In an arithmetic sequence, the seventh term is −9 and the nineteenth term is 39.
Find the common difference. Give only the exact value as your answer.

Answer:

the 1 one will be the answer

Answer:

The answer is (A)

Step-by-step explanation:

[tex]\bold{30s^{5}t^{9}u^{10}v^{8}}[/tex]

Answer:

Express your answer using positive exponent.

[tex]\bold{(5st³u^{9}v^{7})(6s⁴t^{6}uv)}[/tex]

adding power of common term and multiply constant term:

[tex]\bold{5*6*s^{1+4}*t^{3+6}*u^{9+1}*v^{7+1}}[/tex]

[tex]\bold{30s^{5}*t^{9}*u^{10}*v^{8}}[/tex]

[tex]\bold{30s^{5}t^{9}u^{10}v^{8}}[/tex]

Answer:

[tex]30s^5t^9u^{10}v^8[/tex]

Step-by-step explanation:

We'll be using the following exponent property to solve this problem:

[tex]a^b\cdot a^c=(a)^{b+ c}[/tex]

This will allow us to combine terms with the same variable.

In [tex](5st^3u^9v^7)(6s^4t^6uv)[/tex], we have four variables, [tex]s[/tex], [tex]t[/tex], [tex]u[/tex], and [tex]v[/tex].

Let's start with the [tex]s[/tex] terms, [tex]5s[/tex] and [tex]6s^4[/tex]. The number in front of each term is called the coefficients, and can be multiplied directly. Remember that if there is no exponent written, it's the same thing as if there was an exponent of 1.

Therefore, combine using the exponent property I mentioned above:

[tex]5\cdot 6\cdot s^1\cdot s^4=30\cdot s^{1+4}=30s^5[/tex]

Next, we'll move on to the [tex]t[/tex] terms, [tex]t^3[/tex] and [tex]t^2[/tex].

Combine using the exponent property:

[tex]t^3\cdot t^6=t^{3+6}=t^9[/tex]

Repeat for the [tex]u[/tex] and [tex]v[/tex] terms:

[tex]u^9\cdot u=u^{9+1}=u^{10}[/tex]

[tex]v^7\cdot v=v^{7+1}=v^8[/tex]

Finally, combine all the terms together:

[tex]\implies \boxed{30s^5t^9u^{10}v^8}[/tex]

Answer:

3560 people.

Step-by-step explanation:

You have to do 89% × 4000.

Or 0.89×4000=3560.

So 3560 is the answer.

Answer:

v = 25.6

Step-by-step explanation:

1. Multiply both sides of the equation by 4.

(6.4)(4) = 25.6

Answer:

please mark me brainlist

Step-by-step explanation:

Answer:

Step-by-step explanation:

Scientific notation is always written as a number between 1 and 9.9999999 repeating. There follows a power of 10. I'm not sure which answer would help you see it clearer but

4.8 * 10^4 the decimal is shifted 4 places the right which is 48000 where you have no numbers, you use zeros.

2.01 * 10^6 means that you shift the decimal 6 places to the right.

2010000

So 2 million is larger than 48 thousand.

The other way to do it is just to look at the power. 6 is more than 4. 6 describes the number of places you move. So does 4. 6>4 so that's the larger number.

Answer:

Step-by-step explanation:

I'm pretty sure its b

Answer:

i'm pretty sure the answer is option C. (x^2 + 9x) = 6^2

Step-by-step explanation:

i'm not 100% sure, but i hope this helps.

Answer:

it should be $30 so letter a

Answer:

A)  [tex](-3)^{2} \neq -9[/tex]

Step-by-step explanation:

Answer:

A) is correct

Step-by-step explanation:

(-3)**2 = 9,  not equal -9

The issue is negative numbers can only be imaginary numbers. The sq root of -9 would be 3i, where i is defined as the sq root of -1.

Answer:

D. 15/√346

Hope this helps! Have a nice day :)!

Answer:

E the base equation shifts to the right to five unit from the midpoint

Answer:

2.1

Step-by-step explanation:

Angle Q of the triangle, SRQ is 47. Let find Length of RQ of SRQ.

If we apply tangent ratio, we get

[tex]x = 5.9[/tex]

Now let find the measure of RP of Triangle SRP.

If we apply tangent ratio, we get

[tex]x = 3.8[/tex]

We can find PQ by Subtraction Poustulate.

[tex]5.9 - 3.8 = 2.1[/tex]

so

Pq=21

Answer:

PQ ≈ 2 cm

Step-by-step explanation:

 We know that SRQ is 47.  

