Answer: a.Oxygen
Explanation:
Please help me with this homework
Answer:
The answer is C density.
What does this image represent?
A) A methyl group present in fatty acids
B) A ketone group present in fat molecules
C) An aldehyde group present in monosaccharides molecules
D) An acid group present in lipids
Answer:
D) An acid group present in lipids
Can someone help on this question.
Select the correct structure that
corresponds to the name.
2,2-dimethyl-3-hexyne
A. CH3CH2C=CC(CH3)3
B. CH3CH(CH3)C = CCH(CH3)2
C. both
Answer: A
Explanation:
The correct structure of the name of the compound given is CH₃CH₂C=CC (CH₃)₃.
What is 2,2-dimethyl- 3- hexyne?Dimethyl hexyne is an organic compound. Its chemical formula is C8H14. The compound hexyne is used to make a complex compound, agrochemical, and pharmaceutical compounds.
Thus, the correct option is A, CH₃CH₂C=CC (CH₃)₃.
Learn more about 2,2-dimethyl- 3- hexyne
https://brainly.com/question/24617388
#SPJ2
Can someone help with question 16?
ASAP
1. carbon lies in the 2nd period where silicon in the third period.
2. carbon is a non metal whereas silicon is a metalloid.
3. there are only 3 isotopes of carbon and 23 isotopes of silicon
4. size of silicon atom is larger
5. silicon is heavier than carbon.
(52.6 cm)(1.214cm) what is the product expressed to the correct number of significant figures?
Which compound in the following reaction serves as the Bronsted-Lowry acid?
NaOH + HCl → NaCl + H2O
O NaOH, because it is a proton donor
O HCI, because it is a proton donor
O NaOH, because it is a proton acceptor
HCI, because it is a proton acceptor
Alanna spots a bird in her back yard. The bird is sitting on a tree. Explain how the outer coverings of the bird and tree are different and have different functions.
Answer:
A bird's feathers are supposed to keep the bird warm and help them fly. A tree's bark is supposed to protect the inside of the tree.
Explanation:
If a tree has no bark, the inside of it is exposed. If a bird has no feathers, the bird is cold and cant fly.
A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s new volume?
Answer:
8.68 L is the new volume
Explanation:
You use Boyle's law for this.
[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]
[tex]P_{1}[/tex] = first pressure
[tex]P_{2}[/tex] = second pressure
[tex]V_{1}[/tex] = first volume
[tex]V_{2}[/tex] = second volume
Convert pressure from atm to mmHg (use same units):
5.97 x 760 = 4537.2 -> 4.54 x 10³
...maintain 3 significant figures in calculation, and round as needed...
(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)([tex]V_{2}[/tex])
(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = [tex]V_{2}[/tex] = 8.68 L
Hope this helps :)
Please help me with number 43
Answer:
The reason why atomic mass is usually not a whole number is because it is a weighted average of the mass numbers of isotopes
Explanation:
5. What is the difference between a reflected and a diffracted sound wave?
A. A reflected sound wave is absorbed by the medium. A diffracted sound wave changes
direction as it passes through an opening.
B. A diffracted sound wave bounces back to the place of origin. A reflected sound wave is
absorbed as it passes through an opening.
C. A reflected sound wave bounces back to the place of origin. A diffracted sound wave
changes direction as it passes through an opening.
D. A diffracted sound wave bounces back to the place of origin. A reflected sound wave
changes direction as it passes through an opening.
Answer:
Reflection involves a change in direction of waves when they bounce off a barrier; refraction of waves involves a change in the direction of waves as they pass from one medium to another; and diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path.
Explanation:
https://www.physicsclassroom.com/class/waves/Lesson-3/Reflection,-Refraction,-and-Diffraction#:~:text=Diffraction%20of%20Waves-,Reflection%20involves%20a%20change%20in%20direction%20of%20waves%20when%20they,a%20barrier%20in%20their%20path.
Reflection of sound wave differs from diffraction of sound wave in that a reflected sound wave bounces back to the place of origin while a diffracted sound wave changes direction as it passes through an opening.
What is reflection?Reflection is the bouncing back of a wave when it hits an obstacle along its path.
What is diffraction?Diffraction is the spreading out of a wave in a circular path as it passes through a tiny opening.
Therefore, the difference between reflection and diffraction is that a reflected sound wave bounces back to the place of origin while a diffracted sound wave changes direction as it passes through an opening.
