look at the image below plz correct answers Surface area of cones 15 points

Look At The Image Below Plz Correct Answers Surface Area Of Cones 15 Points

Answers

Answer 1

Answer:

[tex]A\approx 282.7\ m^2[/tex]

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to use the Pythagorean theorem to find the height of the cone. Then one can substitute the values given and found on the cone into the formula to find the surface area in order to solve for the surface area of the given cone.

2. Height of the cone

Imagine drawing a line from the tip of the cone down to the center of the base. This line will form a right angle with the base, thus, a right triangle is formed between the line, the radius (the distance from the center to the circumference or outer edge on a circle) of the base, and the incline of the cone. The Pythagorean theorem is a formula that relates the sides of a right triangle. This formula is as follows:

[tex]a^2+b^2=c^2[/tex]

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle, and (c) is the hypotenuse or the side opposite the right angle of the right triangle. Substitute the given values into the formula and solve for the unknown, or rather the height of the cone:

[tex]a^2+b^2=c^2[/tex]

[tex]a^2+5^2=13^2[/tex]

Simplify,

[tex]a^2+5^2=13^2[/tex]

[tex]a^2+25=169[/tex]

Inverse operations,

[tex]a^2+25=169[/tex]

[tex]a^2=144[/tex]

[tex]a=12[/tex]

[tex]h=12[/tex]

3. Find the surface area of the cone.

The following formula can be used to find the surface area of a cone:

[tex]A=\pi r(r+\sqrt{h^2+r^2})[/tex]

Where ([tex]\pi[/tex]) represents the numerical value (3.1415...), (r) represents the radius of the base, and (h) represents the height of the cone. Substitute the given values into the formula and solve for the surface area:

[tex]A=\pi r(r+\sqrt{h^2+r^2})[/tex]

[tex]A=\pi 5(5+\sqrt{12^2+5^2})[/tex]

Simplify,

[tex]A=\pi 5(5+\sqrt{12^2+5^2})[/tex]

[tex]A=\pi 5(5+\sqrt{144+25})[/tex]

[tex]A=\pi 5(5+\sqrt{169})[/tex]

[tex]A=\pi 5(5+13)[/tex]

[tex]A=\pi 5(18)[/tex]

[tex]A=\pi 90[/tex]

[tex]A\approx 282.743[/tex]


Related Questions

What is the slope? Please Help

Answers

Answer:

-1

Step-by-step explanation:

Pick two points on the line

(0,2) and (2,0)

Using the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 0-2)/(2-0)

    = -2/2

  = -1

Answer:

-1

Step-by-step explanation:

Use two points on the line to find the slope, using rise over run.

We can use the points (0, 2) and (2, 0).

From the first point to the other, the y value decreases by 2 and the x value increases by 2.

Use rise (change in y value) over run (change in x value):

-2 / 2

= -1

So, the slope is -1.

A ball is thrown straight up into the air from an initial height of 5 feet at time t = 0. The height, in feet, of the ball above the ground is given by h(t), where t is measured in seconds for 0 ≤ t ≤ 15. Based on the values of t and h(t) given in the table, for which value of t would the speed of the ball most likely be the greatest?

t (seconds) 0 3 6 9 12 15
h(t) (feet) 5 12 15 11 6 0

Select one:
a. 2 seconds
b. 5 seconds
c. 9 seconds
d. 15 seconds

Answers

Answer:

5 seconds

Step-by-step explanation:

The speed of an object is the rate of distance over time. The value of time (t) at the greatest speed of the ball is at 2 seconds

First, we calculate the speed using:

[tex]Speed = \frac{h(t)}{t}[/tex] --- i.e. distance/time

At t = 0, h(t) = 5

So;

[tex]Speed = \frac{5}{0} = unde fine d[/tex]

At t = 3, h(t) = 12

[tex]Speed = \frac{12}{3} = 4[/tex]

At t = 6, h(t) = 15

[tex]Speed = \frac{15}{6} = 2.5[/tex]

At t = 9, h(t) = 11

[tex]Speed = \frac{11}{9} = 1.2[/tex]

At t = 12, h(t) = 6

[tex]Speed = \frac{6}{12} = 0.5[/tex]

At t = 15, h(t) = 0

[tex]Speed = \frac{0}{15} = 0[/tex]

By comparing the above values, we notice that as time and height increases, the value of speed reduces.

This means that the greatest value of speed will be at the least value of time (t).

