Lisa kicked a ball against the wall at the indicated angle. What is the measure, in degrees, of <1?

Answer:

13

Step-by-step explanation:

The diagonals of rectangle are equal in length.

Answer:

a union b= {1,2,3,4,5}

a intersection b ={2,3}

Step-by-step explanation:

The union of two sets A and B is a set that contains all the elements of A and B and is denoted by A U B

the set composed of all elements that belong to both A and B is A intersection B (A ∩ B)

Answer:

∠ L ≈ 21.6°

Step-by-step explanation:

Using the Sine rule in the triangle

[tex]\frac{MN}{sinL}[/tex] = [tex]\frac{LM}{sinN}[/tex] , that is

[tex]\frac{34}{sinL}[/tex] = [tex]\frac{42}{sin27}[/tex] ( cross- multiply )

42 × sinL = 34 × sin27° ( divide both sides by 42 )

sinL = [tex]\frac{34sin27}{42}[/tex] , then

∠ L = [tex]sin^{-1}[/tex] ( [tex]\frac{34sin27}{42}[/tex] ) ≈ 21.6° ( to the nearest tenth )

Answer:

The answer of this question is 78°.

Step-by-step explanation:

Let angle X be denoted by y then angle Z=y (because isosceles angles of a traingle is equal)

Now,

y+y+24°=189°

2y+24°=180°

2y=180°-24°

y=156/2

y=78°

Answer:

so the answer is 78°

Step-by-step explanation:

Uhm I hope it helps

B::: m ≠ -2.............

Answer:

total blackberry: $23

total blueberry: $12.80

total: $35.80

Step-by-step explanation:

the blackberry jam is $5/lb

therefore, 4.6 pounds of it -

5 x 4.6

=23

the blueberry jam is $8/lb

using the same method we do

8 x 1.6

=12.8

adding the two totals -

23 + 12.8 = 35.8

in other words, the two jams will be $35.80

Answer:

Below

Step-by-step explanation:

Let's say that x represents the mystery number

3(x + 3) = 4x - 23

3x + 9 = 4x - 23

3x - 4x = -23 - 9

x = 32

Hope this helps!

Answer:

Each dog has 2 ears (unless a dog had genetic disorder)

So-

14 x 2

= 28

So she counted of 28 Ears of total

(honestly that's a weird thing to do but ok)

Answer:

14 x 2 = 28

Step-by-step explanation:

Each dog has 2 ears

14 dogs has 28 ears

- Hey Risap! :)

[tex] \large{ \tt{❁ \: ANSWER : \boxed{ \tt{25\%}}}}[/tex]

[tex] \large{ \tt{♕ \: REFER \: TO \: THE \: ATTACHMENT \: !!}}[/tex]

Answer:

x=±sqrt (33)

Step-by-step explanation:

y=(x+2)(x-2)

29=x^2-4. x^2=33, x=±sqrt (33)

Answer:

[tex]\sqrt{33}[/tex]

Step-by-step explanation:

y = (x+2) (x-2)

y =  [tex]x^{2}[/tex] +2x -2x-4

y =  [tex]x^{2}[/tex] - 4

29 = [tex]x^{2}[/tex] - 4

29 + 4 = [tex]x^{2}[/tex] -4 + 4

33 = [tex]x^{2}[/tex]

[tex]\sqrt{33}[/tex] = x

Hope this is clear and you can understand it. :)

70

Step-by-step explanation:

here,

area of parallelogram =base ×height

so,

base is given 10 cm and height is given 7 cm

Now

base ×heights

10×7

70

Answer:

x=2

Step-by-step explanation:

We can use the Pythagorean theorem since this makes a right triangle

a^2+b^2 = c^2

The radius is 1.5

1.5^2 + x^2 = (1+1.5)^2

1.5^2 +x^2 = 2.5^2

2.25+x^2=6.25

Subtract 2.25 from each side

x^2 = 4

Taking the square root of each side

x= 2

Answer:A

Step-by-step explanation:Took quiz

Answer:

SinA=k/g

cotA=k/j

secA=g/j

cosecB=g/k

tanB=l/k

cosB=k/g

Step-by-step explanation:

Ans 6 Use Pythagoras theorem...

Hypotneuse²=Base²+Height²

6²=4²+H²

36-16=H²

20=H²

√20=H

√2×2×5=H

2√5 = H....

hope it helps

Problem 4

Draw a diagonal to connect the opposite non-right angles as shown below. This forms two right triangles. As you can probably guess, we'll use the pythagorean theorem to find the length of this segment. We'll call it x.

a^2+b^2 = c^2

7^2+24^2 = x^2

49+576 = x^2

x^2 = 625

x = sqrt(625)

x = 25

The hypotenuse of each right triangle is 25 units long.

Move your focus to the upper right triangle. We can use the pythagorean theorem again in a slightly different way to find y.

a^2+b^2 = c^2

15^2+y^2 = 25^2

225+y^2 = 625

y^2 = 625-225

y^2 = 400

y = sqrt(400)

y = 20

====================================================

Problem 6

The largest triangle, ignore segment x for now, is isosceles because we have two congruent sides.

