In AABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of
AC. If MN = 8, ML = 5, and NL = 6, find the perimeter of trapezoid BMNC.
Need help ASAP pls

Answer:

Step-by-step explanation:

see attached image.

perimeter of trapezoid = sides (6 + 8 + 5 + 8 + 8)

                                     = 35

the perimeter of trapezoid BMNC is 35

Given :

In  triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. If MN = 8, ML = 5, and NL = 6

By midpoint theorem ,

[tex]BC= 2 \cdot MN\\BC=2 \cdot 8\\BC=16[/tex]

M is the midpoint of AB, AB= 2 times NL

BM=NL

BM=6

N is the midpoint of AC

AC is 2 times of ML

NC=ML

NC=5

Perimeter of trapezoid is  sum of all the sides

Perimeter of BMNC = BM+MN+NC+CB

Perimeter =[tex]6+8+5+16=35[/tex]

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