In 32 days, a field is cleared by 8 workers. How many workers would clear the same field in 8 days if working at the same time

Answer:

(f+g)(x)=5x+2x²-7x+4+3x-7 = 2x²+x-3

Step-by-step explanation:

Answer:

=6x^3-20x^2+26x-28

Step-by-step explanation:

Answer:

(8,7)

Step-by-step explanation:

Because our x-value for this ordered pair is 1, and it says to move to the right 7 units, 1+7 = 8. Therefore, our x-value for the ordered pair would be 8.

Because our y-value for this ordered pair is 6, and it says to move up 1 unit, 6+1=7. Therefore, our y-value for the ordered pair would be 7.

Once we have our x- and y-value, we can set up the ordered pair:

(8,7)

Answer:

(7, 8)

Step-by-step explanation:

In the picture below, when the point is moved up, it only changes the y part of the point, and the x part is kept the same. When the point is moved right by 7 units, the x part is changed while the y part is kept the same.

Hope this helps.

Answer:

[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]

By expanding the expression, we get;

[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]

Collecting like terms gives;

[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

(b) The given expression is presented as follows;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]

Therefore, we get;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]

Collecting like terms gives;

[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]

[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

[tex]N= 177\\\\a=46\\\\b=52\\\\c=36\\\\d=43[/tex]

[tex]\to \chi _{1}^{2}=\frac{N(ad-bc)^{2}}{(a+c)(b+d)(a+b)(c+d)}[/tex]

         [tex]=\frac{177((46\times 43)-(52 \times 36))^{2}}{(98)(79)(82)(95)}\\\\=\frac{177((1978)-(1872))^{2}}{60310180}\\\\=\frac{177(106)^{2}}{60310180}\\\\=\frac{177(11236)}{60310180}\\\\=\frac{1988772}{60310180}\\\\= 0.032976[/tex]

P-value= [tex]CHIDIST(0.032976,1) = 0.86.[/tex]

thus, the surgical-medical patients and Medicare are dependent.

Answer:

D.

Step-by-step explanation:

The gragh crosses the y-axis at (0,-5), decreasing from x=-10 to x=-2 and remaining constant from x=-2 to x=10

4 sin(x) + 9 cos(x) = 0

4 sin(x) = -9 cos(x)

tan(x) = -9/4

x = arctan(-9/4) + nπ … … … (in radians)

or

x = arctan(-9/4) + 180n ° … … … (in degrees)

where n is any integer.

I'm guessing you're solving for x over some domain, probably 0° ≤ x < 360°. In that case, you would have two solutions for n = 1 and n = 2 of

x ≈ 113.96°   and   x ≈ 293.96°

Answer:

Step-by-step explanation:

I answered your question in #24317186. Apparently you asked it twice and no one helped you yesterday.

Answer:

¼ và 2017

Step-by-step explanation:

Answer: For following equation x = 7 not a solution:

-5 = 2x-9

Answer:

Step-by-step explanation:

Put x to the equation.

4=-7+11 => 4=4 ✓

-3•7=7-28 =>-21=-21 ✓

-5•7= 2•7-9 =>-35=5 is incorrect.

5•7=2•7+21 =>35=35 ✓

Hence,for the third equation x is not a solution.

Answer: SP is Rs 690

Step-by-step explanation:

CP= Rs 750

loss percent = 8%

so

loss = 8% of CP

= 8/100 * 750

= Rs 60

Loss = Rs 60

so

SP = Rs 750-60

= Rs 690

Answer:

here,

CP=750

loss%=8%

now,

SP= (100-L)×cp/100

= (100-8)×750/100

= (92×750)/100

= 69000/100

= 690

hence the SP of the article is Rs 690

any problem then comment it

hope this helped you ☺️

Answer:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

Step-by-step explanation:

ok

Answer:

The question is incomplete.

It should be:

Find n(U)

Find n(A∩B):

If 24 and 7 are the lengths of the legs of the right triangle, the missing side, which is the hypotenuse, has a length of 25.

To find the missing side of the triangle, we need more information about the triangle. Specifically, we need to know which side is missing: the hypotenuse (longest side) or one of the legs.

If 24 and 7 are the lengths of the legs of a right triangle, we can use the Pythagorean theorem to find the length of the hypotenuse.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

Let's label the hypotenuse as 'c' and the legs as 'a' and 'b'.

Using the Pythagorean theorem:

[tex]c^2 = a^2 + b^2[/tex]

Substituting the given values:

[tex]c^2 = 24^2 + 7^2\\c^2 = 576 + 49\\c^2 = 625[/tex]

Taking the square root of both sides:

c = √625

c = 25

Therefore, if 24 and 7 are the lengths of the legs of the right triangle, the missing side, which is the hypotenuse, has a length of 25.

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Answer:

x = t/4 and y = (t+17)/3

Step-by-step explanation:

4x-3y+17=0

or, 4x=3y-17

let, 4x = t

so, x = t/4

and 3y-17 = t

or, 3y = t+17

or, y = (t+17)/3

Answered by GAUTHMATH

The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.

