In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 55.4 inches, and standard deviation of 4.1 inches.

A) What is the probability that a randomly chosen child has a height of less than 61.25 inches?

Answer= (Round your answer to 4 decimal places.)

B) What is the probability that a randomly chosen child has a height of more than 46.5 inches?

Answer= (Round your answer to 4 decimal places.)

Answer:

P( yellow) =  8/23

P( blue or green) =  9/23

P(orange) = 0

Step-by-step explanation:

6 red, 5 green, 4 blue, and 8 yellow M&M's = 23  total

P( yellow) = yellow / total = 8/23

P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23

P(orange) = orange/ total = 0/23

Answer:

there are 23 m&m's.

Step-by-step explanation:

Probability of getting red is 6/23

Probability of getting  green is 5/23

Probability of getting blue is  4/23

Probability of getting yellow is 8/23

Orange = red + yellow = 6+8/23

Probability of getting Orange = 14/23

Answer:

See Below.

Step-by-step explanation:

We have the equation:

[tex]\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}[/tex]

And we want to show that:

[tex]\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}[/tex]

Instead of differentiating directly, we can first square both sides:

[tex]\displaystyle y^2 = 3e^{2x} -4x + 1[/tex]

We can find the first derivative through implicit differentiation:

[tex]\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4[/tex]

Hence:

[tex]\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}[/tex]

And we can find the second derivative by using the quotient rule:

[tex]\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}[/tex]

Substitute:

[tex]\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}[/tex]

Simplify:

[tex]\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}[/tex]

Combine fractions:

[tex]\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}[/tex]

Simplify:

[tex]\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}[/tex]

Simplify:

[tex]6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}[/tex]

Q.E.D.

Answer:

not similar

Step-by-step explanation:

32/26 = 16/13

18/12 = 3/2

16/13 is not equal to 3/2, so the rectangles are not similar.

Lets check

[tex]\\ \sf\longmapsto \dfrac{32}{18}\boxed{}\dfrac{26}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{16}{9}\boxed{}\dfrac{13}{6}[/tex]

Hence

[tex]\\ \sf\longmapsto \dfrac{16}{9}\neq\dfrac{13}{6}[/tex]

Both rectangles are not similar

Answer:

-1/6

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 10-8)/(-21 - -9)

  = ( 10-8)/(-21 +9)

   = 2 /-12

  = -1/6

Answer:

The standard deviation of your weight over a day is of 1.1547 pounds.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b, and the standard deviation is:

[tex]S = \sqrt{\frac{(b-a)^2}{12}}[/tex]

Assume that the changes in water weight is uniformly distributed between minus two and plus two pounds in a day.

This means that [tex]a = -2, b = 2[/tex]

What is the standard deviation of your weight over a day?

[tex]S = \sqrt{\frac{(2 - (-2))^2}{12}} = \sqrt{\frac{4^2}{12}} = \sqrt{\frac{16}{12}} = 1.1547[/tex]

The standard deviation of your weight over a day is of 1.1547 pounds.

Answer:

Linear

Step-by-step explanation:

cost = 79 * weeks

79*1=79

79*2=158

etc.

Answer:

N(t) = 0.188t + 22.76

Step-by-step explanation:

Number of licensed drivers in 2004 = 22.76 million

Number of licensed drivers in 2009 = 23.7 million

Number of licensed drivers, N as a function of t since year 2004 ;

General form of a linear function :

y = mx + c

c = intercept ; m = slope

Intercept c = value of y ; when x = 0

Here, population after uerssmmx,

Hence,

In 2004 ;

22.76 = mx + c

x = 0

22.76 = c

Number in 2009

x = number of yesrs after 2004 ; x = 2000 - 2004 = 5years

We can find the slope :

y = m*5 + 22.76

y = 23.7 in 2009

23.7 = 5m + 22.76

23.7 - 22.76 = 5m

m = 0.94 / 5

m = 0.188

Hence, the linear function can be written as :

N(t) = 0.188t + 22.76

Answer:

third answer "a"

Step-by-step explanation:

Answer:

Sin A = o/h

= 9/41

Step-by-step explanation:

since Sin is equal to opposite over hypotenuse, from the question, the opposite angle of A is 9 and hypotenuse angle of A is 41. Thus the answer for Sin A= 9/41

We have 4⁶ = 4096 and 4⁷ = 16,384, which is to say that the given sum only contains the first six powers of 4.