Learn more about reflection and diffraction at: https://brainly.com/question/11176463
Calculate the amount of heat gained by the water in cup 2 after adding the hot object(s) to it.
Use the data recorded in parts B and C and the formula Q = mCΔT. The specific heat capacity of water is 4.186 J/(g °C).
(part B and C numbers are included)
Answer:
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
Explanation:
As we know
Amount of heat gained
Q = mc (T2-T1)
Here,
mass of water in cup 2 (m) = 79.10 grams
Temperature of water in cup 2 = 16.8 degree Celsius
Specific heat of water (c) = 4.186 J/(g °C)
Final Temperature of water in cup 2 = 23.2 degree Celsius
Substituting the given values, we get -
Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
Can someone help me
Answer:
Its refraction
Explanation:
becuase refraction is the change in direction of a wave passing from one medium to another, where the straw appears to be split apart because of the waters direction.
Two ways the atmosphere can be divided
Answer:
The atmosphere can be divided into layers based on its temperature, as shown in the figure below. These layers are the troposphere, the stratosphere, the mesosphere and the thermosphere.
What is the right answer to these questions?
How many moles are in 100 g of K3PO4 ?
In steps 3 and 4 of the citric acid cycle, successive oxidations produce ________ as a waste product and the four-carbon carrier ________. In steps 3 and 4 of the citric acid cycle, successive oxidations produce ________ as a waste product and the four-carbon carrier ________. CO2; malate CO2; succinyl-SCoA ADP; oxaloacetate ADP; succinyl-SCoA CO2; oxaloacetate
Answer:
CO2; succinyl-SCoA
Explanation:
Citric acid cycle, also called Krebs cycle is the second stage of aerobic cellular respiration, which occurs in the mitochondrion. The kreb's cycle is made up of 7 distinct steps, with each involving series of enzymatic reactions.
According to this question, step 3 and 4 of the citric acid cycle involves an oxidation and decarboxylation reaction to produce 2 molecules of carbon dioxide (CO2) and a 4-carbon compound called succinyl group. A coenzyme A binds to the succinyl group to form succinyl-SCoA.
the distance between two points on a map is 0.04 kilometers what is the distance in meters
Explain the process of fermentation.
Answer:
Fermentation, chemical process by which molecules such as glucose are broken down anaerobically. More broadly, fermentation is the foaming that occurs during the manufacture of wine and beer, a process at least 10,000 years old. The frothing results from the evolution of carbon dioxide gas, though this was not recognized until the 17th century.
Explanation:
looked it up-
Answer:
like babies or milk and cheese?
Explanation:
DIRECTIONS: Classify the following unbalanced chemical equations according to the six types
of chemical reactions. Write your answer on the space provided for each number.
1. NaOH + KNO3 NaNO3 + KOH
2. CH4 + O2 CO2 + 2H2O
3. Fe + NaBr FeBr3 + Na
4. CaSO4 + Mg(OH)2 Ca(OH)2 + MgSO4
5. NH4OH + HBr H2O + NH4Br
6. P4 + O2 P2O4
7. NaNO3 NaNO2 + O2
8. C18H18 + O2 CO2 + H2O
9. H2SO4 + NaOH NaSO4 +H2O
10.NiSO4 + Li3PO4 Ni3(PO4)2 + Li2SO4
Help asap plzzzz 30 points
A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 g KOH into 3.0 L of solution.
Each lab group needs 0.023 mol of KOH for their experiment. How many milliliters of the solution does each group need to provide enough dissolved moles?
mL of solution
Answer:
Do you need your 0.00 2 oz
Explanation:
Because that is the right answer
For the enough dissolving of given moles each group will need to provide 92mL of solution.
How we determine Molarity for further calculation?Molarity can be calculated as: M = n/V mol/L where,
V = volume = 3L (given)
n = no. of moles, which can be calculated as:
n = W/M, where
W = given mass = 42.1g (given)
M = molar mass = 56.1g/mol (known)
First of all we have to calculate molarity to determine the volume of solution of each groups. By putting value of n in the 1st equation, molarity can be calculated as follow:
M = 42.1 / 56.1 × 3 = 0.250 mol/L
Now in the question it is given that each group have KOH solution of 0.023 moles. So, we can calculate the volume by using the 1st equation:
M = n/V
0.250 = 0.023/V
V = 0.023mol / 0.250mol per L = 0.092L = 92mL.
Hence, 92mL of the solution will each group need to provide enough dissolved moles
To learn more about molarity, visit the below link:
https://brainly.com/question/489225
Calculate the average reading for all three trials for both the wet bulb and dry bulb thermometers. Convert the average
temperatures for both thermometers to Celsius using this formula:
(°F - 32) = °C.