Answer:

4.5

Step-by-step explanation:

We are given opposite and adjacent, so use tangent

tan(37)=x/6

6tan(37)=4.521324301

A function is only a function if it passes the vertical line test, meaning every x-value has only one y-value. In the case of this graph, it does not pass the vertical line tests and has multiple y-values for each x-value.

Correct Answer: A. No; the graph fails the vertical line test.

B is incorrect because y-values can have more than 1 x-value, such as a function like y = 2. The opposite is the correct statement; x-values can have no more than 1 y-value. For example, x = 2 would not pass the vertical line test.

Hope this helps!

Answer:

8.49

Step-by-step explanation:

there is a little formula related to the famous formula of Pythagoras.

it says that the height of a triangle is the square root of the product of both segments of the baseline (the segments the height splits the baseline into).

so, x is actuality the height of the triangle.

x = sqrt(3×24) = sqrt(72) = 8.49

Answer and explanation:

Given two natural numbers n and n+3, we prove that the difference or their squares is even thus:

(n+3)²-(n)²= (n+3)(n+3)-(n)²

=n²+3n+3n+9-n²

=6n+9

Since the value of the difference of square of the natural numbers n and n+3 is in the form 6n+9, the difference is not an even number.

Answer:

1. a. 2

b. -½

c. y - 3 = -½(x - 8) => point-slope form

y = -½x + 7 => slope-intercept form

2. a. -1

b. 1

c. y - 5 = 1(x - 3) => point-slope form

y = x + 2 => slope-intercept form

Step-by-step explanation:

1. (8, 3) and (10, 7):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (8, 3) = (x_1, y_1) [/tex]

[tex] (10, 7) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]

Gradient = [tex] \frac{4}{2} [/tex]

Gradient = 2

b. The gradient of the line perpendicular to this line = the negative reciprocal of 2

Negative reciprocal of 2 = -½

c. The equation of perpendicular line if it passes through the first point, (8, 3):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (8, 3)

Slope (m) = -½

Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - 3 = -½(x - 8) => point-slope form

We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:

Thus:

y - 3 = -½(x - 8)

y - 3 = -½x + 4

y - 3 + 3 = -½x + 4 + 3

y = -½x + 7

2. (3, 5) and (4, 4):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (3, 5) = (x_1, y_1) [/tex]

[tex] (4, 4) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]

Gradient = [tex] \frac{-1}{1} [/tex]

Gradient = -1

b. The gradient of the line perpendicular to this line = the negative reciprocal of -1

Negative reciprocal of -1 = 1

c. The equation of perpendicular line if it passes through the first point, (3, 5):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (3, 5)

Slope (m) = 1

Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).

Thus:

y - 5 = 1(x - 3) => point-slope form

We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:

Thus:

y - 5 = 1(x - 3)

y - 5 = x - 3

y - 5 + 5 = x - 3 + 5

y = x + 2

Answer:

Step-by-step explanation:

[tex]in~the~expansion~of~(x+a)^n\\T_{r+1}=ncr x^{n-r}a^r\\r+1=3\\r=3-1=2\\n=4\\4c2=\frac{4 \times 3}{2 \times 1} =6\\T_{2}=4(x^2)^{4-2}(2)^2\\=16(x^2)^2\\=16x^4[/tex]

the third term is: 24*x^4

We want to find the third term of the equation:

(x^2 + 2)^4

So we need to expand that.

Remember the rule:

(a + b)^2 = a^2 + 2*a*b + b^2

(a + b + c)^2 = a^2 + b^2 + c^2 + 2*a*b + 2*b*c + 2*c*a

Then we can write:

(x^2 + 2)^4 = (x^2 + 2)^2*(x^2 + 2)^2

and we have:

(x^2 + 2)^2 = (x^4 + 2*2*x^2 + 2^2) = (x^4 + 4*x^2 + 4)

Then we have:

(x^2 + 2)^4 = (x^2 + 2)^2*(x^2 + 2)^2

(x^2 + 2)^4 = (x^4 + 4*x^2 + 4)^2

And we can expand this as:

(x^4)^2 + (4*x^2)^2 + 4^2 + 2*(x^4)*(4*x^2) + 2*(4*x^2)*(4) + 2*(x^4)*(4)

now we have this expanded, so we need to simplify this:

x^8 + 16*x^4 + 16 + 8*x^6 + 32*x^2 + 8*x^4

Putting the terms in order (larger degrees go in the left) we get:

x^8 + 8*x^6 + 16*x^4 + 8*x^4 + 32*x^2 + 16

x^8 + 8*x^6 + (16 + 8)*x^4 + 32*x^2 + 16

x^8 + 8*x^6 + 24*x^4 + 32*x^2 + 16

So the third term would be the third counting from the left, which is:

24*x^4

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Step-by-step explanation:

a+b+c=78

b=10+a

c=2b

then, we back the first

a+10+a+2b=78

2a+2b=78- 10

2a+2(10+a)=68

2a+2a=48

4a=48

a=12

b=22

c=44

Answer:

D.  y=x+1                   Linear

A.   y=x^2                 Quadratic

B.   y=(3/2)^x             Exponential

C.   y=x^2+2/x^2-2    Rational

Step-by-step explanation:

got it right :)

The correct option for the equations are:

The linear equation is an equation whose highest degree of the variable is 1 which represents the graph of the straight line.