Now,

[tex]\displaystyle 1+2+3+\cdots+5000 = \sum_{k=1}^{5000}k[/tex]

and you subtract the sum of the first six powers of 4 to get the sum S that you want,

[tex]\displaystyle S = \boxed{\sum_{k=1}^{5000}k - \sum_{k=1}^64^k}[/tex]

Answer:

F(x) =5(-1)-4(-1)^2+3,

=-5-4+3

=-6

Answer: 4.25

Step-by-step explanation:

2.5/100 = 0.025

0.025 × 170 = 4.25

but the question there is any goats in 2.5 cm ??

that is impossible

Answer:

a) The rocket travels 200 meters horizontally.

b) The height of the rocket mid-flight is of 1000 meters.

Step-by-step explanation:

Height of the rocket:

The height of the rocket, in meters, after an horizontal distance of x, is given by:

[tex]y = 0.1x(200 - x)[/tex]

a) How far does the rocket travel horizontally?

This is x when [tex]y = 0[/tex]. So

[tex]0.1x(200 - x) = 0[/tex]

Then

[tex]0.1x = 0[/tex]

[tex]x = 0[/tex]

And

[tex]200 - x = 0[/tex]

[tex]x = 200[/tex]

So

The rocket travels 200 meters horizontally.

b How high does the rocket reach mid-flight?

This it the height y when x = 0, so:

[tex]y = 20*100 - 0.1*100^2 = 1000[/tex]

The height of the rocket mid-flight is of 1000 meters.

Every morning there are expected 240 customers who arrive at bank for the customer service.

There are on average 240 customers arriving to the bank every morning.

There are total 5 bank tellers and they take average 3 minutes to help customer.

The average time each bank teller spends on satisfying a customer will be calculated using the linear model,

Using wait time calculator:

Average service time / standard deviation

Ce = 3/1.5 = 2

The spent time on a customer is 3.4 minutes.

Learn more at https://brainly.com/question/24379767

Answer:

Customers spend 3.4 minutes in the bank on average.

Step-by-step explanation:

The customer arrives at the bank every morning. There is a line at bank goes to 5 bank teller. The customer takes 3 minutes with a 1.5-minute standard deviation.

The customer = 240

Time = 3

Where R = (240/4)

=60/hr

Where CVa = 1

Answer:

The answer is always your welcome

Answer:

always

Step-by-step explanatia;won:

Answer:

x = -8

Step-by-step explanation:

-9x = 67+ 5

x = 72/-9

x = -8

Answer:

x=-8

Step-by-step explanation:

Answer:

no solution

Step-by-step explanation:

a negative number cannot be square rooted

Answer:

"not possible". no such thing as a negative squared number

Answer:

angle bisectors

Step-by-step explanation:

The incentre is where a triangle's three angle bisectors intersect ( an angle bisector is a ray that cuts an angle in half ). The incentre is the centre of a triangle drawn inside the triangle.

Step-by-step explanation:

here's the answer to your question

Step-by-step explanation:

With this kind of problem, we're looking at an equation in the form

y - y1 = m(x - x1)

(m = slope)

so we can substitute m, y1, and x1 with the values we're given.

y - y1 = m(x - x1)

y - 1/3 = 3/4(x - 4)

Answer:

y - 1/3 = 3/4(x - 4)

Answer:

Step-by-step explanation:

3/16 = 0.1875

As a % this is 18.75%

18.75/100 * 200 = 37.5

I'm not sure from the question, exactly what you want. 18.75% of 200 is one possibility.