From the given options, the least value of time is at:

[tex]t = 2[/tex]

Hence, the value of time (t) at the greatest speed of the ball is at 2 seconds

Read more about speed at:

https://brainly.com/question/7359669

Simplify: 2(6+1)-|-10|+3x2

Answers

Answer:

10

Step-by-step explanation:

2(6+1)-|-10|+3*2

First start with the absolute values and parentheses

2(7)-10+3*2

Then multiply from left to right

14 -10 +6

Then add and subtract from left to right

4 +6

10

(4.8 × 10⁷) + 6,500,000

Answers

Answer:

5.45 * 10^7

Step-by-step explanation:

[tex](4.8 * 10^7) +6,500,000[/tex]

= [tex](4.8 * 10^7) + 6.5 * 10^6[/tex]

= [tex](4.8 * 10^7) + (0.65 * 10^7)[/tex]

= [tex]5.45 * 10 ^7[/tex]

✓ 1 N 3 4 5 6 Conv A rectangular field is 300 meters long and 250 meters wide. What is the area of the field in square kilometers? Do not round your answer. 1000 millimet 100 centimet 10 decimet 1 decame 2 km Х X 5. ? 1 hectomei 1 ​

Answers

Answer:

75 km

Step-by-step explanation:

Area = Length × Width

= 300m and 250m

= 75000m

M to Km => ÷1000

= 75000m ÷ 1000

= 75 km #

ch of the following collections are w A collection of first six even number A collection of tall girls of class X. A collection of good football player A collection of wild animals. A collection of days of a week. he symbols e or €: {a, e, i, o, u}​

Answers

Pls Tell question corretly

Find two consecutive whole numbers that 29 lies between.

Answers

Answer:

28 and 30

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Solve
0.9(7x + 14) = 1.5 - (x + 2)

Answers

[tex]\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)[/tex]

[tex]\\ \sf\longmapsto 6.3x+12.6=1.5-x-2[/tex]

[tex]\\ \sf\longmapsto 63x+12.6=-x-0.5[/tex]

[tex]\\ \sf\longmapsto 63x+x=-0.5-12.6[/tex]

[tex]\\ \sf\longmapsto 64x=-13.1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-13.1}{64}[/tex]

[tex]\\ \sf\longmapsto x=0.2[/tex]

Help me plz 20 points to who ever gets it right

Answers

Step-by-step explanation:

2., 3., 4., 5.

yes, you had the right idea to calculate the half distances between the coordinates. just create the absolute values of the full distance before cutting it in half.

you need to remember : we have to go this half distance from one point to the other (meaning adding our subtracting the half distance to/from the starting point).

2.

(-4, 6) to (10, -10)

in x the distance is 10 - -4 = 14. half is 7.

in y the distance is |-10 - 6| = |-16| = 16. half is 8.

so the midpoint is

(-4 + 7, 6 - 8) = (3, -2)

remember, to go the half distance in the direction towards the second point (so we have to choose properly, when to use "+" and "-" depending on the change of the coordinate : from -4 to 10 we have to add, from 6 to -10 we have to subtract, of course).

3.

(-3, -8) to (-6.5, -4.5)

in x distance : -3 - -6.5 = 3.5. half is 1.75

in y distance : -8 - -4.5 = |-3.5| = 3.5. half is 1.75

midpoint is

(-3 - 1.75, -8 + 1.75) = (-4.75, -6.25)

4.

(3, 7) to (-8, -10)

x : 3 - -8 = 11. half is 5.5

y : 7 - -10 = 17. half is 8.5

midpoint is

(3 - 5.5, 7 - 8.5) = (-2.5, -1.5)

5.

(-6, -13) to (-6.4, -3.8)

x : -6 - -6.4 = 0.4. half is 0.2

y : -13 - -3.8 = |-9.2| = 9.2. half is 4.6

midpoint is

(-6 - 0.2, -13 + 4.6) = (-6.2, -8.4)

6.

(-1, 7) to (5, 1)

x : -1 - 5 = |-6| = 6. 1/3 is 2.

y : 7 - 1 = 6. 1/3 is 2.

1/3 from C to D

(-1 + 2, 7 - 2) = (1, 5)

7.

2/3 of the way from D to C is the same point as in 6. (1/3 from C to D).

again

(1, 5)

8.

2/3 of the way from C to D.

so, we need to double what we added in 6.

(-1 + 4, 7 - 4) = (3, 3)

9.

1/3 of the way from D to C is the same point as in 8. (2/3 of the way from C to D).

again

(3, 3)

10.

exactly. Pythagoras.

the square root of the sum of the squares of the coordinate differences.

distance = sqrt((x1 - x2)² + (y1 - y2)²)

11.