For example y=2x+3

The quadratic equation is an equation whose highest degree of the variable is 2 and it has at most 2 solutions.

For example, y=3x²

Here given that the functions are given in the figure and we have to identify the appropriate graph.

Checking all the equations individually

Therefore the correct option for the equations are:

Learn more about linear equation

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Answer:

Solution given:

16+28=44

(4+7)=11

Answer:

The solution is 4

Step-by-step explanation:

Step 1:  Find the correct answer

I'm not really sure what you are asking but I will give it a shot.

16 + 28 = ___ (4 + 7)

44 = ___ (11)

44 / 11 = ___ (11) / 11

4 = ___

Answer:  The solution is 4

Answer:

120

Step-by-step explanation:

Since the figures are similar the angles are the same

<A = <F

<B = <E

<C = <C

<D = <G

We know <G = 120 so angle D = 120

W = <D = 120

Answer:

w = 120 degrees

Step-by-step explanation:

ABCD and FECG are the same shapes, which means they also have the same angles.

∠A = ∠F

∠B = ∠E

∠C = ∠C

∠D = ∠G

∠G = 120°, so D = 120°

So, w = 120°

Step-by-step explanation:

3(t-3)=5(2t-1)

= 3t-9=10t-5

= 3t-10t = -5+9

= -7t = 4

= -t = 4/7

= - 4/7 Answer

hope it helps

Answer:

50 Candy

Step-by-step explanation:

We know that 2/5 of the bag is 60 candy. By taking this information we can conclude that 1/5 of the bag is 30 candy. We know that 1/5 of the bag is 30, so 30 times 5 is 150 candy.

Now that we have found out that there is 150 candy total we can know divde 150 by 3 to find out how much candy is in 1/3 of the bag.

150/3 = 50 Candy

1/3 of the bag represent 50 candy.

Answer:

[tex](x + 7) * (3x + 1) = (3x^2 + 22x + 7)[/tex]

Step-by-step explanation:

Given

[tex](3x^2 + 22x + 7) \div (x + 7) = 3x + 1[/tex]

[tex](x + 7) * (\ ) = [\ ][/tex]

Required

Complete the blanks

We have:

[tex](3x^2 + 22x + 7) \div (x + 7) = 3x + 1[/tex]

Rewrite as:

[tex]\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1[/tex]

Cross multiply

[tex](x + 7) * (3x + 1) = (3x^2 + 22x + 7)[/tex]

Answer:

Answer B, C, C

Answer:

The average, mode, and median of the results are 5, meaning that half of the time the quarter will land on heads.

Step-by-step explanation:

The required dot plot shows the result of the experiment performed by flipping a quarter 21 times.

In an experiment, a student is to flip a quarter 10 times and record the number of times heads appears. A group of students performs the experiment 21 times, with these results. 6 4 5 6 5 6 4 6 2 4 3 4 5 7 5 8 7 5 3 5 5.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

Statistics is the study of mathematics that deals with relations between comprehensive data.

Here,
The dot plot has been made, for the number of outcomes and their frequencies. The dot plot gives the info about the mean mode and median.

Thus, the required a dot plot showing the result of the experiment performed by flipping a quarter 21 times.

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Answer:

Step-by-step explanation:

We need to first find the perimeter of this oddly-shaped rink. We have a rectangle for which we are enclosing 3 of its sides, and the fourth "side" is a half-circle. Let's find the perimeter (or circumference) of the circle, divide it in half because we have half a circle, then add in the remaining 3 sides from the rectangle, shall we?

C = πd. The diameter of the circle is the same as the shorter length in the rectangle, 26. Therefore,

C = (3.14)(26) so

C = 81.64 m for a whole circle, and for half of that circle, the circumference is

C = 40.82 m

Now we can find the perimeter of the rink:

40.82 + 61 + 26 + 61 = p so

p = 188.82 m

If the fencing costs $6.20 per meter and we have 188.82 m, then the total cost is

[tex]cost=\frac{6.20dollars}{meter}*188.82meters[/tex]. The label "meter" cancels out, leaving us with

cost = $1170.82

Answer: (13,-7)

Step-by-step explanation:

By using the formula [tex](x_{m},y_{m}) =(\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2} )[/tex]

[tex](x_{m},y_{m})\\[/tex] is the coordinates of the midpoint.

For finding the midpoint X variable do:

[tex](\frac{4+22}{2})=13[/tex]

For finding the midpoint Y variable do:

[tex]\frac{-10+(-4)}{2} = -7[/tex] (you can either keep the parenthesis or take them out. Either way, the answer is the same.

Considering coordinate numbers follow the format: (x,y), you'll simply just substitute the numbers found above into their respective places.

x: 13

y: -7

(13,-7).