Infrared and ultraviolet waves have different frequencies.
Both types of wave can have harmful effects on human beings.

Describe the harmful effects of infrared and ultraviolet waves, relating them to the frequencies of the waves.​​

As the box compresses the spring, the spring performs

-1/2 (85 N/m) (0.065 m)² ≈ -0.18 J

of work on the box. By the work energy theorem, the total work performed on the box (which is done only by the spring since there's no friction) is equal to the change in the box's kinetic energy. At full compression, the box has zero instantaneous speed, so

W = ∆K   ==>   -0.18 J = 0 - 1/2 (2.5 kg) v ²

where v is the box's speed when it first comes into contact with the spring. Solve for v :

v ² ≈ 0.14 m²/s²   ==>   v ≈ 0.38 m/s

Answer:

I know it's groceries

Explanation:

electronics ship before clothing

electronics ship after groceries

urgent items are first so

order:

1.) A/Electronics

2.) Clothing/B

3.) Groceries(since groceries aren't urgent)

thing is it's C or D I'm leaning to D since it says it ships last but i dont know so if I'm wrong sorry.

Answer:

I wish I could help but iam srry

Answer:

A RECIPE NEEDS A COMBINED WEIGHT OF 720G OF FLOUR AND SUGAR. IF THE RECIPE NEEDS 5TIME FLOUR THAN SUGAR,HOW MUCH OF EACH IS NEEDED

Answer:

potential energy=mgh

4×9.8×2.4

Explanation:

may be hope this will help you

Answer:

The submarine's maximum safe depth in sea water is 801.678 m.

Explanation:

P=Po+(rho)*g*h

Max Pressure = Initial Pressure + (Water Density)(Gravity)(Max Depth)

Area of Window = Pi*(Diameter/2)^2 = Pi*(.4m/2)^2 = 0.125664 m^2

Max Pressure= (1.0*10^6 N)/(0.125664 m^2)= 7.95775-E6 Pa

Initial Pressure= 1atm= 101.3kPa= 101300Pa

Water Density (rho) = 1000kg/m^3

Gravity= 9.8m/s^2

So rearranging for h= (P-Po)/((rho)*g)

h=((7.95775-E6Pa)-(101300Pa))/((1000kg/m^3)(9.8m/s^2))= 801.678 m

[tex]\textbf{A}×\textbf{B}= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}[/tex]

Explanation:

Given:

[tex]\textbf{A} = 5\hat{\textbf{i}} - 7\hat{\textbf{j}} - 3\hat{\textbf{k}}[/tex]

[tex]\textbf{B} = -4\hat{\textbf{i}} + 4\hat{\textbf{j}} - 8\hat{\textbf{k}}[/tex]

The cross product [tex]\textbf{A}×\textbf{B}[/tex] is given by

[tex]\textbf{A}×\textbf{B} = \left|\begin{array}{ccc}\hat{\textbf{i}} & \hat{\textbf{j}} & \hat{\textbf{k}} \\\:\:5 & -7 & -3 \\ -4 & \:\:4 & -8 \\ \end{array}\right|[/tex]

[tex]= \left|\begin{array}{cc}-7 & -3\\\:4 & -8\\ \end{array}\right|\:\hat{\textbf{i}}\:+\:\left|\begin{array}{cc}-3 & \:\:5\\-8 & -4\\ \end{array}\right|\:\hat{\textbf{j}}\:+\: \left|\begin{array}{cc}\:\:5 & -7\\-4 & \:\:4\\ \end{array}\right|\:\hat{\textbf{k}}[/tex]

[tex]= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}[/tex]

Answer:

A. True

Explanation:

Answer:

Solution

Verified by Toppr

Correct option is

C

3 cm

RI=apparent depthreal depth

Substituting, 34=apparentdepth12

Therefore, apparent depth=412×3=9

The height by which it appears to be raised is 12−9=3cm

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SIMILAR QUESTIONS

A coin is placed at the bottom of a glass tumbler and then water is added. It appeared that the depth of the coin has been reduced because

Medium

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>

A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?

Answer:

C. A force must be acting on the object.

Explanation:

This is due to the action of its momentum direction.

[tex].[/tex]

Answer:

P = density (p) * g * h

P = 1000  kg/m^3 * 9.8 m/s^2 * 40 m = 392,000 N/m^2

since kg m / s^2 = Newtons

The average pressure is 1/2 (pressure at 0m +  pressure 80 m) for liquid of uniform density

Answer:

solving for: velocity

equation: velocity = distance / time

substitution: velocity = 1425 km / 12.5 hrs

answer: 114 km/hr

R(parallel) = product/ sum

50×30/50+30

1500/80

18,75 ohms

Answer: 18.75

above is right but you need to put a dot after the number 18

Answer:

q=9.43×10^-5C

Explanation:

F=kq^2/r^2

500= 9×10^9 × q^2/ (0.4)^2

500N×0.16m=9×10^9Nm^2C^2 × q^2

80/(9×10^9)= q^2

√(8.8889×10^9) = q

q= 9.43×10^-5C

since they are identical both charges, q=9.43×10^-5C

The magnitude of the two charges is ​9.43×10^-5 C.

To calculate the magnitude of an electric force, it is necessary to use the following expression:

                                          [tex]F = k \frac{q_{1} \times q_{2} }{d^{2}}[/tex]

Assuming that the constant is:

                                          [tex]k = 9\times 10^{9}[/tex]

We can apply the values ​​in the formula above, obtaining:

                                     [tex]500 = 9 \times 10^{9} \times \frac{q^{2}}{0.4^{2}}[/tex]

                                         [tex]q = \sqrt{0.88\times10^{-8}}[/tex]

                                          [tex]q = 9.43 \times 10^{-5} C[/tex]

So, the magnitude of the two charges is   ​9.43×10^-5 C.