(6, 8) to (-1, 8)

distance = sqrt((6 - -1)² + (8 - 8)²) = sqrt(49) = 7

12.

(5, -6) to (5, 6)

sqrt((5-5)² + (-6-6)²) = sqrt(144) = 12

13.

(-2, 0) to (11, 0)

sqrt((-2 - 11)² + (0-0)²) = sqrt(169) = 13

14.

(1, -5) to (9, 1)

sqrt((1-9)² + (-5 - 1)²) = sqrt(64 + 36) = sqrt(100) = 10

15.

ST and MT are basically the same equation.

MT is half of ST.

ST equation based on 2 points :

y – yS={(yT – yS)/(xT – xS)}(x – xS)

M = (xS + (xT - xS)/2, yS +(yT - yS)/2)

so, let's put that into the general equation :

y - yM={(yT - yM)/(xT - xM)}(x - xM)

y - (yS +(yT - yS)/2) = {(yT - (yS +(yT - yS)/2))/(xT - (xS + (xT - xS)/2))}(x - (xS + (xT - xS)/2))

16.

the two corners farthest away are (5, 10) and (9, 6).

what distance from (0, 0) is now bigger ?

since it is (0, 0), we can skip the 0s and just sum up the squares of the coordinates.

5² + 10² = 125

9² + 6² = 117

so, the corner (5, 10) is the farthest away.

Dan scored 1/4 of the points at last nights basketball game. What percentage of the total points did he score

Answers

Divide 1 by 4 to get a decimal:

1 / 4 = 0.25

Multiply by 100 to get percent:

0.25 x 100 = 25%

Answer: 25%

Points scored by dan = 1/4

Percentage = 1/4×100

= 25%

Therefore he scored 25% of total points.

Must click thanks and mark brainliest

Find the area of the shaded figure


Please help I apréciate everything

Answers

Answer:

2000*pi

Step-by-step explanation:

Shaded area= Area of bigger circle - Area of smaller circle

Shaded area= pi*(60)^2-pi*(40)^2=(60+40)(60-40)*pi=2000*pi

Describe the following sequence using an algebraic expression as a rule 0; 2,4; 6​

Answers

Answer:

Step-by-step explanation:

I assume the sequence is 0, 2, 4, 6

nth term = 2(n-1)

Tables A telephone exchange operator assumes that 8%8% of the phone calls are wrong numbers. If the operator is correct, what is the probability that the proportion of wrong numbers in a sample of 535535 phone calls would differ from the population proportion by more than 3%3%

Answers

Answer:

0,375

Step-by-step explanation:

Divide de 3 percent from 8 percent den u get your answer

Pleasure helping you, hope it was helpful

find the surface area of the prism HURRY HURRY

Answers

Answer:

should be 192

Step-by-step explanation:

pls help! I need the answer quickly! thank you!

Answers

Answer:

C) 82/2

Step-by-step explanation:

The area of a square is calculated by multiplying a side by itself

so one side of the square is 9 in

the area of a triangle is calculated by multiplying height and base and that divided by 2

since E is the midpoint, if we draw a line show the height from there

the height would be 9

9*9/2 = 82/2

What are the solutions of the system 7x + 3y=-3 and y= -2*?

Answers

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

Answers

Answer:

1,4,16,64,245,1024

Step-by-step explanation:

a1 =1

an = 4 * an-1

Let n = 2

a2 = 4*a1 = 4*1=4

Let n = 3

a3 = 4*a2 = 4*4 = 16

Let n = 4

a4 = 4*a3 = 4*16 = 64

Let n = 5

a5 = 4*a4 = 4*64 = 256

Let n = 6

a6 = 4*a5 = 4*256 = 1024

In order to pass a class, Amanda needs to have a score higher than 86 on her final. Which graph represents possible scores that Amanda could get to pass this class?

Answers

Answer:

graph C

Step-by-step explanation:

Amanda needs to have a score higher than 86 on her final.

That means she can't get lower than 86 (Obviously) but not even an 86.

It has to be higher than 86 for her to pass

Let x represent Amanda's score

[tex]x>86[/tex]

Bolded dots on graphs mean that she can have a 86 but if it's not a bolded dot she can have either higher or lower

Just keep that in mind

The answer will be C. because it describes Amanda's score higher than 86

Answer:

c

Step-by-step explanation:

Question 6. Which expression is equivalent to 3x(x-6)+5(x-4)?

