List the first five multiples of 6.

a )

List the first five multiples of 9.

b )

What is the Lowest Common Multiple of 6 and 9?

c)

Answer:

Kazan also SOS jz zks zj sj aka always zks. aiwow

Answer:

y = -7x + 52

Step-by-step explanation:

y = -7x - b

-4 = -7(8)  + b

-4 = -56 + b

52

Answer:

Step-by-step explanation:

ok so this is pretty simple,

Imagine a was the number 1

45% of 1, which would obviously be

45/100 * 1

Same thing here but for the variable a.

45/100 * a!

That would be the algebraic expression for 45% of a!

Cheers! I hope you can understand the problem better now.

Answer:

x³-7x-6

Step-by-step explanation:

Find the products of the factors

(x+1)(x+2)(x-3)

x²+3x+2(x-3)

x³+3x²+2x-3x²-9x-6

x³-7x-6

Answer:

SP is Rs 800.

Step-by-step explanation:

MP = Rs 875

Discount = Rs 75

so

SP = MP - discount

= Rs 875 - Rs 75

= Rs 800

Answer:

x = 8cm

Step-by-step explanation:

17² = 15² + x²

289 = 225 + x²

- x² = 225 - 289

x² = 64

x = √64

x = 8

[tex]{ \boxed{ \sf \color{blue}{answer}}}[/tex]

x = 8 cm

Step-by-step explanation:

17² = 15² + x²

289 = 225 + x²

x² = 225 - 289

x² = 64

x = √64

x = 8

Teorema pythagoras

Positive parabola that has a minimum.

It’s positive if it opens upward, negative if it opens downward. It has a minimum if it opens upward, and maximum when it opens downward.

Answer:

x=-3

Step-by-step explanation:

Answer:

hello,

answer C

Step-by-step explanation:

area of the rectangle=2b*b=2b²

area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]

Area in blue= 2b²-πc²/8

Answer:

x = 37.3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan 63 = x /19

19 tan 63 =x

x=37.28959

To the nearest tenth

x = 37.3

Answer:

Option B

Step-by-step explanation:

From the picture attached,

In ΔABC,

m∠B = m∠C = 75° [Isosceles triangles]

By applying triangle sum theorem,

m∠A + m∠B + mC = 180°

m∠A + 75° + 75° = 180°

m∠A = 180° - 150°

m∠A = 30°

In triangle PQR,

m∠P = m∠Q [Isosceles triangle]

By applying triangle sum theorem,

m∠P + m∠Q + m∠R = 180°

2(m∠P) + 30° = 180°

m∠P = 75°

m∠P = m∠Q = 75°

In ΔABC and ΔRPQ,

m∠B ≅ m∠Q [Given]

m∠C ≅ m∠R [Given]

Therefore, by AA property of similarity of two triangles, both the triangles will be similar.

ΔABC ~ ΔRPQ

Option B will be the answer.

Answer:

729

Step-by-step explanation:

because the square of 27 gives 729

I can check this through long division

Answer:

Part 1)

[tex]\displaystyle \left((2-x)^2 + 1)\right) + (2\sqrt{3} - 1 ) \left(x^2 + 1\right)[/tex]

Or simplified:

[tex]\displaystyle = 2\sqrt{3}x^2 - 4x + 4 + 2\sqrt{3}[/tex]

Part 2)

The value of x for which the given expression will be the lowest is:

[tex]\displaystyle x = \frac{\sqrt{3}}{3}\approx 0.5774[/tex]

And the magnitude of ∠BAC is 60°.

Step-by-step explanation:

We are given a ΔABC with an area of one. We are also given that AB = 2, BC = a, and CA = b. CD is a perpendicular line from C to AB.

Please refer to the diagram below.

Part 1)

Since we know that the area of the triangle is one:

[tex]\displaystyle \frac{1}{2} (2)(CD) = 1[/tex]

Simplify:

[tex]\displaystyle CD = 1[/tex]

From the Pythagorean Theorem:

[tex]\displaystyle x^2 + CD^2 = b^2[/tex]

Substitute:

[tex]x^2 + 1 = b^2[/tex]

BD will simply be (2 - x). From the Pythagorean Theorem:

[tex]\displaystyle (2-x)^2 + CD^2 = a^2[/tex]

Substitute:  

[tex]\displaystyle (2-x)^2+ 1 = a^2[/tex]

We have the expression:

[tex]\displaystyle a^2 + (2\sqrt{3} - 1) b^2[/tex]

Substitute:

[tex]\displaystyle = \boxed{\left((2-x)^2 + 1)\right) + (2\sqrt{3} - 1 ) \left(x^2 + 1\right)}[/tex]

Part 2)

We can simplify the expression. Expand and distribute:

[tex]\displaystyle (4 - 4x + x^2 + 1)+ (2\sqrt{3} -1)x^2 + 2\sqrt{3} - 1[/tex]

Simplify:

[tex]\displaystyle = ((2\sqrt{3} -1 )x^2 + x^2) + (-4x) + (4+1-1+2\sqrt{3})[/tex]

Simplify:

[tex]\displaystyle = 2\sqrt{3}x^2 - 4x + 4 + 2\sqrt{3}[/tex]

Since this is a quadratic with a positive leading coefficient, it will have a minimum value. Recall that the minimum value of a quadratic always occur at its vertex. The vertex is given by the formulas:

[tex]\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]

In this case, a = 2√3, b = -4, and c = (4 + 2√3).

Therefore, the x-coordinate of the vertex is:

[tex]\displaystyle x = -\frac{(-4)}{2(2\sqrt{3})} = \frac{1}{\sqrt{3}} =\boxed{ \frac{\sqrt{3}}{3}}[/tex]

Hence, the value of x at which our expression will be the lowest is at √3/3.

