John walked a distance of 900 meters in 10 minutes what was his average speed in kilomerters per hour

Answers

Answer 1

Answer:

5.4

Explanation:

900/10=90 and 90(60)=5400 meters. 5400/100=5.4


Related Questions

the value of 1.0004 to the power 1 by 2 using Binomial approximation is​

Answers

Given:

The given value is [tex](1.0004)^{\frac{1}{2}}[/tex].

To find:

The value of the given expression by using the Binomial approximation.

Explanation:

We have,

[tex](1.0004)^{\frac{1}{2}}[/tex]

It can be written as:

[tex](1.0004)^{\frac{1}{2}}=(1+0.0004)^{\frac{1}{2}}[/tex]

[tex](1.0004)^{\frac{1}{2}}=1+\dfrac{1}{2}\times 0.0004[/tex]      [tex][\because (1+x)^n=1+nx][/tex]

[tex](1.0004)^{\frac{1}{2}}=1+0.0002[/tex]

[tex](1.0004)^{\frac{1}{2}}=1.0002[/tex]

Therefore, the approximate value of the given expression is 1.0002.

The question is given in the picture below.... please help me and mention all the steps..​

Answers

Answer:

a)water is turning into ice it is changing it's state from liquid to solid

b)B to C  ice is melting and it  is changing  it's state from solid to liquid

C to D water is boiling and it is changing it's state from liquid to vapours(steam)

c) temperature

At A 0

At B 0

At C 100

At D 100

Explanation: The temperature will remain 0 degrees Celsius until all the ice becomes water and the temperature will remain 100 degrees Celsius until all the  water changes into steam.

If the ring rolls (without slipping) all the way to point 2, what is the ring's energy at point 2 in terms of h2 and v2?

Answers

Answer:

Following are the response to the given question:

Explanation:

[tex]F_2=mgh_2+\frac{1}{2}mv_2^2+\frac{1}{2}mR^2(W)^2\\\\\therefore \\\\ \to WR=v_2\\\\E_2=Mgh_2+MV_2^2[/tex]

Explain why a person travelling in a bus falls forward when bus stops suddenly

Answers

Answer:

Cause of Inertia of Motion

Explanation:

It can be explained as follows...when the moving bus suddenly stops, the lower part of the body of the passenger contact with the bus suddenly comes to rest while the upper part of the body tends to retain its state of motion due to inertia. As a result, the passenger is thrown forward.

Ра:
5. Mass of the earth is 6x10-kg and its radius is 6400km. What is the
mass of a man weighting 977N?
(99.99kg)
ma
Orth
be​

Answers

Answer:

what do u need help with

Explanation:

Pа: 5. Mass of the earth is 6x10-kg and its radius is 6400km. What is the mass of a man weighting 977N? (99.99kg) ma. Orth be​.

why does apparent depth of different liquids vary

Answers

It’s due to the refraction of light rays as they traverse the boundary between water and air. The greater the viewing angle, the more the bending of the light and therefore the less the apparent depth. An object placed in a denser medium, when viewed from rarer medium appears to be at a lesser depth than its real depth due to refraction of light.

Which of the elements below have seven electrons in their outermost energy levels? A.) Cr, Mn, and Fe B.) Br, I, and Ci C.) O, S, and Se D.) He, Ne, and Ar

Answers

Answer:

B

Explanation:

the Halogen families have 7 valence electrons

Ignore friction. A 20. Lb. Object was lifted to a height of 10 feet by a force of 30. Lb. (a) How much work (ft.Lb) is done by the force? (b) Find the change in potential energy (ft.Lb) of the object

Answers

a)
W = Fd
W = (30Lb)(10 ft)
W = 300ft.Lb

b)
work-energy theorem: W = ∆E
∆E = 300ft.Lb

(a) The work done by force in lb-ft is 300 lb-ft.

(b) The change in potential energy of the object is 200 lb-ft.

Work done by force

The work done by force in lb-ft is calculated as follows;

W = Fd

W = 30 x 10

W = 300 lb-ft

Change in potential energy

The change in potential energy of the object is calculated as follows;

ΔP.E = P.Ef - P.Ei

ΔP.E = 20 x 10 - 0 = 200 lb-ft

Learn more about work done here: https://brainly.com/question/8119756

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calculate the mass 9f the earth, assuring that uts is sphere with radius 6.67×10^6m.​

Answers

Answer:

6.86 × 10²⁴ kg

Explanation:

The mass of the earth m = density of earth, ρ × volume of earth, V

m = ρV

The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m

Since m = ρV

m = ρ4πr³/3

So, substituting the values of the variables into the equation for the mass of the earth, m, we have

m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3

m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3

m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3

m = 6546105.64378π × 10¹⁸ kg/3

m = 20565197.400122 × 10¹⁸ kg/3

m = 6855065.8 × 10¹⁸ kg

m = 6.8550658 × 10²⁴ kg

m ≅ 6.86 × 10²⁴ kg

A ball is dropped from the roof of a 25-m-tall building. What is the velocity of the object when it touches the ground? Suppose the ball is a perfect golf ball and it bounces such that the ve locity as it leaves the ground has the same magnitude but the op posite direction as the velocity with which it reached the ground How high will the ball bounce? Now suppose instead that the ball bounces back to a height of 20 m. What was the velocity with which it left the ground?