Answers

Answer:

8x- 38

Step-by-step explanation:

3(x-6)+5(x-4)

Distribute

3x- 18+5x -20

Combine like terms

3x+5x -18-20

8x- 38

Answer:

[tex]3(x-6)+5(x-4)[/tex]

[tex]3x-18+5x-20[/tex]

[tex]=(3+5)x-(20x+18)[/tex]

Add:- 3+5= 8, and 20+18= 38

[tex]=8x-38[/tex]

OAmalOHopeO

Need help please thank you

Answers

Answer:

first term (a1) = 3/2

common difference (d) = 7/4-3/2 = 1/4

Let a and b be real numbers, where a<b, and let A=(a,a^2)  and B= (b,b^2) The line AB (meaning the unique line that contains the point A and the point B) has x-intercept (-3/2,0) and y-intercept (0,3). Find a and b. Express your answer as the ordered pair (a,b)​

Answers

The slope of the line passing through points A and B is

slope = (b ² - a ²) / (b - a) = ((b - a) (b + a)) / (b - a) = b + a

Since this line passes through (0, 3), its equation would be

y - 3 = (b + a) (x - 0)   ==>   y = (b + a) x + 3

It also passes through (-3/2, 0), so that

y - 0 = (b + a) (x + 3/2)   ==>   y = (b + a) x + 3/2 (b + a)

If these equations describe the same line, then they must have the same slope and y-intercept, so that

3 = 3/2 (b + a)   ==>   a + b = 2

It also passes through (a, a ²), so that

a ² = (b + a) a + 3   ==>   a ² = ab + a ² + 3   ==>   ab = -3

Solving for b in the first underlined equation, we get

b = 2 - a

Substituting into the second equation and solving for a gives

a (2 - a) = -3   ==>   2a - a ² = -3   ==>   a ² - 2a - 3 = (a - 3) (a + 1) = 0

==>   a = 3   or   a = -1

==>   b = -1   or   b = 3

Since a < b, we pick a = -1 and b = 3, so the solution is (a, b) = (-1, 3).

The charge of eletricity for the first 20 unit is Rs 80 and Rs 7 per unit from 21 unit to 30 units. If service is Rs 75 find the total charge of 28 units​

Answers

First 20 units = Rs 80

28 - 20 = 8 units

8 x 7 = Rs 35

80 + 35 = Rs 115

Determine whether the ordered pair is a solution of the equation. Show your work to receive credit.

9. Is (-1,3) a solution to the equation y = -3x + 10?

10. Is (7,-2) a solution to the equation x – 4y = 15?

Please show work to help me understand.

Answers

Answer:

3=3 + 10

3 = 13(NO)

x-4y=15

7--8=15

15=15(YES)

Maggie's brother is 6 years younger than four times her age. The sum of their ages is
59.
How old is Maggie?
Maggie is
years old.

Answers

Answer:

Maggie is 11 years old

Step-by-step explanation:

let m be Maggie and b be her brother.

[tex]m+b=59[/tex]

[tex]b=4m-6[/tex]

substitute for b.

[tex]m+4m-6=59[/tex]

[tex]5m-6=59[/tex]

add 6 to both sides

[tex]5m=55[/tex]

divide by 5 on both sides

[tex]m=11[/tex]

double check by finding the brother's age by substituting for m

[tex]11+b=59[/tex]

[tex]b=48[/tex]

13 is subtracted from the product of 4 and a certain number. The result is equal to the sum of 5 and the original number. Find the number.​

Answers

Answer:

Step-by-step explanation:

4x - 13 = x +  5           Add 13 to both sides

4x = x + 18                 Subtract x

3x = 18                       Divide by 3

x = 6

A grocery store sells apples in bags. Each bag weighs 3/5 of a pound. Alberto's mother buys 6 pounds of apples to make applesauce. How many bags of apples does she buy?​

Answers

Answer:

10

Step-by-step explanation:

these are small bags (just as comment), so in real life the cost of using bags would add significantly to the price of the apples.

anyway, so we need to find how many units of 3/5 pounds do we need to get 6 pounds ?

3/5 × x = 6

3 × x = 30

x = 10

she buys 10 bags to get 6 pounds.

Write decimal for each model

Answers

Answer:

Please attach a picture or more details about "each model" so we can help you!

Step-by-step explanation:

What is lim j(x)?
X-3

Answers

9514 1404 393

Answer:

  (b)  4

Step-by-step explanation:

The point (3, 4) is a "hole" in the graph. The function approaches the value y=4 from either direction, so that is the limit as x → 3.

  [tex]\displaystyle\lim_{x\to3}f(x)=4[/tex]

Kế hoạch đi dã ngoại của một gia đình sẽ bị hủy nếu trời có mây hoặc mưa. Biết xác suất để trời có mây là có mưa là có cả mây và mưa là . Tính xác suất để kế hoạch được thực hiện.

