since she has been constantly running. So, she only runs at 3ms−1 for the final 60m. What is the average speed of the baton in ms−1?

The average speed of the baton can be determined by dividing the total distance travelled by the total time taken for that travelling.

[tex]Average\ Time = \frac{Total\ Distance}{Total\ Time}[/tex]

First, we will find the total distance, by adding the distances travelled by both Mahiya and Mrinmoy, while carrying the baton.

[tex]Total\ Distance = Distance\ Travelled\ by\ Mahiya\ to\ pass\ the\ baton\ to\ Mrinmoy\ +\ Distance\ Travelled\ by\ Mrinmoy\ to\ pass\ the\ baton\ to\ Mahiya\ +\ Final\ Distance\ Travelled\ by\\ Mahiya[/tex]Total Distance = 60 m + 120 m + 60 m = 240 m

Now, we will find the total time taken for this travelling. To find out the total time we will divide each distance travelled by the speed of the traveller during that distance:

[tex]Total\ Time = \frac{60\ m}{6\ m/s}+\frac{120\ m}{4\ m/s}+\frac{60\ m}{3\ m/s}\\\\Total\ Time = 10\ s\ +\ 30\ s\ +\ 20\ s[/tex]

Total Time = 60 s

Now, we finally find the average speed of the baton by using the formula:

[tex]Average\ Time = \frac{Total\ Distance}{Total\ Time}\\\\Average\ Time = \frac{240\ m}{60\ s}[/tex]

Average Speed = 4 ms⁻¹

Learn more about average speed here:

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