As with any isosceles triangle, the vertex angle is bisected by the perpendicular bisector as shown in the diagram. This produces two identical right triangles. Most importantly, it means that horizontal side 4 is cut in half to 4/2 = 2 units.

In short, each smaller right triangle has a horizontal leg of 2, vertical leg x, and hypotenuse 6. Let's focus on just one of those right triangles.

Like the previous problem, we'll use the pythagorean theorem to find x.

a^2+b^2 = c^2

x^2+2^2 = 6^2

x^2+4 = 36

x^2 = 36-4

x^2 = 32

x = sqrt(32)

x = sqrt(16*2)

x = sqrt(16)*sqrt(2)

x = 4*sqrt(2)

Answer:

6

Step-by-step explanation:

The absolute value of 2(7)=14. b=-4, so 14+4=18. 18/3=6.

Answer:

6

Step-by-step explanation:

2(7)-(-4)/3

14+4/3

18/3

6

Answer:

85.2

Step-by-step explanation:

we can represent this in an equation where the initial value is going to be and to this we will subtract 2.6% of it

x - x * 2.6/100 = 83

x - 0.026x = 83

0.974x = 83

x = 83 / 0.974

x = 85.2156

we round to the nearest tenth and finally, we get that the result is 85.2

Answer:

[tex] = \frac{2}{4} \div \frac{1}{4} [/tex]

find reciprocal of ¼:

[tex] = \frac{2}{4} \times \frac{4}{1} \\ \\ = \frac{2}{1} \\ \\ = 2[/tex]

Answer:

2

Step-by-step explanation:

the first step is to change the sign from a division sign to a multiplication sign and when you change the sign you also have to swap one side by placing the numerator down and the denominator up

2/4÷1/4

2/4×4/1

8/4

2

I hope this helps

Answer:

How many balls have “R” written on them initially? We can see this is 2.

How many balls are there initially? This is 9.

As a result, the probability of initially drawing a ball with an R on it is 2/9, as out of the 9 possible draws we could make, 2 of them result in a ball with R on it.

How many balls have “R” written on them now? We can see this is 1, since we just drew one ball with R on it and didn’t replace.

How many balls are there in total right now? This is 8, because we took away one.

As a result, the probability of drawing a ball with an R on it after having already done so is 1/8, as out of the 8 possible draws we could make, 1 results in a ball with R on it.

We then multiply these two values (2/9)*(1/8) = 2/72, which is our probability.

Another way to think about this is that there are 72 possible combinations of balls that we could draw, counting each ball uniquely. This is because of our denominator, since 8*9=72. Out of those 72 outcomes that could possibly happen, 2 outcomes will result in both balls being written with R.

Step-by-step explanation:

Answer:

y=-4x+16

Step-by-step explanation:

Okay, so a perpendicular line has an opposite reciprocal slope.

The slope for the first line is x/4, but I like to write it as 1/4x, since it's easier to look at.

The opposite reciprocal for 1/4x is -4x

So far, we have y=-4x+ [  ]

To find the remaining b value, we can use the given point intersection.

plug in the x and y values given (4, -1) and solve for b.

The equation for the perpendicular line is y=-4x+16

Answer:

80%

Step-by-step explanation:

8 + 4 + 3 + 5 = 20 (total candies)

8 + 3 + 5 = 16 (not KitKats)

16 ÷ 20 = 0.8

0.8 × 100 = 80

Answer:

Step-by-step explanation:

Answer:

First question: answer is d. 4) -i

[tex] {i}^{16} + {i}^{6} - 2 {i}^{5} + {i}^{13} \\ = ( {i}^{2} ) {}^{8} + ( {i}^{2} ) {}^{3} - 2( {i}^{2} )( {i}^{2})(i) + ( {i}^{5} ) {}^{ \frac{13}{5} } \\ = {( - 1)}^{8} + {( - 1)}^{3} - 2(1i) + ( - 1) {}^{ \frac{13}{2} } \\ = 1 - 1 - 2i + i \\ = - i[/tex]

Second question: answer is d. 4) 0

[tex] = {i}^{99} - {i}^{3} \\ =( {i}^{3} )( {i}^{96} ) - {i}^{3} \\ = {i}^{3} ( ({i {}^{2} )}^{48} - 1) \\ = - i(1 - 1) \\ = 0[/tex]

Answer:

12jjmhhxkuyrgtjwkso9xbhvsiy5xbgueyr3gskzhxo

Answer: point of tangency

Step-by-step explanation:

125 -30 = 95..

125 - 60 = 65

======================================================

Explanation:

We get this point by doing two things.

If we started with x = -3, then x-2 = -3-2 = -5. Also, if we had y = -1 then y-7 = -1-7 = -8

So that's how we end up with Z(-3,-1) moving to Z ' (-5, -8)

You could also show your work like this

[tex](x,y) \to (x-2, y-7)\\\\(-3,-1) \to (-3-2, -1-7)\\\\(-3,-1) \to (-5, -8)\\\\[/tex]