Answers

Answer:

itditsktxjtcv6tgcxufh-&#€#€($*:'₹€$*^'ditx_*^,tsitsitxmvditxitsitsjfxkhcoucuofoydoy

Use the Laplace transform to solve the given system of differential equations. d2x dt2 + x − y = 0 d2y dt2 + y − x = 0 x(0) = 0, x'(0) = −6, y(0) = 0, y'(0) = 1

Answers

I'm going to assume that "−" is supposed to be some kind of minus character, so that the given system of DEs is supposed to be

[tex]\begin{cases}\dfrac{\mathrm d^2x}{\mathrm dt^2} + x - y = 0 \\ \dfrac{\mathrm d^2y}{\mathrm dt^2} + y - x = 0 \\ x(0) = 0, x'(0) = -6, y(0) = 0, y'(0) = 1\end{cases}[/tex]

Take the Laplace transform of both sides of both equations. Recall the transform for a second-order derivative,

[tex]L_s\left\{\dfrac{\mathrm d^2f(t)}{\mathrm dt^2}\right\} = s^2 F(s) - sf(0) - f'(0)[/tex]

where F(s) denotes the transform of f(t). You end up with

[tex]\begin{cases}s^2X(s)-sx(0)-x'(0) + X(s) - Y(s) = 0 \\ s^2Y(s) - sy(0) - y'(0) + Y(s) - X(s) = 0\end{cases} \\\\ \begin{cases}(s^2+1)X(s) - Y(s) = -6 \\ (s^2+1)Y(s) - X(s) = 1\end{cases}[/tex]

and solving for X(s) and Y(s) (nothing tricky here, just two linear equations) gives

[tex]X(s) = -\dfrac{6s^2+5}{s^2(s^2+2)} \text{ and } Y(s) = \dfrac{s^2-5}{s^2(s^2+2)}[/tex]

Now solve for x(t) and y(t) by computing the inverse transforms. To start, split up both X(s) and Y(s) into partial fractions.

• Solving for x(t) :

[tex]-\dfrac{6s^2+5}{s^2(s^2+2)} = \dfrac as + \dfrac b{s^2} + \dfrac{cs+d}{s^2+2} \\\\ -6s^2-5 = as(s^2+2) + b(s^2+2) + (cs+d)s^2 \\\\ -6s^2-5 = (a+c)s^3 + (b+d)s^2 + 2as + 2b \\\\ \implies \begin{cases}a+c=0\\b+d=-6\\2a=0\\2b=-5\end{cases} \implies a=c=0, b=-\dfrac52, d=-\dfrac72[/tex]

[tex]\implies X(s) = -\dfrac5{2s^2} - \dfrac7{2(s^2+2)}[/tex]

Taking the inverse transform, you get

[tex]L^{-1}_t\left\{X(s)\right\} = -\dfrac52 L^{-1}_t\left\{\dfrac{1!}{s^{1+1}}\right\} - \dfrac7{2\sqrt2} L^{-1}_t\left\{\dfrac{\sqrt2}{s^2+(\sqrt2)^2}\right\} \\\\ \implies \boxed{x(t) = -\dfrac52 t - \dfrac7{2\sqrt2}\sin(\sqrt2\,t)}[/tex]

• Solving for y(t) :

[tex]\dfrac{s^2-5}{s^2(s^2+2)} = \dfrac as + \dfrac b{s^2} + \dfrac{cs+d}{s^2+2} \\\\ s^2 - 5 = as(s^2+2) + b(s^2+2) + (cs+d)s^2 \\\\ s^2 - 5 = (a+c)s^3 + (b+d)s^2 + 2as + 2b \\\\ \implies \begin{cases}a+c=0\\b+d=1\\2a=0\\2b=-5\end{cases} \implies a=c=0, b=-\dfrac52, d=\dfrac72[/tex]

[tex]\implies Y(s) = -\dfrac5{2s^2} + \dfrac7{2(s^2+2)}[/tex]

Inverse transform:

[tex]L^{-1}_t\left\{Y(s)\right\} = -\dfrac52 L^{-1}_t\left\{\dfrac{1!}{s^{1+1}}\right\} + \dfrac7{2\sqrt2} L^{-1}_t\left\{\dfrac{\sqrt 2}{s^2+(\sqrt2)^2}\right\} \\\\ \implies \boxed{y(t) = -\dfrac52 t + \dfrac7{\sqrt2} \sin(\sqrt2\,t)}[/tex]

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