Answers

Answer:

a)  [tex]h=25m[/tex]

b)  [tex]v=19.8m/sec[/tex]

Explanation:

From the question we are told that:

Height [tex]h=25m[/tex]

Bounce Height [tex]h'=20m[/tex]

Generally the Kinematic equation is mathematically given by

[tex]V=\sqrt{2gh}\\\\V=\sqrt{2*9.81*25}[/tex]

[tex]V=22.1m/sec[/tex]

Therefore Height

[tex]h=\frac{V^2}{2g}\\\\h=\frac{22.1^2}{2*9.81}[/tex]

[tex]h=25m[/tex]

b)

Generally the Kinematic equation is mathematically given by

[tex]v^2=2ah[/tex]

[tex]v^2=2*9.8*20[/tex]

[tex]v=\sqrt{2*9.8*20}[/tex]

[tex]v=19.8m/sec[/tex]

Resistivity of metallic wire
depends on *

It's length
It's shape
It's thickness

Nature of material​

Answers

Answer:

nature of the material

hope this help you

please answer fast..........​

Answers

Answer:

The correct answer is a. Subsonic

Hope this helps you^_^

Please mark as Brainliest.

Yea your answer is subsonic wave I hope this help

Define derived unit with example​

Answers

Answer:

A derived unit is a SI unit of measurement comprised of a combination of the seven base units. Like SI unit of force is the derived unit, newton or N where N=s21×m×kg. There are some commonly used derived units which includes: 1. Pressure = AreaForce=m2N.

Explanation:

If the force on a spring is 2 N and it stretched 0.5 m, what is the spring constant?
O A. 2 N/m
OB. 0.2 N/m
OC. 0.4 N/m
OD. 4 N/m

Answers

It solved by the Hooke's law states F=kx

answer is

0.4n/m

A 250–g piece of gold is at 19 °C. 5.192 kJ of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature.




We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat. Calculate
the specific heat of the metal.

Answers

Answer:

A. DT is given by Q= MCs DT

m = mass of the substances

Cs= is it's specific heat capacity

Ck= Q

Mk ×DTk

=250 × 9 × 5

129

=Dt = 180.1085271

answer is 180degree C.

Explanation:

B. = 25×10 ×100

1.082

=2500

1.082

= 23105.360 g/kj.

The final temperature is 180 degree. and the specific heat of the metal is 23105.360 g/kj.

How to calculate the specific heat?

Q = m . C . ΔT

Q = heat; m = mass; C is the specific heat and

ΔT = Final T° - Initial T°

Q = C lat . m

Q = Heat

m = mass

C lar = Latent heat of fusion

A) DT is given by Q= M Cs DT

where, m = mass of the substances

Cs= is it's specific heat capacity

Ck= Q

Mk × DTk

=250 × 9 × 5

129 =Dt = 180.1085271

Thus, the final temperature is 180 degree.

B) We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat = 25×10 ×100

=2500

1.082

Q = 23105.360 g/kj

Hence, the specific heat of the metal is 23105.360 g/kj.

Learn more about heat here;

https://brainly.com/question/12909121

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Two forces of equal magnitude F
have a resultant of the same
magnitude F. The angle between the
two forces is
45°
120°
O 60°
O 35°​

Answers

Answer:

the ans is 120 degree hope it will help

Pls help me solve these two questions!!! Tq​

Answers

Answer:

Part A would be 80 Joules and Part B would be 20 meters.

Explanation:

For Part A:

The first step is to convert the mass to SI units.

400 g = 0.4 kg

Next, we need to know that the law of conservation of energy states that the total energy of an isolated system is conserved. In this case, it means that the total energy at the bottom, where kinetic energy is greatest, will be equal to the total energy at the top, where gravitational potential energy is greatest.