Next we apply the tangent ratio. We get x = 5.9  

Now we find the measure of RP of the triangle SRP.  

If we apply tangent ratio, we get x = 3.8    

We can find PQ with this:

5.9 - 3.8 = 2.1 ≈ 2 cm

Answer:

y=2x-4

Step-by-step explanation:

y=x2-4

ygjn bcgh ccfjm kbhh

Answer:

→ m∠ABE + m∠EBC =180°

→ m∠ABF + m∠FED + ∠DBC =180°

→ ∠ABF ≅ ∠EBC

→ ∠ABE ≅ FBC

~OAmalOHopeO

Circumference of a circle = 2πr

So,

[tex]circumference = 2\pi \: r \\ = > circumference = 2 \times \frac{22}{7} \times \frac{63 \: cm}{2} \\ = > circumference = 2 \times \frac{11}{7} \times 63 \: cm \\ = > circumference = 2 \times 11 \times 9 \: cm \\ = > circumference = 198 \: cm[/tex]

Answer: Therefore, the circumference of circle is 198 cm.

Step-by-step explanation:

diameter = 63 cm

radius = 63/2 = 31.5 cm

circumference = ?

circumference or perimeter of circle = 2*pi*r

= 2*(22/7)*31.5

= (44/7)*31.5

= 198 cm

Answer:

4 and 6.2

Step-by-step explanation:

ABC=sqrt(2.4^2+3.2^2)=4

ABD=sqrt(2.4^2+3.2^2+4.8^2)=6.2

Answer:

1/4

Step-by-step explanation:

Count all of the vowels (this will be your numerator):

A and E

2

Count all of the letters (this will be your denominator):

A, B, C, D, E, F, G, and H

8

Write this as a fraction:

2/8

Simplify:

2/8 = 1/4

Answer:

brackets stand for multiplication therefore this means multiply 5.9 by 1.102..

I hope this helps and sorry if it's wrong

Answer:

here's the answer to your question

Answer: √18

√(4-1)^2 + (5-2)^2

√9 + 9

√18

Answered by Gauthmath must click thanks and mark brainliest

Answer:

90°

Step-by-step explanation:

Angle C = arccos((84²+13²-85²)/(2×84×13))

= arccos(0/2184)

= arccos(0)

= 90°

Answered by GAUTHMATH

Answer:

There are 104 nickels and 33 quarters

Step-by-step explanation:

Start of with the equation N = 3Q + 5. q is the amt of quarters n is the nickels. Then substitute Q with 33 since that is the amount of quarters and solve the equation for the amount of nickels that there are.

Answer:

25 feet is equal to 300 inch

Answer:

300 inches

Step-by-step explanation:

12 inches equal a foot, so just multiply 12 by 25 and BOOM, you get 300 inches :)

Answer:

-114

Step-by-step explanation:

f(x) = -4x^2 +5x

Let x = 6

f(6) = -4(6)^2 +5(6)

     = -4(36) +30

     - 144+30

   = -114

Answer:

D

Step-by-step explanation:

A function means that each input value (in this case, x) has only one output value (y). The vertical line test states that if a vertical line intersects with the relation more than once, it is not a function. Therefore, as a vertical line at x=0 intersects with the graph twice, the graph fails the vertical line test

Answer: Day 4 and 15

Step-by-step explanation:

Set up system of equations:

[tex]25x+136=-x^2+44x+76[/tex]

Simplify:

[tex]x^2-19x+60=0[/tex]

Factor: Both factors must be positive as the days can only be natural numbers.

[tex](x-15)(x-4)=0[/tex]

x=4,15

Answer: [tex]\Large \boldsymbol{} (x-y-z+1)(x+y-z-1)[/tex]

Step-by-step explanation:

[tex]\Large \boldsymbol{} 1) \ {(a-b)^2=a^2+2ab+b^2 } \\\\2) \ {a^2-b^2=(a-b)(a+b)} \\\\\\ x^2-y^2+z^2-2xz+2y-1= \\\\\underbrace{x^2-2xz+z^2}_{(x-z)^2} -\underbrace{(y^2-2y+1)}_{(y-1)^2}= \\\\\\ (x-z)^2-(y-1)^2 =(x-y-z+1)(x+y-z-1)[/tex]

Answer: Her sister's age 3 years ago = x

so, her age now = x+3

so Janice's present age = 2/3 of (x+3) {as Janice's present age is two-third of her sister's age now}

Therefore, Janice's age determining the value of x is 2/3 of (x+3).