Learn more about electrical force in: brainly.com/question/16888648

Answer: it would be daddy

Explanation:

Because I’m daddy

Answer:

Hah yyytttdvooophhfdbbb hhhctuionmm hhdtjjjov

The percentage by which the water density increased is 4.1[tex]\mathbf{\overline 6}[/tex] %

The known values are;

The increase in pressure per 10 meter increase in depth = 1.0 atm

The depth of the deepest ocean = 12 km = 12,000 m

The compressibility of the ocean = 5.0 × 10⁻⁵ 1/atm

The unknown

The percentage the density of water increased in the deepest ocean

Strategy;

Find the pressure at the deepest point of the deepest ocean and apply the compressibility

We have;

[tex]\mathbf{Compressibility = \dfrac{1}{V} \times \dfrac{\partial V}{\partial p}}[/tex]

The change in pressure, [tex]\partial p[/tex] = (12,000 m/(10 m)) × 1.0 atm = 1,200 atm

Therefore, we have for one cubic meter of water

[tex]\mathbf{5.0 \times 10^{-5} \ atm^{-1} = \dfrac{1}{1 \, m^3} \times \dfrac{\partial V}{1,200 \, atm}}[/tex]

Therefore;

[tex]\mathbf{\partial}[/tex]V = 5.0 × 10⁻⁵ atm⁻¹ × 1 m³ × 1,200 atm = 0.06 m³

The new volume = V - [tex]\mathbf{\partial}[/tex]V

∴ The new volume = 1 m³ - 0.06 m³ = 0.94 m³

The initial density = mass/(1 m³)

The new density = mass/(0.96 m³)

The percentage increase in density, [tex]\partial[/tex]ρ%, is given as follows;

[tex]\mathbf{\partial p \% = \dfrac{ \dfrac{Mass}{0.96 \ m^3} - \dfrac{Mass}{1 \ m^3} }{ \dfrac{Mass}{1 \ m^3}} \times 100 = \dfrac{25}{6} \% = 4.1 \overline 6 \%}[/tex]

∴  [tex]\mathbf{\partial}[/tex]ρ% =  4.1[tex]\mathbf {\overline 6}[/tex] %

The percentage by which the water density increased, [tex]\partial[/tex]ρ% = 4.1[tex]\mathbf{\overline 6}[/tex] %

Learn more about compressibility here;

https://brainly.com/question/18746977

Answer

E - 1/2 K x^2      potential energy of compressed spring

E = 1/2 * 4 N / m * (.5 m)^2 = 2 * .5^2 N-m = .5 N-m

Answer:

red blood cell, also called erythrocyte

Explanation:

Hope it helps

Mark me as Brainliest plz

:DD

Answer:

Option C

Explanation:

Divide the issue into its main parts and discuss each part.

Check attached photo

Check attached photo

Answer:

d_t = 3.05km

v_a = 4.3km/h

Explanation:

42mins*(2/3) = 28mins

42mins-28mins = 14mins

d = v*t

d_1 = (4km/h)*(1h/60mins)*(28mins)

d_1 = 1.87km

d_2 = (5km/h)*(1h/60mins)*(14mins)

d_2 = 1.17km

d_t = d_1+d_2

d_t = 1.87km+1.17km

d_t = 3.05km

v_a = (v_1+v_2)/2

v_a = [(2*4km/h)+5km/h)]/3

v_a = 4.3km/h

Answer:

The inner and outer surfaces of a 0.5-cm thick 2-m by 2-m window glass in winter are 10°C and 3°C, respectively. If the thermal conductivity of the glass

Explanation:

Answer:

4.38 m/s

Explanation:

what do you mean about it

Answer:

Explanation:

This depends on where you are.

The YMCA where I grew up was affordable. Very. Or my mother would not have let me go.

Answer:

Metal or conductors , what they do is that they allow full flow of current that is conduction is due to free electrons only and there is literally no gap between valence and conduction band,so free electrons can easily jump into conduction band from valence band.

And now lets talk about insulators,what they do is that they don’t allow any current to flow i.e they act as strong dielectric,and gap between valence band and conduction band is so big that free electron can never come into conduction band from valence band ever if they try is for eternity…

But semiconductors can act both as an insulator as well as a conductor based on the voltage input. Hence, there is a possibility to control the current flow in semiconductors , so they don’t just relax and let the current pass by, they can control it, and that is why you can design logic circuits with it.

But as the temperature increases free electrons from valence band of insulators can jump to conduction band and can cause a little conductivity, and then the insulator will act as a semi-conductor.

force between two parallel wire is

f/l = mueo*i1i2/2pir

f/l = 2*10^-7*i1i2/rl

i2 = f*r/2*10^-7*i1

i2 = 342.9 A

Answer:

hellooooo :) ur ans is 33.5 m/s

At time t, the displacement is h/2:

Δy = v₀ t + ½ at²

h/2 = 0 + ½ gt²

h = gt²

At time t+1, the displacement is h.

Δy = v₀ t + ½ at²

h = 0 + ½ g (t + 1)²

h = ½ g (t + 1)²

Set equal and solve for t:

gt² = ½ g (t + 1)²

2t² = (t + 1)²

2t² = t² + 2t + 1

t² − 2t = 1

t² − 2t + 1 = 2

(t − 1)² = 2

t − 1 = ±√2

t = 1 ± √2

Since t > 0, t = 1 + √2.  So t+1 = 2 + √2.

At that time, the speed is:

v = at + v₀

v = g (2 + √2) + 0

v = g (2 + √2)

If g = 9.8 m/s², v = 33.5 m/s.

E= [tex]\frac{1}{2}[/tex]×k×x² = 1J

given k=800n/m x=0.05m