Max Gravitational Potential Energy = Max Kinetic Energy

Max Gravitational Potential Energy = [tex]\frac{1}{2} mv^{2}[/tex]

Max Gravitational Potential Energy = [tex](\frac{1}{2} )(.4kg)(20m/s)^2[/tex] = 80[tex]J[/tex]

For Part B:

We need to once again set gravitational potential energy to kinetic energy, only this time we use the GPE equation and solve for height. We already solved for the kinetic energy so we just plug everything in and solve.

[tex]mgh = \frac{1}{2} mv^{2}[/tex]

[tex](.4kg)(10m/s^{2} )h = 80J\\h = 20m[/tex]

What is the relation between the weight of a body and acceleraton due to gravity?​

Answers

Answer:

All objects on Earth, regardless of their mass, accelerate due to gravity at the same rate - that is, 9.8 m/sec2. The weight of an object can be calculated using the formula for force - F = m * a - where F equals the weight of the object and now the acceleration (a) is the acceleration of gravity (g).

3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?​

Answers

Answer:

Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.

why football players boots have spikes their sole
Give short and sweet answer​

Answers

Answer:

it helps with balance and speed.

"The football shoes have spikes or studs because the studs or spikes provides larger frictional force than normal shoes while running on the grass. The studs prevents player from slipping on the grass and help to run faster and change direction quickly without slipping"

Answer:

they provide a larger frictional force than normal shoes while running on the grass.

Si la fuerza de fricción cinetica es 250N ¿Qué fuerza se necesita para mantener a la caja deslizándose a una velocidad constante ¿

Answers

Answer:

250N

Explanation:

According to newton second law,

\sumF = ma

Fm - Ff = ma

Since the velocity is constant, a = 0m/s

Frictional force Ff = 250N

Substitute

Fm - 250 = m(0)

Fm - 250 = 0

Fm = 250N

Hence the force to keep the box sliding at constant speed is 250N

A converging lens of focal length 20cm, forms a real image twice the size of the object. Calculate:
i) the power of the lens;
ii) the position of the image.

Answers

Answer:

Solition given:

focal length(f)=20cm

size of image(v)=2x

size of object(u)=x

we have

power of lens= reciprocal to focal length=1/20=0.05/cm

ii.

the position of the image is beyond C.

Explanation:

See the attachment !!!!!!!

Will mark brainlest helpp!!!!!!​

Answers

Answer:

I don't know if it is correct or not.

initial velocity=u=0m/sFinal velocity=60km/h=v

Convert to m/s

[tex]\\ \Large\sf\longmapsto v=60\times \dfrac{5}{18}=16.6m/s[/tex]

Time=t=5min=5×60=300s

We know

[tex]\boxed{\Large{\sf Acceleration=\dfrac{v-u}{t}}}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6-0}{300}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6}{300}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=0.05m/s^2[/tex]

Distance=s

Using second equation of kinematics

[tex]\boxed{\Large{\sf s=ut+\dfrac{1}{2}at^2}}[/tex]

[tex]\\ \Large\sf\longmapsto s=0(300)+\dfrac{1}{2}(0.05)(300)^2[/tex]

[tex]\\ \Large\sf\longmapsto s=0.05\times 150^2[/tex]

[tex]\\ \Large\sf\longmapsto s=0.05\times 22500[/tex]

[tex]\\ \Large\sf\longmapsto s=1125m[/tex]

Quả bóng 200g chuyển động với v 4m/s đập vào tường rồi bật ra ngược chiều với cùng tốc độ độ biến thiên động lượng của quả bóng là

Answers

bièn shhddkjn usb’s svyevtec tectev ev

10. Explain the principle of electric motor. Write its uses.

Answers

Explanation:

The principle of an electric motor is based on the current carrying conductor which produces magnetic field around it. A current carrying conductor is placed perpendicular to the magnetic field so that it experiences a force.

The largest electric motors are used for ship propulsion, pipeline compression and pumped-storage applications with ratings reaching 100 megawatts. Electric motors are found in industrial fans, blowers and pumps, machine tools, household appliances, power tools and disk drives.

People who get population education are also aware of health issues and environment education justify

Answers

I believe this statement is correct if not I am sorry

Enlight the contribution of science and technology for current pandemic of Corona virus??​

Answers

The vaccine ofcourse. They helped in making the vaccine.

How can we drop eggs the fewest amount of times without breaking it?​

Answers

Answer:

drop in water

Explanation:

follow me m mm m

what ia measurement in science?
= The process of comparing an unknown quantities with an standard known quantities is called measurement.​

Answers

Yes it is the measurement in science

A 550N object has a coefficient of .012 against a smooth surface. What
force is needed to keep the object sliding?(ANSWER to 1 decimal place, no
units)

Answers

Vertically, the object is in equilibrium, so that the net force in this direction is

F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

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