To find ∠BAC, we can use the tangent ratio. Recall that:

[tex]\displaystyle \tan \theta = \frac{\text{opposite}}{\text{adjacent}}[/tex]

Substitute:

[tex]\displaystyle \tan \angle BAC = \frac{CD}{x}[/tex]

Substitute:

[tex]\displaystyle \tan \angle BAC = \frac{1}{\dfrac{\sqrt{3}}{3}} = \sqrt{3}[/tex]

Therefore:

[tex]\displaystyle\boxed{ m\angle BAC = \arctan\sqrt{3} = 60^\circ}[/tex]

Answer:

its the 3rd choice.

Step-by-step explanation:

Firstly, we find angle BDC (180-90-30=60)

Now that we found it we can use the sine rule to find DB (which i put as an x), which is sin60/14=sin30/x, by cross multiplication, we find that its equal to a decimal number, i will use its root version to this easier, its equal to 14sqrt3/3 inches.

And now we use the pythagorean theorem to find DC, we find that it is equal to 28sqrt3/3

Now, we find angle BAC (180-90-(30+15)=45)

Again, we use the sine rule to find AB (whom i will refer to as x and from whom we will subtract DB to find the length of AD), so we cross multiply in sin45/14=sin(30+15)/x, it is equal to 14.

So since AB-DC=AD

14-(14sqrt3/3)= 5.917096231 (and we ound that to a 5.9)

Answer:

x = 27°

Step-by-step explanation:

180° - 72° = 108°

108° / 4 = 27°

72° + (27° * 4) = 180°

Hope it helps!

Answer:

-17 < g [tex]\leq[/tex] 8

Step-by-step explanation:

'g' is within the range of numbers that are greater than -17 and less than or equal to 8. we know that it is less than or equal to because the circle is closed or filled in, at 8.

If the perimeter is 16' the sum of the length and width must be 8'. Assuming that area is non 0 possible dimensions are:

1x7 2x6 3x5 4x4 5x3 6x2 7x1

Answer:

[tex]A = 135(1.11)^{12}[/tex]

A= $472.29  

Step-by-step explanation:

Answer:

$687.5

Step-by-step explanation:

Cost of the rug per square foot = $22

Length of the rug = 31.25 feet

Total amount Mrs brown will pay = Cost of the rug per square foot × Length of the rug

= 31.25 × 22

= $687.5

Total amount Mrs brown will pay = $687.5

Answer:

13

Step-by-step explanation:

7 cm +1 cm +2cm +2cm :12cm

Answer:

60

Step-by-step explanation:

Since the angles are shown equal in the diagram, ABD=DBC=60

Answer:

the answer is -10

Step-by-step explanation:

x=x

y=5

then

3x+5y=-5

3x+5*5=-5

3x=-5-25

3x=-30

x=-30/3

•°•x=-10

Answer:

A

Step-by-step explanation:

3x+5*5=-5

x=-10

Step-by-step explanation:

o ne demek kaarrrşiömm hııı

Answer:

The answer is $82.46 sales tax

$1,260.46 Total

Step-by-step explanation:

Since the price before the Sales tax is $1,178.00 and if you add the 7% Sales tax the total is $1,260.46 and the price of the Sales tax is $82.46

Answer:

PR = 39 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

PR² + PQ² = QR² , that is

PR² + 80² = 89²

PR² + 6400 = 7921 ( subtract 6400 from both sides )

PR² = 1521 ( take the square root of both sides )

PR = [tex]\sqrt{1521}[/tex] = 39

Answer:

[tex]PR=39[/tex]

Step-by-step explanation:

The triangle (PQR) is a right triangle. This means the triangle has a (90) degree angle, such is indicated by the box around one of the angles in the triangle. One of the properties of the sides of a right triangle is the Pythagorean theorem. The Pythagorean theorem states the following:

[tex]a^2+b^2=c^2[/tex]

Where (a) and (b) are the legs of the right triangle, or the sides adjacent to the right angle. (c) is the side opposite the right angle of the triangle triangle, in other words, the hypotenuse. Substitute the respective legs into the formula for the Pythagorean theorem and solve for the unknown,

[tex]a^2+b^2=c^2[/tex]

Substitute,

[tex]a^2+b^2=c^2[/tex]

[tex]PQ^2+PR^2=QR^2[/tex]

[tex]80^2+PR^2=89^2\\[/tex]

Simplify,

[tex]80^2+PR^2=89^2\\[/tex]

[tex]6400+PR^2=7921[/tex]

Inverse operations,

[tex]6400+PR^2=7921[/tex]

[tex]PR^2=1521\\\\PR=39[/tex]

Answer:

b = 2√3

a = 4

Step-by-step explanation:

Here taking 60 as reference angle

so

tan60 = p/b

[tex]\sqrt{3}[/tex]    = p/2

so p = 2√3

so

b = 2√3

so

[tex]h^2 = p^2 + b^2\\h^2 = (2\sqrt{3})^2 + 2^2\\h^2 = 12 + 4\\h^2 = 16\\h = \sqrt{16} \\h = 4[/tex]

a = 4

Answer:

6.8=6 8/5

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hope it help

Answer and explanation:

Assume Almond is a

Cashew is c

Peanuts is p

The system of equations satisfies this thus:

a+c+p= 10

7a+5c+2p= $20

The system of equations has three unknowns. Solving for the unknown variables here would yield parametric equations or dependent system where given x y z we may find x in terms of y and z in terms of x, in that form. This would give many results for our problem which may not be very accurate.