3/16 of 200 as a percentage is 3750%

The question can be represented as:

[tex]\frac{3}{16} * 200[/tex]

Rewrite as:

[tex]\frac{3}{16} * 200 =\frac{3* 200}{16}[/tex]

Multiply the numerator

[tex]\frac{3}{16} * 200 =\frac{600}{16}[/tex]

[tex]\frac{3}{16} * 200 =37.5[/tex]

Multiply by 100% to represent it as a percentage

[tex]\frac{3}{16} * 200 =37.5 * 100\%[/tex]

[tex]\frac{3}{16} * 200 =3750\%[/tex]

Read more at:

https://brainly.com/question/19994306

Answer:

x = 2.536 m

y = 2 m

Step-by-step explanation:

Considering the three sides of the rectangle and the isosceles triangle

when resolving the width and height of the rectangle to achieve the smallest possible perimeter.

step 1 :

Area of window =  xy + 1/2 xz  , perimeter = x + 2y + 2c

c = [tex]\sqrt{z^2 + 1/4 x^2 }[/tex]

we are tasked with minimizing the perimeter ( p ) subject to A = 6

attached below is the detailed solution of the given problem

Answer:

а²-ab+8b+b²-1=a(a-b)+b(8+b)-1

Complete Question

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)  

t=8.169  

P-value= ?

Answer:

a)  [tex]P-value=0[/tex]

b)  Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=10[/tex]

Mean [tex]\=x= 51.3[/tex]

Standard deviation [tex]\sigma=1.2[/tex]

Significance level is taken as [tex]\alpha=0.05[/tex]

t test statistics

[tex]t=8.169[/tex]

Therefore

[tex]P-Value=P(t>8.169)[/tex]

Critical point

[tex]t_{\alpha,df}[/tex]

[tex]\alpha=0.05[/tex]

[tex]df=10-1=>9[/tex]

Therefore

P-value from T distribution table

[tex]P-value=0[/tex]

Conclusion

[tex]P-value (0)< \alpha(0.05)[/tex]

We Reject the Null Hypothesis [tex]H_0[/tex]

Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Answer:

1100 and 130 (km/h)

Step-by-step explanation:

1. if the velocity of the wind is 'w' and the velocity of the plane in still air is 'p', then

2. it is possible to make up two equations:

the fly against the wind: (p-w)*8=7760;

the fly with the wind: (p+w)*3=3690.

3. if to solve the system made up, then:

[tex]\left \{ {{3(p+w)=3690} \atop {8(p-w)=7760}} \right. \ => \ \left \{ {{p+w=1230} \atop {p-w=970}} \right. \ => \ \left \{ {{p=1100} \atop {w=130}} \right.[/tex]

4. the required rate of the plane in still air is p=1100 km/h; the rate of the wind is w=130 km/h.

Answer:

4

Step-by-step explanation:

Slope = y2-y1/x2-x1

We need to find two points on the graph, let's take these two points:

(x1, y1) (X2,y2)

(0,-6) and (2,2)

(2-(-6)/ (2-0) = 8/2 = 4

Answered by Gauthmath

Solution :

Given information :

A sample of n = 10 adults

The mean failure was 24 and the standard deviation was 3.2

a). The formula to calculate the 95% confidence interval is given by :

[tex]$\overline x \pm t_{\alpha/2,-1} \times \frac{s}{\sqrt n}$[/tex]

Here, [tex]$t_{\alpha/2,n-1} = t_{0.05/2,10-1}$[/tex]

                       = 2.145

Substitute the values

[tex]$24 \pm 2.145 \times \frac{3.2}{\sqrt {10}}$[/tex]

(26.17, 21.83)

When the [tex]\text{sampling of the same size}[/tex] is repeated from the [tex]\text{population}[/tex] [tex]n[/tex] infinite number of [tex]\text{times}[/tex], and the [tex]\text{confidence intervals}[/tex] are constructed, then [tex]95\%[/tex] of them contains the [tex]\text{true value of the population mean}[/tex], μ in between [tex](26.17, 21.83)[/tex]

b). The formula to calculate 95% prediction interval is given by :

    [tex]$\overline x \pm t_{\alpha/2,-1} \times s \sqrt{1+\frac{1}{n}}$[/tex]

   [tex]$24 \pm 2.145 \times 3.2 \sqrt{1+\frac{1}{10}}$[/tex]

   (31.13, 16.87)

answer:

120°

Step-by-step explanation:

∠OPM=∠ONM=90°

X°＝360°-60°-90°*2＝120°