Answer: °32= 0 °C.
Explanation:
Answer:
Explanation:
Please add the temperature readings from all three trials for both thermometers. Will do the calculation with readings.
HEELLLP
How many liters of hydrogen gas, at STP, are required to produce 2.50 x 1022 molecules of CH4? C + 2H2 → CH4
Answer:
1.8 L
Explanation:
According to Avogadro;
1 mole of CH4 contains 6.02 * 10^23 molecules of CH4
x moles of CH4 contains 2.50 x 10^22 molecules of CH4
x = 1 * 2.50 x 10^22 molecules/ 6.02 * 10^23 molecules
x = 0.04 moles of CH4
2 moles of H2 yields 1 mole of CH4 gas
x moles of H2 gas yields 0.04 moles of CH4
x = 2 moles * 0.04 moles / 1mole = 0.08 moles of H2
x = 0.08 moles of H2
Since 1 mole of H2 occupies 22.4 L
0.08 moles of H2 occupies 0.08 moles * 22.4 L/ 1 mole
= 1.8 L
A 33.05 g sample of a substance is initially at 28.5 °C. After absorbing 2589 J of heat, the temperature of the substance is 107.9 'C.
What is the specific heat (c) of the substance?
Answer:
[tex]0.985\ \text{J/g}^{\circ}\text{C}[/tex]
Explanation:
m = Mass of sample = 33.05 g
[tex]\Delta T[/tex] = Change in temperature = [tex]107.9-28.5=79.5^{\circ}\text{C}[/tex]
Q = Heat absorbed = 2589 J
c = Specific heat of substance
Heat is given by
[tex]Q=mc\Delta T\\\Rightarrow c=\dfrac{Q}{m\Delta T}\\\Rightarrow c=\dfrac{2589}{33.05\times 79.5}\\\Rightarrow c=0.985\ \text{J/g}^{\circ}\text{C}[/tex]
The specific heat of the substance is [tex]0.985\ \text{J/g}^{\circ}\text{C}[/tex].
When water droplets in a cloud combine, become too heavy, and fall to the ground as rain, snow, sleet, or hail, we are experiencing _____.
Answer:
precipitation
Explanation:
Answer:
precipitation
Explanation:
Any event where water (in any form- frozen or liquid or any other form) falls from sky it is called precipitation.
Only producers are able to capture energy from the sun and the matter from the environment to make food.How does energy that come from the sun get to every other organism?How does matter from the environment enter every other organism?
Answer:
Explanation:
Plants get energy from sunlight to produce carbohydrates. When a consumer such as herbivore consume plants, he gets energy and when a canivore or omnivore consume the primary consumer, energy is also transfered to them and this is called food chain.
Matter from the environment which include fallen leaves or trees will decompose after a while in the ground when decomposers begin to act on it and it will eventually give them energy. Decomposer help break down organic matter such as leaves,dead animals and get little amount of of energy in the energy flow pyramid
What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?
O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH
Solution :
Molecular mass of NaOH is 23 g/mol .
So, number of moles of NaOH is given by :
[tex]n = \dfrac{10}{40}\ mole[/tex]
Now, we know molarity is given by :
[tex]Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }[/tex]
[tex]M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M[/tex]
Hence, this is the required solution.
Answer: The answer is A O0.104 M NaOH
Explanation:
what is the percentage of oxygen in air
ASAP...
Explanation:
21 % of oxygen is present in air .
hope it is helpful to you
What type of circuit is shown in the diagram below?
Answer:
Its a simple SERIES circuit
Explanation:
A sample of 10.0 grams of carbon dioxide gas is contained in a tank with a volume of 6.0 L so that the pressure inside the tank is 1.00 atm. What is the
temperature of the gas sample in °C?
Given: R = 0.0821 L.atm/molek
O 280°C
O 322°C
O 49°C
O 595°C
Answer:
49°C
Explanation:
Let's apply the Ideal Gases Law in order to solve this question:
P . V = n . R . T
Pressure = 1 atm
Volume = 6 L
n = number of moles → 10 g. 1mol /44g = 0.227 moles
R = Ideal Gases Constant
We replace data: 1 atm . 6 L = 0.227 mol . 0.082 . T
6 atm.L / ( 0.227 mol . 0.082) = T
T° = 322 K
We convert T° from K to °C → 322 K - 273 = 49°C
